a fraction is less than 1. Choose a counterexample that will prove this conjecture false
Answers
Answer:
1st option
Step-by-step explanation:
Here we are trying to prove that not all fractions are less than 1. So we have to choose an example in which the fraction is more than 1.
1) [tex] \frac{8}{7} = 1 \frac{1}{7} [/tex]
This fraction is greater than 1 hence it can prove that the conjecture is false.
2) ½ is lesser than 1 and will not prove that the conjecture is false.
Related Questions
Which of the following points satisfies the inequality x ≥ -3? (select all that apply) a(0, -2) b(-3, 4) c(-4, 2) d(5, -5)
Answers
Answer:
a, b, d
Step-by-step explanation:
For the inequality x ≥ -3 . . .
a(0, -2) . . . 0 ≥ -3, true
b(-3, 4) . . . -3 ≥ -3, true
c(-4, 2) . . . -4 ≥ -3, FALSE
d(5, -5) . . . 5 ≥ -3, true
Points a, b, d satisfy the inequality.
What is the quotient in polynomial form?
Answers
Answer:
The quotient in polynomial form= 2x + 6
Step-by-step explanation:
In order to calculate the quotient in polynomial form of the following synthetic division we would have to make the following:
According to the given data we have the following:
-1|2 8 6
Therefore, quotient in polynomial form would be calculated as follows:
-1 | 2 8 6
-2 -6
2 6 0
Therefore, quotient in polynomial form= 2x + 6
The quotient in polynomial form= 2x + 6
Last winter Armand had StartFraction 5 Over 6 EndFraction of a row of stacked logs. At the end of the winter he had StartFraction 8 Over 15 EndFraction of the same row left. How much wood did he burn over the winter?
Answers
Answer:
3/10
Step-by-step explanation:
We have that the Armans last winter had 5/6 of a row of stacked logs and at the end of the winter he had 8/15 of the same row left, therefore:
Ambitious
First we have to do is that the denominator is the same.
in the case of 5/6 it would be 25/30
and for 8/15 it would be 16/30
Now if we can do the subtraction and it would be:
25/30 - 16/30 = 9/30 or what equals 3/10
3/10 was the amount of wood he burned in the winter
Answer:
D) 3/10 row
Step-by-step explanation:
evaluate the expression 5 square minus (3 square+4)
Answers
Answer:
12
Step-by-step explanation:
We have 5 squared minus (3 squared plus 4). Convert this to mathematical expression:
- "5 squared" = 5²
- "minus" = -
- "3 squared" = 3²
- "plus 4" = + 4
Put it altogether:
5² - (3² + 4)
5² = 5 * 5 = 25 and 3² = 3 * 3 = 9, so:
25 - (9 + 4) = 25 - (13) = 12
The answer is thus 12.
~ an aesthetics lover
Answer:
12
Step-by-step explanation:
Math
I NEED HELP PLEASE, THANKS! :)
Answers
Answer:
Symmetric with respect to the polar axis in agreement with the second answer listed.
Step-by-step explanation:
This is the shape of a cardioid [tex]14\,(1+cos(\theta))[/tex] it contains the function cosine of the angle so it must be symmetric with respect to the polar axis, since the cosine function is also symmetric for positive and negative values of the angle.
Find the value of x.
Answers
Answer:
[tex]\huge\boxed{x=\sqrt{66}}[/tex]
Step-by-step explanation:
ΔADC and ΔABD are similar (AAA)
Therefore the cooresponging sides are in proportion:
[tex]\dfrac{AD}{AC}=\dfrac{AB}{AD}[/tex]
Substitute
[tex]AD=x;\ AC=6+5=11;\ AB=6[/tex]
[tex]\dfrac{x}{11}=\dfrac{6}{x}[/tex] cross multiply
[tex](x)(x)=(11)(6)\\\\x^2=66\to x=\sqrt{66}[/tex]
Finding missing angles
Answers
Answer:
x=15
Step-by-step explanation:
165+x=180
180-165=15
Hope this helps!!
In a random sample of 400 registered voters, 120 indicated they plan to vote for Candidate A. Determine a 95% confide
Answers
Answer:
Step-by-step explanation:
Using the formula
p +/- (z* √[p(1-p) /n]
Where p is sample proportion = 120/400= 0.3 z*= 1.96 (z score for 95% confidence) and n is 400.
