A lead fishing weight of mass 0.20 kg is tied to a fishing line that is 0.50 m long. The weight is then whirled in a vertical circle. The finishing line will break if its tension exceeds 100.0 N. (a) If the weight is whirled at higher and higher speeds, at what point in the vertical circle will the string break (top, bottom, or random position)

Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.

Answer:

Nine, Brazil, Venezuela

Explanation:

Answer:

C.

Explanation:

the closer you get to the centre of an object the greater its gravitational pull- A is correct

If the radius increases the gravity decreases and rise versa - B is correct

the answer is C

The force of gravity acting on you will increase if you  stand on a planet with a radius that is shrinking. So, option (B) is orrect.

Force is an external agent that has the power to alter a body's resting or moving condition. It has a size and a movement. The direction of the force is referred to as the force's direction, and the application of force is the place at which the force is applied.

The force of gravity acting on an object due to a planet is given by: F = GMm/R².

Where, G is universal gravitational constant . M and m is masses of the planet and the object respectively and R is distance between them.

Hence, when you stand on a planet with a radius that is shrinking; distance between you and planet decreases. So, the force of gravity acting on you will increase. So, option (B) is correct.

But in the case of burrow deep inside the planet: gravitational force due to outer shell  becomes zero. So, effective gravitational force decreases.

Learn more about force here:

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Answer:

momentum does

Explanation:

Answer:

The correct solution will be "12.48 in/s²".

Explanation:

The given values are:

Angular speed

= 79.0 rev/min

Time

= 3.80 seconds

Now,

⇒  [tex]Angular \ acc.=\frac{(\frac{79\times 2\times \pi}{60})}{3.8}[/tex]

                          [tex]=\frac{8.2}{3.8}[/tex]

                          [tex]=2.1 \ rad/s^2[/tex]

Tangential acceleration will be:

= [tex]Angular acc.\times radius[/tex]

= [tex]2.1\times 6.5\times 0.0254[/tex]

= [tex]0.3467 \ m/s^2[/tex]

= [tex]12.48 \ in/s^2[/tex]

Answer: Gamma rays, x-rays, ultraviolet rays, visible light, and infrared rays.

Answer:

C) radio → infrared → ultraviolet → gamma

Explanation:

It Increases left to right therefore it decreases right to left

Answer:

v₃ = 1.625 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.

Since the collision is inelastic, the two bodies are joined after the collision.

P = m*v [kg*m/s]

m = mass [kg]

v = velocity [m/s]

where:

P = lineal momentum [kg*m/s]

Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.

Pbefore = Pafter

(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃

where:

m₁ = mass one = 5 [kg]

v₁ = velocity of the mass one = 2 [m/s]

m₂ = mass two = 3 [kg]

v₂ = velocity of the mass two = 1 [m/s]

v₃ = velocity of the combined masses after the collision [m/s]

Now replacing we have:

(5*2) + (3*1) = (5 + 3)*v₃

10 + 3 = 8*v₃

v₃ = 13/8

v₃ = 1.625 [m/s]

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, what is described in the question is known as upthrust. Upthrust is an upward force on an object (in this case the wooden block) provided by the liquid (water) as a result of it displacing some of the liquid. Thus floating objects will normally displace some part of the liquid; making some part of it to be submerged in water.

The percentage of the submerged wooden block can be calculated as

length (in height) of the wood block submerged in water/total length (in height) of the wood × 100

Answer:

A. An electromagnetic wave

Explanation:

A P E X

Answer:

there's no picture

Explanation:

and what would the question be anyways?

Answer:

what is the question

Explanation:

Answer:

This is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. This enables more atoms in the metal to become aligned hence becoming more magnetized.

or...

A method of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.

Hope this helps☺️

Answer:

2.4m

Explanation:

Given parameters:

Radius of circle  = 1.65m

Acceleration  = 3.5m/s²

Unknown:

Velocity of the object = ?

