A group of hens lays 69 eggs in a single day. On one particular day, there were 7 brown eggs and 62 white eggs. If four eggs are selected at random, without replacement, what is the probability that all four are brown?

Answer:

1.-0.25     2..0173   3. .1/16    4. 1/7     5.2.2

Step-by-step explanation:

You want to put all numbers in fractions to see which numbers are smallest

Answer:

Step-by-step explanation:

34.375 Liters of milk make 11 tins of cheese. Assuming that milk is available in whole liters only, 35 Liters of milk are needed.

A(t)=P(1+r)t

A = accrued amount = what you are solving for

P = principle investment = $400

r = rate of growth = 5% = 0.05

t = time = 10 years

A(10) = 400(1.05)10 (use calculator to solve)

A(10) ≈ 4,200

I believe that the answers in order are: Rational, Irrational, Irrational, Irrational. I think these answers are correct, but if not, please let me know. Thanks.

Answer:

I think 0.5 and 0/100 are rational

the others are irrational

Total weight of the gravel, in tons used for the driveway is 8.6 tons

Weight of first load = 8 tons

Weight of second load = 1200 pounds

Convert pounds to tons:

1 pound = 0.0005 ton

1200 pounds = 0.6 ton

Then,

Weight of second load = 0.6 ton

Total weight of the gravel, in tons = Weight of first load + Weight of second load

= 8 tons + 0.6 tons

= 8.6 tons

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Answer: 0.584

Step-by-step explanation:

We have:

5 discs

6 jump ropes

3 balls

12 pieces of sidewalk.

5 + 6 + 3 + 12 = 26

If all of them have exactly the same probability of being removed, then:

in the first selection, we do not want to remove a jump rope, so we can remove one disc, one ball or one piece of sidewalk.

The total number of those objects is:

5 + 3 + 12 = 20.

Then the probability of removing one of those objects is:

P1 = 20/26 = 0.769

Now in the second selection, we have the same situation, but now we have 25 objects in total, and because in the previous selection we removed one ball, or one disc, or one piece of sidewalk, the total number of these things now is 19.

So the probability of removing another object of that set is:

P2 = 19/25 = 0.76

The joint probability is equal to the product of the individual probabilities, so we have:

P = P1*P2 = 0.769*0.76 = 0.584

Answer:

Slope passes through (-6, 5) and (-2, 7)

[tex]m_1=\frac{y_2-y_1}{x_2-x_1} =m_1=\frac{7-5}{-2+6}[/tex]

[tex]m_1=\frac{2}{4} =\frac{1}{2}[/tex]

Slope passes through (4, 2) and (6, 6)

[tex]m_2=\frac{6-2}{6-4}[/tex]

[tex]\frac{4}{2} =2[/tex]

[tex]m_1\times m_2 \neq -1[/tex] [tex]m_1\neq m_2[/tex]

Answer:- A) neither perpendicular nor parallel.

OAmalOHopeO

Answer:

sorry gave wrong answer

Step-by-step explanation:

Answer:

6 or 5 or 4...........

Step-by-step explanation:

Answer:

x=N :x<7

Step-by-step explanation:

123456

hope it's helpful

Answer:

Attachment 1 : 5x + 6y = 5, Attachment 2 : 4cotθcscθ

Step-by-step explanation:

Remember that we have three key points in solving these types of problems,

• x = r cos(θ)

• y = r sin(θ)

• x² + y² = r²

a ) For this first problem we need not apply the third equation.

( Multiply either side by 5 cos(θ) + 6 sin(θ) )

r [tex]*[/tex] ( 5 cos(θ) + 6 sin(θ) ) = 5,

( Distribute r )

5r cos(θ) + 6r sin(θ) = 5

( Substitute )

5x + 6y = 5 - the correct solution is option c

b ) We know that y² = 4x ⇒

r²sin²(θ) = 4r cos(θ),

r = 4cos(θ) / sin²(θ) = 4 cot(θ) csc(θ) = 4cotθcscθ - again the correct solution is option c

Step-by-step explanation:

3n-5=(-8*6)+(-8*5n) distributive property

3n-5=-48-40n

3n+40n=-48+5 add property

43n=-43 add property

43n/43=-43/43 division property

n=-1

9514 1404 393

Answer:

  1 11/49 ≈ 1.224 miles

Step-by-step explanation:

Let m represent the length of the morning walk. Then the length of the evening walk is 2.5m, and the total each day is m+2.5m = 3.5m.

