A home with a market value of $240,000 is assessed at 40% of the market value. What's the assessed value?

Answer:

-4*4^7

Step-by-step explanation:

Answer:

-65536

Step-by-step explanation:

I do not think I understand the question but -4*4*4*4*4*4*4*4=-65536

I think there may be missing information like if the question is multiple choice.

Hope that helps

Answer:

x = -25/3

Step-by-step explanation:

The equation simplifies to -3x - 25 = 0, so

-3x = 25 =>

x = -25/3

Answer:

Step-by-step explanation:

We shall find the solution of this problem with the help of vector notation of i , j , which show east and  north direction .

The first displacement can be represented by the following

D₁ = - 3 cos 45 i + 3 sin45 j = - 3 / √2 i + 3 / √2 j

The second  displacement can be represented by the following

D₂ = - 5 cos 45 i - 5 sin45 j = - 5 /√2 i - 5 /√2 j

The third  displacement can be represented by the following

D₃ =  4 cos 45 i + 4 sin45 j =  4 /√2 i + 4 /√2 j

Total displacement D =

D₁ +D₂ + D₃

= i ( -3 -5 + 4 ) / √2 + j ( 3 - 5 + 4 ) / √2 j

= - 4  / √2 i + 2 / √2 j

D = - 2.8288 i + 1.414 j

Magnitude of D

= √ ( 2.8288² + 1.414² )

= 3.16 miles

For direction we calculate angle with X axis

Tanθ = 1.414 / 2.8288

θ = 26 °

As x is negative and Y is positive ,

the direction will be north of west .

Answer:

Option (A)

Step-by-step explanation:

For equation of the line,

Let the equation is, y = mx + b

Slope 'm' of the line passing through two points (-3, 4) and (2, -1),

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

   = [tex]\frac{4+1}{-3-2}[/tex]

   = -1

y-intercept of this line, b = 1

Now we substitute these values in the equation,

y = -x + 1

Let the equation of the parabola is,

y = a(x - h)² + k

Here, (h, k) is the vertex of the parabola,

Since vertex of the given parabola is (0, -5),

then the equation will be,

y = a(x - 0)²- 5

y = ax² - 5

Since a point (2, -1) lies on this parabola,

-1 = a(2)² - 5

5 - 1 = 4a

a = 1

Equation of the parabola will be,

y = x² - 5

Therefore, Option (A) will be the answer.

Answer:

The equation in vertex form is:

[tex]y=(x-2)^2+1[/tex]

Step-by-step explanation:

Recall that the formula of a parabola with vertex at [tex](x_{vertex},y_{vertex})[/tex] is given by the equation in vertex form:

[tex]y=a\,(x-x_{vertex})^2+y_{vertex}[/tex]

where the parameter [tex]"a"[/tex] can be specified by an extra information on any other point apart from the vertex, that parabola goes through.

In our case, since the vertex must be the point (2, 1), the vertex form of the parabola becomes:

[tex]y=a\,(x-x_{vertex})^2+y_{vertex}\\y=a\,(x-2)^2+1[/tex]

we have the information on the extra point (0, 5) where the parabola crosses the y-axis. Then, we use it to find the missing parameter [tex]a[/tex]:

[tex]y=a\,(x-2)^2+1\\5=a(0-2)^2+1\\5=a\,*\,4+1\\5-1=4\,a\\4=4\,a\\a=1[/tex]

The, the final form of the parabola's equation in vertex form is:

[tex]y=(x-2)^2+1[/tex]

Answer:

Nothing can be further done to this equation. It has been simplified all the way.

Answer:

US

World

Step-by-step explanation:

It depends on where you are. A "trapezium" outside the US is the same as a "trapezoid" in the US, and vice versa.

A trapezium (World; trapezoid in the US) is characterized by exactly one pair of parallel lines. One of the lines that are not parallel may be perpendicular to the parallel lines, but that will only be true for the specific case of a "right" trapezium.

__

A trapezium (US; trapezoid in the World) is characterized by no parallel lines. It may have one angle or opposite angles that are right angles (one or two sets of perpendicular lines), but neither diagonal may bisect the other.

In the US, "trapezium" is rarely used. The term "quadrilateral" is generally applied to a 4-sided figure with no sides parallel.

