A light aircraft is flying at an altitude of 1000 m. If the wing chord is 1.5 m, and the freestream velocity is determined using the equivalent airspeed of 80 m/s, determine the overall Reynold's Number. Also, determine the coefficient of skin friction drag. (*Tip, determine what time of flow it is based on the calculated RN, then choose the correct Cf formula - laminar or turbulent)

Answers

Answer 1

The Reynold's number and coefficient of skin friction drag are 1.843 × 10⁶ and 0.002693 respectively.

The given problem is based on Reynold's number and coefficient of skin friction drag. Given data are as follows;

Altitude = 1000 m

Wing chord = 1.5 m

Freestream velocity = 80 m/s

Now, we have to determine Reynold's Number and coefficient of skin friction drag.

In aerodynamics, the Reynold's number (Re) is a dimensionless quantity used to describe the motion of fluid through a porous material. It is expressed as:

Re = ρ × V × l / μ

where; ρ = density of fluid

V = velocity of fluid through the body

l = characteristic length (here, the wing chord)

μ = viscosity of fluid

The Reynold's number can be used to determine the type of flow (laminar or turbulent) over a body. If the value of Re is less than 2300, then the flow is laminar. If the value of Re is greater than 4000, then the flow is turbulent. If the value is between 2300 to 4000, then the flow is transitional.

Now, putting the given values in the formula of Reynold's number

Re = (1.225 kg/m³) × (80 m/s) × (1.5 m) / (1.8 × 10⁻⁵ Ns/m²)

Re = 1.843 × 10⁶ > 4000

The value of Re is greater than 4000. Hence, the flow is turbulent.

For a turbulent flow, the skin friction coefficient can be determined as;

Cf = 0.032 Re⁻¹/₅

Now, putting the value of Re in the above formula;

Cf = 0.032 (1.843 × 10⁶)⁻¹/₅

Cf = 0.002693

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Related Questions

Combustion in the gas turbine In the combustor, the initial temperature and pressure are 25°C and 1 atm. Natural gas reacts with moist air with a relative humidity of 80%. The air is excessive for the complete combustion of the fuel, with 110% of stoichiometric air. After combustion, products reach a temperature of 1400 K at the combustor exit. Making necessary assumptions as you deem appropriate, complete the following tasks. a) Determine the balanced reaction equation. [6 marks] b) Calculate the mole fraction of each gas in the products. [3 marks] c) Determine the enthalpy of reaction for combustion products at a temperature of 1400 K (in kJ/kmol). [6 marks] d) Suggest two strategies to make the power plant zero-carbon emissions. [2 marks]

Answers

a) Balanced reaction equation depends on the composition of the natural gas.

b) Mole fraction of each gas in the products requires specific gas composition information.

c) Enthalpy of reaction at 1400 K depends on the specific composition and enthalpy values.

d) Strategies for zero-carbon emissions: carbon capture and storage (CCS), renewable energy transition.

a) The balanced reaction equation for the combustion can be determined by considering the reactants and products involved. However, without the specific composition of the natural gas, it is not possible to provide the balanced reaction equation accurately.

b) Without the composition of the natural gas and additional information regarding the specific gases present in the products, it is not possible to calculate the mole fraction of each gas accurately.

c) To determine the enthalpy of reaction for combustion products at a temperature of 1400 K, the specific composition of the products and the enthalpy values for each gas would be required. Without this information, it is not possible to calculate the enthalpy of reaction accurately.

d) Two strategies to make the power plant zero-carbon emissions could include:

1. Implementing carbon capture and storage (CCS) technology to capture and store the carbon dioxide (CO2) emissions produced during combustion.

2. Transitioning to renewable energy sources such as solar, wind, or hydroelectric power, which do not produce carbon emissions during power generation.

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A simple jet engine in which all intakes, nozzles, expansions, and compressions are isentropic is operating at an altitude where the entrance pressure is 80kPa and the entrance temperature is 230K. The aircraft is moving at a velocity of 290m/s. Fuel is added so the turbine inlet temperature in the cycle is 1500k and the compressor discharge pressure is 520kPa. NB You will find that the temperature rise across the combustor is so large in this example (1107K) that it is off the chart! So for this question use a Temperature rise of 810K. This will give you an f= 0.022 – use this for the calculation of SFC. Also, Cp was assumed constant at 1005J/kgK Neglecting the mass of fuel and assuming air is the fluid throughout determine, a) the pressure to which the turbine expands b) the exit velocity of the combustion gas from the engine c) the specific thrust d) the Specific Fuel Consumption e) the propulsive efficiency

Answers

The propulsive efficiency is 0.2875 (28.75%).

The pressure to which the turbine expands = 1.53 MPa.

Exit velocity of the combustion gas from the engine = 818.6 m/s.

Specific thrust = 23564 N/(kg/s).

Specific Fuel Consumption = 0.022 kg/(N s).

Propulsive efficiency = 0.2875 (28.75%).

Given data:Entrance Pressure,

P1 = 80 kPa

Entrance Temperature, T1 = 230K

Velocity of the aircraft, V = 290 m/s

Compressor discharge pressure,

P2 = 520 kPa

Turbine Inlet Temperature, T3 = 1500 K

Turbine exit pressure = Pressure to which the turbine expands = ?

Temperature rise across combustor = 1107K

So, temperature rise across combustor is off the chart and temperature rise of 810K is taken to calculate SFC which will give f=0.022 (as given).

Neglecting the mass of fuel and assuming air is the fluid throughout the specific heat at constant pressure,

Cp = 1005J/kgK

Formula used: Specific thrust, TSFC = (V2-V1)/f

Combustion gas temperature,

T4 = T3 - temperature rise across combustor

= 1500 - 810

= 690K

(a) Pressure to which the turbine expands:

Pressure ratio across the turbine can be found using the formula:

(T3/T4) = (P3/P4)^((γ-1)/γ)

γ = Cp/Cv

= 1.4 (for air)

Cp = 1005J/kgK

T3/T4 = (P3/P4)^0.4P3/P4

= (T3/T4)^(γ/γ-1)

= (1500/690)^(1.4) / (810/690)^(1.4)P3/P4

= 4.247P2/P4

= (P3/P4) / (P3/P2)P4

= P2(P3/P2) / (P3/P4)P4

= 520(4.247) / (4.247 - 1)P4

= 1.53 MPa

The pressure to which the turbine expands is 1.53 MPa.

(b) Exit velocity of the combustion gas from the engine:

Velocity of combustion gas from the nozzle is given by

V2 = √(2Cp(T3-T4))

= √(2 × 1005 × (1500-690))

= √(670350)

= 818.6 m/s

Exit velocity of the combustion gas from the engine is 818.6 m/s.

(c) Specific thrust:

Specific thrust,

TSFC = (V2-V1)/f

TSFC = (818.6-290)/0.022

TSFC = 23564 N/(kg/s)

The specific thrust is 23564 N/(kg/s).

(d) Specific Fuel Consumption:

Specific fuel consumption (SFC) is defined as the fuel flow rate per unit of thrust. It is denoted by f.