The total for 7 days is ...

  7(3.5m) = 30

  m = 30/24.5 = 60/49 ≈ 1.224 . . . . miles

Mia's morning walks are 1 11/49 miles, about 1.224 miles.

Answer:

If your test statistic is positive, first find the probability that Z is greater than your test statistic (look up your test statistic on the Z-table, find its corresponding probability, and subtract it from one). Then double this result to get the p-value.

Answer:

The p-value is calculated using the sampling distribution of the test statistic under the null hypothesis, the sample data, and the type of test being done (lower-tailed test, upper-tailed test, or two-sided test). The p-value for: a lower-tailed test is specified by: p-value = P(TS ts | H 0 is true) = cdf(ts)

Step-by-step explanation:

May this answer is helpful for you

Answer:

If the perimeter of the rectangle is 30cm , find its area. W=5 FOR THE WIDTH. 5*10=50 FOR THE AREA.

Step-by-step explanation:

The area of the Rectangle is 50 sq.m

The area of rectangle for a rectangle of length L and width W is given by

                                              A =  L* W

It is measured in square units.

Let the length of the rectangle be L

The width of the rectangle is W

The length of a rectangle is twice its width

L = 2W

Perimeter of the Rectangle is 2( Length + Width)

30 = 2 (L +W)

15 = L + W

15 = 2W +W

15 = 3W

W = 5m

L = 10m

The area of the rectangle is Length * Width

Area = 10 *5

Area = 50 sq.m

To know more about Area of Rectangle

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Answer:

D. (25π - 50) sq m

Step-by-step explanation:

Since ABCD is a square with the area of 100, we know that the dimensions are 10 by 10. With that, we can find that triangle ABC = 50 sq m because of (h*l)/2. Since A is the center of the circle that contains arc BD, we know that 10 is the radius of the quarter-circle ABC. Using (πr^2)/4 to get the area of the quarter-circle, we get that the quarter-circle ABC = 25π sq m. But the original triangle ABC in the quarter-circle is not shaded. Therefore, we subtract 50 from 25π, which leads to (25π - 50) sq m.

I hope this helped! :D

$121 and $12 ok isn't available in your ma er bishal bishal bishal

Step-by-step explanation:

The value of the numerical expression 1 + 32 – 10 ÷ 2 will be 28.

Algebra is the study of graphic formulas, while logic is the interpretation among those signs.

The numerical expression is given below.

⇒ 1 + 32 – 10 ÷ 2

According to the PEMDAS rule, the computation wrapped in quotes or the parenthesis comes first in the sequence of operation.

This rule is used to solve the equation in a proper and correct manner.

PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction.

⇒ 1 + 32 – (10 ÷ 2)

Simplify the numerical expression, then the expression will be

⇒ 1 + 32 – 5

⇒ 33 – 5

⇒ 28

Then the value of the numerical expression 1 + 32 – 10 ÷ 2 will be 28.

More about the Algebra link is given below.

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Answer:

Yes, your right!

Answer:

Hope this helps :)

Step-by-step explanation:

A scatter plot is a two-dimensional diagram that displays individual data points based on the intersection of two variables, shown as vertical and horizontal axes. Individual data points or values are plotted at particular coordinates of the two variables being studied. Patterns of data points provide a visual representation of relationship between the two variables. A wide range of jobs and careers use this valuable analytical tool for data analysis and decision making.

My conclusion,

They help organize important data for future occurences.

