Answer:
the charge of each small sphere, which is + Q / 2
Explanation:
For this exercise we must use the fact that a charged object induces charges on nearby bodies
Induced charge comes from the fact that charges of the same sign repel and charges of different signs attract.
In this case the large, fixed ball with a -Q charge induces a positive charge in the nearest part and the negative charges are repelled to the furthest point, but the net charge on the metallic sphere remains zero. It should be emphasized that since the charges are of different signs, there is an attractive force between the two spheres.
This first metallic sphere now has a negative charge on the back, this charge induces a positive charge on the second sphere, as the charges are of a different sign, they attract each other, which is why the force is attractive.
When the first sphere stops the second sphere hits it, at this moment the charge of the two spheres is equal, therefore the induced charge in the two spheres is + Q. When the two spheres are separated, the charge on each of them is half, that is, the sphere has a charge + Q / 2 and the second sphere has a charge + Q / 2.
Therefore the first sphere is subjected to two forces: an attractive force with the large sphere of charge -Q and a repulsive force with the second sphere of charge + Q / 2.
So the first sphere must approach the big ball and the second sphere must move away from the big sphere.
This is the process of the movement of this exercise, unfortunately the statements with which to compare this process do not appear, but one of the most common questions of what is the charge of each small sphere, which is + Q / 2
The foundation of psychology is?
Case Studies
O Experiments
O Research
O Analysis
Answer:
Case Studies
Explanation:
A case study in psychology is a descriptive research approach used to obtain in-depth information about a person, group, or phenomenon.Case studies use techniques such as personal interviews, direct observation, psychometric tests, and archival records to gather information.
and aunt travels toward the right along a meter stick. if it starts at the 25.00 cm mark and then travels to the 80.00 cm mark, what is its displacement
Answer:
displacement = 55 cm
Explanation:
Initial position = 25 cm
Final position = 80 cm
Displacement = final position-finitial position
Putting values in above formula,
D = 80 cm - 25 cm
D = 55 cm
It means that the displacement of the ant is 55 cm.
Air conditioners operate on the same principle as refrigerators. Consider an air conditioner that has 7.00 kg of refrigerant flowing through its circuit each cycle. The refrigerant enters the evaporator coils in phase equilibrium, with 54.0 % of its mass as liquid and the rest as vapor. It flows through the evaporator at a constant pressure and when it reaches the compressor 95% of its mass is vapor. In each cycle, how much heat Qc is absorbed by the refrigerant while it is in the evaporator? The heat of vaporization of the refrigerant is 1.50×105 J/kg
Answer:
5.15J
Explanation:
First. 54% of the 7kg refrigerant is liquid
So we find mass of vapour at inlet generator
M1 = ( 1-0.54)*7= 3.2kg
At compressor mass of vapour will be
M2= 0.95*7= 6.7kg
So the Mass of vapour at exit generator is
M2-M1= 3.5kg
So to find heat absorbed by refrigerant in evaporation
Its using
Q= mh
°= 3.5x 1.50×10^5 J/kg
=5.15J
Two satellites orbit earth at altitudes of 7500 km and 15000 km above earth's surface. Which satellite is faster and by what factor?
