A group of 8 students paid $48.24 for food at a picnic whats each persons share

Answers

Answer 1

Answer:

Each persons share is 6.03

Step-by-step explanation:

Divide the total cost by the number of students

48.24 / 8

6.03

Each persons share is 6.03

Answer 2

Answer:

$6.03

Step-by-step explanation:

A group of 8 students paid $48.24 for food.

Each of their shares would be divided among the 8 students.

48.24/8=6.03

Each student paid a share of $6.03.


Related Questions

Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. Find the 95th percentile of the hip breadth of adult men. Round your answer to one decimal place; add a trailing zero as needed. The 95th percentile of the hip breadth of adult men is [HipBreadth] inches.

Answers

Answer:

[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]

And if we solve for a we got

[tex]a=14.4 +1.64*1.1=16.204[/tex]

The 95th percentile of the hip breadth of adult men is 16.2 inches.

Step-by-step explanation:

Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(14.4,1.1)[/tex]  

Where [tex]\mu=14.4[/tex] and [tex]\sigma=1.1[/tex]

For this part we want to find a value a, such that we satisfy this condition:

[tex]P(X>a)=0.05[/tex]   (a)

[tex]P(X<a)=0.95[/tex]   (b)

We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64

Using this value we can set up the following equation:

[tex]P(X<a)=P(\frac{X-\mu}{\sigma}<\frac{a-\mu}{\sigma})=0.95[/tex]  

[tex]P(z<\frac{a-\mu}{\sigma})=0.95[/tex]

And we have:

[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]

And if we solve for a we got

[tex]a=14.4 +1.64*1.1=16.204[/tex]

The 95th percentile of the hip breadth of adult men is 16.2 inches.



Which leader was a member of the Kikuyu tribe?

A. Kwame Nkrumah

B. Marcus Garvey

C. Mohandas Gandhi

D. Jomo Kenyatta

Answers

Answer:

Jomo Kenyatta

Step-by-step explanation:

Jomo Kenyatta was a Kenyan politician, who was one of the first African anti-colonial figures. He became the prime minister of Kenya from 1963 to 1964, and after Kenyan independence in 1964, he became president of Kenya. Jomo Kenyatta was born into a family of Kikuyu farmers in Kiambu, present day Kenya which was then, British East Africa. He had his basic schooling in a missionary school before proceeding to study at Moscow's Communist University of the Toilers of the East, University College London, and the London School of Economics.

Answer:

Jomo Kenyatta

Step-by-step explanation:

took the test

Help needed ASAP please !!!!

Answers

Answer:I believe that it is A but i am not fully sure

Step-by-step explanation:

What is the area of the triangle below?
18

Answers

Answer:

D. 32 sq. unit s

Step-by-step explanation:

4×18/2=32

) Let an denote number of n-digit ternary sequences (sequences of 0,1 and 2) which have no consecutive 0’s in them. Find a recurrence relation for an. (Do not solve the recurrence. However, depending on the order of the recurrence, provide a sufficient number of initial conditions. )

Answers

Answer:

The recurrence relation for aₙ is  aₙ = 2aₙ - 1 + 2aₙ -2 ; is n≥ 3 with the initial conditions as a₁ =3; a₂ = 8

Step-by-step explanation:

Solution

Recurrence relation for n - digit ternary sequence with no occurrence of consecutive 0's in them.

Ternary sequence is sequence with each of digits either 0, 1 or 2.

Now

Let aₙ = denote the number of n - digit ternary sequence with no occurrence of consecutive 0's in them.

Let us first find few initial values of aₙ

For n = 1

a₁ represent the number of 1- digit ternary sequence with no occurrence of consecutive 0's in them.  

This 1-digit sequence can be either 0 or 1 or 2.

Thus,

a₁ = 3

For n =2

a₂ represent the number of 2- digit ternary sequence with no occurrence of consecutive 0's in them.

