A guitar player tunes the fundamental frequency of a guitar string to 560 Hz. (a) What will be the fundamental frequency if she then increases the tension in the string by 15%? (b) What will it be if, instead, she decreases the length along which the string oscillates by sliding her finger from the tuning key one-third of the way down the string toward the bridge at the lower end?

Answers

Answer 1

Answer:

(a) if she increases the tension in the string is increased by 15%, the fundamental frequency will be increased to 740.6 Hz

(b) If she decrease the length of the the string by one-third the fundamental frequency will be increased to 840 Hz

Explanation:

(a) The fundamental, f₁, frequency is given as follows;

[tex]f_1 = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L}[/tex]

Where;

T = The tension in the string

μ = The linear density of the string

L = The length of the string

f₁ = The fundamental frequency = 560 Hz

If the tension in the string is increased by 15%, we will have;

[tex]f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T\times 1.15}{\mu}} }{2 \cdot L} = 1.3225 \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = 1.3225 \times f_1[/tex]

[tex]f_{(1 \, new)} = 1.3225 \times f_1 = (1 + 0.3225) \times f_1[/tex]

[tex]f_{(1 \, new)} = 1.3225 \times f_1 =\dfrac{132.25}{100} \times 560 \ Hz = 740.6 \ Hz[/tex]

Therefore, if the tension in the string is increased by 15%, the fundamental frequency will be increased by a fraction of 0.3225 or 32.25% to 740.6 Hz

(b) When the string length is decreased by one-third, we have;

The new length of the string, [tex]L_{new}[/tex] = 2/3·L

The value of the fundamental frequency will then be given as follows;

[tex]f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \times \dfrac{2 \times L}{3} } =\dfrac{3}{2} \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = \dfrac{3}{2} \times 560 \ Hz = 840 \ Hz[/tex]

When the string length is reduced by one-third, the fundamental frequency increases to one-half or 50% to 840 Hz.


Related Questions

1. How far does a 70 kg object move in meters (m) if it
accelerates at 13 m/s2 and 50 joules of work is done?

Answers

Answer:

Units of work would be equivalent to a Newton times a meter. ... An individual force does NOT do positive work upon an object if the object is moving at ... FALSE - Watt is the standard metric unit of power; Joule is the standard metric unit of energy. ... TRUE - A kg•m2/s2 is a mass unit times a speed squared unit, making it a ...

Which statement describes the relationship between bond strength and the melting and boiling points of a substance?

A. As the force between the particles increases, the melting point increases and the boiling point decreases
B. As the force between the particles increases, the melting point decreases and the boiling point increases
C. As the force between the particles increases, the melting and boiling points decrease.
D. As the force between the particles increases, the melting and boiling points also increase.​

Answers

Answer:

D

Explanation:

The relationship between bond strength and the melting and boiling points can be explained as the force between the particles increases, and the melting and boiling points also increase.​Therefore the correct option is D.

What is the boiling point?

It is a temperature at which the pressure exerted by the external atmosphere is equal to the vapor pressure of the substance.

The boiling point depends on atmospheric pressure, temperature, bond strength, and vapor pressure of the liquid.

The bond strength between different atoms of the substance greatly influences the boiling point and melting point.

Learn more about boiling point

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EXERCISE 1

An object and an image are displayed on either side of a lens. Copy the figure to your sheet.

A) Calculate the focal length using the lenses formula.
B) Determine where the focal length should be, using the light construction beams.
C) Draw the light beam that illuminates the entire lens from point B. Draw how it continues after the lens.
D) Measure the focal length, object distance and image distance and write it down as shown in the figure under the graph paper.

Answers

.........The answer is A

What is one advantage of using electromagnets instead of permanent magnets

Answers

The main advantage of an electromagnet over a permanent magnet is that the magnetic field can be quickly changed by controlling the amount of electric current in the winding. However, unlike a permanent magnet that needs no power, an electromagnet requires a continuous supply of current to maintain the magnetic field.

HELPPP ILL GIVE YOU BRAINLIST

which example below best illustrates electrical energy being converted into radiant energy?