Answer:
The satellite that is 7500 km above earth's surface is 1.24 times faster than the satellite at 15000 km above earth's surface
Explanation:
Generally the gravitational force acting on each satellite is mathematically represented as
[tex]F = \frac{G * M_e * m_2 }{r^2}[/tex]
Here [tex]M_e[/tex] is the mass of the earth
[tex]r = r_e + R [/tex]
So [tex] r_e [/tex] is the radius of the satellite and R is the radius of earth with value R = 6371 km
This force is also equivalent to the centripetal force acting on each satellite which is mathematically represented as
[tex]F = \frac{mv^2}{ r^2}[/tex]
So
[tex]\frac{mv^2}{ r^2} = \frac{G * m_1 * m_2 }{r^2}[/tex]
=> [tex]v = \sqrt{ \frac{GM_e}{r} }[/tex]
So for [tex]r = 7500+ 6371 = 13871 \ km [/tex]
We have that
[tex]v_1 = \sqrt{ \frac{GM_e}{13871} }[/tex]
and [tex]r = 15000+ 6371 = 21371 \ km [/tex]
We have that
[tex]v_2 = \sqrt{ \frac{GM_e}{21371} }[/tex]
So
[tex]\frac{v_1}{v_2} = \frac{\sqrt{\frac{GM_e}{13871} } }{ \sqrt{\frac{GM_e}{21371}} }[/tex][tex]v = \sqrt{ \frac{GM_e}{r} }[/tex]
=> [tex]\frac{v_1}{v_2} = \sqrt{ \frac{21371}{13871} }[/tex]
=> [tex]v_1 = 1.24 v_2[/tex]
So satellite that is 7500 km above earth's surface is 1.24 times faster than the satellite at 15000 km above earth's surface
If a person is standing up in a moving bus that stops suddenly,the person can easily fall forwards.Has a force acted to push the person forwards? Use Newton's law of motion to explain what is happening.
Answer:
i think gravity created a force strong enough to push him down.but it also depends how slow or fast the bus is going
Explanation:
gravity as we all now it is pretty strong so if the bus is going fast then the person standing up will fall but if the bus is going pretty slow then it'll just nudge him.
If all other things remain equal, which of the following changes to a closed circuit
would result in increased resistance to the flow of electric current?
Reducing the temperature of the conductor
Reducing the thickness of the conductor
Replacing the conductor with a more conductive material
Reducing the length of the conductor
Answer:
the answer is b reducing the thickness of the conductor
Explanation:
The resistance to electric current increases as the cross-section of the conductor is reduced, as the conductor is lengthened, and as the conductor is heated. Replacing the conductor with a less-conductive material increases the resistance as well.
Answer:
Reducing the thickness of the conductor
Explanation:
can anyone help me with this.
Answer:
A. smaller arteries
Explanation:
A. because it makes no sence.
Scientific notation: Convert 7.1 x 10-3 to decimal notation.
Answer: hey
your answer is gonna be
71000.
Explanation:
Is steel considered matter
Answer:
yes. everything around you is matter including you!
Answer:
yes
Explanation:
because it takes up space
4. Two people each have a mass of 55 kg. They are both in an
elevator that has a mass of 240 kg. When the elevator
begins to move, the people and the elevator have an upward
acceleration of 1.00 m/s2. What is the net force that acts on
the elevator as it accelerates upward at 1.00 m/s2?
Answer:
350 N
Explanation:
F=ma
[tex]f = force \\ m = mass \\ a = acceleration[/tex]
[tex]m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} } [/tex]
Force = 350 Newtons
The net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2.
What is Newton's second law?
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = ma
As given in the problem two people each have a mass of 55 kg. They are both in an elevator that has a mass of 240 kg. When the elevator begins to move, the people and the elevator have an upward acceleration of 1.00 m/s2, then we have to find the net force acting on the elevator,
The net force acting on the elevator,
F = ma
F =(2×55 + 240)×1
= 350 Newtons
Thus, the net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2
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How fast must the space shuttle go to cover 20,000 meters in 4.0 seconds?
Answer:
5000 m/s
Explanation:
Car wheel's slip in mud. why?
Answer:
Because its wet
Explanation:
When a piano tuner strikes both the A above middle C on the piano and a 440 Hz tuning fork, he hears 4 beats each second. The frequency of the piano's:____________.
A) 444 Hz
B) 880 Hz
C) 436 Hz
D) either 436 Hz or 444 Hz
Answer:
D) either 436 Hz or 444 Hz
Explanation:
frequency of the tuning fork, F₁ = 440 Hz
frequency of the piano, F₂ = ?