0.3 + (1.96 √[0.3(1-0.3) / 400])
0.3 + (1.96 √[(0.3*0.7)/400
0.3 + (1.96√ (0.21/400))
0.3 + (1.96 √0.000525)
0.3 + (1.96* 0.023)
0.3 + (0.045)
= 0.345 ~ 35%
For the lower interview
0.3 - (0.045)
= 0.255 ~ 26%
Thus, a 95% confidence interval for this study is between 26% and 35%
Evaluate. Write your answer as a fraction or whole number without exponents. 3^–2 =
Answers
Answer:
The answer is 1/9
Step-by-step explanation:
3^-2 can be written as 1/3²
And
1/3² = 1/9
Hope this helps you
Suppose you are starting your own company selling chocolate covered strawberries. You decide to sell the milk chocolate covered strawberries for a profit of $2.25 $ 2.25 /box and the white chocolate covered strawberries at $2.50 $ 2.50 /box. Market tests and available resources, however, have given you the following constraints. The combined production level should not exceed 800 800 boxes per month. The demand for the white chocolate is no more than half the demand for milk chocolate strawberries. The production level for white chocolate should be less than or equal to 200 200 boxes.
Answers
Answer:
$1850 per month
Step-by-step explanation
There are two types of chocolates that can be produced milk chocolate and strawberry covered chocolate. To find the profit we make following equation,
P = $2.25 SC + $2.50 WC
where SC is strawberry chocolate and WC is White milk chocolate.
The maximum production level can be 800 boxes per month and white chocolates can not exceed the 200 boxes per month so we assume making 600 boxes of Strawberry covered chocolates and 200 boxes of white chocolates.
Profit = 2.25 * 600 + 2.50 * 200
Profit = $1850
This is the maximum profit that can be earned after making combination of two types of chocolates.
What ray is a common side of
Answers
Hope this helps!
true or false? the circumcenter of a triangle is the center of the only circle that can be inscribed about it
Answers
Answer:
TRUE
Step-by-step explanation:
The circumcenter of a triangle is the center of the only circle that can be circumscribed about it
Answer:
False
Step-by-step explanation:
Bill must take an 8-question true/false quiz and has to guess on each problem. How many
ways is it possible to answer the quiz questions?
Answers
Answer:40320
Step-by-step explanation:
8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320 and there are 8 questions total
A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 75 pounds. The truck is transporting 55 large boxes and 50 small boxes. If the truck is carrying a total of 4025 pounds in boxes, how much does each type of box weigh?
Answers
Answer:
There are 50 large boxes.
Step-by-step explanation:
First, "boxes of two sizes" means we can assign variables:
Let x = number of large boxes
y = number of small boxes
"There are 115 boxes in all" means x + y = 115 [eq1]
Now, the pounds for each kind of box is:
(pounds per box)*(number of boxes)
So,
pounds for large boxes + pounds for small boxes = 4125 pounds
"the truck is carrying a total of 4125 pounds in boxes"
(50)*(x) + (25)*(y) = 4125 [eq2]
It is important to find two equations so we can solve for two variables.
Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x:
x = 115 - y [from eq1]
50(115-y) + 25y = 4125 [from eq2]
5750 - 50y + 25y = 4125 [distribute]
5750 - 25y = 4125
-25y = -1625
y = 65 [divide both sides by (-25)]
There are 65 small boxes.
Put that value into either equation (now, which is easier?) to solve for x:
x = 115 - y
x = 115 - 65
x = 50
A test of a printed circuit board uses a random test pattern with an array of 8 bits and each is equally likely to be 0 or 1. Write down the number of different bytes of possible different series.
Answers
Answer:
256.
Step-by-step explanation:
Each position can be one of 2 states so the number of possibilities
is 2^8 = 256.
Evaluate triple integral ∫ ∫ ∫ 8xydV, where E lies under the plane z = 1+x+y and above the E region in the xy-plane bounded by the curves y = √ x, y = 0, and x = 1.
Answers
Answer:
[tex]\mathbf{=\dfrac{163.384}{15}}[/tex]
Step-by-step explanation:
[tex]\int \int \limits_{E} \int \ 8 xy dV = \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} \int\limits^{1+x+y}_{0} \ 8xy dz dydx[/tex]
[tex]= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} [ 8xyz]^{z=1+x+y}_{z=0} \ \ dy dx[/tex]
[tex]= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy (1+x+y) dy dx[/tex]
[tex]= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy+8x^2y+8xy^2 \ \ dy dx[/tex]
[tex]= \int\limits^{1}_{0} \ [ 4xy^2+4x^2y^2+2.7xy^3]^{ y= \sqrt{x}}_{y-0} \ \ dx[/tex]
[tex]= \int\limits^{1}_{0} \ 4x (\sqrt{x})^2+4x^2(\sqrt{x})^2+2.7x(\sqrt{x})^3\ \ dx[/tex]
[tex]= \int\limits^{1}_{0} \ 4x^2+4x^3+2.7x^{5/2} \ dx[/tex]
[tex]\mathbf{=\dfrac{163.384}{15}}[/tex]
Find the median of: 1, 3, 4, 6, 2, 4, 5, 6, 2, 3, 1, 4, 0, 4, 4, 4, 8, 9, 7, 4
Answers
Answer:
4
Step-by-step explanation:
1, 3, 4, 6, 2, 4, 5, 6, 2, 3, 1, 4, 0, 4, 4, 4, 8, 9, 7, 4
Arrange the numbers from smallest to largest
0,1, 1,2,2, 3,3, 4, 4,4,4,4,4 , 4, 5, 6, 6, 7, 8, 9,
There are 20 numbers
The middle number is between 10 and 11
0,1, 1,2,2, 3,3, 4, 4,4 ,4,4,4 , 4, 5, 6, 6, 7, 8, 9,
The median is 4
Solution,
Arranging the data in ascending order:
0,1,1,2,2,3,3,4,4,4,4,4,4,4,5,6,6,7,8,9
N(total number of items)= 20
Now,
Median:
[tex] (\frac{n + 1}{2)} ) ^{th \: item} \\ = (\frac{20 + 1}{2} ) ^{th \: item} \\ = \frac{21}{2} \\ = 10.5 \: th \: \: item[/tex]
Again,
Median:
[tex] \frac{10 \: th \: item + 11 \: th \: item}{2} \\ = \frac{4 + 4}{2} \\ = \frac{8}{2} \\ = 4[/tex]
Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of the first year he had earned $590 in interest. How much was in each account? $_____ at 12% $_____ at 7%
Answers
Answer:
The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
Step-by-step explanation:
Let x be the amount in the account at 12% interest
So, 6000-x is the amount in the second account at 7% interest
[tex]SI = \frac{P \times T \times R}{100}[/tex]
First account:[tex]SI=\frac{x \times 1 \times 12}{100}[/tex]
Second account : [tex]SI =\frac{(6000-x) \times 1 \times 7}{100}[/tex]
We are given that At the end of the first year he had earned $590 in interest.
So, [tex]\frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400[/tex]
So,the amount in the account at 12% interest is $3400
The amount in the second account at 7% interest =6000-x=6000-3400=2600
Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
There are no solutions to the system of inequalities shown below.
y< 3x+ 5
y> 3x-1
True or false
Someone help please
Answers
Answer:
False, there are actually infinite solutions as these are parallel lines.
Step-by-step explanation:
Don’t know this one
Answers
Answer:
B
Step-by-step explanation:
The answer is B because in order for the square root of a number to be equal to another number, the answer squared should be the number under the square root.
B. [tex](-4)^2\neq -16[/tex].
Hope this helps.
(2m^4) • m3
Need help ASAP I have the answer but I need help showing work
Answers
Answer:
4m^11
Step-by-step explanation:
2m^4.2 you multiply powers in paranthesis
2m^8 result
2m^8.m^3
You add the exponents together because it is same base and put the 4 because 2 to the power of 2 is 4
4m^11
Answer: 4[tex]m^{11}[/tex]
Step-by-step explanation:
(2m^4)^2 * m^3
Expand
[tex]2^{2} * m^{8} *m^{3}[/tex] add the exponents since they have the same base
[tex]4m^{11}[/tex]
b) A grocer sold 5 kg of wheat flour at Rs 30 per kg and gained 20%. If he had sold
it at Rs 27 per kg, what would be his gain or loss percent?
Answers
Answer:
22.5%
Step By Step Explanation:
1) the amount which will be obtained when 5 kg of rice is sold for Rs30 per kg=150 kg
2) the amount which will be obtained when 5 kg of rice is sold for Rs27 per kg=135 kg
3)difference of Both the no. = 150-135
= 15 kg
4) ans as percentage = 15% of 150
= 22.5%
WARNING:- NOT SURE WITH THE ANSWER
Please answer this correctly as soon as possible
Answers
Answer:
Number of cards = 7
Number of cards not greater than 4 = 2
P( not greater than 4) = 2/7
Hope this helps
We are given 7 cards and we choose at random.