A ) Fusing hydrogen nuclei in the sun
B ) Igniting fireworks
C ) lighting an Bunsen burner with a flint striker
D ) Turing on a light bulb

Answers

Answer:

Turning on a light bulb.

It would be d because light blud is used to make electricity and conveys to light which I radiant

A backpack weighs 8.2 Newtons and has a mass of 5 kilograms on the moon what is the strength of gravity on the moon

Answers

i dont get it so much but

The weight of the bag pack is 8.2 N. g = 1.64 m/s2. Hence, the acceleration due to gravity on moon is 1.64 m/s2. sooo? is it right

A man started at his house and went to the post office, then to the pet store, and finally home again. What is the average velocity if this trip took three hours?


Explain how you arrived at your answer.

Answers

Answer:

0

Explanation:

Defining velocity :

Velocity is a vector which is the ratio of a person's total displacement with time.

Displacement, in simple terms refers to the distance between an individual's initial position to his final position.

Man's initial position = House

After all his navigation and points covered irrespective of the distance ;

Final position = House

Hence, we can conclude that the man's Displacement is ;

Final position - Initial position = 0

Hence,

Velocity = Displacement / time taken

Velocity = 0 / 3

Velocity = 0

How long a workout session last is called?

Answers

Explanation:

Assuming the strength training sessions last roughly 20 minutes each, that breaks down to about three hours of exercise a week. According to these recommendations, beginner exercisers should work up to three to four 40-minute gym sessions per week.

Answer:

The American Heart Association recommends 75 to 150 minutes of aerobic activity, and two strength training sessions per week. Assuming that strength training sessions last approximately 20 minutes each, that totals about three hours of exercise per week.

Two objects of mass 5 kg and 8 kg at rest F1 and F2 meters force applied on both the boxes respectively If the speed of both the objects after 5 sec become 16m/s and 15m/s respectively find the value of F1 and F2?

Answers

Answer:

F1 = 16 N and F2 = 24 N

Explanation:

Formula used => F = a and v-u= at

So, as we know force = mass × acc.

so acc. of first block = <math> F1/5 </math>. and acc. of second block = <math> F2/ 8 </math>.......... so as v-u= at.. now

Here u= 0 as the objects are placed at rest initially..

thus, v= at

FOR 1ST BLOCK

16= <math> F1/5 </math> × 5 ==> F1 = 16 N

FOR 2ND BLOCK

15= <math> F2/ 8 </math> × 5 ==> F2= 24 N

3.
Where is the weight of an object more on earth, Equator or poles? Why?​

Answers

Answer:

The weight of an object at the poles is more than the weight of the object at the equator

Explanation:

The shape of the Earth is an ellipsoid such that the distance from the North and South poles to the Earth's center, R₁, is less than the distance from the Equator to the center of the Earth, R₂

The weight of an object is given by the universal gravitational law as follows;

[tex]Weight = F_{gravity} =G\times \dfrac{M \cdot m}{R^{2}}[/tex]

Where;

[tex]F_{gravity}[/tex] = The force of gravity = The weight of an object

G = The universal gravitational constant

M = The mass of the Earth

m = The mass of the object

R = The radius of the Earth

Where R₁ < R₂, we have;

The weight at the Poles, W₁ = [tex]G\times \dfrac{M \cdot m}{R_1^{2}}[/tex]

The weight at the Equator, W₂ = [tex]G\times \dfrac{M \cdot m}{R_2^{2}}[/tex]

We have;

[tex]\left(G\times \dfrac{M \cdot m}{R_1^{2}} \right) > \left(G\times \dfrac{M \cdot m}{R_2^{2}} \right) \because R_1 < R_2[/tex]

Therefore, the weight of an object at the poles, W₁, is more than the weight of the object at the equator, W₂

You are standing on the bleachers in the gym. What supporting force are you experiencing?
a. Friction
b. Tension
c. Gravity
d. Normal

Answers

B I’m pretty sure might be c either one of those

[They are both the same passage]
What was Deborah Ashcraft’s motivation for organizing the Canstruction project in 1992? Use at least 2 details from the article to support your answer.

Answers

Answer:

jejeje

Explanation:

jejejejejee

Un cilindro contiene 10 L de oxígeno y otro contiene 10 L de dióxido de carbono, ambos se encuentran a 25 °C. De acuerdo con el modelo cinético de partículas, se puede afirmar que...