Beat frequency, F = 4 Hz
Beat frequency is given as the difference between the frequency of the two instruments and it is given by;
F = F₂ - F₁ or F = F₁ - F₂
F₂ = F + F₁ or F - F₁ = - F₂
F₂ = 4 Hz + 440 Hz or 4 - 440 = - F₂
F₂ = 444 Hz or - 436 = - F₂
F₂ = 444 Hz or F₂ = 436 Hz
Therefore, the frequency of the piano is 444 Hz or 436 Hz
Calculate the average speed between 0 s and 20 s
Answer:
2 m/s
Explanation:
The following data were obtained from the question:
Distance (D) = 40 m
Time (t) = 20 s.
Average speed =?
Average speed is the total distance travelled divided by the total time taken. Mathematically, it is expressed as:
Average speed = Total distance /Total time
Thus, we can obtain the average speed as follow:
Total Distance (D) = 40 m
Time time (t) = 20 s.
Average speed =?
Average speed = Total distance /Total time
Average spee= 40/20
Average speed = 2 m/s
Therefore, the average speed between 0 and 20 seconds is 2 m/s.
6. What is Mass????????????????
Nami conducts an investigation on plants. She places a grow light on a timer to give the plants different amounts of light to see if this would affect their growth. Which term describes the amount of light in this investigation?
Answer:
It is independent variable
Explanation:
Answer:
D!!!!!
Explanation:
edge 2021!
A bird flies 3.7 meters in 46 seconds, what is its speed?
Answer:
Speed is 0.08 m/s.
Explanation:
Given the distance that the bird flies = 3.7 meters
The time is taken by the bird to fly the 3.7 meters = 46 seconds
We have given distance and time. Now we have to find the speed at which the bird flies. So, to calculate the speed of the bird we have to divide the distance by the time.
Below is the formula to find the speed.
Speed = Distance / Time
Now insert the given value in the formula.
Speed = 3.7 / 46 = 0.08 m/s
Acceleration occurs when velocity changes. O True O False
Answer:
True
Explanation:
Acceleration by definition is the change in velocity divided by the change in time. Thus when the velocity changes, there must be an acceleration.
13.
14. Why does a person feel weightlessness during freefall?
Answer:
When in free fall, the only force acting upon your body is the force of gravity - a non-contact force. Since the force of gravity cannot be felt without any other opposing forces, you would have no sensation of it. You would feel weightless when in a state of free fall.
A bucket is being lowered by a very light rope with a constant downward velocity. The tension in the rope must be
Answer:
The tension in the light rope must be equal to the weight of the bucket
Explanation:
Given that,
Constant velocity of bucket and direction of bucket in downward
We need to find the tension in the rope
Using given data,
When a bucket moves downward with a constant velocity then the net force does not applied on the bucket.
So, The weight of the bucket will be equal to the tension in the light rope
In mathematically,
[tex]T=mg[/tex]
Where, T = tension
m = mass of bucket
g = acceleration due to gravity
Hence, The tension in the light rope must be equal to the weight of the bucket.
is the
What is the tendency to move to a drive-free state?
O A. Homeostasis
OB. Equality
OC. Homogeneity
OD. Motivationless
360 s to ms? Need help! Converting units, with work pls
1 s = 1,000 ms
2 s = 2,000 ms
3 s = 3,000 ms
.
.
10 s = 10,000 ms
20 s = 20,000 ms
30 s = 30,000 ms
.
.
.
100 s = 100,000 ms
200 s = 200,000 ms
300 s = 300,000 ms
310 s = 310,000 ms
320 s = 320,000 ms
.
.
.
350 s = 350,000 ms
360 s = 360,000 ms
370 s = 370,000 ms
.
.
.
What do we know has to be TRUE about the action and reaction force below?
the boot kecked the ball which is frictinal force
A baseball pitcher's average fastball pitch speed is 98.6 mph. What is that speed in
m/s?
Answer:
44.078 m/s
Explanation:
convert 98.6 miles to meters then convert the hour to minutes and minutes to seconds
Part A
Your GPS shows that your friend’s house is 10.0 km away (Figure 2). But there is a big hill between your houses and you don’t want to bike there directly. You know your friend’s street is 6.0 km north of your street. How far do you have to ride before turning north to get to your friend’s house?