There are only 2 cards that are less then 4 so that means 2/7 is not greater than 4.
So P(2/7)
The answer is 2/7
Best of Luck!
(i) You are the cost Engineer for a construction company in charge of building a new
bridge. The construction company will be penalized each day of delay in
construction for bridge. The penalty will be $4500 for the first day and will increase
by $12000 for each following day. Based on its budget, the company can afford to
pay a maximum of $ 155000 toward penalty. By modelling this as an arithmetic
progression, find the maximum number of days by which the completion of work can
be delayed.
Answers
Answer:
The work can only be delayed for 13 days
Step-by-step explanation:
The construction company will be penalized $4500 for delaying the project for the first day after that day the amount will increase by $12000 for each day. The company can only afford to pay $155000 towards the penalty.
Using arithmetic progression,
a = 4500
d = common difference = 12000
nth term = 155000
n = number of days
a + (n - 1)d = 155000
4500 + (n - 1)12000 = 155000
4500 + 12000n - 12000 = 155000
12000n - 7500 = 155000
12000n = 162500
divide both side by 12000
n = 162500/12000
n = 13.5416666667
n = 13.5
The work can only be delayed for 13 days
Answer:
approximately 13 days
Step-by-step explanation:
Which of the following lists of ordered pairs is a function?
Α. (Ο, 2), (2, 3), (ο, - 2), (4, 1)
Β. (1, 2), (1,2), 2), (3, 4)
C. 1, 5). 2, 1, 4, 9), το, 5)
D. (2, 4), (0, 2), (2, -4), (5, 3)
Answers
Answer:
the answer will be D
Step-by-step explanation:
Ujalakhan01! Please help me! ASAP ONLY UJALAKHAN01. What's (x-1)(x-1)?
Answers
Answer:
[tex]x^2-2x+1[/tex]
Step-by-step explanation:
=> (x-1)(x-1)
Using FOIL
=> [tex]x^2-x-x+1[/tex]
=> [tex]x^2-2x+1[/tex]
Answer:
[tex]\boxed{x^2-2x+1}[/tex]
Step-by-step explanation:
[tex](x-1)(x-1)[/tex]
Apply FOIL Method.
[tex]x(x-1)-1(x-1)[/tex]
[tex]x^2-x-x+1[/tex]
Combine like terms.
[tex]x^2-2x+1[/tex]
Determine the probability of randomly selecting two individuals who are issued exactly two credit cards. [Hint: Are the events independent?] Interpret this result.
Answers
Answer:
They are dependent because we have to select from people who are given cards.
Step By Step Explanation:
So we'll take away people not given cards first den find the probability of selecting people with cards over the total number of people present .
Probability we'll be equal to = number of people with card(C) two persons/total number of people
Where C represent combination
Two parallel lines are crossed by a transversal.What is the value of d?
Answers
Step-by-step explanation:
if there is any confusion then again ask me always with you
Answer:
d = 125
Step-by-step explanation:
E2020
pls mark Brainliest
What is the domain of the equation y=1/X+5?
Answers
Answer:
Domain is
{
x
∈
R
;
x
≠
−
5
}
Range is
{
y
∈
R
;
y
≠
0
}
Step-by-step explanation:
Explanation:
Domain: Denominator should not be
0
∴
x
+
5
≠
0
or
x
≠
−
5
Domain is any real value except
x
=
−
5
or
{
x
∈
R
;
x
≠
−
5
}
Range is any real value except
y
=
0
or
{
y
∈
R
;
y
≠
0
}
graph{1/(x+5) [-10, 10, -5, 5]}
Suppose H is an ntimesn matrix. If the equation Hxequalsc is inconsistent for some c in set of real numbers R Superscript n, what can you say about the equation Hxequals0? Why?
Answers
Answer:
The answer is explained below
Step-by-step explanation:
Given that, the equation H*x = c is inconsistent for some c in R^n, we can say that the equation A*x = b has at least one solution for each b in R^n of IMT (Inverse Matrix Theorem) is not fulfilled.
Thanks to this we can say that by equivalence of theorem statement, the equation H*x = 0 will not have only the trivial solution. It will have non-trivial solutions too.