A force of 20N changes the position of a body. If mass of the body is 2kg, find the acceleration produced in the body.2. A ball of mass 500g is thrown upwards with a velocity of 15m/s. Calculate its momentum at the highest point.

Answer:

The correct option is;

3. The total mechanical energy is constant as the block moves back and forth

Explanation:

The total mechanical energy is the sum of the potential and kinetic energies of the system

For a system that is isolated from the effects of external forces, but being acted upon by the internal conservative forces within the system, the total mechanical energy is constant

For a black and spring system, we have total mechanical energy, E = 1/2×K×A².

Where;

K = Constant

A = The amplitude of motion

Therefore, where there is no loss to friction, with A, remaining constant, the total mechanical energy will be constant.

Explanation:

meter=100cm

cm=10^-2 m

min=60 sec

0.0141666667 m / s

The conversion of 85 cm/min would be 0.0133 m/s

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

As given in the problem position-time graph of an object.

As we know that slope of the position time curve represents the velocity of the object

As given in the problem we have to convert 85 cm/min to m/s.

Let us first convert the displacement in cm to meters

100 cm = 1 m

1 cm = 1/100 m

85 cm = 85×1/100 m

          = 0.85 m

similarly, convert time given in minutes to the seconds

1 min = 60 s

velocity = displacement /time

velocity  =  0.85 / 60 m/s

             =0.01333 m/s

Thus, we converted  85 cm/m into 0.0133 m/s

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Convert to m/s

[tex]\\ \sf \longmapsto 72\times \dfrac{5}{18}=5(4)=20m/s[/tex]

[tex]\\ \sf \longmapsto Acceleration=\dfrac{v-u}{t}[/tex]

[tex]\\ \sf \longmapsto Acceleration=\dfrac{0-20}{2}[/tex]

[tex]\\ \sf \longmapsto Acceleration=\dfrac{-20}{2}[/tex]

[tex]\\ \sf \longmapsto Acceleration=a=-10m/s^2[/tex]

Using second equation of kinematics

[tex]\\ \sf \longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf \longmapsto s=20(2)+\dfrac{1}{2}(-10)(2)^2[/tex]

[tex]\\ \sf \longmapsto s=40+(-20)[/tex]

[tex]\\ \sf \longmapsto s=40-20[/tex]

[tex]\\ \sf \longmapsto s=20m[/tex]

Now

Using newtons second law

[tex]\\ \sf \longmapsto Force=ma[/tex]

[tex]\\ \sf \longmapsto Force=5000(-10)[/tex]

[tex]\\ \sf \longmapsto Force=-50000N[/tex]

[tex]\\ \sf \longmapsto Force=50kN[/tex]

Answer . The acceleration of the truck is 10m/[tex]s^{2}[/tex], and the distance covered is 40 m. Have attached the picture for solution.

Hope that helps.

Answer:

Gravitational force will be 16 times more.

Explanation:

we know;

Gravitational force (F) = (Gm1m2)/d^2

when mass of each is doubled and distance between them is halved;

F= (G2m1×2m2)/(d/2)^2

=(4Gm1m2)/(d^2/4)

=4×4(Gm1m2)/d^2

=16(Gm1m2)/d^2

=16F

Answer:

Both are the same.

Explanation:

[tex]pressure= \frac{force}{area} = \frac{f}{a} = \frac{n}{m {}^{2} } [/tex]

The SI unit was named after Bláise Pascal to honor him.

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Answer:

v = 60 m/s

Explanation:

It is given that,

A wave is represented by the equation :

[tex]y=0.2\sin [0.4\pi (x-60)t][/tex]

We need to find the velocity of the wave

The general equation of a wave is given by :

[tex]y=A\sin (kx-\omega t)[/tex] ....(1)

Equation (1) can be written as :

[tex]y=0.2\sin (0.4\pi x-24\pi t)[/tex] ...(2)

If we compare equation (1) and (2) we get :

[tex]k=0.4\pi[/tex]

[tex]\omega=24\pi[/tex]

The velocity of a wave is given by :

[tex]v=\dfrac{\omega}{k}\\\\v=\dfrac{24\pi}{0.4\pi}\\\\v=60\ m/s[/tex]

So, the velocity of the wave is 60 m/s.

Answer:

I assume its c. Since its talking about testing.

Explanation:

Answer:

The answer is test of durability

Explanation:

Answer:

F = 0.408 N

Explanation:

It is given that,

Weight of a wooden block, W = 8 N

Weight, W = mg

m is mass of wooden block

[tex]m=\dfrac{W}{g}\\\\m=\dfrac{8\ N}{9.8\ m/s^2}\\\\m=0.816\ kg[/tex]

Acceleration of the block, a = 0.5 m/s²

Force, F = ma

[tex]F=0.816\ kg\times 0.5\ m/s^2\\\\F=0.408\ N[/tex]

So, the magnitude of force applied to the wooden block is 0.408 N.