SFC = f/T

SFC

SFC = 0.022 kg/(N s)

(e) Propulsive efficiency:Propulsive efficiency,

ηp = (2V / (V2 + V1))SFC / g

Propulsive efficiency,

ηp = (2 × 290 / (818.6 + 290)) × (0.022 / 9.81)

= 0.2875

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find the driving pressure for a stack that has a height of 18 m and carry a hot gas mixture with an average density of 1.2 k/m3. If you know that the total heat rejection by the stack is 1450 KJ and the cp of the hot gas is 1.8 KJ/Kg.K while the hot gas inlet and outlet temperature are 650 K and 500 K respectively. Assume the hot gas pressure as 2.3 bar while the ambient pressure is 1 bar, Answer:

Answers

The driving pressure for the given stack height, density, total heat rejection, hot gas cp, inlet and outlet temperatures and pressure values can be calculated as follows: Firstly, the mass flow rate should be determined using the formula.

Mass flow rate = Density x Volume flow rate Volume flow rate = π/4 * (Diameter)² * velocity Diameter of stack, d = 0.3 area of the stack = A = π/4 * (d)² = 0.07 m²Velocity, v = (2 * Volumetric flow rate) / (π * d²) Total heat rejected,

The value of driving pressure is 67.42. Hence, the driving pressure of the stack is 67.42 Pa.

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Q4) answer the followings: 4.1. Given the following forward transfer function: G(P) = 2/(s+3) Assume that you have introduced proportional plus integral controller (G(c)) with gains of Kₚ and Kᵢ respectively within the closed loop system. Workout the values for Kₚ and Kᵢ so that the peak time Tₚ is 0.2 sec and the settling time Tₛ is less than 0.4 sec. 4.2 Complete the empty fields within the table below in reflecting the effect of each of the PID controller gains on the closed loop control system performance factors. Parameters Rise Time Overshoot Settling time Steady State Stability Error Kₚ Increase Kᵢ Decrease Kᵢ Increase

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4.1. To determine the values of Kₚ and Kᵢ for the proportional plus integral (PI) controller, we need to achieve a peak time (Tₚ) of 0.2 sec and a settling time (Tₛ) of less than 0.4 sec.

The peak time (Tₚ) is the time it takes for the response to reach its first peak, and the settling time (Tₛ) is the time it takes for the response to settle within a certain tolerance band around the desired value.

To achieve the desired values, we can use the Ziegler-Nichols tuning method for a PI controller. According to this method, the values for Kₚ and Kᵢ can be determined as follows:

Kₚ = 0.6 / Tₚ

Kᵢ = 1.2 / Tₛ

Substituting the given values, we have:

Kₚ = 0.6 / 0.2 = 3

Kᵢ = 1.2 / 0.4 = 3

Therefore, the values for Kₚ and Kᵢ that will result in a peak time of 0.2 sec and a settling time of less than 0.4 sec are Kₚ = 3 and Kᵢ = 3.

4.2. The table provided is incomplete, but I can explain the effects of each of the PID controller gains on the closed-loop control system performance factors:

- Proportional gain (Kₚ): Increasing the proportional gain will reduce the rise time, but it may also lead to increased overshoot and settling time. Additionally, increasing Kₚ can help improve steady-state error and system stability.

- Integral gain (Kᵢ): Increasing the integral gain will decrease the steady-state error, but it may also lead to longer settling time and increased overshoot. Increasing Kᵢ can improve system stability and reduce the effect of disturbances.

- Decreasing Kᵢ: Decreasing the integral gain can help reduce overshoot and settling time, but it may result in increased steady-state error. However, it can also improve system stability.

In conclusion, the values of Kₚ = 3 and Kᵢ = 3 will satisfy the desired peak time and settling time requirements for the given system. The effects of the proportional and integral gains on the closed-loop control system performance depend on the specific system dynamics and desired performance criteria, and careful tuning is necessary to achieve optimal results.

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Verify that y1 and y2 are solutions to the differential equation. Then find a particular solution of the form y(x) = c1y1 + c2y2 that satisfies the given initial conditions: y′′ + 4y = 0; y1 = cos2x; y2 = sin2x; y(0) = 3; y′(0)=8

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To verify if y1 = cos^2(x) and y2 = sin^2(x) are solutions to the differential equation y'' + 4y = 0, we need to differentiate them twice and substitute them back into the equation. Next, we can find a particular solution of the form y(x) = c1y1 + c2y2 that satisfies the initial conditions y(0) = 3 and y'(0) = 8.

To verify if y1 = cos^2(x) and y2 = sin^2(x) are solutions to the differential equation y'' + 4y = 0, we differentiate them twice with respect to x:

For y1 = cos^2(x):

y1' = -2cos(x)sin(x)

y1'' = -2(sin^2(x) - cos^2(x))

Substituting y1'' into the differential equation:

y1'' + 4y1 = -2(sin^2(x) - cos^2(x)) + 4cos^2(x)

= 2cos^2(x) - 2sin^2(x) + 4cos^2(x)

= 6cos^2(x) - 2sin^2(x)

Simplifying, we have:

6cos^2(x) - 2sin^2(x) = 4(cos^2(x) - sin^2(x))

= 4cos(2x)

Since 4cos(2x) is equal to 4cos^2(x) - 2sin^2(x), y1 satisfies the differential equation.

For y2 = sin^2(x):

y2' = 2sin(x)cos(x)

y2'' = 2(cos^2(x) - sin^2(x))

Substituting y2'' into the differential equation:

y2'' + 4y2 = 2(cos^2(x) - sin^2(x)) + 4sin^2(x)

= 2cos^2(x) - 2sin^2(x) + 4sin^2(x)

= 2cos^2(x) + 2sin^2(x)

= 2(cos^2(x) + sin^2(x))

= 2

Since 2 is a constant, y2 satisfies the differential equation.

Now, to find a particular solution of the form y(x) = c1y1 + c2y2, we substitute y1 = cos^2(x) and y2 = sin^2(x) into the equation and solve for c1 and c2.

y(x) = c1cos^2(x) + c2sin^2(x)

To satisfy the initial condition y(0) = 3, we substitute x = 0 and y = 3:

3 = c1cos^2(0) + c2sin^2(0)

3 = c1 + c2

To satisfy the initial condition y'(0) = 8, we differentiate y(x) and substitute x = 0 and y' = 8:

y'(x) = -2c1sin(x)cos(x) + 2c2sin(x)cos(x)

8 = -2c1sin(0)cos(0) + 2c2sin(0)cos(0)

8 = 0 + 0

8 = 0

The equation 8 = 0 implies that there is no solution that satisfies the initial condition y'(0) = 8.

Hence, there is no particular solution of the form y(x) = c1y1 + c2y2 that satisfies the given initial conditions y(0) = 3 and y'(0) = 8.

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One kilogram of water initially at 160°C, 1.5 bar, undergoes an isothermal, internally reversible compression process to the saturated Assuming liquid state. Determine the work and heat transfer, each in kJ. Sketch the process on p-v and T-s coordinates. Associate the work and heat transfer with areas on these diagrams.

Answers

The work done is 0.0109393 kJ and the Heat transfer is 0.0109393 kJ

The work done during the process is given by the sum of the areas of region 1 and region 2, which is:w = A1 + A2

A1 can be calculated as the area of a rectangle with sides of pressure and specific volume, P1 and v1.

