Answer:
R ≈ 15 ohms
Explanation:
Using ohm's law equation,
I = V/R, to solve for the resistance of the heating coil.
R = V/I
Known:
V = 220 v = 220 kgm^2s^-3A^-1
I = 15 A
Unknown:
R =?
Solution:
R = (220 kgm^2s^-3A^-1)/ 15.0 A
R = 14.6 kgm^2s^-3A^-2
R ≈ 15 kgm^2s^-3A^-2
R ≈ 15 ohms
A bullet with mass m = 5.21 g is moving horizontally with a speed v = 443 m/s when it strikes a block of hardened steel with mass M = 14.8 kg (initially at rest). The bullet bounces off the block in a perfectly elastic collision. (a) What is the speed (m/s) of the block immediately after the collision?
[tex]V_{f2} =0.29 \dfrac{m}{s}[/tex] :Speed of the block immediately after the collision.
What is the elastic collision?
From elastic collision theory.
Momentum of a body is given as
[tex]P=m\times v[/tex]
where
p:Linear momentum
m: mass
v:velocity
There are 3 cases of collisions : elastic, inelastic and plastic.
For elastic collision the change in momentum remains constant
[tex]P_{i} =P_{f}[/tex]
Nomenclature and data
m₁: ball mass= 5.21 g= 5.21*10⁻³kg
V₀₁: initial ball speed, =412 m/s
[tex]V_{f1}[/tex]: final ball speed
m₂: block mass = 14.8 kg
V₀₂: initial block speed, = 0
[tex]V_{f2}[/tex]: final block speed
We apply furmula
[tex]P_{i} =P_{f}[/tex]
m₁[tex]\times[/tex]V₀₁+m₂[tex]\times[/tex]V₀₂=m₁[tex]\times[/tex]Vf₁+m₂[tex]\times[/tex]Vf₂
5.21[tex]\times[/tex]10⁻³[tex]\times[/tex]412+14.8[tex]\times[/tex]0= 5.21[tex]\times[/tex]10⁻³[tex]\times[/tex]Vf₁+14.8[tex]\times[/tex]Vf₂
2.15= 5.21*10⁻³[tex]\times[/tex]Vf₁+14.8[tex]\times[/tex]Vf₂ Equation (1)
For perfectly elastic collision the coefficient of elastic restitution (e) is equal to 1, and e is defined like this:
[tex]e=\dfrac{v_{f2-V_{f1} } }{v_{01-V_{ 02} } }[/tex]
1*(V₀₁-V₀₂) =Vf₂-Vf₁ , V₀₂=0, V₀₁ =412 m/s
412=Vf₂-Vf₁
Vf₁=Vf₂-412 Equation (2)
We replace Equation (2) in Equation (1)
2.15= 5.21[tex]\times[/tex]10⁻³(Vf₂-412)+14.8[tex]\times[/tex]Vf₂
2.15= 5.21[tex]\times[/tex]10⁻³*Vf₂-2.15+14.8*Vf₂
4.3=14.805Vf₂
[tex]Vf_{2} =\dfrac{4.3}{14.805} =0.29 \dfrac{m}{s}[/tex]: (+) ,with equal direction of the movement of the ball before the collision.
Hence [tex]V_{f2} =0.29 \dfrac{m}{s}[/tex] Speed of the block immediately after the collision.
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A 2:2 kg toy train is con ned to roll along a straight, frictionless track parallel to the x-axis. The train starts at the origin moving at a speed of 1:6m=s in the +x direction, and continues until it reaches a position 7:5m down the track from where it started. During its journey, it experiences a force pointing in the same direction as the vector 0:6 +0:8 , with magnitude initially 2:8N and decreasing linearly with its x-position to 0N when the train has finished its journey.
Required:
a. Calculate the work done by this force over the entire journey of the train.
b. Find the speed of the train at the end of its journey.