Answer:

we learned that an object that is vibrating is acted upon by a restoring force. The restoring force causes the vibrating object to slow down as it moves away from the equilibrium position and to speed up as it approaches the equilibrium position. It is this restoring force that is responsible for the vibration. So what forces act upon a pendulum bob? And what is the restoring force for a pendulum? There are two dominant forces acting upon a pendulum bob at all times during the course of its motion. There is the force of gravity that acts downward upon the bob. It results from the Earth's mass attracting the mass of the bob. And there is a tension force acting upward and towards the pivot point of the pendulum. The tension force results from the string pulling upon the bob of the pendulum. In our discussion, we will ignore the influence of air resistance - a third force that always opposes the motion of the bob as it swings to and fro. The air resistance force is relatively weak compared to the two dominant forces.

The gravity force is highly predictable; it is always in the same direction (down) and always of the same magnitude - mass*9.8 N/kg. The tension force is considerably less predictable. Both its direction and its magnitude change as the bob swings to and fro. The direction of the tension force is always towards the pivot point. So as the bob swings to the left of its equilibrium position, the tension force is at an angle - directed upwards and to the right. And as the bob swings to the right of its equilibrium position, the tension is directed upwards and to the left. The diagram below depicts the direction of these two forces at five different positions over the course of the pendulum's path.

that's what I know so far

Answer:

Answer:

[tex] \boxed{\sf Work \ done = 4 \ J} [/tex]

Given:

Force = 8 N

Distance covered by the body = 50 cm = 0.5 m

Explanation:

Work Done = Force × Distance covered by the body

= 8 × 0.5

= 4 J

Answer:

OPTION (C)

Explanation:

m(magnification) = -0.4 means a real, inverted and diminished image is formed in front of the mirror.

Answer:

Kelvin

Explanation:

The SI unit to use in measuring the temperature of hot liquid is kelvin (K)

Answer:

10N

Explanation:

Applying the Hooke law:

F = kx

F: Force

k: stiffness coefficient

x: stretched distance

F = 10N/m x 1m = 10N

[tex]\\ \sf\longmapsto P.E=mgh[/tex]

[tex]\\ \sf\longmapsto P.E=150(2)(10)[/tex]

[tex]\\ \sf\longmapsto P.E=3000J[/tex]

In 2nd case

[tex]\\ \sf\longmapsto P.E=200(2)(10)[/tex]

[tex]\\ \sf\longmapsto P.E=4000J[/tex]

We can observe that

Answer:

3.14*1²

3.14 cm²

I hope this will help

Answer:

3.14 cm squared

Explanation:

I hope this will help.

Answer:

13.6 cm

Explanation:

From Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.

Given n₂ = 4/3:

1 = 4/3 sin θ

sin θ = 3/4

If x is the radius of the circle, then sin θ is:

sin θ = x / √(x² + 12²)

sin θ = x / √(x² + 144)

Substituting:

3/4 = x / √(x² + 144)

9/16 = x² / (x² + 144)

9/16 x² + 81 = x²

81 = 7/16 x²

x ≈ 13.6

Answer:

The distance traveled by the ball is 8.5 m

Explanation:

Initial height of the ball, h₁ = 1.5 m above the ground

final height of the ball, h₂ = 5m

Upward distance = distance traveled by the ball from a height of 1.5m to 5m = 5m - 1.5m = 3.5 m

Downward distance = distance traveled by the ball from 5m height to the ground =5m - 0 = 5m

Total distance traveled = upward distance + downward distance

Total distance traveled = 3.5 m + 5m = 8.5 m

Therefore, the distance traveled by the ball is 8.5 m

Answer:

hlo

Explanation:

hlo olz mark me as brainlest

Answer:

 w = -101 rad / s

Explanation:

For this exercise we will use Faraday's law

          E = - dФ / dt

where the magnetic flux is

          Ф = B. A = B A cos θ

In this case, the angle between the magnetic field and the normal to the disk is zero, cos 0 = 1, they indicate that the field is constant, let's find the area

The area rotated by the disk is

         A = ½ r s

if we express the angles in radians

         θ = s / r

         s = r θ

where is the arc supported

         A = ½ r (r θ)

let us substitute in the Faraday equation

          E = - d (B ½ r² θ) / dt

          E = - ½ B r² dθ/dt

the definition of angular velocity is

          w = dθ/dt

          E = - ½ B r² w

           w = - 2E / B r²

let's calculate

         w = - 2 3.86 / (0.0314 1.56²)

         w = -101 rad / s

Answer:

Using

1/2mv^2 = work done by friction

work done = force x distance

lets call the force 3 N

lets call v = 3 m/s

lets call mass = 2 kg

0.5 x 2 x 3^2 = 9 J

9/3N = 3 m/s

now times 3 m/s by square root of 2 of which is 1.4142

3 x 1.4142= 4.2426 m/s

0.5 x 2 x 4.2426^2 = 18

18/2N = 9 m

Answer:

i) 60 W

ii) 100 W

Explanation:

In each case, the bulb that dissipates the most power is the bulb that glows brighter.  Power is voltage times current (P = VI).  Using Ohm's law, we can rewrite this as P = I²R or P = V²/R.

