Answer:
669.1 ft and 743.1 ft
Explanation:
Given data
Lenght of wire= = 1000ft
Angle = 42˚
Applying SOH CAH TOA
1. How tall is the tower?
SOH
sine ∅= opp/hyp
sin 42= opp/1000
0.6691= Opp/1000
0.6691*1000= Opp
Opp=669.1 ft
Applying SOH CAH TOA
2.How far away from the base of the tower does the wire hit the ground?
CAH
cos ∅= adj/hyp
cos 42= adj/1000
0.7431*1000=adj
adj=743.1 ft
It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest with 6.4 g bullets at the rate of 92 bullets/min, and the speed of each bullet is 400 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets
Answer:
Magnitude of the average force = 7.85 N
Explanation:
Data given:
Mass of bullets, m = 6.4 g
Rate of bullets/min, r = 92 bullets/min
Speed of each bullet, v = 400 m/s
Change in momentum here, Δ B = Bf - Bi
where f is the final and i is the initial
Note that change in momentum = force X time
So, Δ B = m(vf - vi)
= 2mv
= 2 X 0.0064 kg X 400 m/s (convert g to kg)
= 5.12 kg.m/s (for one bullet)
so for the 92 bullets = 92 X 5.12 kg.m/s
= 471.04 kg.m/s
The force = Δ B ÷ Δt
where t = time measured in 60 seconds
= 471.04 kg.m/s ÷ 60 seconds
= 7.85 N
What is Ship Handling, an art or a science? Why?
Ship handling is both a science and an art. Science because it requires knowledge of various forces acting on the ship. Art because it requires the skills of an experienced navigator to use these forces in his favour. We may learn the science part from the various ship handling courses.
please give brainliest
A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.65 ms from an initial speed of 5.25 m/s . What is the magnitude of the average contact force exerted on the leg, assuming the total mass of the hand and the forearm to be 1.75 kg
Answer:
the magnitude of the average contact force exerted on the leg is 3466.98 N
Explanation:
Given the data in the question;
Initial velocity of hand v₀ = 5.25 m/s
final velocity of hand v = 0 m/s
time interval t = 2.65 ms = 0.00265 s
mass of hand m = 1.75 kg
We calculate force on the hand F[tex]_{hand[/tex]
using equation for impulse in momentum
F[tex]_{hand[/tex] × t = m( v - v₀ )
we substitute
F[tex]_{hand[/tex] × 0.00265 = 1.75( 0 - 5.25 )
F[tex]_{hand[/tex] × 0.00265 = 1.75( - 5.25 )
F[tex]_{hand[/tex] × 0.00265 = -9.1875
F[tex]_{hand[/tex] = -9.1875 / 0.00265
F[tex]_{hand[/tex] = -3466.98 N
Next we determine force on the leg F[tex]_{leg[/tex]
Using Newton's third law of motion
for every action, there is an equal opposite reaction;
so, F[tex]_{leg[/tex] = - F[tex]_{hand[/tex]
we substitute
F[tex]_{leg[/tex] = - ( -3466.98 N )
F[tex]_{leg[/tex] = 3466.98 N
Therefore, the magnitude of the average contact force exerted on the leg is 3466.98 N
Two children are throwing a ball back-and-forth straight across the back seat of a car. The ball is being thrown 7 mph relative to the car, and the car is travelling 45 mph down the road. If one child doesn't catch the ball and it flies out the window, in what direction does the ball fly (ignoring wind resistance)
Answer:
the ball will fly in AX direction, making angle of 8.84° from the motion of the car
Explanation:
Given the data in the question and as illustrated in the diagram below;
Now, Lets assume line AB represent the movement of the car,
AC is the movement of the ball been thrown back and forth in the back seat
Ax is the motion of the ball it flies off the window
so from the diagram, We can see triangle ABC
where AB is 45 mph and AC = 7 mph
and angle ∠CAB = 90°
using SOH CAH TOA
TOA; tanθ = Opposite / Adjacent
tanθ = Opposite / Adjacent
tan( ∠ ABC ) = AC / AB
we substitute
tan( ∠ ABC ) = 7 / 45
tan( ∠ ABC ) = 0.15555
( ∠ ABC ) = tan⁻¹ 0.15555
( ∠ ABC ) = 8.84°
Therefor, angle ( ∠ ABC ) is 8.84°
Meaning angle ( ∠ XAA' ) is also 8.84°
Therefore, the ball will fly in AX direction, making angle of 8.84° from the motion of the car
A uniform electric field exists everywhere in the x,y plane. The electric field has a magnitude of 3500 N/coil, and is directed in the positive x direction. A point charge of -9.0 x 10-9 coil is placed at the origin. Determine the magnitude of the net electric field at: (a) x
Answer:
5525 N/C
Explanation:
Magnitude of electric field ( E ) = 3500 N/c
Direction of electric field : positive X axis
point charge ( q ) = -9.0 * 10^-9
Calculate the Magnitude of the net electric field at (a) x = -0.20 m
Magnitude = 5525 N/C
Electric field due to q = ( 9 * 10^9 * 9 * 10^-9 ) / ( -0.2 )^2
= 81 / 0.04 = 2025 N/c
Therefore the magnitude of the net electric field
= 2025 + 3500
= 5525 N/C
How do tsunamis cause flooding? Please answer in 4-5 sentences.