Answer:
a) 10.51 J
b) 3.48 m/s
Explanation:
Given data :
mass of train ( M ) = 2.2 kg
Given initial velocity ( u ) = 1.6 m/s
a) calculating work done by the force over the journey of the train
F = mx + b ------ ( 1 )
m = slope = ( Δ f / Δ x ) = 2.8 / -7.5 = - 0.373 N/m
x = distance travelled on the x axis by the train = 7.5 m
F = force experienced by the train = 2.8 N
x = 0
∴ b = 2.8
hence equation 1 can be written as
F = ( -0.373) x + 2.8 ----- ( 2 )
hence to determine the work done by the force
W = [tex]\int\limits^7_0 { ( -0.373) x + 2.8 )} \, dx[/tex] Note: the limits are actually 7.5 and 0
∴ W ( work done ) = -10.49 + 21 = 10.51 J
b) calculate the speed of the train at the end of its journey
we will apply the work energy theorem
W = 1/2 m*v^2 - 1/2 m*u^2
∴ V^2 = 2 / M ( W + 1/2 M*u^2 ) ( input values into equation )
V^2 = 12.11
hence V = 3.48 m/s
15 points!
a. Calculate the electric potential energy stored in a 1.4 x 10-7 F capacitor
that stores 3.40 x 10-6 C of charge at 24.0 V.
Answer:
[tex]4.12\times 10^{-5}\ J[/tex].
Explanation:
Given that,
Capacitance, [tex]C=1.4\times 10^{-7}\ F[/tex]
Charge stored in the capacitor, [tex]Q=3.4\times 10^{-6}\ C[/tex]
We need to find the electric potential energy stored in the capacitor. The formula for the electric potential energy stored in the capacitor is given by :
[tex]E=\dfrac{Q^2}{2C}[/tex]
Put all the values,
[tex]E=\dfrac{(3.4\times 10^{-6})^2}{2\times 1.4\times 10^{-7}}\\\\=4.12\times 10^{-5}\ J[/tex]
So, the required electric potential eenergy is equal to [tex]4.12\times 10^{-5}\ J[/tex].
A candle is placed 50 cm from a diverging lens with a focal length of 28. What is the image distance in cm.
Answer:
v = -17.94 cm
Explanation:
Given that,
The candle is placed at a distance of 50 cm, u = -50 cm
The focal length of the diverging lens, f = -28 cm (negative in case of a concave lens)
We need to find the image distance. We know that the lens formula is as follows:
[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(-28)}+\dfrac{1}{(-50)}\\\\v=-17.94\ cm[/tex]
So, the image distance is equal to 17.94 cm.
Which of these will be the correct relationship between work input and work output?
A) Work input = Work output + Work against friction
B) Work input = Work output – Work against friction
C) Work input = Work output * Work against friction
D) Work input = Work output / Work against friction
Answer:
Work input = Work output * Work against friction is your answer so C
Explanation:
I hope this helps you :)
Answer:
A) Work input = Work output + Work against friction
Explanation:
A student must analyze data collected from an experiment in which a block of mass 2M traveling with a speed v0 collides with a block of mass M that is initially at rest. After the collision, the two blocks stick together. What applications of the equation for the conservation of momentum represent the initial and final momentum of the system for a completely inelastic collision between the blocks?
Solution :
In the question, it is given that the collision is inelastic and the blocks stick together.
In an inelastic collision, the linear momentum is conserved but the kinetic energy is not conserved.
The linear momentum is given by :
[tex]$\vec p = m \vec v$[/tex] (mass x velocity)
So according to the conservation of linear momentum,
[tex]$\vec p_{(\text{before collision})}=\vec p_{(\text{after collision})}$[/tex]
Let the velocity after the collision is [tex]$v_F$[/tex]
[tex]$m_1v_0+m_2 \times 0 = m_1v_F+m_2v_F$[/tex]
Putting the values of [tex]$m_1 \text{ and}\ m_2$[/tex]
[tex]$m_1=2M \text{ and}\ m_2=M$[/tex]
∴ [tex]$2Mv_0=2Mv_F+Mv_F$[/tex], as the blocks stick together after the collision.
and [tex]$2MV_0=3Mv_F$[/tex], as the blocks stick together after the collision.