This 2-digit sequence can have either 0 or 1 or 2 as each of its two digit, but making sure that there are no two consecutive 0 in the sequence.

here are " 9 " 2-digit ternary sequence ........... (three choices for 1st digit and three choices for 2nd digit)  

But one of these 9 sequence there are consecutive 0's .... (00)  

So we eliminate this one sequence.

So, a₂ = 8

Now

let us find the recurrence relation

Fir n ≥ 3

aₙ s the number of n - digit ternary sequence with no occurrence of the consecutive 0's in them.

For the first case: if 1st digit of this n - digit ternary sequence is 1 or 2

Let assume the 1st digit of this n - digit ternary sequence is 1.  

Then for remaining n - 1 digits of this n - digit ternary sequence we have to make sure that there is no consecutive 0's in them.

For example, we have to form a n-1-digit ternary sequence with no occurrence of consecutive 0's in them which is by definition aₙ -1

So,

The number of n - digit ternary sequence with no occurrence of consecutive 0's in them if 1st digit of this sequence is 1 is aₙ -1.

Likewise, the number of n - digit ternary sequence with no occurrence of consecutive 0's in them if 1st digit of this sequence is 2 is aₙ -1.

So  

If 1st digit of this n - digit ternary sequence is 1 or 2, then the number of n - digit ternary sequence with no occurrence of consecutive 0's in them is shown as:

aₙ-1 + aₙ -1 = 2aₙ -1

For the second case: if 1st digit of this n - digit ternary sequence is 0

If 1st digit of this n - digit ternary sequence is 0, then the next digit cannot be 0 as well because that would make two consecutive 0's in the sequence Thus,

If 1st digit of this n - digit ternary sequence is 0, the next term can be either 1 or 2.

So there are 2 choices for 2nd digit.  

After this there are more n-2 digits.  

Then

For remaining n - 2 digits of this n - digit ternary sequence we have to make sure that there is no consecutive 0's in them  

For example, we have to form a n-2-digit ternary sequence with no occurrence of consecutive 0's in them. which is by definition aₙ - 2.

Now,

The total number of sequence in this case is given as:

2aₙ -2........... (2 choices for 2nd digit and aₙ - 2 choices for remaining n-2 digit)

Hence  

The number of n - digit ternary sequence with no occurrence of consecutive 0's in them if 1st digit of this sequence is 0 is aₙ = 2aₙ - 1 + 2aₙ -2 which is n≥ 3

Now,

The recurrence relation for aₙ is shown below:

aₙ = 2aₙ - 1 + 2aₙ -2; is n≥ 3

With the initial conditions as a₁ =3; a₂ = 8

In a pizza takeout restaurant, the following probability distribution was obtained for the number of toppings ordered on a large pizza. Find the mean and standard deviation for the random variable.

Answers

Answer:

The random variable (number of toppings ordered on a large pizza) has a mean of 1.14 and a standard deviation of 1.04.

Step-by-step explanation:

The question is incomplete:

The probability distribution is:

x   P(x)

0   0.30

1    0.40

2   0.20

3   0.06

4   0.04

The mean can be calculated as:

[tex]M=\sum p_iX_i=0.3\cdot 0+0.4\cdot 1+0.2\cdot 2+0.06\cdot 3+0.04\cdot 4\\\\M=0+0.4+0.4+0.18+0.16\\\\M=1.14[/tex]

(pi is the probability of each class, Xi is the number of topping in each class)

The standard deviation is calculated as:

[tex]s=\sqrt{\sum p_i(X_i-M)^2}\\\\s=\sqrt{0.3(0-1.14)^2+0.4(1-1.14)^2+0.2(2-1.14)^2+0.06(3-1.14)^2+0.04(4-1.14)^2}\\\\s=\sqrt{0.3(-1.14)^2+0.4(-0.14)^2+0.2(0.86)^2+0.06(1.86)^2+0.04(2.86)^2}\\\\ s=\sqrt{0.3(1.2996)+0.4(0.0196)+0.2(0.7396)+0.06(3.4596)+0.04(8.1796)}\\\\s=\sqrt{0.3899+0.0078+0.1479+0.2076+0.3272}\\\\ s=\sqrt{ 1.0804 }\\\\s\approx 1.04[/tex]