PLEASE HELP! GIVING BRAINLIEST!
Answer: YES
Explanation: The main difference between flood and tsunami is that the flood is overflow of water that submerges land and tsunami is a series of water waves caused by the displacement by large volume of a volume of water
Answer:
WEEEEEEEEEEEEEEEEEEEEEEEEE
Explanation:
A physics student mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them, and they appear concentric when viewed from either end). The lenses are identical, each with a positive (converging) focal length of 14.8 cm. They are separated by a distance of 39.4 cm. Lens 1 is to the left of Lens 2.
Required:
a. What is the final image's distance (in cm) from Lens 2?
b. Where is the final image located?
c. What is the overall magnification of the lens pair, considered as a single optical instrument?
Answer:
A) q₂ = 75.98 cm, B) q₂' = 115.38 cm, C)
Explanation:
A) This is an exercise in geometric optics, as the two lenses are separated by a greater distance than their focal lengths from each lens, they must be worked as independent lenses.
Lens 1. More to the left
let's use the constructor equation
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and the image, respectively,
We must assume a distance to the object to perform the calculation, suppose that the object is 50 cm from lens 1 that is further to the left of the system.
[tex]\frac{1}{q_1} = \frac{1}{f} - \frac{1}{p}[/tex]
[tex]\frac{1}{q_1} = \frac{1}{14.8} - \frac{1}{50}[/tex]
1 / q₁ = 0.04756
q₁ = 21.0227 cm
this image is the object for the second lens that has f₂ = 14.8 cm
the distance must be measured from the second lens
p₂ = 39.4 -q₁
p₂ = 39.4 -21.0227
p₂ = 18.38 cm
let's use the constructor equation
1 / q₂ = 1 / f - 1 / p2
[tex]\frac{1}{q_2} = \frac{1}{14.8} - \frac{1}{18.38}[/tex]
[tex]\frac{1}{q_2}[/tex] = 0.01316
q₂ = 75.98 cm
measured from the second lens
B) the position of the final image with respect to the first lens is
q₂’= q₂ + 39.4
q₂'= 75.98 +39.4
q₂' = 115.38 cm
C) the magnification of a lens is
m = - q / p
in this case the image measured from lens 2 is q2 = 75.98 cm
the distance to the object from the first lens is p1 = 50cm
m = - 75.98 / 50
m = -1.5 X
the negative sign indicates that the image is inverted
A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for small-angle oscillations is 0.940 s. (a) What is the moment of inertia of the wrench about an axis through the pivot
Answer:
[tex]I=0.0987kg.m^2[/tex]
Explanation:
From the question we are told that:
Mass [tex]M=1.80kg[/tex]
Deviation [tex]d=0.250[/tex]
Time [tex]t=0.940s[/tex]
Generally the equation for moment of inertia is mathematically given by
[tex]I=\frac{T}{2\pi}^2(mgd)[/tex]
[tex]I=\frac{0.94}{2.3.142}^2(1.80*9.8*0.250)[/tex]
[tex]I=0.0987kgm^2[/tex]
What is an electron?
(it’s D lol)
Answer:
D
Explanation:
Explain what happens during stages A and B.
Which type of energy is demonstrated by a person jogging?