What is a negative effect of increased carbon dioxide within the carbon cycle?
Answer:
Explanation:
Carbon dioxide controls the amount of water vapor in the atmosphere and thus the size of the greenhouse effect. Rising carbon dioxide concentrations are already causing the planet to heat up.
People, animals, and all matter on Earth are
A. drawn toward the center of Earth by the planet's gravity
B. drawn toward other matter on Earth like the trees and the buildings, since all matter has gravity
C. not affected by Earth's gravity because people are so small in
comparison to the planet
D. held to Earth's surface by their own gravity
Answer:
A
Explanation:
To answer this, we can use process of elimination.
B: This question states that all matter has gravity. This is not correct. All matter is *effected* by gravity, but we do not have gravity inside of us.
C: If this were the case, we would all be floating off into space.
D: Same issue as question B.
1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.
How far will it go before it is moving at 20 m/s?
A) 83
B) 43
C) 39
D) 94
E) 20
Answer:
(D) x = 93.8 m
Explanation:
v^2 = v0^2 + 2ax
(20 m/s)^2 = (5 m/s)^2 + 2(2 m/s^2)x
Solving for x,
x = 93.8 m
The fictional rocket ship Adventure is measured to be 65 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c. As rocket ship Adventure passes by the space dock, the ship's captain flashes a flashlight at 1.20-s intervals as measured by space-dock personnel.
Required:
How often does the flashlight flash relative to the captain?
Answer:
1.04 s
Explanation:
The computation is shown below:
As we know that
t = t' × 1 ÷ (√(1 - (v/c)^2)
here
v = 0.5c
t = 1.20 -s
So,
1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)
1.20 = t' × 1 ÷ (√(1 - (0.5)^2)
1.20 = t' ÷ √0.75
1.20 = t' ÷ 0.866
t' = 0.866 × 1.20
= 1.04 s
The above formula should be applied
How does the presence of a nucleus provide a method of basic cell
classification? *
Answer:
The nucleus-containing cells are called eukaryotic cells. Eukaryote means having membrane-bound organelles.
Explanation:
I hope this is what you were looking for?!
Hope this helps!
Have a great day!
-Hailey!
The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.
What is a nucleus?
The nucleus is the controlling center of the body. It performs all the major activities in the cell. The cell which possesses a nucleus is called a eukaryote. The cell which does not have a nucleus is called prokaryote.
A prokaryotic cell is a straightforward, one-celled (unicellular) organism that is devoid of a nucleus or any other organelle that is membrane-bound. The nucleoid, a dark area in the center of the cell, is where prokaryotic DNA is located.
Therefore, The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.
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5. A 6.0-kilogram mass is moving with a speed of 2.0 m/s. What is the kinetic energy of the mass?
Answer:
K.E. = ½ × mv²
= ½ × 6 × (2)²
= ½ × 6 × 4
= 3 × 4
= 12 J
The diagram shows a charge moving into an electric field. The charge will most likely leave the electric field near which letter? OW OX OY OZ
you haven't attached the diagram, but i assume that this diagram is what you were talking about
Answer:
near Y
Explanation:
the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. the field lines are created from +vely charged plate to -vely charged plate so the negative charged particles moves towards the lower plate which is positively charged, and opposite to the direction of field lines.
The charge will most likely leave the electric field near Y letter. Hence option C is correct.
What is electric charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C
The charge on the electron is negative, and the force is directed in the opposite direction as the electric field. When an electron is projected perpendicular to a uniform electric field, it experiences an electric force in the opposite direction of the field.
the trajectory of the charged particle in the electric filed is parabolic and in magnetic field it is circular. when this electron moves perpendicular to the electric field, electron experience force in opposite direction to the electric field and due to parabolic nature, it will leave at Y.