Answer:

mean: 1.14; standard deviation: 1.04

Step-by-step explanation:

Which of the following statements are equivalent to the statement "Every integer has an additive inverse" NOTE: (The additive inverse of a number x is the number that, when added to x, yields zero. Example: the additive inverse of 5 is -5, since 5+-5 = 0) Integers are{ ... -3, -2,-1,0, 1, 2, 3, ...} All integers have additive inverses. A. There exists a number x such that x is the additive inverse of all integers.B. All integers have additive inverses.C. If x is an integer, then x has an additive inverse.D. Given an integer x, there exists a y such that y is the additive inverse of x.E. If x has an additive inverse, then x is an integer.

Answers

Answer:

B, C and D

Step-by-step explanation:

Given:

Statement: "Every integer has an additive inverse"

To find: statement that is equivalent to the given statement

Solution:

For any integer x, if [tex]x+y=0[/tex] then y is the additive inverse of x.

Here, 0 is the additive identity.

Statements ''All integers have additive inverses '', '' If x is an integer, then x has an additive inverse'' and  ''Given an integer x, there exists a y such that y is the additive inverse of x'' are equivalent to the given statement "Every integer has an additive inverse".

The management of a chain of frozen yogurt stores believes that t days after the end of an advertising campaign, the rate at which the volume V (in dollars) of sales is changing is approximated by V ' ( t ) = − 26400 e − 0.49 t . On the day the advertising campaign ends ( t = 0 ), the sales volume is $ 170 , 000 . Find both V ' ( 6 ) and its integral V ( 6 ) . Round your answers to the nearest cent.

Answers

Answer:

Step-by-step explanation:

Given the rate at which the volume V (in dollars) of sales is changing is approximated by the equation

V ' ( t ) = − 26400 e^− 0.49 t .

t = time (in days)

.v'(6) can be derived by simply substituting t = 6 into the modelled equation as shown:

V'(6) = − 26400 e− 0.49 (6)

V'(6) = -26400e-2.94

V'(6) = -26400×-0.2217

V'(6) = $5852.88

V'(6) = $5,853 to nearest dollars

V'(6) = 585300cents to nearest cent

To get v(6), we need to get v(t) first by integrating the given function as shown:

V(t) = ∫−26400 e− 0.49 t dt

V(t) = -26,400e-0.49t/-0.49

V(t) = 53,877.55e-0.49t + C.

When t = 0, V(t) = $170,000

170,000 = 53,877.55e-0 +C

170000 = 53,877.55(2.7183)+C

170,000 = 146,454.37+C

C = 170,000-146,454.37

C = 23545.64

V(6) = 53,877.55e-0.49(6)+ 23545.64

V(6) = -11,945.63+23545.64

V(6) = $11,600 (to the nearest dollars)

Since $1 = 100cents

$11,600 = 1,160,000cents

AC =
Round your answer to the nearest hundredth.
A
5
35
B
C

Answers

Answer:

2.87 = AC

Step-by-step explanation:

Since this is a right triangle we can use trig functions

sin theta = opp / hyp

sin 35 = AC /5

5 sin 35 = AC

2.867882182= AC

To the nearest hundredth

2.87 = AC

Solve the linear equality 4x-7 <5

Answers

Answer:

X<3

Step-by-step explanation:

4x-7 <5

4x < 5+7

4x < 12

X < 12/4

X < 3

Hope this helps..

Good Luck!

Jiangsu divided 751.6 by 10 by the power of 2 and got a quotient of 0.7516. yesseinafhinks that the quotient should be7.516. Who is correct?

Answers

Answer:

yesseinafhinks

Step-by-step explanation:

Dividing by 10² is also the same thing as multiplying by 10^-2. In that case, we simply move the decimal places only 2 places back. That would give us 7.516, not 0.7516 (which is 3 times, not 2).

If the denominator of 5/9 is increased by a number and the numerator is doubled, the result is 1. Find the number.