A. electrical energy
B. nuclear energy
C. electromagnetic energy
D. kinetic energy
What happens to the force between two magnets as the magnets come closer together? *
Explanation:
So if two magnets are pointing with unlike-poles together (north pole to a south pole), then bringing them closer together decreases the energy stored up in the magnetic field. They will be pushed in the direction that decreases the amount of stored-up energy.
Explanation:
depending on the polarity they'll increasingly repel or attract
The amount of change between the crest or trough of a wave and the normal
What is the resistance of a rheostat coil, if 0.05 A of current flows through it when 6 V is applied
across it? 1200
Answer:
i have no idea i came here to find out too :(
Explanation:
An engine flywheel initially rotates counterclockwise at 5.03 rotations/s. Then, during 23.5 s, its rotation rate changes to 2.63 rotations/s clockwise. Find the flywheel's average angular acceleration (including its sign) in radians per second squared. Define counterclockwise rotation as positive.
Answer:
the flywheel's average angular acceleration is -2.05 rad/s²
Explanation:
Note: counterclockwise is positive
clockwise is negative
Given;
initial angular velocity, [tex]\omega _i[/tex] = 5.03 rev/s = [tex]5.03\frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 31.61 \ rad/s[/tex]
final angular velocity, [tex]\omega_f[/tex]= -2.63 rev/s = [tex]-2.63 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = -16.53 \ rad/s[/tex]
duration of the flywheel rotation, Δt = 23.5 s
The average acceleration of the flywheel is calculated as;
[tex]a_r = \frac{\Delta \omega}{\Delta t} = \frac{\omega_f - \omega _i}{t_2-t_1} = \frac{-16.53 \ - \ 31.61}{23.5} = -2.05 \ rad/s^2[/tex]
Therefore, the flywheel's average angular acceleration is -2.05 rad/s²
True or false in order for light to be emitted electrons must move from high energy state to a lower energy state?
1 point
A.True
B.False
Answer:
B
I think it is false.
It does not move to lower energy state.
I will mark u brainlist
Answer:
DragonFly or a dog
Explanation:
Help me please! I'm confused!
Answer: To cause disease, a pathogen must successfully achieve four steps or stages of pathogenesis: exposure (contact), adhesion (colonization), invasion, and infection.
Explanation:
Our Most Plentiful Resources
Which two renewable technologies do not
rely on energy from the Sun?
wind and hydroelectric
What is the typical pH of acid rain?
Answer:
5.0-5.5 is the answer to your question
His eyes are 1.83 m above the floor, and the top of his head is 0.15 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet.
Answer:
y_lower = 0.915 m, y_superior = 1,905 m
Explanation:
In this exercise we use the law of reflection for a flat mirror.
θ’= θ
To see the feet of the person a ray of light that part of them must reach the bottom of the mirror and its reflection has to reach the eyes.
As the law of reflection the incident and reflected angles are equal, the distance from the floor to the point where the two rays (incident and reflected) touch the mirror must be symmetrical, oses from the floor
y = 1.83 / 2
y = 0.915 m
To see the head, a ray of light that comes from the tip of the head and is reflected in the mirror must reach the eyes. As the head is 0.15 m above the eyes and the incident and reflected rays have the same angle, the mirror must be at half the height, that is, the mirror is 0.075 m below the tip of the head.
In summary
* the bottom of the mirror is 0.915 m from the ground
* the top of the mirror is at 1.83 + 0.075
y_superior = 1,905 m
ground
An object with a mass of 2.00 kg is placed at the end of a spring, having a spring constant of 180.0 N/m. The spring is then compressed 0.890 m. What is the maximum velocity of the mass?
Answer:
the velocity of the mass is 8.44 m/s
Explanation:
Given;
mass of the object, m = 2 kg
spring constant, k = 180 N/m
extension of the spring, x = 0.89 m
The maximum velocity of the mass is calculated as follows;
By the principle of conservation of energy;
Elastic potential energy = kinetic potential energy
¹/₂kx² = ¹/₂mv²
kx² = mv²
[tex]v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s[/tex]
Therefore, the velocity of the mass is 8.44 m/s
The table shows the relationship between the masses of two objects, the distance between the two objects, and the gravitational force between the objects. A 4-column table with 5 rows. The first column labeled Mass of Object 1 (kilograms) has entries 1, 2, 2, 3, 9. The second column labeled Mass of Object 2 (kilograms) has entries 1, 1, 2, 3, 3. The third column labeled Distance between Objects 1 and 2 (meters) has entries 1, 1, 2, 1, 3. The fourth column labeled Gravitational Force Objects 1 and 2 (Newtons) has entries 1 G, 2 G, 1 G, 9 G, 3G. Which conclusion is supported by the data in the table? An increase in the mass of an object causes the same decrease in the gravitational force. An increase in the distance between the objects causes the same decrease in the gravitational force. An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. An increase in the mass causes a greater change in the gravitational force than the same increase in the distance between the objects. Brainlyest for correct answer!