Answers

Answer:

Ver explicacion

Explanation:

Según el modelo cinético, las moléculas de gas están en constante movimiento.

La energía cinética promedio de las moléculas del gas depende de la temperatura del gas y de la masa molar del gas.

Si los dos gases ocupan el mismo volumen a la misma temperatura, la energía cinética promedio ahora depende de la masa molar de los gases individuales. Cuanto menor sea la masa molar del gas, mayor será la velocidad media de las moléculas del gas.

El oxígeno gaseoso tiene una masa molar menor que el dióxido de carbono. Por lo tanto, el oxígeno tiene una velocidad molecular promedio mayor que el dióxido de carbono.

An airplane traveling at 201 m/s makes a turn. What is the smallest radius of the circular path (in km) that the pilot can make and keep the centripetal acceleration under 5.0 m/s2 ?

Answers

Answer:

the smallest radius of the circular path is 8.1 km

Explanation:

The computation of the smallest radius of the circular path is given below:

Given that

V = Velocity = 201 m/s

a_c = acceleration = 5 m/s^2

radius = ?

As we know that

a_c = V^2 ÷ r

5 = 201^2 ÷ r

r = 201^2 ÷ 5

= 8,080.2 g

= 8.1 km

Hence, the smallest radius of the circular path is 8.1 km

An 6 kg object accelerating from 17 m/s to 10 m/s. What is the change in momentum of the object?

Answers

Answer:

Explanation:

Comment

It's a deceleration. You are slowing down.

Givens

vi = 17 m/s

vf = 10 ms

m = 6 kg

delta mv = ?

Formula

delta mv = m * (vf - vi)

Solution

delta mv = 6 (10 - 17)

delta mv = 6 ( -7)

delta mv = - 42

A rocket is fired at 60 to the horizontal with an initial speed of 200m5 calculate it time of flight and it range on the horizontal plane

Answers

Answer:

See answer below

Explanation:

In order to do this, we just need to apply the expression to determine the time of flight. This is given by:

t = 2 V₀ Sinθ / g   (1)

We have the initial speed which is 200 m/s, the angle of elevation to the horizontalis 60° and the gravity is 9.8 m/s². Replacing this data in the above expression we have:

t = 2 * 200 Sin60° / 9.8

t = 35.348 s

Now that we have the time, we can determine the range or distance in the horizontal plane. This can be calculated using the following expression:

X = V * t   (2)

We already have the time, which is the time of flight, the initial speed using cos 60° (Cause it's horizontal plane), and replacing we have:

X = 200 cos60° * 35.348

X = 100 * 35.348

X = 3534.8 m

Hope this helps

(a) If a person can jump a maximum horizontal distance (by using a 45° projection angle) of 3.0 m on Earth, what would be his maximum range on the Moon, where the free-fall acceleration is g/6 and g 5 9.80 m/s2 ? (b) Repeat for Mars, where the acceleration due to gravity is 0.38g.

Answers

Answer:

See explanation

Explanation:

Range of a projectile is given by; U^2sin2θ/g

When θ = 45°

The maximum range is obtained as;

Rmax = U^2/g

Maximum range on earth = RME = U^2/g

Maximum range in the moon= RMM =U^2/g/6

Maximum range in Mars = RMMA = U^2/0.38g

a)

RME/RMM =  U^2/g/U^2/g/6

RME/RMM = 6

But RME = 3 m

RMM = 3 * 6 = 18 m

b)

RME/RMMA =U^2/g/U^2/0.38g

RME/RMMA = 1/0.38

But RME = 3 m

RMMA = 3/0.38

RMMA = 7.9 m

bill nye electricity notes

Answers

Answer:

the answer is c

Explanation:

PLS HELP! I WILL GIVE BRAINLIEST TO BEST/ CORRECET ANSWER! 15 POINTS PER PERSON! PLS HELP!


Logan lists the causes of floods in Florida.



Which cause does not belong in the list?


A. big storms

B. inadequate drainage system

C. mild storms

D. rip currents


BTW: The fact that I selected an answer in the picture does not matter. Thank you!