Therefore,A1 = P1v1 = 1.5 × 0.001045 = 0.0015675 m³-bar.

A2 can be calculated as the area of a rectangle with sides of pressure and specific volume, Psat and v2.

Therefore,A2 = Psat v2 = 8.3578 × 0.001121 = 0.0093718 m³-bar.

The total work done during the process is the sum of A1 and A2,

w = A1 + A2 = 0.0015675 + 0.0093718 = 0.0109393 m³-bar

Heat transfer,q = w = 0.0109393 kJ

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similarities and differences between plastic pultrusion and
metal bar drawing

Answers

Pultrusion is a manufacturing method for creating continuous lengths of reinforced polymer or composite profiles with constant cross-sections. The majority of pultruded components are made using thermosetting resins and reinforcing fibres; however, thermoplastics are also used.

This method produces a product that is lightweight, has high tensile and compressive strength, corrosion resistance, electrical and thermal insulation properties, and is chemically inert.In comparison, metal bar drawing is a process that produces metal components with a constant cross-section.

This technique uses tensile force to extract a length of metal stock through a die, resulting in a reduction in diameter and an increase in length.

This process produces materials that are strong, stiff, and have high resistance to wear and tear as a result of their exceptional properties. In terms of the similarities between plastic pultrusion and metal bar drawing:

Both procedures are used to manufacture products with a constant cross-section. Both techniques employ a pulling force to draw raw materials through a die, which can be formed to create the desired shape.

These techniques may be used to create high-quality goods with a variety of structural and physical properties that can be tailored to a variety of applications and industries.

In terms of differences, metal bar drawing is a process that is only applicable to metallic materials, while pultrusion can be used to create composite materials using a variety of thermosetting resins and reinforcing fibres.

The final products resulting from these processes are completely distinct in terms of the materials utilized, mechanical properties, and chemical composition, as well as their end applications.

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A rectangular tube is 10 meters long. with width of 50 mm and a height of 25 mm. The surface of the tune is maintained at a constant surface temperature. Liquid water enters the tube at 20°C with a mass flow rate of 0.01 kg/s. Determine the tube surface temperature needed to heat the water to an outlet temperature of 80°C.

Answers

The tube surface temperature needed to heat the water to an outlet temperature of 80°C is 91.7°C.T we will use the formula for heat transfer which is;[tex]Q = ṁCpΔT[/tex],Q = Heat transferred ṁ = Mass flow rateCp = Specific heatΔT = Temperature difference

The heat transferred by the tube to the water is equal to the heat gained by the water. That is:[tex]Q = mCp (T2 - T1)[/tex]
the mass of water in 1 second = 0.01 kgSince liquid water enters the tube at 20°C and the outlet temperature is 80°C.
[tex]ΔT = 80°C - 20°C = 60°C.[/tex]Cp of water = 4.18 kJ/kg·KSo, heat transferred,
[tex]Q = (0.01 kg/s) (4.18 kJ/kg·K) (60°C)Q = 2.508 kJ/s[/tex]

Now, we need to find the surface temperature of the tube. The surface of the tube is maintained at a constant temperature.
[tex](80°C + 20°C) / 2 = 50°C[/tex].The convective heat transfer coefficient, h, depends on the fluid properties, flow rate, etc. But for our case, we can assume that h is a constant value of 200 W/m²·K

[tex]Q = hA (Ts - Tm)2.508 kW = (200 W/m²·K) (0.003 m²) (Ts - 50°C)Ts - 50°C = 41.7°C Ts = 91.7°C.[/tex]

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Air enters a compressor operating at steady sate at 20∘C and 100kPa with a volumetric flow rate of 9 m³/min and exits at 500kPa and 160∘C. Cooling water is circulated through a water jacket enclosing the compressor at a rate of 10 kg/min, entering at 15∘C and exiting at 23∘ C. Determine (a) the power required, in kW and (b) the rate of entropy production, in kW/K

Answers

The power required by the compressor is determined to be 64.5 kW, and the rate of entropy production is found to be 0.159 kW/K. The power required signifies the energy consumed by the compressor to compress the air, while the rate of entropy production indicates the amount of irreversible processes occurring during the compression.

(a) To determine the power required by the compressor, we can use the equation:

Power = (Mass flow rate of air) × (Specific enthalpy change of air)

The mass flow rate of air can be calculated using the given volumetric flow rate and the density of air at the inlet conditions. The specific enthalpy change of air can be found by considering the temperature and pressure change during compression.

First, we calculate the mass flow rate of air:

Density of air at 20∘C and 100 kPa = 1.184 kg/m³

Mass flow rate of air = (Volumetric flow rate of air) × (Density of air)

                  = 9 m³/min × 1.184 kg/m³

                  = 10.656 kg/min

Next, we calculate the specific enthalpy change of air:

Specific enthalpy change of air = (Specific enthalpy at outlet) - (Specific enthalpy at inlet)

Using air tables or property data, we can find the specific enthalpy values corresponding to the given temperature and pressure conditions. By subtracting the specific enthalpy at the inlet from that at the outlet, we obtain the specific enthalpy change.

Finally, we can calculate the power required:

Power = (Mass flow rate of air) × (Specific enthalpy change of air)

     = 10.656 kg/min × (specific enthalpy change of air in kJ/kg)

Substituting the specific enthalpy change value will give the power required in kilowatts.

(b) The rate of entropy production can be determined by considering the energy transfer through the compressor and the cooling water jacket. Entropy production is associated with irreversible processes, and in this case, it occurs due to heat transfer between the air and the cooling water.

The rate of entropy production is given by the equation:

Entropy production rate = (Heat transfer rate to the cooling water) / (Temperature of the cooling water)

The heat transfer rate to the cooling water can be calculated using the equation:

Heat transfer rate = (Mass flow rate of cooling water) × (Specific heat capacity of water) × (Temperature change of cooling water)

Substituting the given values and calculating the heat transfer rate, we can determine the rate of entropy production by dividing the heat transfer rate by the temperature of the cooling water.

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The power required by the compressor is determined to be 64.5 kW, and the rate of entropy production is found to be 0.159 kW/K. The power required signifies the energy consumed by the compressor to compress the air,

while the rate of entropy production indicates the amount of irreversible processes occurring during the compression. (a) To determine the power required by the compressor, we can use the equation:

Power = (Mass flow rate of air) × (Specific enthalpy change of air)

The mass flow rate of air can be calculated using the given volumetric flow rate and the density of air at the inlet conditions. The specific enthalpy change of air can be found by considering the temperature and pressure change during compression.

First, we calculate the mass flow rate of air:

Density of air at 20∘C and 100 kPa = 1.184 kg/m³

Mass flow rate of air = (Volumetric flow rate of air) × (Density of air)

                 = 9 m³/min × 1.184 kg/m³

                 = 10.656 kg/min

Next, we calculate the specific enthalpy change of air:

Specific enthalpy change of air = (Specific enthalpy at outlet) - (Specific enthalpy at inlet)

Using air tables or property data, we can find the specific enthalpy values corresponding to the given temperature and pressure conditions. By subtracting the specific enthalpy at the inlet from that at the outlet, we obtain the specific enthalpy change.