Answer:5

Step-by-step explanation:

Complete Question

Assume that adults have IQ scores that are normally distributed with a mean μ=100 and a standard deviation σ=15. Find the probability that a randomly selected adult has an IQ between 81 and 119.

Answer:

The probability is  [tex]P( x_1 < X < x_2) = 0.79474[/tex]

Step-by-step explanation:

From the question we are told that

   The standard deviation is  σ = 15.

    The mean μ= 100

     The range we are considering is [tex]x_1 = 81 , \ x_2 = 119[/tex]

Now given that IQ scores are normally distributed

    Then the probability that a randomly selected adult has an IQ between 81 and 119 is mathematically represented as

               [tex]P( x_1 < X < x_2) = P(\frac{x_1 - \mu }{\sigma } <\frac{X - \mu }{\sigma } < \frac{x_2- \mu }{\sigma } )[/tex]

 Generally

                [tex]\frac{X - \mu }{\sigma } = Z(The \ standardized \ value \ of \ X )[/tex]

So

              [tex]P( x_1 < X < x_2) = P(\frac{x_1 - \mu }{\sigma } <Z < \frac{x_2- \mu }{\sigma } )[/tex]

substituting values

               [tex]P( x_1 < X < x_2) = P(\frac{81 - 100 }{15 } <Z < \frac{119- 100 }{15 } )[/tex]

               [tex]P( x_1 < X < x_2) = P( -1.2667 <Z <1.2667 )[/tex]

               [tex]P( x_1 < X < x_2) = P(Z <1.2667 )-P( Z < -1.2667 )[/tex]

From the standardized Z table

               [tex]P(Z <-1.2667 ) = 0.10263[/tex]

And        [tex]P(Z <1.2667 ) = 0.89737[/tex]

So

            [tex]P( x_1 < X < x_2) = 0.89737 - 0.10263[/tex]

            [tex]P( x_1 < X < x_2) = 0.79474[/tex]

Answer:

80

Step-by-step explanation:

x      y

2 = 20

8 = x

cross multiply( 8*20)/2

= 4 * 20

= 80

(A) The blue line has a slope of 5/2, red has slope 4/4 = 1, and purple has slope 3/9 = 1/3.

To find the slope, take any two points (a, b) and (c, d) on the line, then

slope = (d - b)/(c - a)

i.e. the ratio between the changes in the y and x coordinates.

(B) Each line has equation

• blue: y = 5/2 x

• red: y = x

• purple: y = 1/3 x

This follows from the general equation for a line with slope m and y-intercept b,

y = mx + b

or from the more general equation for a line with slope m passing through a point (a, b),

y - b = m (x - a)

(C) Consider the blue line. If you take units into account, its slope is

(5 units of distance)/(2 units of time) = 5/2 (units of distance/time)

which means, per unit time, some object travels a 5/2 units of distance, and this is the definition of speed.

(D) The competitor with the blue line, Mary, would win the race because their speed is the highest (5/2 > 1 > 1/3).

(E) Average velocity is defined as

v (ave) = ∆d/∆t = (change in distance)/(change in time)

At time 0, no one has moved yet. At time 4,

• Mary has covered a distance of 5/2 × 4 = 10, giving her an average velocity of (10 - 0)/(4 - 0) = 5/2

• Mike has covered a distance of 4, so his average velocity is (4 - 0)/(4 - 0) = 1

• Sam has covered a distance of 1/3 × 4 = 4/3, so his average velocity is (4/3 - 0)/(4 - 0) = 1/3

It's not a coincidence that the average velocities are the same as the slopes, because each racer travels at a constant speed.

(F) The racers' instantaneous velocities are the same as their respective average velocities, again because they are each moving at a constant speed.

Answer:

see below

Step-by-step explanation:

      (ab)^n=a^n * b^n

We need to show that it is true for n=1

assuming that it is true for n = k;

(ab)^n=a^n * b^n

( ab) ^1 = a^1 * b^1

ab = a * b

ab = ab

Then we need to show that it is true for n = ( k+1)

or (ab)^(k+1)=a^( k+1) * b^( k+1)

Starting with

  (ab)^k=a^k * b^k    given

Multiply each side by ab

ab *  (ab)^k= ab *a^k * b^k

   ( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)

Therefore, the rule is true for every natural number n

Hello, n being an integer, we need to prove that one statement depending on n is true, let's note it S(n).