Answers

Answer: 1

Explanation:

The numerator is doubled, so the fractions looks like 10/9. To make it one, it must be 10/10 and 9+1=10

◇Given :-

The denominator of a fraction is increased by a number and numerator will be doubled

To find

We have to find the required number or fraction

[tex]\underline{\bigstar{\sf\ \ Solution:-}}[/tex]

Now let us consided as the number be a

Then

[tex]\underline{\bigstar{\textit\ According\ to \ Question:-}}[/tex]

The given fraction is 5/9

[tex]:\implies\sf \dfrac{5\times 2}{9+a}= 1\\ \\ \\ :\implies\sf \dfrac{10}{9+a}=1\\ \\ \\ :\implies\sf 10= 1(9+a)\\ \\ \\ :\implies\sf 10-9=a\\ \\ \\ :\implies\sf 1=a [/tex]

[tex]\underline{\therefore{\textit{\textbf { The \ required \ number \ is \ 1}}}}[/tex]

∠A and ∠B are supplementary, and ∠A and ∠C are supplementary. Which conclusion is valid? Select one: A. ∠B and ∠C are supplementary. B. ∠B and ∠C are acute. C. ∠B and ∠C are complementary. D. ∠B and ∠C are congruent.

Answers

Option D is the correct answer.

Answer:

D. ∠B and ∠C are congruent.

Step-by-step explanation:

Since, ∠A and ∠B are supplementary.

Therefore,

∠A + ∠B = 180°.....(1)

Since, ∠A and ∠C are supplementary.

Therefore,

∠A + ∠C = 180°.....(2)

From equations (1) & (2)

∠A + ∠B = ∠A + ∠C

=> ∠B = ∠C

Hence, ∠B and ∠C are congruent.

What number should go in the space? Multiplying by 0.65 is the same as decreasing by _____%

Answers

Answer: 35%

Step-by-step explanation:

If no is 10, 10 x 0.65 = 6.5. OR

10 - 35% of 10 = 6.5

  Multiplying by 0.65 is the same as decreasing by 35%

Conversion of statements into algebraic expression:To convert the statement into algebraic expression choose the variables first.Then form the expression or equation as per given statements.

Let the number is 'a' and percentage decrease is 'b',

Expression for the given statement will be,

a × 0.65 = a - (b% of a)

[tex]0.65a=a(1-\frac{b}{100})[/tex]

[tex]0.65=1-\frac{b}{100}[/tex]

[tex]\frac{b}{100}=1-0.65[/tex]

[tex]b=100(0.35)[/tex]

[tex]b=35[/tex]

    Therefore, Multiplying by 0.65 is the same as decreasing by 35%.

Learn more about the Algebraic expressions for the statements here,

https://brainly.com/question/2043566?referrer=searchResults

26
Ping lives at the corner of 3rd Street and 6th Avenue. Ari
lives at the corner of 21st Street and 18th Avenue. There is
a gym į the distance from Ping's home to Ari's home.
24
22
20
n
Ari (21.18)
7
x =
18
(x2 – x) + x3
mi+n
16
Avenue
14
-- ( , Jive - y) +
12
10
Where is the gym?
00
6
Ping (36)
4
2
9th Street and 10th Avenue
12th Street and 12th Avenue
0 14th Street and 12th Avenue
15th Street and 14th Avenue
2
x
4 6 8 10 12 14 16 18 20 22 24 26
Street

Answers

Corrected Question

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym 2/3 the distance from Ping's home to Ari's home.  Where is the gym?

9th Street and 10th Avenue 12th Street and 12th Avenue 14th Street and 12th Avenue 15th Street and 14th Avenue

Answer:

(D)15th Street and 14th Avenue

Step-by-step explanation:

Ping's Location: (3rd Street, 6th Avenue)

Ari's Location: (21st Street, 18th Avenue)

The gym is at point P which is [tex]\dfrac{2}{3}[/tex] the distance from Ping's home to Ari's home.

That is, Point P divides the line segment in the ratio 2:1.