Bulbs are rated at a certain power for a certain voltage.  P = V²/R, so the bulb with the lower resistance will have the higher power rating.  Therefore, the 100 W bulb has a lower resistance than the 60 W bulb.

i) They are in series, so they have the same current.  P = I²R, so the bulb with the higher resistance will glow brighter.  That's the 60 W bulb.

ii) They are in parallel, so they have the same voltage.  P = V²/R, so the bulb with the lower resistance will glow brighter.  That's the 100 W bulb.

your answer is...

C. potassium

Answer:

To summarize, an object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is constant, its velocity is changing. Velocity, being a vector, has a constant magnitude but a changing direction.

Explanation:

Speed refers to how fast an object is moving. It can be thought of as the rate at which an object covers distance.

Velocity refers to the rate at which an object changes its position. If you picture a person moving rapidly - one step forward and one step back- always returning to the original starting position, the speed is very rapid, but the velocity is zero. Because the person always returns to the original position, this motion would bébé result in a change in position. Since velocity is defined as the rate at which the position changes, this motion results in zero velocity. To maximize velocity, every effort must be made to maximize the amount an object is displaced from its original position. Every movement should be moving the object further from where it started. Velocity is DIRECTION AWARE. When evaluating the velocity of an object, you have to keep track of direction. This is one of the essential differences between speed and velocity: speed does not keep track of direction, while velocity is directionally aware.

So, when the moon moves around the Earth, the speed remains constant, but since it's moving in an elliptical orbit, it's direction is constantly changing.

Answer:

Since N/m is the unit of spring constant N/nm would be the possible unit for a spring constant.

A. N/nm is the possible unit for a spring constant.

The units at the spring regular are Newton/meter (N/m). The poor signal within the above equation is an indication that the direction that the spring stretches is opposite the path of the pressure that the spring exerts.

Because the force is measured in Newtons and the spring consistent is multiplied with the aid of the gap in meters, the spring constant need to have devices that get rid of meters, ensuing most effective force. The most effective devices that work for the spring regular are for that reason, Newtons in step with the meter.

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Answer:

As rocket mass increases, acceleration decreases.

Explanation:

From Newton's second law of motion;

F= ma

Where;

m= mass of the object

a= acceleration of the object

Hence we can write;

a= F/m

This implies that an increase in mass (m) will lead to a decrease in acceleration if the force on the object is held constant.

Hence, if the rockets have different masses, they will have different accelerations.

Hello!

---------

As rocket mass increases, acceleration decreases.

Hope this helps! The rest are available on Quizlet at "Unit 6: Lesson 4 Force, Mass and Acceleration". Thanks and good luck!

Answer:

V = 26.6 volts

Explanation:

Let Initial Potential Difference be V.

Charge (Q) accumulated in 30 mF Capacitor =

Q = C * V

Q= 30 * V

Now, Common Potential after connecting to uncharged 10mF capacitor in parallel = 20 Volt

Total Charge =Total Capacity * Common Potential

30 * V = ( 30 + 10) * 20

V = 26.6 volts

The unknown potential across the 30-µF capacitor is 6.67 V.

The given parameters;

Since the potential difference between the two capacitors are different, the two capacitors are in series connection.

In series circuit arrangement, the quantity of charge flowing in each capacitor is the same.

[tex]Q_{30\ \mu F} = Q_{10 \ \mu F}[/tex]

[tex]Q_{10 \ \mu F} = CV = 10\times 10^{-6} \times 20 = 0.0002 \ C[/tex]

The potential difference are different and the total potential is given as;

[tex]V_{T} = V_1 + V_2\\\\V_1 = \frac{Q}{C_1} \\\\V_2 = \frac{Q}{C_2} \\\\V_1+V_2 = \frac{Q}{C_1} + \frac{Q}{C_2}\\\\V_1 + V_2 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1 + 20 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1+ 20 = \frac{Q(C_2+ C_1)}{C_1 C_2} \\\\V_1 = \frac{Q(C_2+ C_1)}{C_1 C_2} - 20[/tex]

[tex]V_1 = \frac{0.0002(10\times 10^{-6}\ + \ 30\times 10^{-6})}{(30\times 10^{-6}) (10\times 10^{-6})} - 20\\\\V_1 = \frac{8\times 10^{-9}}{3\times 10^{-10}} - 20\\\\V_1 = 26.67 - 20\\\\V_1 = 6.67 \ V[/tex]

Thus, the unknown potential across the 30-µF capacitor is 6.67 V.

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Answer:

40085 Hz

Explanation:

We are given; Sound frequency emmision of bat;f = 38.9 kHz = 38900 Hz

Bat is moving at 0.015 times the speed of sound in air.

Speed of sound in air = 343 m/s

The formula for waves reflected off the wall is calculated from Doppler equation as:

f' = f(v + v_d)/(v - v_s)

Where;

f is the frequency = 38900 Hz

f' is the detected frequency,

v_d is the velocity of the detector = 0.015 × 343 = 5.145

v_s is the velocity of the source = 0.015 × 343 = 5.145 m/s

v is the velocity of the sound = 343 m/s

Thus;

f' = 38900(343 + 5.145)/(343 - 5.145)

f' ≈ 40085 Hz

Answer:

A dark fringe