A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?

Answers

Answer 1

Answer:

you can simply answer vl/t1=v2/t2


Related Questions

A student was asked to determine the activity of four unknown metals W,X,Y and, Z.

Answers

Answer:

BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

The activity of four unknown metals based on their chemical changes is option B.

What is a chemical change?

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

Learn more about chemical change,here:

https://brainly.com/question/23693316

#SPJ3

HELP ASAPPP!!! ON EXAM!

The arrangement of electrons within an atom is called it's...

a
Electron Flow
b
Electron Configuration
c
Atomic Number
d
Ionization Energy

Answers

Answer:

The arrangement of electrons within an atom is called electron configuration

If I help you, will you help other people?

Actually "this is the worst question i've ever seen use the internet bud" why don't you do that.

help!!!!!!!!!!!!!!!!!!!!! i have less than 3 hours please help! image below!!!!

Answers

Answer:

friction

Explanation:

conduction doesn't really need much to start it. it basically has that reaction from the start so it's not conduction. Since heat is produced by friction in this situation it causes static to happen. so i think its friction

A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?

Answers

V2 = 276 ml

Explanation:

Given:

V1 = 250 ml V2 = ?

T1 = 293K. T2 = 324K

Here, we use Charles's law:

V1/T1 = V2/T2

Solving for P2, we get

V2 = (T2/T1)V1

= (324K/293K)(250 ml)

= 276 ml

6. The fusion of 4 H-1 nuclei to produce two positrons and one other nuclei.​

Answers

Explanation:

Normally, fusion involves two heavy hydrogen nuclides but since we have 4 light hydrogen nuclides, two of which underwent positron emission, thus changing two protons into neutrons plus 2 positrons and 2 neutrinos. The resulting nucleus from this fusion reaction is an He-4 nucleus.

Select the correct choices to complete the sentence.
In the ionic solid sodium chloride (NaCl), there is a________
ratio of sodium ions to chlorine ions.
one and half to one
tow to one
one to two
one to one

Answers

Answer:

one to one

Explanation:

Answer:

In the ionic solid sodium chloride, there is one to one ratio of sodium ions to chloride ions

Science
How is the total magnification of a
cell calculated?

Answers

A scale bar can be used to calculate magnification. Magnification is calculated by dividing the image of the scale bar by the length of the scale bar (written on the scale bar).

The diagram shows the water cycle. At point 4, condensation is occurring. How is water changing?

A) Water vapor (gas) is becoming liquid.

B) Water is being stored in the atmosphere.

C) Liquid water in the atmosphere is becoming a gas.

D) Liquid water from the earth's surface is becoming water vapor (gas)

Answers

Answer:

water vapor (gas) is becoming liquid

Gather data: experiment with a variety of initial concentrations of no2 and n2o4. for each set of initial concentrations, use the gizmo to determine the equilibrium concentrations of each substance. in the last column, find kc for that trial. run three trials for each set of initial conditions.

Answers

Solution :

[tex]$H_2 +I_2\rightleftharpoons 2HI$[/tex]

Initial concentration               Equilibrium concentration           [tex]$K_c=\frac{[HI]^2}{[H_2][I_2]}$[/tex]

  (mol/L)                                           (mol/L)

[tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]    [tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.38 \times 10^{-2}$[/tex]  0     [tex]$1.14 \times10^{-2}$[/tex]    [tex]$0.12 \times 10^{-2}$[/tex]  [tex]$2.52 \times 10^{-2}$[/tex]        46.42

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.68 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.20 \times 10^{-2}$[/tex]  [tex]$2.96 \times 10^{-2}$[/tex]        47.61

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.98 \times 10^{-2}$[/tex]  0     [tex]$0.77 \times10^{-2}$[/tex]    [tex]$0.31 \times 10^{-2}$[/tex]  [tex]$3.34 \times 10^{-2}$[/tex]        46.73

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.76 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.22 \times 10^{-2}$[/tex]  [tex]$3.08 \times 10^{-2}$[/tex]        46.86

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$3.04 \times 10^{-2}$[/tex]     [tex]$0.345 \times10^{-2}$[/tex]    [tex]$0.345 \times 10^{-2}$[/tex]  [tex]$2.35 \times 10^{-2}$[/tex] 46.39

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$7.58 \times 10^{-2}$[/tex]     [tex]$0.86 \times10^{-2}$[/tex]    [tex]$0.86 \times 10^{-2}$[/tex]  [tex]$5.86 \times 10^{-2}$[/tex]     46.42

Average [tex]$K_c=46.738$[/tex]

Can you pls answer This question

Answers

Answer:

a) pentane

b) 1,3-dimethyl butane

c) 3,4-diethyl-5-methlyl heptane

d) 1,3,5-triethyl-2,4,6-trimethyl  cyclohexane

Explanation:

The essence of IUPAC nomenclature is to provide a generally accepted nomenclature for chemical compounds which enables the structure of a compound to be drawn from its name without ambiguity.

In order to name straight chain organic compounds, we have to identify the parent chain and then give numbers to the substituents or locants such that they have the lowest possible numbers in alphabetical order.

The correct names of the organic compounds in the question are;

a) pentane

b) 1,3-dimethyl butane

c) 3,4-diethyl-5-methlyl heptane

d) 1,3,5-triethyl-2,4,6-trimethyl cyclohexane

1.How many moles of each element are in 0.0250 mol of K 2 Cr O 4? 2. How many moles of ammonium ions are in 4.50 mol of (N H 4 ) 2 CO 3 ? With all the process to see where you get the answers please

Answers

Answer:

1. 0.0500 moles K, 0.0250 moles Cr and 0.1000 moles O.

2. 9.00 moles ammonium ions are present.

Explanation:

1. In 1mol of K2CrO4 there are 2 moles of K, 1 mole of Cr and 4 moles of O.

The moles in 0.0250 moles K2CrO4 are:

0.0250mol * 2 = 0.0500 moles K

0.0250mol * 1 = 0.0250 moles Cr

0.0250mol * 4 = 0.1000 moles O

2. In 1 mole of (NH4)2CO3 there are 2 moles of ammonium ions, NH₄⁺.

In 4,50 moles are:

4.50 moles * 2 = 9.00 moles ammonium ions are present

At 298 K, the rate constant for a reaction is 0.0346 s-1. What is the rate constant at 350K if the Ea = 50.2kJ/mol

Answers

Answer:

0.702 /s

Explanation:

Rate constant at [tex][298 \mathrm{~K}, \mathrm{~K}_{1}=3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]

Rate constant at [tex]350 \mathrm{~K}, \mathrm{~K}_{2}=?[/tex]

[tex]T_{1}=298 \mathrm{~K}[/tex]

[tex]T_{2}=350 \mathrm{~K}[/tex]

Activation energy, [tex]\mathrm{Ea}=50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}[/tex]

Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]

Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]

[tex]\ln \frac{\mathrm{K}_{2}}{\mathrm{~K}_{1}}=\frac{\mathrm{Ea}}{\mathrm{R}}\left[\frac{1}{\mathrm{~T}_{1}}-\frac{1}{\mathrm{~T}_{2}}\right][/tex]

Therefore,

 [tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{1}{298 \mathrm{~K}}-\frac{1}{350 \mathrm{~K}}\right][/tex]

[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{52 \mathrm{~K}}{298 \mathrm{~K} \times 350 \mathrm{~K}}\right][/tex]

[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=\mathrm{e}^{3.01}[/tex]

[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=20.3[/tex]

[tex]K_{2} &=20.3 \times 3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]

[tex]&=0.702 \mathrm{~s}^{-1}[/tex]

hence, the rate constant at [tex]350 \mathrm{~K} [/tex] is 0.702[tex]\mathrm{~s}^{-1}[/tex]

How many joules of heat is needed when 5 g of water is heated from 25°C to 75°C?

Answers

Answer:

1045 J

Explanation:

By using the formula Eh= mass×specific heat capacity × change in tempreture

With it being a known fact that the specific heat capacity of water is 4.16g/j/°c

balance
Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O

Answers

Equation balance:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

2Al(OH)3+3H2SO4

H=12

SO4=3

O=6

Al=2

Al2(SO4)3+6H2O

H=12

SO4=3

O=6

Al=2

balance the following equations:
a. ____AgI + _____Na2S → _____Ag2S + _____NaI

b. ____Na3PO4 + ____HCl →_____NaCl + _____H3PO4

c. _____Ba3N2 + _____H2O →_____Ba(OH)2 + _____NH3

d. _____TiCl4 + _____H2O →_____TiO2 + _____HCl

e. _____CaCl2 + _____Na3PO4 →_____Ca3(PO4)2 + _____NaCl

Answers

Answer:

A. 2AgI + Na2S → Ag2S + 2NaI

B. Na3PO4 + 3HCl → 3NaCl + H3PO4

C. Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3

D. TiCl4 + 2H2O → TiO2 + 4HCl

E. 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl

Explanation:

2CO +0, 200, what is the mole ratio of carbon monoxide to carbon
dioxide
A 1.2
B 2.2
C 2:1
D 3:1

Answers

Answer:

B. 2.2

Explanation:

what were Lamarck's ideas about evolution and why were those ideas incorrect

Answers

what were Lamarck's ideas about evolution and why were those ideas incorrect

What were Lamarck's ideas about evolution and Why were those ideas incorrect?

These and other examples show that Lamarck's theory does not explain how life formed and became the way it is. The other way that Lamarck's theory has been proven wrong is the study of genetics. Darwin knew that traits are passed on, but he never understood how they are passed on.

[tex]#CarryOnLearning[/tex]

What is the specific heat capacity of silver metal if 110.00 g of the metal
absorbs 396 J of heat and the temperature rises 15.0°C ?

Answers

Answer:

"0.24 J/g.k" is the appropriate solution.

Explanation:

Mass of substance,

m = 110.00 g

Heat,

q = 396 J

Change in temperature,

ΔT = 15.0°C  

Now,

The specific heat will be:

⇒  [tex]q=ms \Delta T[/tex]

On putting the given values, we get

⇒  [tex]396=110.00\times s\times 15.0[/tex]

⇒  [tex]396=s\times 1650[/tex]

⇒      [tex]s=\frac{396}{1650}[/tex]

⇒         [tex]=0.24 \ J/g.k[/tex]

define restivity and conductivity?​

Answers

Answer:

Electrical resistivity is a property of a material that tells you how much it resists the flow of electric current, while conductivity quantifies how easily current flows.

The primary function of a chloroplast is to -
F . Convert food into energy a cell can use
G . Control the function of a cell and control genetic traits
H . Convert radiant energy into chemical energy through photosynthesis
J . Store water and nutrients
Please help!!!

Answers

the answer is

H. Convert radiant energy into chemical energy through photosynthesis

Imagine you had HCl with a concentration of exactly 0.10 mol/dm3. If 0.023 dm3 of a sodium hydroxide solution, NaOH (aq), could exactly neutralize 0.040 dm3 of the HCl solution, what is the concentration of the NaOH (aq)

Answers

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

Help me plz plz bbbbb

Answers

Answer:

The respiratory system is the network of organs and tissues that help you breathe. basically your airways, lungs, and blood vessels so you quite literally need these to survive I mean your muscles need oxygen to function and your brain needs oxygen to function so without your respiratory system you wouldn't be able to move much and you would quickly pass out and die from the lack of oxygen to your brain there are other body processes that need oxygen as well but these are just two examples.

Explanation:

Answer:

Maybe it’s dark ??????????????

Explanation:

Hm

Glucose is a compound made from three elements: carbon, oxygen, and hydrogen. For glucose to be broken down into these elements, it must undergo _____.
A. filtration or distillation
B. an irreversible physical change, such as tearing or slicing
C. a reversible physical change, such as boiling or melting
D. a chemical change

Answers

The answer is D.) a chemical change.

Answer:

D ) Chemical Change

Explanation:

The carbon dioxide is released when limestone is heated during the
production of _____?

Answers

Carbon dioxide is released when limestone is heated during the production of [tex]\sf\purple{cement}[/tex]. ✔

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

If HA, an acid, is 15 percent dissociated in a 2.00 molar solution, what is the Ka for the solution?
A.5.3 × 10-2
B.6.4 × 10-3
C.1.1 × 10-2
D.1.2 × 10-2

Answers

Answer:

A. 5.3 X 10^-2

Explanation:

I got 100 on PLATO

in the structure of an atom why are protons present in the centre and are not pulled outside by the electrons as both are positively charged with some unit of charge?

Answers

Answer:

Electrons and protons are not positively charged

Explanation:

Neutrons are the only ones positively charged in the structure of an atom.... Also like charges repel which means a -ive and a - ive will repel when together

True or False all non - metal elements are gassed at room temperature.​

Answers

Answer:

false

Explanation:

you have bromine , its a non metal and liquid in room temperature

Un profesor desea preparar una disolución de agua oxigenada al 20%v/v y dispone solamente de 50 cm3 h2o2 ¿qué volumen d disolución deberá preparar? Con procedimiento

Answers

Answer:

250cm³ de disolución se deben preparar

Explanation:

El porcentaje volumen volumen (%v/v) se define como el volumen de soluto -En este caso, H2O2- en 100cm³ de disolución.

Se desea preparar una solución que contenga 20cm³ de H2O2 por cada 100cm³

Como solamente se cuenta con 50cm³ de H2O2, el volumen que se debe preparar es:

50cm³ H2O2 * (100cm³ Disolución / 20cm³ H2O2) =

250cm³ de disolución se deben preparar

50 POINTS PLEASE HELP!

A gas diffuses 1/7 times faster than hydrogen gas (H2).

What is the molar mass of the gas?

100.10 g/mol
98.78 g/mol
86.68 g/mol
79.98 g/mol

Answers

Answer: The molar mass of the gas is 9.878 g/mol.

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.

[tex]Rate = \frac{1}{\sqrt{M}}[/tex]

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.

[tex]\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\[/tex]

where,

[tex]M_{1}[/tex] = molar mass of hydrogen gas

[tex]M_{2}[/tex] = molar mass of another given gas

[tex]R_{1}[/tex] = rate of diffusion of hydrogen

[tex]R_{2}[/tex] = rate of diffusion of another given gas = [tex]\frac{1}{7}R_{1}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} = \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol[/tex]

Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.

Answer:

98.78 g/mol

Explanation:

Just took the test

Which of the following is NOT one of the three main global climate zones?
A. Tropical
B. Latitude
C. Polar
D.Temprate

Answers

The answer is Latitude (B)
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