A lab requires 20.5g of KNO₃. How many moles of KNO₃ are being used in the lab. Your answer should include a correct numerical set up. What is the approximate percent by mass of the water in the hydrated salt? [Show all work.] *

Answer:

98.8g (3 s.f.)

Explanation:

Use the mole = mass/mr equation to find the moles of CaO, then use the molar ratio to find the moles of Fe2O3, which is the same as CaO, (assuming the ratio is 1:1, as you haven't stated it clearly in the question). Then use the equation and input to find Mass, which is 98.8g to 3 s.f.

Answer:

i think its B

Explanation:

Answer:

1mpm(1 meters per minute) Explanation: Speed:Distance/time 25/25=1 plz mark as brainliest

Answer:

1mpm(1 meters per minute)

Answer:

planets,meteoroids and asteroids  

Explanation:

Answer:

pH = 9

Explanation:

pOH = -log[OH-] = -log(1.0 x10^-5) = 5

pOH + pH = 14

pH = 14 - 5 = 9

Answer:

Taxonomy

Explanation: Taxonomy formally names and classifies organisms by thier structure, function, and relationships

Answer:

Dilute sulfuric acid reacts with metals higher than hydrogen in the reactivity series to form sulfate salts and hydrogen gas. Note the metal reactions are different with concentrated sulfuric acid. Iron is cleaned free from rust prior to coating with tin to form tinplate and with zinc to form galvanized iron.

Answer:

A. We still feel gravity because of inertia, which occurs all around us. Gravity is not felt as much because although it feels small, gravity is the attraction that keeps objects on Earth.

B. This is due to a field and a law, which states that opposites attract and like repel.

Actually If you look very close to a plant you see this:

And to answer your question leaves are green due to sun nutrients water and im not sure  what else

Answer: The volume of the gas is 1.98 L.

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.

[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.

We are given:

[tex]V_1=2.2L\\T_1=30^oC=(30+273)K=303K\\V_2=?\\T_2=0^0C=(0+273)K=273K[/tex]

Putting values in above equation, we get:

[tex]\frac{2.2}{303}=\frac{V_2}{273}\\\\V_2=1.98L[/tex]

Thus the volume of the gas is 1.98 L

Answer:

a, to reduce air bubbles

Explanation:

all its asking, is what is the purpose of the cover. and a is the most reasonable out of all of them, even though none of them make any sense.

In this exercise we have to use the knowledge of lunar eclipse to identify the alternatives that correspond to this effect, as follows:

A lunar eclipse happens when the Earth is between the Moon and the Sun, at times when they are aligned. Depending on the position of the Moon, it is total, partial or penumbral. Different stages of a lunar eclipse on a full moon night.

Now,  use the knowledge of solar eclipse to identify the alternatives that correspond to this effect, as follows:

Solar eclipse is an astronomical phenomenon that occurs when the Moon is positioned between the Earth and the Sun, hiding the light emitted by the star towards the planet.

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Answer:

Sr

Explanation:

because it's electronegativity is the highest.

Answer: a

Explanation:

Bc I just did it and yeah

Answer:

d an acid - base reaction.

Explanation:

Answer:

single replacement

Explanation:Look it up and got it from quizlet it should be right.

Answer:

A

Explanation:

because need more number to complete the balance equation

Answer:

Bismuth ( Bi )

Explanation:

Answer:

B. increases the relative concentration of uranium-235 to 30-50% to avoid a nuclear explosion at higher percentages.

Explanation:

Uranium enrichment may be defined as a process which is necessary for creating effective nuclear fuel from the mined uranium by mainly increasing the percentage of the uranium-235 that undergoes fission with a thermal neutrons.

The enrichment process removes the unwanted uranium-238, thus making uranium 235 concentration higher. It takes up much work to increase the relative concentration of the uranium 235 to make it 30% to 50% so as to avoid a nuclear explosion at such higher percentages.

it's neutral

Explanation:

on the ph scale 7-8 is in the middle and everything after 8 is acidic and everything under 7 is basic. (you can look up a picture of a ph scale you will see what I mean)

This solution is neutral .

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Answer:

wait are you talking about the bottom question??

Answer:

its both because your hight can change if u do exercises

Hope it helped.

Answer:

1.02mol

Explanation:

Using the general gas equation below;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 2.0 atm

V = 11.4L

T = 273K

n = ?

Using PV = nRT

n = PV/RT

n = 2 × 11.4/ 0.0821 × 273

n = 22.8/22.41

n = 1.017

n = 1.02mol

Answer:

78 ml

Explanation:

Answer:

H

Explanation:

Approximately 1229.80 grams of hydrogen chloride (HCl) is produced.