Solution:

To solve this problem, we have to apply the formula of centripetal acceleration;

   Centripetal acceleration  = [tex]\frac{v^{2} }{r}[/tex]  

v is the velocity

r is the radius

   v² = centripetal acceleration x radius

 Insert parameters and solve;

     v² = 3.5 x 1.65

     v  = √5.775  = 2.4m

The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.

Given the data in the question;

Velocity; [tex]v = \ ?[/tex]

From the centripetal force equation, we use the expression for centripetal acceleration:

[tex]a_c = \frac{v^2}{r}[/tex]

Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.

We substitute our given values into the equation

[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]

Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.

Learn more: https://brainly.com/question/17689540

Answer:

Explanation:

The velocity of the car can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{50}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

(a) 441 W (b) 0.59 hP

Explanation:

Given that,

Mass of a woman, m = 60 kg

Height of a staircase, h = 15 m

Time, t = 20 s

(a) We need to find the power she expend. Work done per unit time is called power. It is given by :

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\P=441\ W[/tex]

( b) Since, 1 hP = 745.7 W

P = 0.59 hP

Answer:

The magnitude of the impulse delivered to the baseball is 7.0 Ns

Explanation:

Given;

mass of the foul ball, m = 0.14 kg

initial velocity, u = 40 m/s

final velocity, v = 30 m/s in perpendicular direction

Impulse is given as change in momentum;

initial momentum in horizontal direction, Pi = mu

Pi = 0.14 x 40 = 5.6 Ns

final momentum in perpendicular direction, Pf = mv

Pf = 0.14 x 30

Pf = 4.2 Ns

The resultant impulse is given by;

J² = 5.6² + 4.2²

J² = 49

J = √49

J = 7.0 Ns

Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns

Answer:

a) [tex] v_{0y} = 9.72 m/s [/tex]

b) [tex] v_{0x} = 20.85 m/s [/tex]

c) [tex] t = 2.01 s [/tex]

d) [tex] h_{max} = 4.82 m [/tex]

Explanation:

a) The initial vertical velocity is given by:

[tex] v_{0y} = v*sin(\theta) [/tex]

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

[tex] v_{0y} = 23 m/s*sin(25) = 9.72 m/s [/tex]

b) The initial horizontal velocity can be calculated as follows:

[tex] v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s [/tex]

c) The flight time can be calculated using the following equation:

[tex] v_{0x} = \frac{x}{t} [/tex]

Where:

x: is the total distance = 42 m

[tex] t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s [/tex]

d) The maximum height is given by:

[tex] v_{fy}^{2} = v_{0y}^{2} - 2gh_{max} [/tex]

Where:

[tex] v_{fy}[/tex]: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

[tex]h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m[/tex]

I hope it helps you!                                  

Answer:

11.48 m

Explanation:

The following data were obtained from the question:

Mass (m) of the roller coaster = 1200 Kg

Initial velocity (u) = 15 m/s.

Final velocity (v) = 0 m/s (at highest point)

Acceleration due to gravity (g) = 9.8 m/s²

Highest point (h) =?

The highest point reached by the roller coaster can be obtained as illustrated below:

h = u²/2g

h = 15² / 2 × 9.8

h = 225/19.6

h = 11.48 m

Therefore, the highest point reached by the roller-coaster is 11.48 m

Answer:

The radius is  [tex]r =1705.44 \ m[/tex]

Explanation:

From the question we are told that

   The speed is [tex]v = 1140 \ km /h = \frac{1140 * 1000}{3600} = 316.67 \ m/s[/tex]

   The centripetal acceleration is  [tex]a = 6 g's = 6 * 9.8 = 58.8 \ m/s^2[/tex]

Generally the centripetal force acting on the jet is mathematically represented as  

        [tex]F_c = \frac{m * v^2 }{r}[/tex]

Generally this centripetal force is equal to the net force acting which according to Newton's third law is mathematically  represented as