We use the section formula:

[tex](x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)[/tex]

m:n=2:1, [tex](x_1,y_1)=(3,6), (x_2,y_2)=(21,18)[/tex]

[tex]=\left(\dfrac{2*21+1*2}{2+1}, \dfrac{2*18+1*6}{2+1}\right)\\=\left(\dfrac{45}{3}, \dfrac{42}{3}\right)\\=(15,14)[/tex]

The gym is located at 15th Street and 14th Avenue.

3. How many different arrangements can be made with the letters in the word
POWER?
O A 100
B 25
OC 20
OD 120

Answers

Answer:

D. 120

Step-by-step explanation:

Array formula: A (n, p) = n! / (n -p)!

At where:

 n = Total number of elements in the set.

p = Quantity of elements per arrangement

A (5.5) = 5! / (5-5)! = (5x4x3x2x1) / 0!

By definition: 0! = 1

Then: 120/1 = 120

⅝ of a school's population are girls. There are 129 boys. If each classroom can hold 25 students. How many classroom does the school have ?​

Answers

Answer:

AT least 14 classrooms to hold the total number of students

Step-by-step explanation:

Since  we don't know the numer of girls in the school, let's call it "x".

What we know is that the number of girls plus the number of boys gives the total number of students. This is:

x + 129 = Total number of students

Now, since 5/8 of the total number of students are girls, and understanding that 5/8 = 0.625 in decimal form, then we write the equation that states:

"5/8 of the school's population are girls" as:

0.625 (x + 129) = x

then we solve for "x":

0.625 x + 0.625 * 129 = x

0.625 * 129 = x - 0.625 x

80.625 = x (1 - 0.625)

80.625 = 0.375 x

x = 80.625/0.375

x = 215

So now we know that the total number of students is: 215 + 129 = 344

and if each classroom can hold 25 students, the number of classroom needed for 344 students is:

344/25 = 13.76

so at least 14 classrooms to hold all those students

I would really appreciate it if you could help me please

Answers

Answer:

Yes, triangle GYK is similar to triangle BAK.

Step-by-step explanation:

The sides of each triangle are proportional to each other.

Take the longest side of each triangle. You are comparing line AK with line KY.

The proportion is 15/25.

Now, take the shortest side of each triangle. You are comparing line KB with GK.

The proportion is 6/10.

To determine if the triangles are proportional, we can see if the two proportions are equal to each other:

15/20=6/10

3/5=6/10

Correct! 3/5 equals to 6/10. Therefore, the two triangles are similar because their sides are proportional.

Hope this helps :)

Answer:

O  Yes!

Step-by-step explanation:

We would check whether the proportionality of their sides is equal

Taking proportionality

= [tex]\frac{6}{10} = \frac{15}{25}[/tex]

Cross Multiplying

6 × 25 = 15 × 10

150 = 150

So, ΔABK is similar to ΔGKY

deandre saves rare coins. he starts his collection with 14 coins and plans to save 3 coins each month. write an equation to represent the number of coins saved, y, in terms of the number of months, x. if deandre saved for 30 months, how many coins will he have?

Answers

Answer:

equation: y = 3x + 14

number of coins after 30 months: 104 coins

Hope this helps :)

An equation is formed of two equal expressions. The number of coins that will be with Deandre after a period of 30 months is 104 coins.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

As it is given that in the initial phase Deandre saves 14 coins. While he adds 3 coins each month. Therefore, the equation that will represent the number of coins that Deandre will have after a period of x months can be written as,

y = 14 + 3x

where y is the number of coins and x is the number of months.

After a period of x=30 months, the number of coins that will be with Deandre can be written as,

[tex]y = 14 + 3x\\\\y = 14 + 3(30)\\\\y = 104[/tex]

Thus, the number of coins that will be with Deandre after a period of 30 months is 104 coins.

Learn more about Equation:

https://brainly.com/question/2263981

The population of a city has increased by 35% since it was last measured. If the current population is 29,700 , what was the previous population?

Answers

Answer:

19305

Step-by-step explanation:

We simply take the percentage of 29700 to find how many people were added.