The mathematical induction involves two steps:

Step 1 - We need to prove S(1), meaning that the statement is true for n = 1

Step 2 - for k integer > 1, we assume S(k) and we need to prove that S(k+1) is true.

Imagine that you are a painter and you need to paint all the trees on one side of a road. You have several colours that you can use but you are asked to follow two rules:

Rule 1 - You need to paint the first tree in white.

Rule 2 - If one tree is white you have to paint the next one in white too.

What colour do you think all the trees will be painted?

Do you see why this is very important to prove the two steps as well ?

Let's do it in this example.

Step 1 - for n = 1, let's prove that S(1) is true, meaning  [tex](ab)^1=a\cdot b =a^1\cdot b^1[/tex]

So the statement is true for n = 1

Step 2 - Let's assume that this is true for k, and we have to prove that this is true for k+1

So we assume S(k), meaning that [tex](ab)^k=a^k\cdot b^k[/tex]

and what about S(k+1), meaning [tex](ab)^{k+1}=a^{k+1}\cdot b^{k+1}[/tex] ?

We will use the fact that this is true for k,

[tex](ab)^{k+1}=(ab)\cdot (ab)^k =(ab) \cdot a^k \cdot b^k[/tex]

We can write it because the statement at k is true and then we can conclude.

[tex](ab)^{k+1}=(ab)\cdot (ab)^k =(ab) \cdot a^k \cdot b^k=a^{k+1}\cdot b^{k+1}[/tex]

In conclusion, we have just proved that S(n) is true for any n integer greater or equal to 1, meaning [tex](ab)^{n}=a^{n}\cdot b^{n}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

it is 9%

Step-by-step explanation: the socks persent is the correct answer

Answer: D. 61%

Step-by-step explanation:

Answer:

46

Step-by-step explanation:

6 more than the product of 8 and a number x

6 more means 6+

product of 8 and a number x means 8x

6+8x

when x=5

6+8(5)=6+40=46

Answer:

[tex]y=43[/tex]

Step-by-step explanation:

[tex]y=2(90-46)/2[/tex]

[tex]y=43[/tex]

------------------------

OAmalOHopeO

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Answer:

A. 9

C. 16  

E. 169

F. 625

Step-by-step explanation:

Answer:

7161

Step-by-step explanation:

7 + 7(2) + 7(2)² + ... + 7(2)⁹

= ∑₁¹⁰ 7(2)ⁿ⁻¹

= 7 (1 − 2¹⁰) / (1 − 2)

= 7161

Answer:

a. True

b. true

c. false

d. false

e. false

Step-by-step explanation:

a. true

polutation = 25% = 0.25

sample = n= 12

n x p

= 12 x o. 25 = 3 and 3 is less than 10

12(1 - p)

= 12 x 0.75

= 9 and is less than 10

b. True

the sample distribution of the population is normal when

sample size x population > or equal to 10

40 x 0.75

= 30 and 30 is greater than 10

c. false

50 x 0.25 = 12.5

50 x 0.20 = 10

z = 10 - 12.5/sqrt(12.5)

= -2.5/3.54

= -0.70

H0: Young american family who delayed

H1: young american family who did not delay

p(z = -0.70)

0.2420>0.005

therefore we accept the null hypothesis

d. false

150 x 0.20 = 30

150 x 0.75 = 37.5

z = 30 - 37.5/sqrt(37.5) = -7.5/6.12 = -1.22

p(z = -1.22) = 0.1112 > 0.05

therefore we do not reject the null hypothesis

e. false

se1 = sqrt(p(1-p)/n

se2 = sqrt(p(1-p)/3n

se2 = 1/sqrt(3)se2