Hence option C is correct.
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A negative charge of 2 C and a positive charge of 3 C are separated by 80 m. What is the force between the two charges?
Answer:
6
Explanation: i looked this up.
According to the Coloumb's law, the force is obtained from the charges and the distance between them is 8.4375×10⁶ N. This force results in the attractive force.
What is Coloumb's law?Coloumb's law states the relation between the charges and the distance between the charges. Coloumb's law states that the Force is directly proportional to the product of charges and inversely proprotional to the square of distance between them.
The Coloumb's law gives the force of attraction or repulsion between the charged bodies. Two charges with positive or negative charges repels each other. One positive and one negative charge attract each other.
The force increases with the product of charges increases as product of charges and force are directly proprotional. The force decreases with the increase in distance of seperation and vice-versa. The SI unit of force is newton (N).
The Coloumb's law is:
F = k (q₁×q₂ / r²)
k is the constant of proportionality and is equal to 9×10⁹ N.m²/C².
q₁, q₂ = charges
r² = distance of seperation of charges.
From the given,
q₁ = -2C ( negative sign represents the negative charge)
q₂ = +3C ( + sign represents the positive charge)
r² = 80 m ( distance between the charges)
F = k (q₁×q₂ / r²)
= 9×10⁹×2×3 / 80×80
= 54×10⁹ / 6400
= 8437500 N
F = 8.4375×10⁶ N
There is the presesnce of both positive and negative charges, hence it results in the attractive force. Hence, the force F between two charges separated by 80m is 8.4375×10⁶ N.
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please help, no links please! I dont understand stand this question and im going to cry
Which part of this system is in the gas phase?
Answer:
I'm pretty sure its helium
In Part 5.2.3 of the experiment, you will measure the index of refraction of yellow light using Lab Manual Equation 5.2. Suppose the minimum angle of deviation is 18 degrees. What is the index of refraction
Answer:
The answer is "1.26".
Explanation:
[tex]D=18^{\circ}[/tex]
The refractive index is:
[tex]\to \mu=2\sin(30^{\circ}+\frac{D}{2})\\\\[/tex]
[tex]=2\sin(30^{\circ}+\frac{18^{\circ}}{2})\\\\=2\sin(30^{\circ}+9^{\circ})\\\\=2\sin(30^{\circ}+9^{\circ})\\\\=2\sin(39^{\circ})\\\\=2 \times 0.63\\\\=1.26[/tex]
Which is a property of bases?
A.
highly metal reactive
B.
sour to the taste
C.
slippery feel
D.
low pH
Answer:
C. Slippery feel
Explanation:
Can someone take there time and answer this :)
Answer: I think B.)
Explanation:
In 2-3 complete sentences, analyze how scientists know dark matter and dark energy exist.
Answer:
It doesn't interact with baryonic matter and it's completely invisible to light and other forms of electromagnetic radiation, making dark matter impossible to detect with current instruments. But scientists are confident it exists because of the gravitational effects it appears to have on galaxies and galaxy clusters.
Explanation:
4. Speedy leaves the ground with an initial vertical velocity of 53 m/s and a horizontal velocity of 42 m/s.
How much time does he spend in the air?
How far (horizontally) does he travel during this time?
5. The Angry Bird is fired at an angle of 35 above the horizontal at a speed of 72 m/s.
Draw the initial velocity vector
Determine the initial horizontal velocity
Determine the initial vertical velocity
How much time does it spend in the air?
What horizontal distance does it go?
