Answer:
2
Explanation:
To find force it's force = mass times acceleration so to find mass you would divide force by acceleration
5. If an object has an acceleration of 0 m/s2, then one can be sure that the object is not ____.
a. moving
b. changing position
c. changing velocity
6. If car A passes car B, then car A must be ____.
a. accelerating.
b. accelerating at a greater rate than car B.
c. moving faster than car B and accelerating more than car B.
d. moving faster than car B, but not necessarily accelerating.
7. Which one of the following is NOT consistent with a car which is accelerating?
a. A car is moving with an increasing speed.
b. A car is moving with a decreasing speed.
c. A car is moving at a high speed.
d. A car is changing direction.
8. A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that
a. he is accelerating
b. he is covering a greater distance in each consecutive second.
c. he is moving with a constant speed (on average).
Answer: c
Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.
If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.
If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.
The not consistent with a car that is accelerating is a car is moving at a high speed.
A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).
What is Acceleration?Acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction). Speed is the distance covered in a unit of time while acceleration is the rate of change in speed. The unit of speed in the metric system is meters per second (m/s) while that of acceleration is meters per second squared (m/s2). Speed is a scalar quantity while acceleration is a vector quantity.To learn more about acceleration and speed, refer to: https://brainly.com/question/25086037
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What is the kinetic energy of a 25kg object moving at a velocity of 2.5 m/s
Answer:
78j
Explanation:
78.125J to be exact
Under constant acceleration, the average velocity of a particle is half the sum of its initial and final
velocities. Is this still true if the acceleration is not constant? Explain.
Answer:
It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant
Explanation:
The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;
v² = u² + 2·a·s
v = u + a·t
Where;
v = The final velocity of the particle
u = The initial velocity of the particle
a = The acceleration of the particle
s = The distance through which the particle travels
t = The time of motion of the particle
By simplifying the above equation, we have;
v² - u² = 2·a·s
(v² - u²)/(2·a) = s
(v - u) × (v + u)/(2 × a) = s
((v - u)/a) × ((v + u)/2) = s
From v = u + a·t, we have;
t = (v - u)/a
∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s
∴ ((v + u)/2) = s/t
The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)
∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity
However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.