A force of 10 newtons toward the right is exerted on a

wooden crate initially moving to the right on a horizontal

wooden floor. The crate weighs 25 newtons.


1. Calculate the magnitude of the force of friction between the crate and the floor.


2. What is the magnitude of the net force acting on the crate?

Answer:

Pic not clear.........

Answer:

If a cow has a greater mass than the tiger, it has greater momentum, but only if they are moving at the same speed, or the tiger is going slower (i think)

Explanation:

the quantity of motion of a moving body, measured as a product of its mass and velocity.

Answer:

The acceleration of the particle as it travels one semicircle is

[tex]a= \frac{\pi R}{t^2}[/tex]

Explanation:'

Kindly see attached a sketch of a semi-circle

Step one:

given data

velocity =v

let the time taken be t

The path PQM is the distance covered

so distance [tex]d= \pi R[/tex]

we know that time= distance/velocity

t= πR/v

step two:

velocity =distance/time

[tex]velocity=\frac{\pi R}{t}[/tex]

also, we know that acceleration is velocity/time

[tex]a= \frac{\pi R}{\frac{t}{t} }[/tex]

[tex]a= \frac{\pi R}{t}*\frac{1}{t}[/tex]

[tex]a= \frac{\pi R}{t^2}[/tex]

Answer:

W=31.99 N

Explanation:

W= 8 N (N= kg*m/ s^2)

W= m* g

8 N= m * 9.8 m/s^2

m= 0.816 kg

m*4= (0.816)4

= 3.264 kg

W= mg

= (3.264 kg)(9.8 m/s^2)

W=31.99 N

60 m

Concept Used:

We know that the area under a velocity-time graph represents the Displacement of the body

Displacement in the Last 6 seconds:

To find the Displacement in the last 6 seconds, we will find the area under the graph between x = 4 and x = 10

We can see that the shape formed is a rectangle also shown in the given graph. So, the area of the rectangle is the Displacement of the car in the last 6 seconds

Area of the Rectangle:

From the graph, we know that the rectangle is 10 (m/s) tall and 6 (s) wide

Area of Rectangle=  length*Breadth        

replacing the values

Area = 10 (m/s) * 6 (s)

Area = 60 m

Hence, the car travelled 60 m in the last 6 seconds of the graph

Explanation:

Step one:

given dara

mass of ball m=0.kg

initial velocity u= 10 m/s

final velocity v=10m/s

Required

momentum before and after impact

the expression for momentum P

P=mv

before impact

P=mv

P1=0.5*10

P1=5(kg⋅m/s)

after impact

P=mu

P2=0.5*10

P2=5(kg⋅m/s)

change  in momentum is =P1-P2= 5-5=0

yes, momentum is conserved.

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

For the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.

Given the data in the question;

Speed of the car; [tex]v_1 = 15m/s[/tex]

Speed for the car to double its kinetic energy; [tex]v_2 = \ ?[/tex]

Using the expression for kinetic energy:

[tex]K_E = \frac{1}{2}mv^2[/tex]

Where m is the mass and v is the velocity

Now, Initial Kinetic Energy will be;

[tex]K_E_1 = \frac{1}{2}mv_1^2 \\\\K_E_1 = \frac{1}{2}*m*(15)^2\\\\K_E_1 = \frac{1}{2}*m*225\\\\K_E_1 = 112.5*m[/tex]

For the kinetic energy to become double

[tex]K_E_2 = 2 * K_E_1\\\\\frac{1}{2}mv_2^2 = 2 * ( 112.5 * m)\\\\\frac{1}{2}mv_2^2 = 2m( 112.5)\\\\v_2^2 = 4( 112.5)\\\\v_2^2 = 450\\\\v_2 = \sqrt{450}\\\\v_2 = 21.21m/s[/tex]

Therefore, for the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.

Learn more: https://brainly.com/question/999862

Answer:

one time i was one the flat ground at my aunts house then we went on a hike so i brought my bike it had just rained that day so it was kinda muddy so there was sticks everywhere.i was riding up hill and noticed that it was very hard,then i rode down hill and it was much better

Explanation:

Correct question is;

In an RC parallel circuit, Et = 480 V, R = 50kΩ, and XC = 47 kΩ. What is the reactive power?