Answers

Answer:

c might be right

Explanation:

c doesn't make any sense. big storms mean more water for flooding, inadequate drainage system means the water can't leave certain areas, I'm not sure what rip currents are tho

Answer:

rip currents

I live in florida, and we don't have mild storms either its big one or none :)

Explanation:

and can you help me please, its 30 points

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https://brainly.com/question/21745542

^^ there the same question but the first website i misspelt it but its 30 points and the 2nd website is the question written out right but its 5 point but there the same thing you need to do, you can put the same thing for both and get extra point idc, i just need help lease

How does sound travel? *
Air molecules move in a straight line in one direction.
Air molecules move in waves that sometimes bounce back.
Air molecules move in waves in one direction.
None of the above.

Answers

Answer: 2 i think

Explanation:

Answer:Im pretty sure its the second one because sound sometimes bounces back and that causes echo and it doesnt travel in one line or direction

Explanation:

A 100-meter sprint is a race using only the straight side
of a racetrack. A 400-meter sprint is a race that makes
one complete lap around a racetrack. Why are velocity
and speed the same for a 100-m sprint but not a 400-m
sprint?

Answers

Answer: : it is so because velocity and speed differ each other by direction. in a 100 m sprint race ,the person moves in a straight path without changing its direction where as in a 400 m race , the person moves in a lap around the race track and the direction changes as he turns according to the race track.

Explanation:

During heavy exercise, muscle cells use oxygen more quickly than normal. Which system responds by carrying extra oxygen to these muscle cells?
a. digestive b. circulatory c. nervous
d. immune

Answers

Answer:

The answer is B. Circulatory

You are so excited that you have finished this test that you give your friend a huge high five with 20N of force.

With how much force does your friend's hand high five you back?

Answers

Answer:

20N

Explanation:

newtons 3rd law every action has an equal opposite reaction

I'm not too sure

How does electricity flow through a conductor?

Answers

Answer:

Electricity works by getting a bunch of conductor elements together and creating a flow of electron-stealing patterns through them. This flow is called a current. Conductors need to be surrounded with insulators so the electrons can only go in one direction.

Explanation:

The simple act of walking requires single leg

full body

and

a strong

and

full body

Answers

you are so wise how do you do it?

Huhhhhhhh??)???????????

A bullet of mass 0.05kg has a speed 400.what is it's kinetic energy.
if the bullet hits a wall of which the average resistive force is 10000 newton.calculate the distance penetrated by the bullet.​

Answers

Answer:

K.E =1÷2M×V^2

= 1÷2×0.05×(400)^2

= 4000

Explanation:

What are isotopes.
Please answer soon

Answers

each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

PLEASE HELP
A 0.200 plastic ball moves with a velocity of 0.30 m/s . It collides with a second plastic ball of mass 0.1200 K B , which is moving along the same line at a speed of 0.10 m/s * A * f * t * e * r the collision , both balls continue in the same direction and the speed of the 0.1200 K B ball is 0.26 m/s . What is velocity of the first ball after the collision?​

Answers

Answer:

29 m/s.

Explanation:

Hope this helps.

how does the angle of incidence compare with the angle of reflection?​

Answers

Answer:

The angle of incidence is the angle between this normal and the incident ray; the angle of reflection is the angle between this normal and the reflected ray. According to the law of reflection, the angle of incidence equals the angle of reflection.

Explanation:

:)

Answer:

hope my answer helps

Explanation:

second law of reflection states that the angle of incidence equals to the angle of reflection,

this is the basic relationship,

so the angle of incidence is also equals to angle of reflection

hope this helps, if not please report it so that someone else gets to try it out

please mark it brainliest

A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of the loop in which the plane is flying?

Answers

Answer:

The radius of the curve is 9,183.67 m.

Explanation:

Given;

velocity of the jet plane, v = 600 m/s

acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²

The radius of the curve is calculated from centripetal acceleration formula as given below;

[tex]a = \frac{v^2}{r} \\\\r = \frac{v^2}{a} \\\\r = \frac{600^2}{39.2} \\\\r = 9,183.67 \ m[/tex]

Therefore, the radius of the curve is 9,183.67 m.

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