A Labrador retriever club has 130 members: 65 black Labs, 44 golden Labs, and 21 chocolate Labs. Pablo is going to perform a chi-square goodness-of-fit test to see if the distribution of Labrador retrievers in the club is the same as the distribution nationally. Pablo is going to test his sample against the following null hypothesis, which reflects the national distribution. H0:pblack=0.53,pgolden=0.39,pchocolate=0.08 If the distribution of Labrador retrievers in the club were to match that of the national average, how many of each type of Labrador retriever would Pablo expect to see in his club? Labrador Type Black Golden Chocolate Expected Counts 68.9 50.7 10.4

Answers

Answer 1

Answer:

Step-by-step explanation:

Ap classroom

A Labrador Retriever Club Has 130 Members: 65 Black Labs, 44 Golden Labs, And 21 Chocolate Labs. Pablo

Related Questions

Dwane has a collection of stamps. He arranges them in 5 rows with 6 stamps in each row. 25 of the stamps are a rare edition. How many rare edition stamps does Dwane have?

Answers

Answer:

Dwane has 25 rare edition stamps, or 5/6.

Step-by-step explanation:

The question is basically answered in the problem.

It says, "25 of the stamps are a rare edition."

And the question is, "How many rare edition stamps does Dwane have?"

So, 25 is the answer.

Hope this helps!

(Worth 10 points)
Please actually answer this question

Answers

Answer:

i belive the correct awnser is A

Step-by-step explanation:

9514 1404 393

Answer:

  A  figure 1

Step-by-step explanation:

The given equation is in slope-intercept form:

  y = mx + b . . . . . . where m is the slope and b is the y-intercept

The slope and y-intercept in your equation are both 2. That means the graph crosses the y-axis at y=2 (above the x-axis), and has a positive slope (goes up to the right.

The two top graphs, figures 1 and 2, show lines with positive slope. Only figure 1 shows a graph with positive slope and a positive y-intercept.

20. What is the solution to the equation By -2(y + 1)-3(y-2) + 6?
A) -10
B) 6
C)-2
D) 2

Answers

The answer is C; -2 as -5y+10 is y=-2

22. Using the graph, state the approximate
x-intercept of the function?
a. (0, -1)
b. (0.5, 0)
C. (-1,-1.75)
d. (1, 2)

Answers

Answer:

I believe Awnser B..  (0.5, 0)

Step-by-step explanation:

The answer is B, because if you look at the graph it’s in between 0 and 1, and the number in between them is 0.5. Also it doesn’t move down or up so it would also be 0.

Answer: So the answer is (0.5, 0).

Hope this helps!!

Use the figure to answer the question. 8 8 What is the area of the shaded region of the circle in terms of a? Enter the answer in the box. The area of the shaded region is f units squared.​

Answers

Answer:

48pi

Step-by-step explanation:

pi x 8² - pi x 4²

64pi - 16pi

48pi

from a random sample of 24 months from january 2006 through december 2016, the mean of number of tornadoes per month in the united states was about 100. assume the population standard deviation is 114

Answers

Wow cool nice fun yay

Find the zeros
[tex]x^3+8x^2-20x+48[/tex]

Answers

Answer:

Graph each side of the equation. The solution is the x-value of the point of intersection.

x≈−10.37392996

Step-by-step explanation:

brainliest for answer

Answers

Answer:

im not gonna help u~ but i can talk to u~ <3

Step-by-step explanation:

The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management must decide how many employees to schedule to start work on each shift. The objective is to minimize the total number of employees required while the constraints stipulate how many employees are required at each time of day. The variables X1 - X4 represent the number of employees starting work on each shift (shift 1 through shift 4).