Answer:

P_r = 4.9 VARs

Explanation:

We are given;

Total voltage: Et = 480 V

Resistance; R = 50kΩ = 50000 Ω

Capacitive reactance; XC = 47 kΩ = 47000 Ω

Formula for current across the capacitor is;

Et = I_c • XC

I_c = Et/XC

l_c = 480/47000

I_c = 0.01021 A

Formula for reactive power is;

P_r = (I_c)² × XC

P_r = 0.01021² × 47000

P_r = 4.9 VARs

Answer:

knee extension is the muscle function that will be difficult to perform.

Explanation:

Barb was kicked in the anterior thigh. Now, the thigh muscles performs a combined operation of moving the knee and leg and they reside in the following compartments.

- Anterior compartment which is composed of knee joint extension and thigh flexion.

- Lateral Compartment which is composed of the tensor fasciae latae, which is a tiny muscle that abducts and centrally will make the thigh to rotate.

-Medial compartment which involves thigh addiction which is rotating of the thigh around the hips.

- Posterior compartment which involves knee joint flexion and high extension.

Thus, from the different compartments listed above, we can see that the muscles that extend the knee and flex the thigh all lie in the anterior compartment of the upper leg.

Thus, we can conclude that knee extension is the muscle function that will be difficult to perform.

Answer:

125 m

Explanation:

m = 3kg

v = 50m/s

u = 0m/s

a = +g = 10m/s²

s = H = ?

using the formula,

v² = u² + 2as

50² = 0² + 2(10)(H)

2500 = 20H

H = 2500/20

H = 125m

Answer:

My worldview is that the world is a beautiful place. IT has many wonders, and many kind people. There are also very nice places, governments, tech and more.

Answer:

The initial and final states of the hydrogen atom were n=2 and n=6 respectively.

Explanation:

We must first obtain the energy of the photon;

E= hc/λ

where;

h= Plank's constant = 6.6 * 10^-34 JS

c= speed of light = 3* 10^8 m/s

λ = wavelength of light= 411 nm = 411* 10^-9 m

Substituting values;

E = 6.6 * 10^-34 * 3* 10^8 / 411* 10^-9

E = 4.8 * 10^-19 J or 3.0 eV

But ;

En = 13.6/n^2

So E = En final - En initial

3.0  = -13.6(1/n^2final - 1/n^2initial)

If we substitute n^2final = 6 and n^2 initial = 2 then the RHS becomes approximately equal to the LHS

Therefore the initial and final states of the hydrogen atom were n=2 and n=6 respectively.

Answer:

Explanation:

charge on the shell = 4πR²  x charge density

= 4 x 3.14 x 7.5² x 10⁻⁴ x 10⁻³ C

= 706.5 x 10⁻⁷ C  

electric field = k Q / d² , d is distance of point from centre

= 9 x 10⁹ x 706.5 x 10⁻⁷ / 10²

= 6358.5 N /C

= 6.358 kV / m

Answer:

Hey, wanna pair our account on Brainly so we can share the perks? https://brainly.com/invite/a88a52bd8e2ff3030b43b9056dfb032b?utm_source=invite&utm_medium=link&utm_campaign=bfp_parental_feed&utm_term

Explanation:

Hey, wanna pair our account on Brainly so we can share the perks? https://brainly.com/invite/a88a52bd8e2ff3030b43b9056dfb032b?utm_source=invite&utm_medium=link&utm_campaign=bfp_parental_feed&utm_term=parent

Answer:

a. a black hole

Explanation:

X-ray emission from the central degrees of the Milky Way Bright X-ray emission traces the coherent edge brightened shell-like feature, dubbed the northern chimney, located north of Sgr A* and characterized by a diameter of about 160 pc. On the opposite side, the southern chimney appears as a bright linear feature. Bright X-ray emission is observed at high latitude

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2 × 5

We have the final answer as

Hope this helps you

An energy of [tex]4.171\times 10^{10}[/tex] joules to move a 1000-kg object from the Earth's surface to an altitude twice the Earth's radius.

Since the object must be moved away to a distance greater than the radius of the Earth, then change in gravitational potential energy must be based on Newton's Law of Gravitation.