8 km
Part B
Referring to the diagram in Part A, what is the sine of the angle
θ at the location of the friend's house?
Answer:
Part A
You have to ride 8.0 km before turning north to get to your friend’s house.
Part B
The sine of the angle θ at the location of the friend's house is 0.8
Explanation:
The remaining part of the question which is an image is attached below
Explanation:
Part A
To determine how far you will ride ride before turning north,
From the diagram, that is the distance of your street.
Let the distance of your street be [tex]A[/tex]
and the distance of your friend's street be [tex]B[/tex]
and let the displacement between your friends house and your house be [tex]C[/tex]
The relation in the diagram shows a right angle triangle.
The sides of the right angle triangle are represented as [tex]A,B[/tex] and [tex]C[/tex].
To find [tex]A[/tex], which is the distance of your street,
From Pythagorean theorem, 'The square of hypotenuse is the sum of squares of the other two sides'
That is,
[tex]/Hypoyenuse/^{2} = /Adjacent/^{2} + /Opposite/^{2}[/tex]
[tex]C[/tex] is the hypotenuse, which is the displacement between your friends house and your house,
Hence, [tex]C = 10.0 km[/tex]
[tex]B[/tex] is adjacent, which is the distance of your friends street
then, [tex]B = 6.0 km[/tex]
and [tex]A[/tex] is the opposite, which is the distance of your house
From Pythagoras theorem, we can then write that,
[tex]C^{2} = B^{2} + A^{2}[/tex]
Then, [tex]10.0^{2} = 6.0^{2} + A^{2}[/tex]
[tex]A^{2} = 100.0 - 36.0\\A^{2} = 64.0\\A = \sqrt{64.0}[/tex]
[tex]A = 8.0km[/tex]
Hence, you have to ride 8.0 km before turning north to get to your friend’s house.
Part B
To find the sine of the angle θ at the location of the friend's house,
In the diagram, the sine of the angle θ is given by
[tex]Sin\theta = \frac{Opposite}{Hypotenuse}[/tex]
Hence, [tex]Sin\theta = \frac{A}{C}[/tex]
Then,
[tex]Sin\theta = \frac{8.0}{10}[/tex]
[tex]Sin\theta = 0.8[/tex]
Hence, the sine of the angle θ at the location of the friend's house is 0.8
A. The amount of distance you have to ride before turning North to get to your friend’s house is 8 kilometers.
B. The sine of the angle (θ) at the location of your friend's house is 0.8.
Let your friend's house be a.Let your friend's street be b.Let the distance between your house and your friend be c.Given the following data:
Distance c = 10 kmDistance a = 6 kmA. To determine the amount of distance you have to ride before turning North to get to your friend’s house, we would apply Pythagorean's theorem:
Mathematically, Pythagorean's theorem is given by the formula:
[tex]c^2 = a^2 + b^2\\\\10^2 =6^2+b^2\\\\100=36+b^2\\\\b^2 =100-36\\\\b^2 =64\\\\b=\sqrt{64}[/tex]
b = 8 kilometers
B. To find the sine of the angle (θ) at the location of the friend's house:
Mathematically, the sine of an angle is given by the formula:
[tex]Sin\theta = \frac{opposite}{hypotenuse}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Sin\theta = \frac{8}{10} \\\\Sin\theta = 0.8[/tex]
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The position of a particular particle as a function of is given by r=(8.5t i+5.6j-2tk )m (a) Determine the particle’s velocity and acceleration as a function of time.
(b) Find the instantaneous velocity and acceleration of the particle at t=3.0 s.
Answer:
use google to find answer
Explanation:
69 69 69 69 69 69
A train rounding a curve at a steady speed, balanced or unbalanced force?
Answer:
Unbalanced
Explanation:
It would be speeding and under the influence of an imbalanced force if it were rounding a curve. The train must be subject to an unbalanced force in order for it to continue moving at a constant speed.