MIN X1 + X2 + X3 + X4

s.t. X1 + X4 ≥ 12 ........(on duty during shift 1)
X1 + X2 ≥ 15 ........(on duty during shift 2)
X2 + X3 ≥ 16 ........(on duty during shift 3)
X3 + X4 ≥ 14 ........(on duty during shift 4)
X1, X2, X3, and X4 ≥ 0

Given the optimal solution: X1* = 13, X2* = 2, X3* = 14, X4* = 0, how many workers would be assigned to shift 2?

a. 13
b. 12
c. 14
d. 15
e. 2

Answers

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1=  13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the  number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting  X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12  in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2  ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

3. Which of the following is the solution for
the inequality below?
-3x+2<8
A x>-3
C x < -2
B x>-2
DX<-3

Answers

x > -2
hope this helps

Jane has:$2
Her ice cream
costs:
What will her
change be?
$1.30

Answers

Answer:

70 cents

Step-by-step explanation:

70 cents
200 cents - 130 cents = 70 cents


4. Your best friend's birthday is tomorrow, and you would like to give her an ice cream cone
balloon. The spherical shaped ice cream on top of the cone has a radius of 6 inches. The cone
itself has a diameter of 12 inches and height of 24 inches. How many cubic inches of helium are
nded to fill the entire ice cream cone balloon? Use 3.14 for it.

Answers

Answer:

1808.64 IN^3

Step-by-step explanation:

Helium needed = volume of spherical shaped ice cream + volume of cone

Volume of a sphere = 4/3 x pi x r^3

4/3 x 3.14 x 6^3 = 904.32 ft^3

Volume of a cone 1/3 x (nr^2h)

n = 22/7

r = radius  = 12/2 = 6

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

h = height

1/3 x 3.14 x 6^2 x 24 = 904.32

helium needed = 2 x 904.32 = 1808.64 in^3

Please help with algebra 2 I took a pic , I have 6 questions n need proof of work

Answers

Here is what I found for this question , hope it helps

find value of x
3x (x+28)

Answers

Answer:

The value of x is 14.

Step-by-step explanation:

3x° = (x + 28)° [ vertically opposite angles

are equal]

3x = x + 28°

3x - x = 28°

2x = 28°

x = 28°/2

x = 14°

A journal article reports that a sample of size was used as a basis for calculating a CI for the true average natural frequency (Hz) of delaminated beams of a certain type. The resulting interval was . You decide that a confidence level of is more appropriate than the level used. What are the limits of the interval

Answers

Answer:

The limit of the (228.533, 234.735)

Step-by-step explanation:

The values are missing in the given question. Therefore, in order to attempt this question, we will make assumptions.

So, let's assume that:

sample size of the journal article that was reported = 5

which is applied for determining a 95% CI

Also, assuming that the resulting interval = (229.764, 233.504)

However, if we are to use a 99% CI which we deemed to be more appropriate;

Then, our objective is to find the limits of this particular interval in question.

To do that:

We need to first find the sample mean at 95% CI by using the formula:

[tex]\Big ( \bar {x} - t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}} \Big) = (229.764,233.504)[/tex]

Since; df = n - 1

df = 5 - 1

df = 4

Then;

[tex]\Big ( \bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} \Big) = (233.504+229.764)[/tex]

[tex]2 \bar {x} = (463.268)[/tex]

[tex]\bar {x} =\dfrac{463.268}{2 }[/tex]

[tex]\bar {x} =231.634[/tex]

Sample mean = 231.634

Using the same formula to determine the standard deviation, we have:

[tex]\Big ( \bar {x} - t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}} \Big) = (229.764,233.504)[/tex]

[tex]\Big ( \bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} \Big) = (233.504-229.764)[/tex]

[tex]\Big ( (\bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} )- (\bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}) \Big) = (233.504-229.764)[/tex]

[tex]\Big ( (\bar x + t_{0.05/2, 4} \ \dfrac{s}{\sqrt{4}}} )- (\bar {x} - t_{0.05/2, 4} \ \dfrac{s}{\sqrt{5}}}) \Big) = (233.504-229.764)[/tex]

At t = 0.025 and df = 4; = 2.776

[tex]2\times 2.776 \dfrac{s}{\sqrt{5}}= 3.74[/tex]

[tex]5.552 \dfrac{s}{\sqrt{5}}= 3.74[/tex]

[tex]\dfrac{s}{\sqrt{5}}= \dfrac{ 3.74}{5.552}[/tex]

[tex]\dfrac{s}{\sqrt{5}}= 0.6736[/tex]

[tex]s = 0.6736 \times \sqrt{5}[/tex]

s = 1.5063

The 99% CI is:

[tex]\implies \Big(\bar x \pm t_{\alpha/2,4} \dfrac{s}{\sqrt{n}} \Big)[/tex]

At t =0.005 and df =4; = 4.604

[tex]\implies \Big(231.634 \pm 4.604 \dfrac{1.5063}{\sqrt{5}} \Big)[/tex]

[tex]\implies \Big(231.634 \pm 4.604 (0.67364) \Big)[/tex]

[tex]\implies \Big(231.634 \pm 3.1014 \Big)[/tex]

[tex]\implies \Big((231.634 - 3.1014), (231.634 + 3.1014) \Big)[/tex]

[tex]\implies \Big( 228.533, 234.735 \Big)[/tex]

I need help pls! optional to give an explanation to help me understand :)

Answers

Answer:
I believe it should be (-4,2)

Explanation:
You can use substitution to solve this, so

1/4x+3 = 2x+10

(Because they both = y)

Then solve for x
X=-4

Then you plug x into one of the equations to solve for y. I used y=1/4(-4)+3

Hope this helps

Answer:

(-4, 2)

Step-by-step explanation:

this is a simultaneous equation;

solving by substitution method, we have;

since y= ¼x + 3 and the same y= 2x + 10

therefore we combine both equations;

¼x + 3= 2x+10

3-10=2x-¼x

to clear out fraction, multiply throughout by 4

-28= 8x-x

-28= 7x

x= -28/7

x= -4

since x is -4, therefore All we have to do is to substitute x into y, doing this, we have;

y=2x+10

y= 2(-4) + 10

y= -8 + 10

y= 2

therefore y= 2 and x= -4

so the values are (-4, 2)

if you still don't understand, check your NGM SS2 textbook or make a comment and I will explain better

at party the pumpkin pie is cut into 14 slices and the cherry pies cut into seven slices if the host wants to serve identical plates that contained the same combination of pumpkin and Cherry sizes with no slices leftover what is the greatest number of plates the host can prepare

Answers

Answer:

The host can only prepare 7 plates

Step-by-step explanation:

7 plates, each will contain 1 slice of cherry pie and 2 slices of pumpkin pie. (14/7 = 2)

Is the equation a linear function?
y = -x + 3 +

Answers

A linear function is y=mx + b so yes (assuming + sign at end is accidental)


The circumference of the circle is about

Answers

Answer:

C=2rPi

Step-by-step explanation:

The circumference of a circle is the 2 times the radius and Pi

What is the value of x

Answers

Answer:

awnser is 36

Step-by-step explanation:

Answer:  x = 37

Step-by-step explanation:

you can use the pythagorean theorem to solve this:

[tex]a^{2} + b^{2} = c^{2}[/tex]

'a' and 'b' in the equation is referring to the legs of the right triangle, or the sides adjacent to the hypotenuse (which is the side opposite the right angle)

plug in the legs into the equation and you get :

[tex]12^{2} + 35^{2} = x^{2}[/tex]

now to solve that we just square 12 and 35 and you get

144 + 1225 = [tex]x^{2}[/tex]

1369 =  [tex]x^{2}[/tex]

x = [tex]\sqrt{1369}[/tex]

x= 37

:))

23 and 25
how do you do the work?
find the areas of each

Answers

9514 1404 393

Answer:

  23)  35.77 in²

  25)  48.19 cm²

Step-by-step explanation:

Use the appropriate area formula with the given information.

__

23) The area of a triangle is given by the formula ...

  A = 1/2bh . . . . . base b, height h

  A = 1/2(9.8 in)(7.3 in) = 35.77 in²

__

25) The area of a parallelogram is given by the formula ...

  A = bh . . . . . . base b, height h

  A = (7.9 cm)(6.1 cm) = 48.19 cm²

_____

The height in each figure is measured perpendicular to the base. This tells you that the length 10.6 cm of the diagonal side of the triangle is not relevant to finding the area.

Answer:

23) 35.77 in2

24) 48.19cm2

A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of 1.2 days. Construct a 95% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits Construct a 92% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits

Answers

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 1.989.

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

[tex]M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

give me a complete and managed answer.​

Answers

Answer:

Solution given:

The given equation of a line is

ax²+2hxy+by²=0

Let y=mx be any one line of

ax²+2hxy+by²=0

Let the perpendicular line of

y=mx is

x+my=0

According to the question the line x+my=0 is one line of Ax²+2Hxy +By²=0

Substituting value of y

Ax²+2Hx [tex] \frac{ - x}{m} [/tex]+[tex]B \frac{x²}{m²} [/tex]=0

Ax²-[tex] \frac{ 2H}{m}x² [/tex]+[tex]B \frac{x²}{m²} [/tex]=0

Taking LCM

we get

Ax²m²-2mHx²+Bx²=0

x²[Am²-2Hm+B]=0..............[1]

Again.

ax²+2hx(mx)+B(mx)²=0

ax²+2hmx²+Bm²x²=0

x²[a+2hm+Bm²]=0

bm²+2hn+a=0.....................[2]

Taking coefficient of equation 1 &2.

equation 1. b 2h a b 2h

equation 2.A. -2h B A -2H

Doing criss cross multiplication

ignore first coefficient and repeat first and second

again

lines are perpendicular so

[tex] \frac{m²}{2hB} [/tex]=[tex] \frac{m}{aA-bB} [/tex]=[tex]\frac{1}{-2Hb-2hA} [/tex]

Taking 1st & 2nd ratio,we get,

m=[tex] \frac{2hB+2Ha}{aA-bB} [/tex]....[*]

Taking 3rd & 2nd ratio,we get,

m=[tex] \frac{aA-bB}{-2Hb-2hA} [/tex] ....[#]

Again

Equating equation * &# we get;

[tex] \frac{2hB+2Ha}{aA-bB} [/tex]=[tex] \frac{aA-bB}{-2Hb-2hA} [/tex]

(aA-bB)²=-4(hB+Ha)(Hb+HA)

(aA-bB)²+4(hB+Ha)(Hb+HA)=0 is a required condition.

Solve.
–51/2 + 63/4 + (-41/4)

Answers

Answer:

-20

Step-by-step explanation:

cause i did the math hope this helped :D

I used a calculator, the answer is

-20

20. Martin sells used cars.
He earns $12.50 per hour, plus 3% commission on
any cars he sells.
On Monday, he worked 6.5 hours and sold a car for
$9,000.
How much money did Martin earn on Monday?
A. $351.25 B. $282.50 C. $243.75

Answers

Answer:

The short answer is that most car salespeople don't earn a whole hell of a lot of money. Dealership salespeople average about 10 car sales per month, and earn an average of about $40k per year. If you do the math, that's about $330 per car.

Step-by-step explanation:

Answer:

You should prob add then multiply

Step-by-step explanation:

i'm sorry if you don't understand !BRB when i get the answer(Let's hope i don't forget.


Solve for x. Round to the nearest tenth. *
9.8
5.3
61.2
8.6

Answers

Answer:

9.85

that is 9.8

Step-by-step explanation:

16sin38=x

x= 9.85

A fence is 8.5 feet tall. How many inches tall is it?

Answers

Answer:

The answer is 102, good luck<3

pls pls pls 4/1 68 The angle that is an alternate exterior angle with angle 2 is angle [?] 57 3/2 A. 3 B. 4 C. 5 D. 6​

Answers

Answer:

B. 4

Step-by-step explanation:

∠4 is an alternate exterior angle with ∠2 because both angles are on the exterior of the lines, and lie on opposite ends on the transversal.

The angle that is an alternate exterior angle with angle 2 is angle 4.

What are Parallel lines?

Parallel lines are those lines that are equidistance from each other and never intersect each other.

Given that;

The figure is shown in figure.

Now,

Since, ∠4 is an alternate exterior angle with ∠2 because both angles are on the exterior of the lines, and lie on opposite ends on the transversal.

Hence, ∠4 is an alternate exterior angle with angle 2.

Thus, The angle that is an alternate exterior angle with angle 2 is angle 4.

Learn more about the parallel lines visit:

https://brainly.com/question/26961508

#SPJ2

How many triangles can the polygon below be divided into? A polygon with 10 sides. 6 7 8 9

Answers

Answer:

240

I think I'm not sure but try

Answer:

C. 8

Step-by-step explanation:

Just took the test (edge)

Good luck soldiers

I’ll make brainly if the answer is right

Answers

The answer is A; 1/2. You add 1 1/2 and 1 1/2 together to get 3. Then you subtract 3 1/2 and 3 to get your answer 1/2. I hope that helps!
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