a horizontal string is stretched between two points a Distance 0.80 metre apart the tension in the string is 90 Newtonand it is mass is 4.5 g calculate the wavelength and frequency of the three lowest frequency modes of vibration of the string​

Answers

Answer 1

Answer:

a)  v = 126.5 m / s,  b)   λ₁ = 1.6 m,   λ₂ = 0.8 m, λ₃ = 0.533 m,   f1 = 79 Hz,    

λ₂ = 0.8 m,   f₃ = 237 Hz

Explanation:

This is an exercise we are going to solve in parts, let's start by looking for the speed of the wave in the string.

         v = [tex]\sqrt { \frac{T}{ \mu } }[/tex]

the rope tension is T = 90 N and the density can be calculated

         μ = m / l

let's calculate

         μ = 4.5 10⁻³ / 0.80

         μ = 5.625 10⁻³  kg/m

let's calculate the speed

         v = [tex]\sqrt{ \frac{90 }{5.625 \ 10^{-3}} }[/tex]

         v = 126.5 m / s

For the second part there is a process of resonance in the string. The points where it is attached are nodes so, if L is the length of the chord

         L = ½ λ         1st harmonic

         L = 2/2 λ      2nd harmonic

         L = 3/2 λ      3rd harmonic

         L = n/2 λ      n harmonic

the wavelength of the first three harmonics is requested

           

let's calculate

          λ₁ = 2L

          λ₁ = 2 0.8

          λ₁ = 1.6 m

         

          λ₂ = L

          λ₂ = 0.8 m

          λ₃ = ⅔ L

          λ₃ = ⅔ 0.8

          λ₃ = 0.533 m

To calculate the frequency we use that the speed is related to the wavelength and the frequency

           v = lam f

           f = v / lam

we calculate

           f1 = 126.5 / 1.6

           f1 = 79 Hz

           f2 = 126.5 / 0.8

           f2 = 158 Hz

           f3 = 126.5 / 0.533

           f3 = 237 Hz


Related Questions

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Answers

May Help:

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Answer:

gravity

Explanation:

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Answers

Answer:

735 J

Explanation:

Total height reached(displaced)=10x15 cm

= 10 x 15/100 m

= 1.5 m

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Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m

Hence,

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Answer:

750J

Explanation:

Solution;

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Answers

As the engine heats up, a natural circulation starts, as coolant rises through the engine block by convection. It passes through the top hose, and into the radiator. Inside the radiator, heat is removed from the coolant as it falls from the top to the bottom.
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What made ancient Rome special?

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Answer:

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Explanation:

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Answers

Answer:

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Explanation:

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Answers

Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

Given the following data;

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = mass * velocity [/tex]

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b. To find the momentum of B;

[tex] Momentum \; B = 120 * 0 [/tex]

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c. To find the total momentum of the two persons;

[tex] Total \; momentum = Momentum \; A + Momentum \; B [/tex]

Substituting into the equation, we have;

[tex] Total \; momentum = 220 + 0 [/tex]

Total momentum = 220 Kgm/s.

The total momentum after the collision will be 220 Kgm/s.Momentum is equal to its mass multiplied by its velocity.

What is momentum?

The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;

Momentum = Mass x Velocity

The given data in the problem is;

m₁ is the mass of player A= 110 kg

m₂  is the mass of player B= 120 kg

v₁ is the velocity of player A= 2m/s

v₂  is the velocity of player B=0m/s

P is the total momentum=?

The momentum of player A;

[tex]\rm P_A= m_A \times v_A \\\\ \rm P_A= 110 \times 2 \\\\ \rm P_A= 220 \ Kgm/sec[/tex]

The momentum of player B;

[tex]\rm P_B= m_B \times v_B \\\\ \rm P_B= 120 \times 0 \\\\ \rm P_B= 0 \ Kgm/sec[/tex]

The total momentum is given by;

Total momentum = momentum of the player A+ momentum of the player B

[tex]\rm P= P_A+P_B \\\\ \rm P= 220+0 \\\\ \rm P=220 \ m/sec[/tex]

Hence the total momentum after the collision will be 220 Kgm/s

To learn more about the momentum refer to the link;

https://brainly.com/question/4956182

Flexibility training helps reduce the range of motion of your joints and muscles.
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Answers

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Answers

Answer:

Plants and animals that live in a biome must be able to live and reproduce in the conditions

Explanation:

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Answers

Answer:

10 kg

Explanation:

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m=25/2.5

m=10 kg

mark as brainliest plzzzzz

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Answers

Answer:

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Explanation:

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Answers

Answer:

Force = 2802.8 Newton

Explanation:

Given the following data;

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Force = 286 * 9.8

Force = 2802.8 Newton

Calculate the weight of a boy of mass 67kg on Earth if gravity = 10m/s/s.