      [tex]F = m * a[/tex]

So

      [tex]\frac{m * v^2 }{r} = ma[/tex]

=>   [tex]\frac{ v^2 }{r} = a[/tex]

=>  [tex]r = \frac{v^2}{a}[/tex]

=>  [tex]r = \frac{316.67^2}{58.8}[/tex]

=>  [tex]r =1705.44 \ m[/tex]

Voltage = (current) x (resistance) (Ohm's law)

Voltage = (15 A) x (0.10 ohm)

Voltage =  1.5 volts (B)

Answer:

what are the answers to select? or do you just say them

Explanation:

???

Answer:

c and d

Explanation:

Answer:

A terrestrial planet, telluric planet, or rocky planet is a planet that is composed primarily of silicate rocks or metals. Within the Solar System, the terrestrial planets are the inner planets closest to the Sun

Answer:

1. No, it is a colloid

2. Yes

Explanation:

Answer:

movement generates energy=heat so 50c should be it

Answer:

The time is  [tex]t_r =21.58 \ s[/tex]  

Explanation:

From the question we are told that

   The  diameter of the circular saw  is [tex]d = 10 \ in = \frac{10}{12} = 0.833 \ feet[/tex]

   The peripheral speed is [tex]u = 230 \ ft/s[/tex]

    The time taken for the blade to come to rest is t = 17 s

    The total  acceleration of the tooth considered is  [tex]a = 130 \ ft/s^2[/tex]  

Generally the radius of the blade is mathematically represented as

            [tex]r = \frac{0.833}{2}= 0. 4165 \ feet[/tex]

Generally the tangential acceleration of the blade is mathematically represented as

           [tex]a__{t}} = \frac{v - u}{t}[/tex]

Here v is the final  velocity of the tooth of the blade which is  zero  since the blade came to  rest

so  

         [tex]a__{t}} = \frac{0 - 230}{ 17}[/tex]

=>      [tex]a__{t}} = - 13.53 \ ft/s^2[/tex]

Generally the total acceleration of the tooth of the blade is mathematically represented as

         [tex]a = \sqrt{a_t^2 + a_r^2}[/tex]

Here [tex]a_r[/tex] is the radial acceleration , now making [tex]a_r[/tex] the subject of the formula we have that

        [tex]130= \sqrt{13.56 ^2 + a_r^2}[/tex]

=>     [tex]a_r = \sqrt{130^2 -(- 13.56)^2}[/tex]

=>     [tex]a_r = 129.3 \ m/s^2[/tex]

Generally radial  acceleration is mathematically represented as

      [tex]a_r = \frac{v_r^2}{r}[/tex]    

Here  [tex]v_r[/tex] is the velocity at which the total acceleration is 130 ft/s2.

=>   [tex]v_r = \sqrt{a_r * r }[/tex]  

=>  [tex]v_r = \sqrt{129.3 * 0.4165 }[/tex]

=>  [tex]v_r = 7.34 \ m/s[/tex]

Generally the time at which the total acceleration is  130 ft/s2. is mathematically represented as

        [tex]t_r = \frac{7.34 - 300}{a_t}[/tex]

=>      [tex]t_r = \frac{7.34 - 300}{-13.56}[/tex]

=>      [tex]t_r =21.58 \ s[/tex]    

Answer:

b?

Explanation:

Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

 Mathematically;

        Power  = [tex]\frac{work done}{time}[/tex]  

   Time  = [tex]\frac{work done}{power}[/tex]  

 Work done  = weight x height

 convert mass to kg;

     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

          1000mm = 1m

          6.34 x 10⁴mm gives 63.4m

  Work done  = 14.7 x 9.8 x 63.4 = 9133.4J

  Time taken = [tex]\frac{9133.4}{2190}[/tex]   = 4.2s

Answer:

By examining its external shape, color, hardness, etc.

Explanation: