Answer:
I gotchu fam. 0.0435 kg
Explanation:
m1v1+m2v2=m1v1f+m2v2f
(0.5)(23)+(m2)(0)=(0.5)(17)+(m2)(69)
11.5=8.5+69m2
3=69m2
0.0435 kg
A stone of mass 0.2kg is thrown vertically upwards from the ground with a velocity of 20m/s. Find the maximum height attained by the stone
Answer: 20.4 m
Explanation: speed v upward is v = vo -gt.
When maximum height v = 0, vo -gt = 0 and
T = vo / g = 20 m/s / 9.81 m/s² = 2.04 s
Now height y = vot -0.5 gt^2 = 20,4 m
This is possible to solve using
Conservation of energy Ek= Ep
0.5mv² = mgh. And h = v²/2g. Results same