Answers

So the equation for weight is mass*gravity. For this example I will use 9.81 and 10.
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Answers

Answer:

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Answers

Complete Question:

Suppose [tex]A = B^n C^m[/tex], where A has the dimensions LT, B has dimensions L²T⁻¹, and C has dimensions LT². Then the exponents n and m have the values

Answer:

The value of n = ¹/₅

The value of m = ³/₅

Explanation:

Given dimensions;

A = LT

B = L²T⁻¹

C = LT²

The values of n and m are calculated as follows;

[tex]LT = [L^2T^{-1}]^n[LT^2]^m\\\\L^1T^1 = [L^{2n}T^{-n}]\times [L^mT^{2m}]\\\\L^1 \times T^1 = [L^{(2n+m)}] \times [T^{(-n +2m)}]\\\\1 = 2n + m -----(1)\\\\1 = -n + 2m ----(2)\\\\from \ (1); \ m = 1-2n, \ \ substitute \ the \ value \ of \ m \ in\ (2)\\\\1= -n +2(1-2n)\\\\1 = -n + 2-4n\\\\1-2 = -5n\\\\-1 = -5n\\\\1= 5n\\\\n = \frac{1}{5} \\\\m = 1 - 2n\\\\m = 1 - 2(\frac{1}{5} )\\\\m = 1- \frac{2}{5} \\\\m = \frac{3}{5}[/tex]

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Answers

Answer:

-4,651.42N

Explanation:

Since we are not asked what to find, we can calculate the force applied by the track as shown;

F = ma

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F = 4400(-44.4)/42

F = -4,651.43N

Hence the required force is -4,651.42N

A box moves 1000 m horizontally as a force F 2000 N is applied downward. What is the work done on the box by F during the displacement?​

Answers

Answer:

D. OJ

Explanation:

An example of any movement showing at least four different energy transformations

Answers

A swinging pirate ship ride at a theme park. Kinetic energy is transferred into gravitational potential energy.
A boat being accelerated by the force of the engine. The boat pushes through the water as chemical energy is transferred into kinetic energy.

Two 15 N forces in same directions are acting on an object. What is the magnitude of the net force?

Answers

Answer:

30N

Explanation:

if it is pushing the object to the left then it would be 30N left and if it is pushing the object to the right it would be 30N right

Answer: 30N

Explanation:

In a free body diagram all the forces are depicted as pointing _______ the central box

Answers

Answer:

There are three forces acting upon the system - the gravity force (the Earth pulls down on the 15.0 kg of mass), the normal force (the floor pushes up on the system to support its weight), and the applied force (the hand is pushing on the back part of the system).

Explanation:

Answer:

what he said

Explanation:

CHECK MY Second post

Answers

Answer:

I dont get it

Explanation:

A rain cloud contains 4.2 × 10^5 kg of water vapor. How long would it take for a 4000 W pump to raise the same amount of water to the cloud’s altitude, 3.500 km?

Answers

Answer:

it will take 1,000.42 hours to raise the same amount of water.

Explanation:

mass of the water to be raised, m = 4.2 x 10⁵ kg

power applied in lifting the water, P = 4000 W

height through which the water will be lifted, h = 3.500 km = 3,500 m

The power applied the water is given as follows;

[tex]Power = Force \times Velocity\\\\P = FV\\\\P = ma \ \times \ V\\\\P = ma \ \times \ \frac{d}{t} \\\\P = mg \ \times \ \frac{h}{t} \\\\P = \frac{mgh}{t} \\\\t = \frac{mgh}{P} \\\\t = \frac{4.2\times 10^5 \times 9.8 \times 3,500}{4,000} \\\\t = 3,601,500 \ s = 1000.42 \ hours[/tex]

Therefore, it will take 1,000.42 hours to raise the same amount of water.

4. A hockey puck with a momentum of -17 kg x m/s when it
collides with a hockey stick moving at 54 kg x m/s on ice.
Once the objects collide, the hockey puck has a momentum
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stick be?

Answers

Answer:

-2 kg x m/s

Explanation:

-17 + 54 = 35 + x

x = -2

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Answer:

I'm pretty sure it's mist, drizzle, droplet, and then rain.

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Answer:

i cant even see it

Explanation:

Spherical mirror is a​

Answers

Answer:

Spherical mirror is a mirror with a curved reflecting surface.

There are two spherical mirrors -

Concave andConvex

Concave Mirror - A spherical mirror , whose reflecting surface is curved inwards , that is , faces towards the centre of the sphere , is called concave mirror.

Cnovex Mirror - A spherical mirror whose reflecting surface is cirved outwards is called convex mirror.

Explanation:

Points of difference :

The reflecting surface of the concave mirror is bulged inwards . But the reflecting surface of the convex mirror is bulged outwards.Concave mirror produces real and inverted images ( except when the object is placed between F and P , concave mirror produces virtual and erect image ) . But is convex mirror always produces virtual and erect images.The image formed by the concave mirror may be enlarged or diminished, according to the position of the object. The image formed by convex will be always diminished.
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