Answer: 24 ounce jar

Step-by-step explanation:

Unit price of 16 ounce jar

= 2.59 / 16

= 0.161875

Unit price of 24 ounce jar

= 3.29 / 24

= 0.137083

Answer:

you will want to have a good understanding of these properties to make the problems in ... Here, the same problem is worked by grouping 5 and 6 first, 5 + 6 = 11. ... “three times the variable x” can be written in a number of ways: 3x, 3(x), or 3 · x. ... Use the distributive property to evaluate the expression 5(2x – 3) when x = 2.

y

The distributive property tells us that if were given an expression such as 3(x + 2), we can multiply the 3 by both the x and the 2 to get 3x + 6.

Answer:

C

Step-by-step explanation:

3x+2-x>8

2x+2>8

2x>8-2

2x>6

x>3

Answer:

C

Step-by-step explanation:

Answer:

[tex] \boxed{\sf Final \ velocity \ (v) = 26 \ m/s} [/tex]

Given:

[tex] \sf v = v_{0} + at[/tex]

[tex]\sf Initial \ velocity \ (v_{0}) = 20 \ m/s \\ \sf Acceleration \ (a) = 1.5 \ m/s^{2} \\ \sf Time \ (t) = 4 \ sec[/tex]

To Find:

Final velocity (v)

Step-by-step explanation:

[tex]\sf Substituting \ value \ of \ Initial \ velocity \\ \sf acceleration \ and \ time \ in \ given \ equation: \\ \\ \sf \implies v = v_{0} + at \\ \\ \sf \implies v = 20 + 1.5(4) \\ \\ \sf 1.5 \times 4 = 6 : \\ \sf \implies v = 20 + \boxed{6} \\ \\ \sf 20 + 6 = 26 : \\ \sf \implies v = 26 \: m/s[/tex]

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

In this question:

[tex]\mu = 2.40[/tex]

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177[/tex]

21.77% probability that the antenna will be struck exactly once during this time period.

Answer:

[tex]71.35-2.093\frac{22.48}{\sqrt{20}}=60.83[/tex]    

[tex]71.35+2.093\frac{22.48}{\sqrt{20}}=81.87[/tex]    

Step-by-step explanation:

Information given

90 34 41 106 84 53 55 48 41 75 49 97 92 73 74 80 94 102 56 83

In order to calculate the mean and the sample deviation we can use the following formulas:  

[tex]\bar X= \sum_{i=1}^n \frac{x_i}{n}[/tex] (2)  

[tex]s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}[/tex] (3)  

[tex]\bar X=71.35[/tex] represent the sample mean for the sample  

[tex]\mu[/tex] population mean (variable of interest)

s=22.48 represent the sample standard deviation

n=20 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

The degrees of freedom are given by:

[tex]df=n-1=20-1=19[/tex]

Since the Confidence is 0.95 or 95%, the significance is [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value would be [tex]t_{\alpha/2}=2.093[/tex]

And replacing we got:

[tex]71.35-2.093\frac{22.48}{\sqrt{20}}=60.83[/tex]    

[tex]71.35+2.093\frac{22.48}{\sqrt{20}}=81.87[/tex]    

Answer:

P(33) = 0.0826

Step-by-step explanation:

The binomial distribution in this case has parameters n=55 and p=0.55.

The probability that k successes happen with these parameters can be calculated as:

[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{55}{k} 0.55^{k} 0.45^{55-k}\\\\\\[/tex]

We have to calculate the probability fo X=33 succesess.

This can be calculated using the formula above as:

[tex]P(x=33) = \dbinom{55}{33} p^{33}(1-p)^{22}\\\\\\P(x=33) =1300853625660220*0.0000000027*0.0000000235\\\\\\P(x=33) =0.0826\\\\\\[/tex]

The result will be the probability that 17 or fewer out of the 50 sampled students are bilingual.

To determine the probability that 17 or fewer out of 50 sampled students are bilingual, we can use the binomial probability formula. Let's calculate it step by step:

First, we need to determine the probability of an individual student being bilingual. We can do this by dividing the number of bilingual students by the total number of students:

P(bilingual) = 466 / 1320

Next, we'll use this probability to calculate the probability of having 17 or fewer bilingual students out of a sample of 50. We'll sum up the probabilities for having 0, 1, 2, ..., 17 bilingual students using the binomial probability formula:

P(X ≤ 17) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 17)

Where:

P(X = k) = (nCk) * (P(bilingual))^k * (1 - P(bilingual))^(n - k)

n = Sample size = 50

k = Number of bilingual students (0, 1, 2, ..., 17)