An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a period of 0.54 s . His older sister pulls the spring a bit more than intended. She pulls the animal 32 cm below its equilibrium position, then lets go. The animal flies upward and detaches from the spring right at the animal's equilibrium position. Part A If the animal does not hit anything on the way up, how far above its equilibrium position will it go
Answer:
the wooden animal will go 0.7068 m above its equilibrium
Explanation:
Given the data in the question;
mass of wooden animal m = 120 g = 0.12 kg
the animal oscillates up and down, T = 0.54 s
older sister pulls the animal 32 cm below its equilibrium position;
x = 32 cm = 0.32 m
g = 9.81 m/s²
We know that
k = mω²
where ω = 2π/T
So, k = m( 2π/T )²
we substitute
k = 0.12( 2π / 0.54 )²
k = 0.12 × (11.6355)²
k = 0.12 × 135.38486
k = 16.25 N/c
so Also,
kx²/2 = mgh
we solve for h
h = kx² / 2mg
we substitute
h = ( 16.25 × (0.32)²) / ( 2 × 0.12 × 9.81 )
h = 1.664 / 2.3544
h = 0.7068 m
Therefore, the wooden animal will go 0.7068 m above its equilibrium
Suppose that a lion moves due EAST as to travel 25km in 4.2 hours. What is the average speed, and what is the average velocity. (2 answers separated by a comma)
Answer:
5.95 km/h
Explanation:
Given that,
Distance moved, d = 25 km
Time taken by the lion, t = 4.2 hours
Average speed = distance/time
And
Average velocity = displacement/time
Here, distance = displacement
So,
[tex]v=s=\dfrac{25\ km}{4.2\ h}\\\\v=5.95\ km/h[/tex]
So, the average speed and the average speed of the lion is equal to 5.95 km/h.
On Apollo Moon missions, the lunar module would blast off from the Moon's surface and dock with the command module in lunar orbit. After docking, the lunar module would be jettisoned and allowed to crash back onto the lunar surface. Seismometers placed on the Moon's surface by the astronauts would then pick up the resulting seismic waves.
Find the impact speed of the lunar module, given that it is jettisoned from an orbit 110 km above the lunar surface moving with a speed of 1600 m/s .
My Approach:
Ei = Ef
1/2*m*vi2 - (G*m*ME)/(radius of moon + orbital distance) = 1/2*m*vf2 - (G*m*ME)/r
=> (0.5 * m * 16002) - (6.67 * 10-11 * 7.35*1022 * m/(1737.4*103 +180*103) = (0.5*m*v^2) - (6.67*10-11 * 7.35*1022 * m/(1737.4*103 )
Answer:
Following are the solution to the given question:
Explanation:
For crashing speed, we can use energy conservation:
kinetic energy [tex]= \frac{1}{2}\times m \times v^2[/tex]
potential energy [tex]= -\frac{GMm}{r}[/tex]
moon mass[tex]= 7.36\times 10^{22} \ kg[/tex]
Radius[tex]= 1738\ km[/tex]
[tex]\to (K + U) \ orbit = (K + U)\ crash\\\\\to \frac{1}{2}\times m \times v_o^2 - \frac{GMm}{(1738000 + 110000)} \\\\ \to \frac{1}{2}\times m \times vc^2 - \frac{GMm}{1738000}[/tex]
Calculating the mass drop for the leave:
[tex]\to \frac{vo^2}{2} - \frac{GM}{1848000}\\\\ \to \frac{vc^2}{2} - \frac{GM}{1738000}[/tex]
Solve the value for
[tex]vc = \sqrt{(vo^2 +2\times GM \times(\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = \sqrt{(1600^2 +2\times 6.67\times 10^{-11} \times 7.36 \times 10^{22}\times (\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = 1701 \ \frac{m}{s}\\\\[/tex]
The approach is correct but misrepresented in replacing 180 km instead of 110 km.
A geologist notices that a river is eroding its valley at a constant rate. Knowing the height of the valley walls, how could the geologist figure out when the river started carving the valley?
A.
Count growth rings of trees growing on the valley floor.
B.
Divide the height of the valley walls by the rate of erosion.
C.
Fill up the river valley with rocks, and time how long it takes the rocks to wash out.