29700(0.35) = 10395 <== so 10395 people have been added

Subtract it from the current:

28700 - 10395 = 19305 people before.

Any help would be appreciated

Answers

5/8- I think that is the right answer

6• 2hen+3pens-5anchors

Answers

Answer:

[tex]180[/tex]

Step-by-step explanation:

[tex]6 \times 2 \times 3 \times 5[/tex]

[tex]12 \times 15[/tex]

[tex]=180[/tex]

Steps to solve:

6 * 2 + 3 - 5

~Multiply

12 + 3 - 5

~Add

15 - 5

~Subtract

10

Best of Luck!

Levi would like to use a credit card to make a $3000 purchase. He is considering two credit options. The first requires
a down payment of $1000 followed by monthly payments of $125. The second requires a down payment of $1300
followed by monthly payments of $110. The two options accumulate the same amount of interest and require the
same number of monthly payments.
What is the amount of interest for this loan?

Answers

Answer:

The amount of interest for this loan is 16.6%.

Step-by-step explanation:

Since Levi will make a purchase for $ 3000 with your credit card, you should explore the two options you have:

-On the one hand, a down payment of $ 1000, with fees of $ 125.

-on the other, a down payment of $ 1,300, with fees of $ 110.

In both cases, the fees are the same, and the interest too. Therefore, to determine the amount of installments and interest, the difference between the down payment of one option and the other must be taken and divided by the difference between the value of the installments of either option.

Thus, the difference of the down payment of 300 (1300 - 1000) must be divided by 15 (125 - 110). This yields a result of 20 (300/15), with which that will be the total of quotas until both have paid the same amount of money.

Thus, given that 1300 + 110 x 20 = 3,500, and that 1000 + 125 x 20 = 3,500, in both cases the total value to be paid is $ 3,500. Since 500 is 16.6% of 3000, the total purchase interest will be 16.6%.


The Venn diagram below is used for showing odd numbers and prime numbers.
Place the numbers 1, 2, 3, 4 and 5 in the Venn diagram.

Answers

Answer:

See attached

Step-by-step explanation:

Given the numbers 1,2,3,4 and 5

Odd Numbers =1, 3 and 5Prime Numbers = 2, 3 and 5

Let O be the event that the number is Odd

Let E be the event that the number is Prime

Then the intersection of Odd and Prime Numbers: [tex]O \cap P =\{3,5\}[/tex]

Since 4 is neither odd nor prime, we place it outside of the two circles.

See the attached diagram for the required Venn diagram.

A product is introduced to the market. The weekly profit (in dollars) of that product decays exponentially as function of the price that is charged (in dollars) and is given by P ( x ) = 95000 ⋅ e − 0.05 ⋅ x Suppose the price in dollars of that product, x ( t ) , changes over time t (in weeks) as given by x ( t ) = 53 + 0.95 ⋅ t 2 Find the rate that profit changes as a function of time, P ' ( t ) dollars/week How fast is profit changing with respect to time 7 weeks after the introduction. dollars/week

Answers

Answer:

1). [tex]P'(t) = (-9025t).e^{-0.05(53+0.95t^2)}[/tex]

2). (-435.36) dollars per week

Step-by-step explanation:

Weekly price decay of the product is represented by the function,

P(x) = [tex]95000.e^{-0.05x}[/tex]

And the price of the product changes over the period of 't' weeks is represented by,

x(t) = [tex]53+0.95t^2[/tex]

Function representing the rate of change in the profit with respect to the time will be represented by,

1). P'(t) = [tex]\frac{dP}{dx}.\frac{dx}{dt}[/tex]

Since, P(x) = [tex]95000.e^{-0.05x}[/tex]

P'(x) = [tex]95000\times (-0.05).e^{-0.05x}[/tex]

       = [tex](-4750).e^{-0.05x}[/tex]

Since, x(t) = 53 + 0.95t²

x'(t) = 1.9t

[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05x}\times (1.9t)[/tex]