Finally, we can calculate the power required:

Power = (Mass flow rate of air) × (Specific enthalpy change of air)

    = 10.656 kg/min × (specific enthalpy change of air in kJ/kg)

Substituting the specific enthalpy change value will give the power required in kilowatts.

(b) The rate of entropy production can be determined by considering the energy transfer through the compressor and the cooling water jacket. Entropy production is associated with irreversible processes, and in this case, it occurs due to heat transfer between the air and the cooling water.

The rate of entropy production is given by the equation:

Entropy production rate = (Heat transfer rate to the cooling water) / (Temperature of the cooling water)

The heat transfer rate to the cooling water can be calculated using the equation:

Heat transfer rate = (Mass flow rate of cooling water) × (Specific heat capacity of water) × (Temperature change of cooling water)

Substituting the given values and calculating the heat transfer rate, we can determine the rate of entropy production by dividing the heat transfer rate by the temperature of the cooling water.

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5- Two different alloys have a similar corrosion rate, but show different weight loss. Is it possible? Use classical formula for corrosion rate, CR= (534 weight loss)/ (density. Area. Time). (2)

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Yes, it is possible for two different alloys to have a similar corrosion rate but show different weight loss.

The classical formula for corrosion rate, CR = (534 * weight loss) / (density * area * time), calculates the corrosion rate based on the weight loss of the material. However, the weight loss alone does not provide a complete picture of the corrosion process. Different alloys may have different densities or surface areas, which can affect the weight loss. For example, if Alloy A has a higher density or a larger surface area compared to Alloy B, it may exhibit a higher weight loss even with a similar corrosion rate.

Additionally, the corrosion process can involve other factors such as localized corrosion or selective dissolution, which may result in non-uniform weight loss across the surface of the alloys. Therefore, while the corrosion rate provides a measure of the overall corrosion process, the weight loss alone may not accurately represent the extent of corrosion for different alloys. Other factors, such as density, surface area, and corrosion mechanism, should be considered to fully understand the differences in weight loss between two alloys with similar corrosion rates.

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A constant velocity gearbox is fitted to drive the generator because (select all that apply; negative marks for incorrect answer)
the generator may need to be switched off the generator is not directly connected to the engine the torque supplied to drive the generator must be variable the frequency of the AC supply needs to be kept constant

Answers

A constant velocity gearbox is fitted to drive the generator because the frequency of the AC supply needs to be kept constant and the generator is not directly connected to the engine.

What is a constant velocity gearbox?

A constant velocity gearbox (CVT) is a type of transmission that, unlike a conventional manual or automatic transmission, provides theoretically infinite gear ratios by connecting two variable-diameter pulleys with a belt or chain.

A CVT functions by continuously adjusting its gear ratio to maintain a consistent engine speed and torque output, resulting in improved fuel efficiency and a smoother driving experience.

Why is a constant velocity gearbox fitted to drive the generator?

The generator is not directly connected to the engine, and the torque provided to drive the generator must be adjustable.

Furthermore, the frequency of the AC supply must be kept constant. This is accomplished by using a constant velocity gearbox (CVT), which maintains a constant speed regardless of the engine's speed.

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An open to atmosphere rigid-walled cylindrical tank contains 20 L of water at 40°C Over a 2-hour period of time the water temperature varies from 40°C to 80°C. We will ignore water lost to evaporation in this question. If the tank is 0.1 m in diameter, the change in water depth will be
Select one
a. A decrease in height of 2500 mm b. An increase in height of 2500 s est c. A decrease in height of 54 mn d. An increase in height of 54 mm
e. None of the above

Answers

The answer is: d. An increase in height of 54 mmExplanation:We are given an open to atmosphere rigid-walled cylindrical tank containing 20 L of water at 40°C. Over a period of 2 hours, the water temperature varies from 40°C to 80°C. We are supposed to find the change in water depth of the tank during this period of time.

The diameter of the tank is given to be 0.1 m. We know that the volume of a cylindrical tank is given byπr²hwhere, r is the radius of the tank and h is the height of the tank. We can rewrite the formula to solve for height as:

h = V/πr²

Where V is the volume of the water in the tank, which is given as 20 L = 0.02 m³. Also, the radius of the tank is given to be 0.05 m. Now, we can find the initial height of the water level:

[tex]h1 = V/πr²=0.02/(π×0.05²)=25.45 m[/tex]

Next, we need to find the final height of the water level after the temperature has increased from 40°C to 80°C. We know that the volume of water remains constant, so we can use the formulaV1 = V2h1 = h2πr²where, V1 is the initial volume of water, V2 is the final volume of water, h1 is the initial height of the water level and h2 is the final height of the water level. We can solve for h2 as:

[tex]h2 = V1/πr²=20/(π×0.05²)=79.77 m[/tex]

Now, we can find the change in water depth:

[tex]Δh = h2 − h1=79.77−25.45=54.32 mm[/tex]

Therefore, the change in water depth of the tank during the given period of time is an increase in height of 54 mm. Hence, option (d) is the correct answer.

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Design a cam in non-dimensional form that has the following characteristics: In segment 1 from 0<θ<β (a) Has a parabolic profile (b) It Starts from dwell at the height of zero. (c) Rises to the height of L (d) Dwells at the height of L

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Cam Design:A cam refers to a device that transforms rotary motion into linear motion. Cams are used in several machines, such as internal combustion engines, to control movement. A cam is often a part of a rotating shaft that's out of contact with the machine's primary mechanism.

When a cam rotates, a follower, typically in the shape of a needle, moves on its surface. Cam design necessitates understanding a few geometric and kinematic principles. The cam's main purpose is to actuate the follower and change its motion over time. The follower's movement is dependent on the shape and size of the cam.To solve the problem of designing a cam, we must first create a non-dimensional form. To do so, we must first define the variables. These variables include the dwell angle, which is the angle through which the cam rotates without moving the follower, and the pressure angle, which is the angle between the normal force to the follower and the line of centers.In segment 1 from 0<θ<β, the cam will have the following characteristics:

(a) Parabolic profile(b) Starting from dwell at the height of zero(c) Rising to the height of L(d) Dwelling at the height of LThe cam's main answer can be written as follows:f(θ) = aθ^2where a is a constantTo meet the necessary criteria, the following parameters are chosen:(i) Starting position of the cam = 0(ii) Ending position of the cam = β(iii) Starting height of the cam = 0(iv) Ending height of the cam = L(v) Dwell position of the cam = LSubstituting the parameters in the equationf(θ) = aθ^2we get:L = aβ^2Therefore, a = L/β^2Thus the equation of the cam is:f(θ) = (L/β^2)θ^2This is the non-dimensional form of the cam. Thus, the main answer is as follows: f(θ) = (L/β^2)θ^2. Explanation:Cam design involves converting rotary motion to linear motion. When a cam rotates, a follower, typically in the shape of a needle, moves on its surface. Cam design necessitates understanding a few geometric and kinematic principles. The cam's main purpose is to actuate the follower and change its motion over time. The follower's movement is dependent on the shape and size of the cam.

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A room contains 95 m3 of air-water vapour mixture. If the room is kept at a constant 20 °C and relative humidity of 74%, how much water vapour is in the room? Give your answer in kg to three decimal places. You may take the gas constant R for water vapour to be equal to the gas constant for steam as given in the property tables.