Now, let's use a calculator to compute these probabilities. Assuming you have access to a scientific calculator, you can follow these steps:

Convert the probability of an individual being bilingual to decimal form: P(bilingual) = 466 / 1320 = 0.353

Calculate the cumulative probabilities for having 0 to 17 bilingual students:

P(X ≤ 17) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 17)

Using the binomial probability formula, we'll substitute the values:

P(X ≤ 17) = (50C0) * (0.353)^0 * (1 - 0.353)^(50 - 0) + (50C1) * (0.353)^1 * (1 - 0.353)^(50 - 1) + ... + (50C17) * (0.353)^17 * (1 - 0.353)^(50 - 17)

Evaluate this expression using your calculator to get the final probability. Make sure to use the combination (nCr) function on your calculator to calculate the binomial coefficients.

for such more question on probability

https://brainly.com/question/23417919

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Using the central limit theorem, the probability that 17 or fewer of them are bilingual.

The following information is given in the question:

Population size N = 1320

Number of bilingual students = 466

Sample size n = 50

number of bilingual students in the sample = 17

Population proportion:

[tex]P =\frac{466}{1320}[/tex]

P =0.3530

Q= 1-3530

Q = 0.647

Sample proportion:

[tex]p = \frac{17}{50}[/tex]

p = 0.34

q = 1-0.34

q = 0.66

Since,

[tex]X \sim B(n, p)[/tex]

E(x) = np and var(x) = npq

Here, the sample size (50) is large and the probability p is small.

So we can use the central limit theorem, which says that for large n and small p :

[tex]X \sim (nP, nPQ)[/tex]

Where, P =0.3530

nP = 50 x 0.3530 = 17.65

and nPQ = 50x0.3530x0.647 = 11.41

Now, we want to calculate P(X≤17)

[tex]P(X\leq 17) = P(\frac{x-nP}{\sqrt{nPQ}}\leq \frac{17-17.65}{\sqrt{11.41}})[/tex]

[tex]P(X\leq 17) = P(z}\leq \frac{-0.65}{3.78}})[/tex]

[tex]P(X\leq 17) = P(z}\leq -0.172)[/tex]

[tex]P(X\leq 17) = P(z}\geq 0.172)[/tex]

[tex]P(X\leq 17) =1- P(z}\leq 0.172)[/tex]

[tex]P(X\leq 17) =1-0.56[/tex]

[tex]P(X\leq 17) =0.44[/tex]

Hence, the probability that 17 or fewer of the students are bilingual is 0.44.

Learn more about central limit theorem here:

https://brainly.com/question/898534

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Answer:

Step-by-step explanation:

Area of the circular zone = [tex]\pi[/tex]r^2

= 3.14 × 40^2 = 3.14 × 1600 = 5024 m^2

Area of the basketball court = l × b

= 30 × 15 = 450 m^2

Area of the trapezium shaped park =  ( 6 + 4 ) 3.5 / 2

= 35/2 = 17.5 m^2

∴ Area left in the circular zone = Area of the circular zone - ( Area of the basketball court + Area of the trapezium shaped park )

= 5024 - ( 450 + 17.5 )

= 5024 - 467.5

= 4556.5 m^2

hope this helps

plz mark it as brainliest!!!!!!!

Answer:

  8.3

Step-by-step explanation:

The Pythagorean theorem helps you find AD:

  AD² +CD² = AC²

  AD = √(AC² -CD²) = √(5² -4²) = √9 = 3

The triangles in the figure are all similar, so

  BD/CD = CD/AD

  BD = CD²/AD = 4²/3 = 5.333

Then

  AB = AD +BD = 3 + 5.333

  AB = 8.333 . . . . rounds to 8.3

Answer:

end

January

April

1st blank might also be (account)

Answer:

January and April

Step-by-step explanation:

Answer:

Function

Step-by-step explanation:

y = 1/3 x - 4

Is a function because for every x, we will get only one value of y.

Answer:

Yes,is a function

We can obtain the points (0,-4)(6,-2)

I hope this help you :)......  

