A lecture hall has 50 seats. 43 seats are occupied and 7 seats are empty. Use this information to answer the questions below. CLEAR CHECK What fraction shows the proportion of empty seats? 7 50 What percent of seats were empty? %

Answer:

14% of the seats are empty

Step-by-step explanation:

7/50 = ?/100

50×2=100

so 7×2=?

?=14

14/100=14%

The percent of seats that are empty in the hall of 50 seats with 43 being occupied is; 14%

We are given;

Total number of seats in hall = 50

Number of occupied seats = 43

Number of empty seats = 7

Now, we want to find the percent of seats were empty.

This is gotten by;

% of empty seats = (number of empty seats/total number of seast) * 100%

% of empty seats = (7/50) * 100%

% of empty seats = 14%

Read morer about Percentages at; https://brainly.com/question/843074

TI
Assessment
Vhich table of values can be used to graph the function y = - 4x +3?
x
y
-1
-1
0
3
1
7
2
11
X
y
3
O
-1
-9
-1
7
1
3
15
x
0
1
3
-1
-5
-9
2
3
3
X
Y
3
7
11
15
3
or False
function's graph may include solutions that do not appear in its table of

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