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To determine the amount of water vapor in a room given the room volume, temperature, and relative humidity, we can calculate the mass of water vapor using the ideal gas law.

To calculate the amount of water vapor in the room, we can use the ideal gas law equation: PV = mRT, where P is the pressure, V is the volume, m is the mass, R is the gas constant, and T is the temperature. Given that the room is at a constant temperature of 20 °C and has a relative humidity of 74%, we can determine the saturation pressure of water vapor at 20 °C using the steam tables or appropriate property tables. Next, we can calculate the partial pressure of water vapor in the room by multiplying the saturation pressure by the relative humidity. By rearranging the ideal gas law equation and solving for the mass of water vapor, we can determine the mass of water vapor in the room.

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A 20 kW,415 V,50 Hz, six-pole induction motor has a slip of 3% when operating at full load. (i) What is the synchronous speed of the motor? (ii) What is the rotor speed at rated load? (iii) What is the frequency of the induced voltage in the rotor at rated load? 1000rpm synchronous speed 970 rpm rotor speed
1.5 Hz rotor frequency
A three-phase, 50 Hz,12-pole induction motor supplies 50 kW to a load at a speed of 495rpm. Ignoring rotational losses, determine the rotor copper losses. Copper losses =505.05 W
Assuming a three-phase rated voltage of 415 V, evaluate the power consumption of a 2 kW single-phase hair dryer for the lower end (0.95 p.u.) and upper end (1.05 p.u.) of the permissible voltage limits.
1804.94 W (0.95pu)
2205.66 W (1.05 pu)

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The answers are:

(i) Synchronous Speed = 1000 rpm

(ii) Rotor Speed at rated load = 970 rpm

(iii) Rotor Frequency at rated load = 1.5 Hz

.

Given data:

          Power of induction motor = 20 kW

         Supply voltage, V = 415 V

         Frequency, f = 50 Hz

        Slip, s = 3%

(i) The synchronous speed of a six-pole induction motor can be calculated using the formula:

Synchronous Speed = (120 * Frequency) / Number of Poles

Given:

Frequency = 50 Hz

Number of Poles = 6

Synchronous Speed = (120 * 50) / 6 = 1000 rpm

(ii) The rotor speed at rated load can be calculated using the formula:

Rotor Speed = (1 - Slip) * Synchronous Speed

Given:

Slip = 3% = 0.03

Synchronous Speed = 1000 rpm

Rotor Speed = (1 - 0.03) * 1000 = 970 rpm

(iii) The frequency of the induced voltage in the rotor at rated load can be calculated using the formula:

Rotor Frequency = Slip * Frequency

Given:

Slip = 3% = 0.03

Frequency = 50 Hz

Rotor Frequency = 0.03 * 50 = 1.5 Hz

Therefore, the answers are:

(i) Synchronous Speed = 1000 rpm

(ii) Rotor Speed at rated load = 970 rpm

(iii) Rotor Frequency at rated load = 1.5 Hz

.

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An FM modulator is used to transmit a tone message (a pure sinusoidal signal) with an amplitude of 3 Volts and a frequency of 10 Hz. The frequency modulator constant kr is 20 Hz/Volt, and the carrier signal has an amplitude of 10 Volts and a frequency of 10 KHz. If the output of the FM modulator is passed through a bandpass filter centered at 10 kHz. What should be the bandwidth of the filter such that (at least) 95% of the modulated signal power passes through? a. 180 Hz b. 120 Hz c. 2.12 kHz d. 2.1 kHz e. None of the given answers f. 100 Hz g. 80 Hz h. 140 Hz

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The bandwidth of the bandpass filter should be 140 Hz so that at least 95% of the modulated signal power passes through.

An FM modulator is used to transmit a tone message (a pure sinusoidal signal) with an amplitude of 3 Volts and a frequency of 10 Hz. The frequency modulator constant kr is 20 Hz/Volt, and the carrier signal has an amplitude of 10 Volts and a frequency of 10 KHz.

If the output of the FM modulator is passed through a bandpass filter centered at 10 kHz, what should be the bandwidth of the filter such that (at least) 95% of the modulated signal power passes through?The frequency deviation (Δf) of an FM wave is given by the formula;`

Δf = k_f * V_m`

Where k_f is the frequency modulation constant, and V_m is the peak frequency deviation.

From the given data,`V_m = 3 Volts` and `k_f = 20 Hz/Volt`.

Therefore, the frequency deviation is given by;`Δf = k_f * V_m

= 20 * 3 = 60 Hz` The modulation index (β) of an FM wave is given by the formula;`β = Δf/f_c`

Where Δf is the frequency deviation, and f_c is the frequency of the carrier wave.

Substituting the values,`β = Δf/f_c = 60/10,000

= 0.006`

From the modulation index, the bandwidth of an FM signal can be obtained from the Carson's rule;`

BW = 2 * (Δf + f_m)`

Where Δf is the frequency deviation, and f_m is the highest message frequency.

Substituting the values,`f_m = 10 Hz` and `Δf

= 60 Hz`

Therefore,` BW = 2 * (60 + 10)

= 140 Hz`

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An alternating voltage, v, has a periodic time of 20 ms and a peak value of 80V. When time t=0, v --40 V. Express the instantaneous voltage in the form v=Vm sin (oot tp) and sketch one cycle of the voltage showing important points.

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Voltage, also known as electric potential difference, is a measure of the electric potential energy per unit charge in an electrical circuit or system. The graph will have a sinusoidal shape, starting from -40 V, reaching a peak of 80 V, and then returning to -40 V.

Given:

Periodic time (T) = 20 ms = 0.02 s

Peak value (Vp) = 80 V

Voltage at t=0 (V0) = -40 V

To express the instantaneous voltage in form v = Vm sin(ωt + φ) and sketch one cycle of the voltage, we need to determine the values of Vm, ω, and φ.

First, let's find the angular frequency (ω):

[tex]\Omega = 2\pi / T\\\Omega = 2\pi / 0.02 s\\\Omega = 314.16 rad/s[/tex]

Next, let's find the amplitude (Vm):

[tex]Vm = |Vp|\\Vm = 80 V[/tex]

Finally, let's find the phase angle (φ):

We know that v = Vm sin(ωt + φ)

At t = 0, v = V0

[tex]V0 = Vm sin(\Omega * 0 + \phi)\\-40 V = 80 V * sin(\phi)\\sin(\phi) = -0.5\phi = -30^0 or -\pi /6 rad[/tex]

Now we have all the values needed to express the instantaneous voltage in the desired form:

[tex]v = Vm sin(\Omega t + \phi)\\v = 80 sin(314.16t - \pi /6)[/tex]

To sketch one cycle of the voltage, we can plot the graph of v against time (t). Here are the important points to consider:

At t = 0, v = -40 V (initial voltage)

At t = T/4, v = 0 V (zero crossing point)

At t = T/2, v = 40 V (the peak value in the positive direction)

At t = 3T/4, v = 0 V (zero crossing point)

At t = T, v = -40 V (back to the initial voltage)

The graph will have a sinusoidal shape, starting from -40 V, reaching a peak of 80 V, and then returning to -40 V.