D.
Sit and observe the river for a few hours until the valley walls double in height.
Answer:
B.
Divide the height of the valley walls by the rate of erosion.
Explanation:
There is a relationship between the rate of erosion and the hieght at which it is eroded according to Newton's law of motion. In the case of the scenario above, the best way to determine the time the river started carving the valley would be the division of the height of the valley walls by the rate of erosion.
Saved Which of the following is NOT an important function of facial display? Multinio Choic
A. emotion
B. attractiveness
c. Primacy
d. identity
Answer:
C
Explanation:
Primacy means being first or important so thats not an important facial display as the others.
What is surface tension
Answer:
Surface tension is, the surface where the water meets the air, water molecules cling even more tightly to each other.
Consider the model of the energy transformation of this system. What can you say about N and M in the model?
A) M < N
B) N = M
C) N < M
D) N + M =
Model of the energy transformation of this system we can say about N and M in the model is M < N.
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
The model shows the energy transformation in electrical appliance Fan the is lass of energy in form of heat so M < N.
Model of the energy transformation of this system we can say about N and M in the model is M < N.
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Why don’t the northern and Southern Hemisphere experience summer at the same time?
Answer:
It is because of the tilt of the earth.
Explanation:
the earth is tilted at 23.5 degrees. this makes it so that either the northern or southern hemisphere will be exposed to more rays from the sun. In the areas that are getting more rays from the sun, it gets warmer. Think about it like this, because the earth is tilted, part of it is more in the shade and part of it is more in the light. And its colder in the shade, so thats why seasons happen and why they dont happen at the same time.
In a physics lab experiment for the determination of moment of inertia, a team weighs an object and finds a mass of 4.07 kg. They then hang the object on a pivot located 0.155 m from the object's center of mass and set it swinging at a small amplitude. As two of the team members carefully count 113 cycles of oscillation, the third member measures a duration of 247 s. What is the moment of inertia of the object with respect to its center of mass about an axis parallel to the pivot axis
Answer:
I = 0.65 kgm²
Explanation:
Since the mass is an inertial pendulum, we use the formula for the period, T of an inertial pendulum.
T = 2π√(I/mgh) where I = moment of inertia of object about pivot point, m = mass of object5 = 4.07 kg, g = acceleration due to gravity = 9.8 m/s² and h = distance of center of mass of object from pivot point = 0.155 m.
Given that the team measures 113 cycles of oscillation in 247 s, the period, T = time of oscillations/total number of oscillations = 247 s/113 oscillations = 2.186 s/oscillation
So, T = 2.186 s
We now find I by making it subject of the formula in the equation for T.
So,
T = 2π√(I/mgh)
dividing both sides by 2π, we have
T/2π = √(I/mgh)
squaring both sides, we have
(T/2π)² = [√(I/mgh)]²
T²/4π² = I/mgh
multiplying both sides by mgh, we have
T²mgh/4π² = I
I = T²mgh/4π²
substituting the values of the variables into the equation, we have
I = T²mgh/4π²
I = (2.186 s)² × 4.07 kg × 9.8 m/s² × 0.155 m/4π²
I = 4.778 s² × 4.07 kg × 9.8 m/s² × 0.155 m/4π²
I = 29.539 kgm²/4π²
I = 0.748 kgm²
Now I = I' + mh² (parallel axis theorem) where I' = moment of inertia of object about its center of mass, m = mass of object = 4.07 kg and h = distance of center of mass object from pivot point.
So, I' = I - mh²
Substituting the values of the variables into the equation, we have
I' = I - mh²
I' = 0.748 kgm² - 4.07 kg × (0.155 m)²
I' = 0.748 kgm² - 4.07 kg × 0.02403 m²
I' = 0.748 kgm² - 0.098 kgm²
I = 0.65 kgm²
How does the wave period relate to the frequency of a wave?
Answer:
its in the picture hope it helps make brainlliest ty