What curves a steady speed, balanced or unbalanced force?Newton's first law is only this one. Unless operated upon by an imbalanced force, an item at rest remains at rest and an object in motion maintains constant speed in the same direction.
The car tends to maintain its travel at a steady speed and direction because the two forces balance each other out and cancel each other out.
The forces are out of balance when an object's motion changes. Equal in size and directed in the opposite direction, balanced forces are. When forces are evenly distributed, motion remains unchanged.
Therefore, One of your scenarios from the previous section involved pushing or pulling an object with the equal amount of force in opposite directions.
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A wire 6.60 m long with diameter of 2.05 mm has a resistance of 0.0310 Ω.
Find the resistivity of the material of the wire.
rho= Ω*m
Answer:
1.551×10^-8 Ωm
Explanation:
Resistivity of a material is expressed as shown;.
Resistivity = RA/l
R is the resistance of the material
A is the cross sectional area
l is the length of the wire.
Given;
R = 0.0310 Ω
A = πd²/4
A = π(2.05×10^-3)²/4
A = 0.000013204255/4
A = 0.00000330106375
A = 3.30×10^-6m
l = 6.60m
Substituting this values into the formula for calculating resistivity.
rho = 0.0310× 3.30×10^-6/6.60
rho = 1.023×10^-7/6.60
rho = 1.551×10^-8 Ωm
Hence the resistivity of the material is 1.551×10^-8 Ωm
The various types of tree sloths share the honor of being the slowest-moving
mammals. An average tree sloth moves with a speed of 0.743 m/s. How long does it
take a sloth moving at this speed to travel 22.30 m?
Answer:
16.568 Minutes
Explanation:
Time = speed (m/s) x distance (m)
To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity as measured in W/m2 changes by a multiplicative factor. The number of decibels increases by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is
The question is incomplete. Here is the complete question.
To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is
[tex]\beta=10log(\frac{I}{I_{0}} )dB[/tex],
where [tex]I_{0}[/tex] is a reference intensity. for sound waves, [tex]I_{0}[/tex] is taken to be [tex]10^{-12} W/m^{2}[/tex]. Note that log refers to the logarithm to the base 10.
Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. [tex]I=10I_{0}[/tex]? Express the sound intensity numerically to the nearest integer.
Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. [tex]I=100I_{0}[/tex]? Express the sound intensity numerically to the nearest integer.
Part C: Calculate the change in decibels ([tex]\Delta \beta_{2},\Delta \beta_{4}[/tex] and [tex]\Delta \beta_{8}[/tex]) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.
Answer and Explanation: Using the formula for sound intensity level:
A) [tex]I=10I_{0}[/tex]
[tex]\beta=10log(\frac{10I_{0}}{I_{0}} )[/tex]
[tex]\beta=10log(10 )[/tex]
β = 10
The sound Intensity level with intensity 10x is 10dB.
B) [tex]I=100I_{0}[/tex]
[tex]\beta=10log(\frac{100I_{0}}{I_{0}} )[/tex]
[tex]\beta=10log(100)[/tex]
β = 20
With intensity 100x, level is 20dB.
C) To calculate the change, take the f to be the factor of increase:
For [tex]\Delta \beta_{2}[/tex]:
[tex]I=2I_{0}[/tex]
[tex]\beta=10log(\frac{2I_{0}}{I_{0}} )[/tex]
[tex]\beta=10log(2)[/tex]
β = 3
For [tex]\Delta \beta_{4}[/tex]:
[tex]I=4I_{0}[/tex]
[tex]\beta=10log(\frac{4I_{0}}{I_{0}} )[/tex]
[tex]\beta=10log(4)[/tex]
β = 6
For [tex]\Delta \beta_{8}[/tex]:
[tex]I=8I_{0}[/tex]
[tex]\beta=10log(\frac{8I_{0}}{I_{0}} )[/tex]
β = 9
Change is
[tex]\Delta \beta_{2},\Delta \beta_{4}[/tex], [tex]\Delta \beta_{8}[/tex] = 3,6,9 dB