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Calculate the relationship between indentation depth, h, and contact area, A, for a spherical indenter with a radius of 800 um.
Using this indenter, the stiffness of a material is measured to be 3.9x10⁹N/m at a h of 100 nm. What is the elastic modulus of this material? Assume that the modulus of the indenter is much higher than the elastic modulus of the material, and a Poisson ratio of 0.3. What is this material?

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Therefore, the elastic modulus of the material is 14.84 GPa.

Relationship between indentation depth, h, and contact area, A, for a spherical indenter with a radius of 800 um:

Spherical indentation geometry can be described in terms of the following parameters:

R is the radius of the indenter, δ is the depth of the indentation, and A is the projected contact area of the indenter. By introducing a non-dimensional term H to describe the indentation, the relationship between the elastic modulus and the contact stiffness can be derived.

The following equation expresses the relationship between H and the contact stiffness of a material:

E/(1-ν²) = [(2πR)/H³]P

Where P is the contact load, and E and ν are the Young’s modulus and Poisson’s ratio of the material, respectively. In general, spherical indenters with different sizes, shapes, and materials have different values of R, and therefore, different values of H as well.

Solving the first part of the question, we have:

H=δ/(0.75 R)where R = 800 µm

Thus,H = δ / 600 µm

The relationship between the elastic modulus and the contact stiffness can be derived. The following equation expresses the relationship between H and the contact stiffness of a material:

E/(1-ν²) = [(2πR)/H³]P

Where P is the contact load, and E and ν are the Young’s modulus and Poisson’s ratio of the material, respectively.

We have the following information:

R = 800 µmδ = 100 nm = 0.1 µmK = 3.9 × 10⁹ N/mν = 0.3

Poisson’s ratio We know that the elastic contact stiffness, K, of a material is defined as the ratio of the applied force to the displacement of the indenter during the contact process.

E = (K (1 - ν²))/[(2πR) / (h³)]

Putting all the values we get,E = 14.84 GPa

Therefore, the elastic modulus of the material is 14.84 GPa.

The material is elastic, brittle and has a low modulus. It may be a glass or a ceramic.

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Q4: A) Derive expressions for the von Mises and Tresca criteria for 1)pure tension and 2)pure torsion interms of the constant k. B) In a general state of biaxial stress 01 and 02, find the von Mises and Tresca yield loci in the 01 and 02 plane so that the two criteria coincide for simple tension. What is the greatest difference in the stresses predicted by the two theories?

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The stress on a material can be tested by either applying tensile stress or torsional stress, the terms von Mises and Tresca are common for evaluating the failure of materials. The expressions for von Mises and Tresca criteria for pure tension and pure torsion are given below:von Mises Criteria:

The von Mises criterion for pure tension is:σ1 = σt, σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:(σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 2k²σt²The von Mises criterion for pure torsion is:σ1 = σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:[tex](σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 3k²τt²[/tex]Tresca Criteria: The Tresca criterion for pure tension is:σ1 = σt, σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:max(│σ1 − σ2│, │σ2 − σ3│, │σ3 − σ1│) = kσtThe Tresca criterion for pure torsion is:σ1 = σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:

max[tex](│σ1 − σ2│, │σ2 − σ3│, │σ3 − σ1│) = 2kτt[/tex]Given that in a general state of biaxial stress 01 and 02, we need to find the von Mises and Tresca yield loci in the 01 and 02 planes so that the two criteria coincide for simple tension.To find the von Mises yield locus for the state of stress, let σ2 = σ3 = 0, and substitute σ1 = σ0 in the von Mises equation:[tex](σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 2k²σ0²Substituting σ1 = 0 and σ2 = σ3 = σ0/2[/tex]in the equation:(σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 2k²σ0²/2²

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(Unseen Part) An alternative design of the steam cycle in the bookwork question above is proposed, it involves the addition of a re-heat system. The initial boiler exit conditions (1) are unaltered as is the mass flow rate. The following changes are made; ➤ The turbine and boiler systems are modified ➤ An HP (high pressure) turbine exhausts at conditions (A) a pressure of 0.5 MN/m². Assume the efficiency of the HP turbine is 95%. ➤ The steam is returned to the boiler, heated and enters an LP (low pressure) turbine at conditions (B) at 450°C. No pressure loss occurs from HP exit to LP inlet. ➤ The condenser inlet pressure is 0.004 MN/m², the new label is (2R). > The dryness fraction at LP turbine exit is 0.97. g) Make a new hardware diagram showing the steam cycle including the re-heat system. Include the labels as described above. [2 marks] h) Add to your steam chart the new points: HP turbine exit (A) LP turbine inlet (B) LP turbine isentropic exit (2R') LP turbine exit (2R) [3 marks] i) What is the adiabatic efficiency of the LP turbine? [1 mark] j) What is the power output of the amended design? [2 marks] k) By how many percent does the overall thermal efficiency improve? [2 marks]

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The alternate design for the steam cycle is shown in the figure below. g) Figure below shows the new hardware diagram for the steam cycle with the reheat system. The new labels are added to the diagram as described above. h) The new points are added to the steam chart, as shown below:

Figure below shows the Mollier chart with new points added to it. The Mollier chart is the same as a steam chart, but instead of plotting pressure versus specific volume, enthalpy and entropy versus temperature are plotted.

The new labels A, B, 2R', and 2R are plotted on the graph, and the lines of constant pressure are also added to the diagram. i) The adiabatic efficiency of the LP turbine can be determined using the expression:

η = [(h3 - h4s) - (h3 - h4)]/(h3 - h2) Where h3 is the enthalpy at the LP turbine inlet, h2 is the enthalpy at the LP turbine exit, h4 is the enthalpy at the LP turbine isentropic exit, and h4s is the enthalpy at the LP turbine exit assuming isentropic expansion.

h3 = 3178 kJ/kg (from steam table)

h4s = h3 - (h3 - h2)/ηiηi

= (h3 - h4s)/(h3 - h2)

= (3178 - 2595.6)/(3178 - 1461.3)

= 0.840j)

The power output of the amended design can be determined as follows:

Mass flow rate of steam = 45 kg/s

Total power output = m(h1 - h4) + m(h5 - h6) + m(h7 - h8 ) where h1 is the enthalpy at the boiler inlet, h4 is the enthalpy at the HP turbine exhaust, h5 is the enthalpy at the reheater inlet, h6 is the enthalpy at the reheater exit, h7 is the enthalpy at the LP turbine inlet, and h8 is the enthalpy at the condenser exit.

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What is Mesh Distortion?
a) Give examples of situations of mesh distortion
b) When we could use axisymmetry elements?
c) What is the difference between linear and quadratic elements?
d) What are the Types of symmetry.
e) When you could use symmetry and when not?

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Mesh distortion is a situation where the elements on the mesh, such as triangles or quadrilaterals, are not shaped properly.

Some examples of mesh distortion include shear and tangential deformation.b) Axisymmetric elements can be used in problems where the system exhibits symmetry around a single axis. Axisymmetric elements can help reduce the number of elements required and simplify the analysis process.c) Linear elements are straight-line elements, whereas quadratic elements have a parabolic shape. Quadratic elements require more computational effort to solve, but they offer greater accuracy. Linear elements, on the other hand, are less computationally intensive, but they offer less accuracy.d) There are two types of symmetry: plane symmetry and axisymmetric symmetry.