Answer:
C
Explanation:
edge 2020... Using elimination it's the only one that makes sense.
The statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
What is gravitational force?The gravitational force is a force that attracts all mass-bearing objects. The gravitational force is referred to as attractive because it always strives to pull masses together rather than pushing them apart.
As we know, the gravitational force is given by:
[tex]\rm F = \dfrac{Gm_1m_2}{r^2}[/tex]
Where, G is the gravitational constant.
m1 and m2 are masses.
r is the distance between the masses.
From the data given in the table, shows that:
The gravitational force is indirectly proportional to the square of the distance.
Thus, the statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
Learn more about the gravitational force here:
https://brainly.com/question/12528243
#SPJ2
What is the period of a wave with a speed of 10 m/s and frequency of 23 Hz?
The frequency calculator will let you find a wave's frequency given the wavelength and its velocity or period in no ... velocity equals 320 m/s and its wavelength is 8 m. Find its frequency. f = 320 m/s / 8 m. f = 40/s. f = 40 Hz.
A wave has a speed of 450 m/s and a frequency of 5 Hz. What is its wavelength?
Give you answer to a 1 decimal place.
Your Answer:
Answer
the wavelength is 90
Explanation:
two spheres of radii 5cm and 3cm are given charges on risk volume and 50 calling respectively and then connected by a wire calculate the loss of energy after connection
Answer:
Solution given:
Radius of small sphere[r]=5cm=0.05m
Radius of large sphere[R]=10cm=0.1m
capacitance of small sphere[c]=4πε0r
=[tex]4π*8.85×10^{-12}×0.05=5.56*10^{-12}F[/tex]
Charge for small sphere[Q1]=100C
Charge for small sphere[Q2]=50C
Potential difference [V1]=[tex] \frac{charge}{capacitance}=\frac{100}{5.56*10^{-12}}=1.8×10^{13}[/tex]V
.
again
capacitance of small sphere[C]=4πε0R
=[tex]4π*8.85×10^{-12}×0.1=1.11*10^{-11}F[/tex]
Potential difference [V2]=[tex] \frac{charge}{capacitance}=\frac{50}{1.11*10^{-11}}=4.5×10^{12}[/tex]V
Now
Loss of energy:
[tex] \frac{cC(V1-V2)^{2}}{2(c+C)}[/tex]
=[tex] \frac{5.56*10^{-12}*1.11*10^{-11}(1.8*10^{13}-4.5*10^{12})^{2}}{2(5.56*10^{-12}+1.11*10^{-11})}[/tex]
=25Joule
An electric motor draws out 5 A of current from a 20 V battery. How much power is it using?
Answer: c
Explanation:
bc x=1 if x^1
Two horizontal strings are attached to a block, resting on a frictionless surface as shown
below.A force of 100N pulls on one string. The block does not move. Find the value o
force, F on the other string
ON
Answer:
100N in the opposite direction
Explanation:
as the block is not moving, we can apply the formula f=ma where the total force is equal to the mass times accelaration, since the block is not moving, the net force is zero meaning that the other force is completely cancelling out the force of 100N, or to put it in a maths equation, 100-force=0 as the block is stationary. we can therefore assume that the force cancelling the 100N out is equal to it and therefore 100N in the opposite direction
What does a Lewis structure diagram represent?
Answer:
Its answer is
The atomic symbol of an element surrounded by valence electrons.
Explanation:
Si un vector tiene una dirección de 2300 a partir del eje x positivo, ¿Qué signos tendrán sus componentes x y y? Si la la razón de R/R, es negativa. ¿cuáles son los ángulos posibles de R, medidos a partir del eje x positivo?