Answer:

97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Step-by-step explanation:

We are given that a random sample of tires is chosen and are driven until they wear out and the number of thousands of miles is recorded;

32, 33, 28, 37, 29, 30, 22, 35, 23, 28, 30, 36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                                P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample average number of miles = [tex]\frac{\sum X}{n}[/tex] = 30.25

            s  = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = 4.71

            n = sample of tires = 12

            [tex]\mu[/tex] = population average number of miles

Here for constructing a 97% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 97% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.55 < [tex]t_1_1[/tex] < 2.55) = 0.97  {As the critical value of t at 11 degrees of

                                              freedom are -2.55 & 2.55 with P = 1.5%}  

P(-2.55 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.55) = 0.97

P( [tex]-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.97

P( [tex]\bar X-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.97

97% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                        = [ [tex]30.25-2.55 \times {\frac{4.71}{\sqrt{12} } }[/tex] , [tex]30.25+2.55 \times {\frac{4.71}{\sqrt{12} } }[/tex] ]

                                        = [26.78 miles, 33.72 miles]

Therefore, 97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Answer:

[tex]n=(\frac{2.58(0.34)}{0.05})^2 =307.79 \approx 308[/tex]

So the answer for this case would be n=308 rounded up to the nearest integer

Step-by-step explanation:

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =0.1/2 =0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} s}{ME})^2[/tex]   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution since the sample size is large enough to assume the estimation of the standard deviation as the population deviation. The critical value for this case is [tex]z_{\alpha/2}=2.58[/tex], replacing into formula (b) we got:

[tex]n=(\frac{2.58(0.34)}{0.05})^2 =307.79 \approx 308[/tex]

So the answer for this case would be n=308 rounded up to the nearest integer

Answer:

Your correct answer is 31/50 + -4/25 i

Step-by-step explanation:

5+4i/6+8i = 31/50 + -4/25 i

Answer:

216-343

Step-by-step explanation:

the number 312 lies between 125 and 330

Answer:

The answer is nothing duh

Step-by-step explanation:

Answer:

The lowest score eligible for an award is 92.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 82.2, \sigma = 5[/tex]

If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award

The lowest score is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975. So X when Z = 1.96. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.96 = \frac{X - 82.2}{5}[/tex]

[tex]X - 82.2 = 5*1.96[/tex]

[tex]X = 92[/tex]

The lowest score eligible for an award is 92.

Answer: The number of quarter inches in 23 inches is 4 × 23 = 92

None of the answers given is correct.

Step-by-step explanation:

The ÷ sign means divide.

There are 4 quarter inches in each inch, so you have to multiply 23 × 4

Dividing by 14 makes no sense.

23 ÷ 1/4 = 92 is also an equation that makes sense.

Answer:

Step-by-step explanation:

max can be found by the formula:

t=-b/2a

t=-9.8/2*(-4.9)

t=-9.8/-9.8

t=1

1 sec

to find maximum height obtained we find the vertex:

plug in 1 for t and simply solve:

h(t)= -4.9t^2 + 9.8t + 1

h(t)= -4.9*1^2 + 9.8*1 + 1

h(t)= -4.9*1 + 9.8 + 1

h(t)= -4.9 + 10.8

h(t)= 5.9

height is 5.9

Answer:

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

Answer:

The value of a is 0.

Step-by-step explanation:

Given that (x+1) is a factor to a function, it means that when x = -1 is substitute into the function, you will get a 0 value. So you have to substitute the value of x into the function and make it 0, to find a :

[tex]p(x) = a {x}^{2} + x + 1[/tex]

[tex]let \: p( - 1) = 0 \\ let \: x = -1[/tex]

[tex]p( - 1) = a {( - 1)}^{2} + ( - 1) + 1[/tex]

[tex]0 = a - 1 + 1[/tex]

[tex]a = 0[/tex]

Answer:

Solution,

To find a,

We should know that,

Factor of polynomial gives root of polynomial like:x-a if a factor of p(X) then p(a)=0 at X=a

So,

X+1=0

X=0-1

X=-1

put x=-1 into p(X) it gives zero.

[tex]p( - 1) = 0 \\ a {( - 1)}^{2} + ( - 1) + 1 = 0 \\ a(1) - 1 + 1 = 0 \\ a = 0[/tex]

hope this helps....

Good luck on your assignment....

Answer:

2

Step-by-step explanation:

Scale Factor = [tex]\frac{AnySideOfDiagram}{AnySideOfMP3Player}[/tex]

So,

Scale Factor = [tex]\frac{8}{4} = \frac{14}{7}[/tex] = 2

So,

The scale factor is 2