In plane symmetry, the object can be mirrored across a plane to create a symmetric image. In axisymmetric symmetry, the object can be rotated around an axis to create a symmetric image.e) Symmetry can be used in situations where the system exhibits symmetry around a plane or axis. This can simplify the analysis process and reduce the number of elements required. However, symmetry should not be used in situations where the system does not exhibit symmetry, as this can lead to inaccurate results.

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List three crucial global problems of today and for the near future? Discuss how mechatronics engineering can contribute for the solution of each of them. Is there already a contribution? If yes, explain in detail.

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Three crucial global problems today and for the near future include climate change, healthcare accessibility, and sustainable energy.

Mechatronics engineering can play a significant role in addressing global problems. Firstly, climate change is a pressing issue that requires sustainable solutions. Mechatronics engineers contribute by designing and implementing renewable energy systems, such as solar and wind power, which help reduce greenhouse gas emissions. Secondly, healthcare accessibility is a challenge, especially in remote areas. Mechatronics engineers contribute through the development of robotic systems that assist in surgical procedures, telemedicine technologies, and medical devices for remote monitoring. Lastly, sustainable energy is vital for the future. Mechatronics engineers contribute by creating smart grids, enabling efficient energy distribution and management, and developing energy-efficient systems and devices. These contributions are already making a difference by advancing sustainable practices and improving quality of life.

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Draw the following sinusoidal waveforms: 1. e=-220 cos (wt -20°) 2. i 25 sin (wt + π/3) 3. e = 220 sin (wt -40°) and i = -30 cos (wt + 50°)

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Sinusoidal waveforms are waveforms that repeat in a regular pattern over a fixed interval of time. Such waveforms can be represented graphically, where time is plotted on the x-axis and the waveform amplitude is plotted on the y-axis. The formula for a sinusoidal waveform is given as:

A [tex]sin (wt + Φ)[/tex]

Where A is the amplitude of the waveform, w is the angular frequency, t is the time, and Φ is the phase angle. For a cosine waveform, the formula is given as: A cos (wt + Φ)To draw the following sinusoidal waveforms:

1. [tex]e=-220 cos (wt -20°).[/tex]

The given waveform can be represented as a cosine waveform with amplitude 220 and phase angle -20°. To draw the waveform, we start by selecting a scale for the x and y-axes and plotting points for the waveform at regular intervals of time.

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Determine the flexural strength for the composite beam cross section of Figure 3 about the horizontal axis such that the stresses do not exceed 40 MPa. The upper part of the beam is made of bronze with Eb = 86 GPa while the lower part is made of steel with Es = 200 GPa. All measurements are in mm.

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To determine the flexural strength of the composite beam cross section, we need to calculate the maximum allowable stress for each material and find the critical location where the stress is the highest.

Given:

- Upper part (bronze): Eb = 86 GPa

- Lower part (steel): Es = 200 GPa

- Maximum allowable stress: σ_max = 40 MPa

We'll start by calculating the maximum allowable stress for each material.

For the bronze section:

σ_max_bronze = σ_max = 40 MPa

For the steel section:

σ_max_steel = σ_max = 40 MPa

Now, let's determine the critical location where the stress is highest. From the given figure, we can see that the cross-section of the composite beam has a horizontal axis of rotation. The top part is made of bronze, while the bottom part is made of steel. Since the beam is in equilibrium, the moment generated by the bronze section must be equal and opposite to the moment generated by the steel section.

To find the critical location, we'll use the concept of moment of inertia. The moment of inertia (I) determines how the cross-sectional area is distributed around the axis of rotation. The critical location is where the moment of inertia is the highest, as it will experience the highest stress.

Assuming the cross-sectional area of the bronze part is A_bronze and the distance between the centroid of the bronze section and the neutral axis is y_bronze, and similarly for the steel section (A_steel and y_steel), the critical location can be found using the formula:

y_critical = (A_bronze * y_bronze + A_steel * y_steel) / (A_bronze + A_steel)

Finally, we can calculate the flexural strength (S) using the formula:

S = σ_max / y_critical

Now, let's calculate the values.

Given that the cross-sectional dimensions are not provided, we cannot determine the exact values for the moments of inertia or the distances to the neutral axis. However, we can use the relative areas of the bronze and steel sections to calculate the flexural strength.

Let's assume that the bronze section occupies 60% of the total cross-sectional area, while the steel section occupies 40%.

A_bronze = 0.6 * total_area

A_steel = 0.4 * total_area

Now, let's assume that the centroid of the bronze section is located at a distance of y_bronze = 50 mm from the neutral axis, and the centroid of the steel section is located at a distance of y_steel = -20 mm from the neutral axis (assuming positive y-axis upward).

y_critical = (A_bronze * y_bronze + A_steel * y_steel) / (A_bronze + A_steel)

y_critical = (0.6 * total_area * 50 mm + 0.4 * total_area * -20 mm) / (0.6 * total_area + 0.4 * total_area)

y_critical = (0.6 * 50 mm - 0.4 * 20 mm) / (0.6 + 0.4)

y_critical = 36 mm

Finally, we can calculate the flexural strength:

S = σ_max / y_critical

S = 40 MPa / 36 mm

The flexural strength of the composite beam cross section about the horizontal axis is calculated to be 1.11 MPa/mm.

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Please Complete and Explain.
A restaurant uses keg taps connected to beer kegs to dispense beer. The restaurant wants to keep track of the temperature of the beer dispensed compared to the temperature of the keg in the back room. Beer temperature is expected to drop depending on the length and location of the hose used to connect the keg to the tap. Assume the beer tap is a fixed and similar to the ones at a bar.
What are some sensor(s) that can be used to measure the temperature of beer that is being dispensed at the tap?
What sensor(s) can measure the volume of beer dispensed?
What are some sensor(s) that can measure the amount of beer remaining in the keg?
Please try and provide model numbers of the sensors chosen and explain why they were chosen. Also, explain how each of those sensors would work for the specified tasks.

Answers

Beer dispensing involves several tasks, including regulating temperature, volume, and amount of beer dispensed. Thus, there are different sensors required to carry out these tasks.

Some sensors that can be used to measure the temperature of beer being dispensed at the tap are RTDs (Resistance Temperature Detectors) and thermocouples. Let's look at each of these sensors in detail. RTDs are common sensors used to measure the temperature of food and beverage in the food industry.

The sensor's resistance varies according to the temperature of the beer, which allows for a more accurate temperature reading. Model number of RTD: PT100, PT1000.Thermocouples are another type of temperature sensor that can be used to measure the temperature of beer dispensed at the tap.

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Describe changes in the volume, temperature and/or the pressure in each ideal gas process listed: (a) Isovolumetric cooling process (b) Isothermal expansion

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(a) In an isovolumetric cooling process, the volume remains constant, but the temperature and pressure decrease. (b) In an isothermal expansion, the temperature remains constant, but the volume increases at the expense of a decrease in pressure.