We must use the specified number of moles of the limiting reactant, in this case chlorine gas [tex](Cl_2)[/tex], to calculate the mass of hydrogen chloride (HCl) produced during the reaction. We can see from the balanced equation that 1 mole of [tex]Cl_2[/tex] results in the formation of 2 moles of HCl.

Given:

Volume of Cl2 gas = 48.5 L

Temperature (T) = 450 K

Pressure (P) = 1.20 atm

Moles of Cl2 = 1.58 moles

The ideal gas law equation can be used to calculate the amount of HCl produced:

PV = nRT

Where:

P = pressure

V = volume

n = moles

R = ideal gas constant

T = temperature

First, we must use the ideal gas law equation to obtain the amount of HCl in moles:

n(HCl) = (P * V) / (R * T)

Using the known values:

n(HCl) = (1.20 atm * 48.5 L) / (0.0821 L·atm/(K·mol) * 450 K)

≈ 33.73 moles

To the nearest two decimal places, the mass of HCl is equal to its molar mass times its molar mass, or 33.73 mol times 36.46 g/mol, or 1229.80 g.

Mass of HCl = moles of HCl * molar mass of HCl

= 33.73 moles * 36.46 g/mol

≈ 1229.80 grams (rounded to two decimal places)

Therefore, approximately 1229.80 grams of hydrogen chloride (HCl) is produced.

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Answer:

The molal concentration of the solution is approximately 0.124 molal

Explanation:

The given parameters are;

The reduced freezing point of the water = -0.23°C

For freezing point depression of a solution, we have;

[tex]\Delta T_f[/tex] = [tex]K_f[/tex]· b·i

Where;

[tex]\Delta T_f[/tex] = The freezing point depression

[tex]K_f[/tex] = Cyroscopic constant (The freezing-point depression constant) = 1.86° Cm⁻¹ for water

b = The molality of the solution

i = van't Hoff factor = 1

Therefore;

[tex]\Delta T_f[/tex] = [tex]T^{\circ}_f - T_f[/tex]

Where;

[tex]T^{\circ}_f[/tex] = The freezing point of pure water = 0°C

[tex]T_f[/tex] = The freezing point of the solution = -0.23°C

∴ [tex]\Delta T_f[/tex] = [tex]T^{\circ}_f - T_f[/tex] = 0°C - (-0.23°C) = 0.23 °C

From, [tex]\Delta T_f[/tex] = [tex]K_f[/tex]· b·i, we have;

0.23°C = 1.86°C/m × b × 1

∴ b  = (0.23°C/1.86°C/m) ≈ 0.124 molal

Therefore, the molal concentration of the solution, b ≈ 0.124 molal.

Answer:

Approximately [tex]0.11823\; \rm g[/tex] in total for the five tablets.

(Approximately [tex]2.3646 \times 10^{-2}\; \rm g[/tex] per tablet.)

Explanation:

The relative atomic mass of an element is the ratio between:

The definition of moles ensures that the relative atomic mass of an element is approximately numerically equal to the mass (measured in grams) of one mole of the atoms of this element.

The question states that the relative atomic mass [tex]A_{\rm r}[/tex] of iron is [tex]56[/tex]. In other words, the mass of one mole of iron [tex]\rm Fe[/tex] atoms would be approximately [tex]56\; \rm g[/tex].

The question is asking for the mass of some amount of [tex]\rm Fe^{2+}[/tex] ions. Each [tex]\rm Fe^{2+}\![/tex] ion contains two fewer electrons than a neutral [tex]\rm Fe[/tex] atom. Hence, [tex]4.2225 \times 10^{4}\; \rm mol[/tex] of [tex]\rm Fe^{2+} \![/tex] ions might be lighter than the same number of [tex]\rm Fe \![/tex] atoms by a very small extent: The mass of one mole of electrons is approximately [tex]5 \times 10^{-4}\; \rm g[/tex], much smaller than the mass of the same number of [tex]\!\rm Fe[/tex] atoms (approximately [tex]56\; \rm g[/tex].)

Estimate the mass of these [tex]4.2225 \times 10^{4}\; \rm mol[/tex] of [tex]\rm Fe^{2+}[/tex] ions using the mass of the same number of [tex]\rm Fe[/tex] atoms:

[tex]\begin{aligned}&m({\rm Fe^{2+}}) \\ &\approx m({\rm Fe}) \\ &\approx 4.2225 \times 10^{-4}\; \rm mol \\ &\quad\quad \times 56\; \rm g \cdot mol^{-1} \\ &\approx 2.3646 \times 10^{-2}\; \rm g \end{aligned}[/tex].

Five of these tablets would contain approximately [tex]5 \times 2.3646 \times 10^{-2}\; \rm g \approx 0.11823\; \rm g[/tex] of [tex]\rm Fe^{2+}[/tex] ions.