By substituting x = 53 + 0.95t²

[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05(53+0.95t^2)}\times (1.9t)[/tex]

   P'(t) = [tex](-9025t).e^{-0.05(53+0.95t^2)}[/tex]

2). For t = 7 weeks,

P'(7) = [tex](-9025\times 7).e^{-0.05(53+0.95(7)^2)}[/tex]

       = [tex](-63175).e^{-4.9775}[/tex]

       = (-63175)(0.006891)

       = (-435.356) dollars per week

       ≈ (-435.36) dollars per week

Not sure how to answer question 4

Answers

Answer:

Option D is correct

Step-by-step explanation:

Applying the cosine theorem for triangle ABC, you would have:

cos (angle BAC) = (BA^2 + CA^2 - BC^2)/(2*BA*CA)

                           = (10^2 + 18^2 - 20^2)/(2*10*18)

                           = 24/360

=> angle BAC = ~86 deg

Hope this helps!

D = 86
Because its the nearest degree to 90 as you see < BAC seems to be 90

Write the rectangular equation (x+5) 2 + y 2 = 25 in polar form.

Answers

Answer:

r = -10*cos(t)

Step-by-step explanation:

To write the rectangular equation in polar form we need to replace x and y by:

[tex]x=r*cos(t)\\y=r*sin(t)[/tex]

Replacing on the original equation, we get:

[tex](x+5)^2+y^2=25\\x^2+10x+25+y^2=25\\(r*cos(t))^2+10*(r*cos(t))+25+(r*sin(t))^2=25[/tex]

Using the identity [tex]sin^2(t)+cos^2(t)=1[/tex] and solving for r, we get that the polar form of the equation is:

[tex](r*cos(t))^2+10*(r*cos(t))+25+(r*sin(t))^2=25\\r^2cos^2(t)+10rcos(t)+r^2sin^2(t)=0\\r^2cos^2(t)+r^2sin^2(t)=-10rcos(t)\\r^2(cos^2(t)+sin^2(t))=-10rcos(t)\\r^2=-10rcos(t)\\\\r=-10cos(t)[/tex]

c) Consider the time 3:40pm where the initial side is the hour hand and terminal side is the

minute hand. Draw the angle between the two hands in standard position. State the angle in

positive degrees and then restate the angle as a negative angle. (2 pts.)

Answers

Answer:

210 degrees-150 degrees

Step-by-step explanation:

When the time is 3:40pm

The Initial Side (hour hand) is at 3.Terminal Side (Minute hand) is at 8.

(a)The angle between the two hands in standard position is drawn and attached below.

(b)Now, each hour = 30 degrees

Therefore, the angle between 3 and 8 in an anticlockwise movement

= 7 X 30 =210 degrees

Stating the angle as a negative angle, we have:

[tex]210^\circ-360^\circ=-150^\circ\\$The angle as a negative angle is -150^\circ[/tex]

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Answers

Answer:

1.90.93

2.90.27

Step-by-step explanation:

Answer:

one above correct

Step-by-step explanation:

1st - 90.93

2nd-90.27

A group of campers is going to occupy 4 campsites at a campground. There are 14 campsites from which to choose. In how many ways can the campsites be chosen?
There are
possible ways to choose the campsites.
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Answers

Answer:

24024 are the total number of ways of choosing 4 campsites out of 14.

Step-by-step explanation:

We are given that there are a total of 14 campsite out of which 4 campsites are to be chosen.

It is a simple example of selection problem.

Number of ways to choose the first campsite = 14

Now, one campsite is chosen, 13 campsites are left.

Therefore,

Number of ways to choose the second campsite = 13

Now, one more campsite is chosen, 12 campsites are left.

Therefore,

Number of ways to choose the third campsite = 12

Now, one more campsite is chosen, 11 campsites are left.

Therefore,

Number of ways to choose the fourth campsite = 11

So, total number of ways for choosing 4 campsites out of 14:

14 [tex]\times[/tex] 13 [tex]\times[/tex] 12 [tex]\times[/tex] 11 = 24024

Hence, answer is 24024.

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