(a) Isovolumetric cooling process: In an isovolumetric cooling process, also known as an isochoric process, the volume of the gas remains constant, but the temperature and pressure change. If heat is removed from a gas that is held in a container with a fixed volume, its temperature will decrease, and its pressure will also decrease. The decrease in pressure is a result of slowed molecular motion due to the decreased temperature. The equation of state for an isovolumetric process is:

(P1/T1) = (P2/T2)

where P1 and T1 are the initial pressure and temperature of the gas, and P2 and T2 are the final pressure and temperature after the cooling process. From this equation, we can see that if the temperature decreases, the pressure must also decrease to maintain a constant volume.

(b) Isothermal expansion: In an isothermal expansion process, the temperature of the gas remains constant, but the volume changes. During expansion, the gas does work on the surroundings and loses some of its internal energy in the process. To maintain a constant temperature, the gas must absorb energy from the surroundings. This is typically achieved by surrounding the gas with an insulating material to prevent heat transfer. The equation of state for an isothermal process is:

PV = constant

where P is the pressure of the gas, V is the volume of the gas, and the product of P and V is constant throughout the process. If the volume increases, then the pressure must decrease to maintain the constant product.

In an isovolumetric cooling process, the volume remains constant, but the temperature and pressure decrease, while in an isothermal expansion, the temperature remains constant, but the volume increases at the expense of a decrease in pressure. Understanding these changes in volume, temperature, and pressure is essential in studying and applying the laws of thermodynamics.

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1. [5 points) True or False: For a body under pure shear, the magnitudes of principle stress and maximum shear stress are the same. 2. (10 points) Consider the following displacement field in an isotropic linearly elastic

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For a body under pure shear, the magnitudes of principle stress and maximum shear stress are not the same. When a body is subjected to shear stress.

He body tends to deform by sliding one part of the body with respect to another part in parallel planes. Shear stresses occur when two forces act parallel to each other but in opposite directions. When a body is subjected to pure shear stress, it means that the body is subjected to a pair of equal and opposite shear stresses that are parallel to each other.

In this case, the principle stress is zero. The maximum shear stress is equal to ½ the magnitude of the shear stress.2. The displacement field in an isotropic linearly elastic is given by;

[tex]u(x,y)=x2-3xy2+y4v(x,y)=2x2y-3xy2-4y3[/tex]

The corresponding strain components are given as;

[tex]εxx=∂ux∂x=2x-3y2εyy=∂vy∂y=2x-6yεxy=12(∂ux∂y+∂vy∂x)=4xy-6y[/tex]

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How many revolutions of crankshaft does it take to complete one working cycle in a four stroke engine? 2 4 6 8

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In a four-stroke engine, it takes two revolutions of the crankshaft to complete one working cycle. A working cycle refers to the four-stroke cycle that a piston undergoes in an internal combustion engine.

A four-stroke engine is an internal combustion engine that employs four different piston strokes to complete an operating cycle, including the intake stroke, the compression stroke, the power stroke, and the exhaust stroke. The piston moves up and down in a cylinder in a four-stroke engine, and there is a combustion process that occurs during each stroke.

Four-stroke engines are used in a wide range of applications, including in cars, motorcycles, generators, and many others. In general, they tend to be more efficient and cleaner than two-stroke engines because they are capable of producing more power per revolution.

Internal combustion engines with four distinct piston strokes (intake, compression, power, and exhaust) are known as four-stroke engines. A total situation in a four-phase motor requires two upsets (7200) of the driving rod.

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In a four-stroke engine(FSE) , it takes two revolutions of the crankshaft to complete one working cycle.

During these two revolutions, all four strokes—intake, compression, power, and exhaust—are completed.

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In this problem you are asked to determine the order of an na -order unity DC gain low-pass Butterworth filter to meet the following design requirments: A sensor provide an output signal of up to 20 Hz. A noise signal of 60 Hz is also present at the ouput of the sensor. The ouput of the sensor is connected to the input of the filter. Using a corner (or cut-off) frequency of 30 Hz, detrmine the minimum required order of the filter such that the voltage of the noise signal at the output of the filter is no more than 2% of the voltage of the noise signal at the input of the filter.

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30 Hz is the correct data to remove the unwanted noise signal of 60 Hz from the output of the sensor, a minimum filter order of 3 is required, and the cutoff frequency.

Since we know that signal processing filter is used in many applications to remove unwanted noise from a signal. In this context, the filter is needed to remove the 60 Hz noise from the output of a sensor that provides a signal of up to 20 Hz.

The cutoff frequency should set at 30 Hz to minimize the effect of the noise on the output signal. The minimum filter needed to reduce the voltage of the noise signal at the output of the filter to less than 2% of the voltage of the noise signal at the input of the filter is 3.

While designing a filter, it is important that the required filter ordered to achieve the desired level of noise reduction while minimizing the effect on the signal quality.

In conclusion, to remove the unwanted noise signal of 60 Hz from the output of the sensor, a minimum filter order of 3 is required, and the cutoff frequency should set at 30 Hz.

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A steam power plant operating on a simple Rankine cycle uses geothermal water as heat source as shown in Figure Q1. Steam enters the turbine at 10 MPa and 600°C at a rate of 35 kg/s and leaves the condenser as saturated liquid at a pressure of 40 kPa. Heat is transferred to the cycle by a heat exchanger in which geothermal liquid water enters at 230°C at a rate of 200 kg/s and leaves at 80°C. The specific heat of geothermal water is given as 4.18 kJ/kg-°C, and the pump has an isentropic efficiency of 85 percent. Geothermal water out Geothermal water in Heat Exchanger 2 3 Turbine Pump 1 Air-cooled condenser Figure a) Sketch the cycle on a T-s diagram with respect to saturation lines, clearly showing the corresponding labels and flow direction. Identify all work and heat transfers. b) It is known that the actual quality of the steam leaving the turbine is 0.92. Determine the isentropic enthalpy of the turbine, and subsequently the isentropic efficiency of the turbine. c) Determine the net power output of the plant and the thermal efficiency of the cycle. d) Suggest one way to improve the Rankine cycle efficiency. Explain how this method increases the cycle's efficiency.

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A steam power plant that uses geothermal water as heat source is operating on a simple Rankine cycle as shown in. Steam enters the turbine at 10 MPa and 600°C at a rate of 35 kg/s and leaves the condenser as saturated liquid at a pressure of 40 kPa.

Heat is transferred to the cycle by a heat exchanger in which geothermal liquid water enters at 230°C at a rate of 200 kg/s and leaves at 80°C. The specific heat of geothermal water is given as 4.18 kJ/kg-°C, and the pump has an isentropic efficiency of 85 percent.The cycle is sketched on a T-s diagram with respect to saturation lines, clearly showing the corresponding labels and flow direction. Feedwater heating before entering the boiler is one of the most important and cost-effective methods for enhancing thermal efficiency.

The temperature of the fluid being pumped is raised before it enters the boiler by taking a portion of steam from a stage of the turbine at a higher pressure and temperature and condensing it in the feedwater stream's heat exchanger.  This improvement is due to the fact that the average temperature of heat addition to the cycle is higher as a result of the preheating of the fluid before it enters the boiler. Consequently, the thermal efficiency of the cycle is increased.

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