By the Work-Energy Theorem, the work ([tex]W[/tex]), in joules, done on the object is equal to the change in gravitational potential energy ([tex]U_{g}[/tex]), in joules:

[tex]W = U_{g}[/tex] (1)

[tex]W = -G\cdot m\cdot M\cdot \left(\frac{1}{r_{f}}-\frac{1}{r_{o}} \right)[/tex] (1b)

Where:

If we know that [tex]G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]m = 1000\,kg[/tex], [tex]M = 5.972\times 10^{24}\,kg[/tex], [tex]r_{o} = 6.371\times 10^{6}\,m[/tex] and [tex]r_{f} = 19.113\times 10^{6}\,m[/tex], then the energy required to move the object from the Earth's surface is:

[tex]W = -\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (1000\,kg)\cdot (5.972\times 10^{24}\,kg)\cdot \left[\frac{1}{19.113\times 10^{6}\,m} - \frac{1}{6.371\times 10^{6}\,m} \right][/tex][tex]W = 4.171\times 10^{10}\,J[/tex]

An energy of [tex]4.171\times 10^{10}[/tex] joules to move a 1000-kg object from the Earth's surface to an altitude twice the Earth's radius.

We kindly invite to check this question on gravitational potential energy: https://brainly.com/question/19768887

Answer:

Yes - si.

Explanation:

Answer:

yes we should use less energy

Answer:

a) the centripetal force causing the cat to turn in a circular path is due to friction between the car's tyres and the surface of the road.

b)

1) a larger centripetal force is required if the car travels faster

2) a larger centripetal force is needed when the bend is less curved.

3) when a car has more passengers, the mass of the car increases, therefore, a larger force is required to move the car.

Explanation:

The friction between the car's tire and the surface provides centripetal force and if the car travels faster, the bend is curved, or the car has more passengers it requires a larger centripetal force.

When an object is moving in a curve path then a force is acting radically in the object this force is called centripetal force, this force helps to maintain the object in the curve e.g. if a car is moving in a well, so the centripetal force is responsible, so the car is not falling. The SI unit used to represent centripetal force is Newton.

A. The friction between the car's tire and the curve surface is responsible for providing the centripetal force, and it also depends on the car's speed.

B.  If a car is traveling faster than a larger centripetal force is required to maintain the curve path of the car, means if the friction between the tire and surface decreases the centripetal force also decreases.

When the bend is less curved, the radius of the curve increase and thus require more centripetal force.

When people in the car increase then the mass of the car also increases so due to this the gravitation force is now more on the car so more centripetal force I required to maintain the curve path of the car.

To know more about Centripetal force:

https://brainly.com/question/11324711

#SPJ2

Answer:

The ability to do work

Explanation:

Energy can be defined as the ability to do work. We apply energy in basically everything we do in life, energy is needed to walk or move from one position to another, it is required to eat and do other basic things of life. The body system converts the food that is being consumed into energy, this energy can be switched from one form to another.

There are various forms of energy which include solar energy , wind energy, electrical energy, mechanical energy, kinetic energy, potential energy etc. This forms of energy can be converted from one form to anothe but cannot be destroyed.

Answer:

ability to work

Explanation:

Answer:

The acceleration of the racecar is [tex]\mathbf{11.17~m/s^2}[/tex]

Explanation:

Uniformly Accelerated Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Following the definition above, the acceleration is defined as:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:

[tex]\displaystyle a=\frac{46.1-18.5}{2.47}[/tex]

[tex]\displaystyle a=\frac{27.6}{2.47}[/tex]

[tex]a = 11.17~m/s^2[/tex]

The acceleration of the racecar is [tex]\mathbf{11.17~m/s^2}[/tex]

Answer:

108 N

Explanation:

Use Newton's second law.

F = ma

F = (90 kg) (1.2 m/s²)

F = 108 N

Explanation:

Unbalanced Forces in Action

Unbalanced forces can change the motion of an object in two ways. ... Second, when unbalanced forces act on a moving object, the velocity of the object will change. Remember that a change in velocity means a change in speed, direction or both speed and direction.

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{25}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

True

Explanation:

I am not 100% on the answer for this question but i hope it was right

Pushing is a force so that statement is true

Answer:

Its color

Explanation: I got it right

Answer:

2613.3 pa

Explanation:

p=F/A

p=ma/A

p=200×9.8/0.75

p=2613.3