A football player kicks a ball with an initial velocity of 25 m/s at an angle of 53 degrees above the horizontal. The vertical component of the initial velocity of the ball

Answer:

Production Engineering defines and works out how the product will be manufactured and/or assembled on the production line including design of packaging, ensuring the right quantity of components/products are delivered and aligned to support the speed of the production line.

Explanation:

Answer:

Production Engineers are responsible for supervising and improving production at plants and factories. They support engineering teams, draw up safety protocols, report issues to the Manager, and develop strategies to improve efficiency and profit.

Explanation:

Answer:

Displacement is how far you are between your initial and finishing position.

Distance is how far you went.

Explanation:

For example, using a baseball field... if the sides are each 100 m..

A batter runs to third base... what is his displacement and distance?

Since the batter ran to 3rd base, it means he ran 300 m to get to 3rd base but his displacement is 100 m becuase that's how far they are from home plate. (which was their starting position)

So the answer to my example above would be:

Distance: 300 m

Displacement: 100 m

I hope this helped you.

Explanation:

Hey there!

Given;

Mass of the Earth (M) = 6.0*10^24kg.

Radius of Earth (R) = 6400km = 6400*1000= 6.4*10^6.

Gravitational constant (G) = 6.67*10^-11Nm^2/kg^2.

Height from surface of Earth (h) = 350km= 3.5*10^5m

Gravity (g) = ?

We have;

[tex]g = \frac{G.M}{ {(R + h)}^{2} } [/tex]

Where "G" is gravitational constant, "M" is mass of earth, "g" is acceleration due to gravity, "h" height from surface of Earth.

Keep all values.

[tex]g = \frac{6.67 \times {10}^{ - 11} \times 6.0 \times {10}^{24} }{ (6.4 \times {10}^{6} + 3.5 \times {10}^{5} )^2} [/tex]

[tex]or \: g = \frac{40.002\times {10}^{13} }{ (6.4\times {10}^{6} + 3.5*10^5)^2} [/tex]

g = 8.7m/s^2

Therefore, gravity from distance 350km above the Earth's surface is 8.7m/s^2.

Hope it helps...

Answer:

Chuck's average speed is 60.

Answer:

diagram: see image, x-component: 84.3 N, acceleration: 4.38 m/s^2

Explanation:

(see image for further explanation)

Answer:

cookie

Explanation:

Answer:

Explanation:

14

Answer:

...........................

Answer:

Explanation:

the net force on the right left is 25 N and is directed upward

the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero

i hope this will help you

The net force on the right left is 25 N and is directed upward.

The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

By looking at both figure we get idea of net force after calculation,

The net force on the right left is 25 N and is directed upward.

The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ2

Field lines become straight and perpendicular because every point of circular loop the concentric circles become larger and larger as we move away from the wire.

Explanation:

Given that,

Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East. At first she traveled North and then East. They are perpendicular to each other.

Total path traveled = distance covered by an object

D = 7 km + 5 km = 12 km

Shortest path covered = Displacement

[tex]d=\sqrt{7^2+5^2} \\\\d=8.6\ km[/tex]

For direction :

[tex]\tan\theta=\dfrac{d_y}{d_x}\\\\\tan\theta=\dfrac{7}{5}\\\\\theta=\tan^{-1}(\dfrac{7}{5})\\\\\theta=54.46^{\circ}[/tex]

She is moving in the direction of 54.46 degrees.

Answer:

35.28m/s; 63.50m

Explanation:

Given the following data;

Time, t = 3.6 secs

Since it's a free fall, acceleration due to gravity = 9.8m/s²

Initial velocity, u = 0

To find the final velocity, we would use the first equation of motion;

[tex] V = u + at[/tex]

Substituting into the equation, we have;

[tex] V = 0 + 9.8 * 3.6[/tex]

V = 35.28m/s

Therefore, the final velocity of the penny is 35.28m/s.

To find the height, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting the values into the equation;

[tex] S = 0(3.6) + \frac {1}{2}*9.8*(3.6)^{2}[/tex]

[tex] S = 0 + 4.9*12.86[/tex]

[tex] S = 0.5 *36[/tex]

S = 63.50m

Therefore, the height of the tower is 63.50m.

Answer:

Conduction, Convection and Radiation

Explanation:

Hope this helps!

Answer:

1.Conduction.

2.Convection.

3.Radiation.

Explanation:

I'm sure it's correct

Answer:

rs 900

Explanation:

the process is given

Answer:

The musculoskeletal system involves the complex interactions of muscles, bones, and connective tissues.

When a muscle contracts, a bone will move. When a bone contracts, a muscle will move. When a ligament contracts, a tendon will move.

Answer:

A. when a muscle contracts , a bone will move

Explanation

thats the correct answer to this question on edg2021 :)

Answer:

2917.4 m/s

Explanation:

From the question given above, the following data were:

Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth

Radius (r) of the Moon = 1737 Km

Escape velocity (v) =?

Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:

Gravitational acceleration of the earth = 9.8 m/s²

Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth

= 0.25 × 9.8 = 2.45 m/s²

Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:

1 Km = 1000 m

Therefore,

1737 Km = 1737 Km × 1000 m / 1 Km

1737 Km = 1737000 m

Thus, 1737 Km is equivalent to 1737000 m

Finally, we shall determine the escape velocity of the rocket as shown below:

Gravitational acceleration of the Moon (g) = 2.45 m/s²

Radius (r) of the moon = 1737000 m

Escape velocity (v) =?

v = √2gr

v = √(2 × 2.45 × 1737000)

v = √8511300

v = 2917.4 m/s

Thus, the escape velocity is 2917.4 m/s

Answer:

Total distance = 6.5 km

Explanation:

Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.

Then the distance covered can be calculated by adding the vectors in the direction given.

Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km

Total distance = 6.5 km

If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.

Answer:

a) t = 14.2 s ,  v = -92 m / s , b) v = - 59.16 m / s ,   t = 0.916 s

c)  t = 7.75 s ,   x = 387.5 m

d) t = 10.64 s , x = 463.9 m ,   v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

          y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

         0 = y₀ + v₀t - ½ g t²

         ½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

         t² - 10 t - 60 = 0

         t = [10 ±√ (10² + 4 60)] / 2

         t = [10 ± 18.4] / 2

         t₁ = 14.2 s

         t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

         v = v₀ - g t

         v = 50 - 10 14.2

         v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

    v² = v₀² - 2g (y-y₀)

    v² = 50 2 - 2 10 ((0- 300)

    v² = 3500

    v = + - 59.16 m / s

as the body is going down the correct sign is the negative

    v = - 59.16 m / s

the time it takes to arrive is

        v = v₀ - g t

        t = (v₀ - v) / g

        t = (-50 + 59.16) / 10

        t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

         y = y₀ + v₀ t - ½ g t²

         0 = 300 + 0 - ½ 10 t²

         t = √ (2 300/10)

         t = 7.75 s

the horizontal displacement at this time is

        x = v₀ₓ t

        x = 50 7.75

        x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

      v₀ₓ = v₀ cos 30

      [tex]v_{oy}[/tex] = v₀ sin 30

       v₀ₓ = 50 cos 30 = 43.3 m / s

       v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

     y = y₀ + v_{oy} t - ½ g t²

     0 = y₀ + v_{oy} t - ½ g t²

     0 = 300 + 25 t - ½ 10 t²

     t² - 5t - 60 = 0

   we solve the second degree equation

     t = [5 ±√ (5² + 4 60)] / 2

     t = [5 ± 16.28] / 2

     t₁ = 10.64 s

     t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

       x = v₀ₓ t

       x = 43.6 10.64

       x = 463.9 m

the ground speed is

      v_{y} = [tex]v_{oy}[/tex] - g t

      v_{y} = 25 - 10 10.64

      v_{y} = -81.4 m / s

speed is

       v = √ (v₀ₓ² + v_{y}²)

       v = √ (43.3² + 81.4²)

       v = 92.2 m / s

Answer:

280N

Explanation:

f = mass x acceleration

Answer:

True

Explanation:

Explanation:

s = ut + 1/2 a t^2

200 = 0 * 6 + 1/2 * a * (6)^2

200 = 1/2 * a * 36

200 = 18 a

a = 200/18

a= 11.1m/sec^2

v = u + at

v = 0 + 11.1 * 6

v = 66.6m/s

hope it helps you

Answer: C.) Efficiency

Explanation: Edge 2020 good luck ^__^

Answer:

i think its b

Explanation:

Answer:

The answer is C

Explanation:

Answer:

its false for sure, its water that becomes to glucose

The ship will speed up while the engine is firing.

Whatever speed it has when the engine cuts off, it will continue at that speed (and in a straight line) from then on, because there's no force acting on it, so it can't have any acceleration.

That's the 3rd choice.

Answer:

If the car is initially travelling at u m/s, then the stopping distance d m travelled by ... the speed of the car at the instant the brakes are applied. ... Common usage will force us to depart from this later in the notes. ... The history of these equations is not absolutely clear, but we do have some ... Newton (1642–1727) and Leibniz.

Explanation:

hope this helped

Answer:

Explanation:

Step one:

given data

initial speed u= 5m/s

time t= 3seconds

acceleration due to gravity g= 9.8m/s^2

Required:

the final velocity v

Step two:

applying the first equation of motion

v=u+gt-----------we used + because the ball is falling with gravity

v=5+9.8*3

v=5+29.4

v=34.4

The final velocity is 34.4m/s

Answer:

-34.4

Explanation:

the person above had the right approach but it would be negative as it is in a downwards motion

Answer:

so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)

Explanation:

(formula, idk it is wrong or right)   °C =°F - 32 then / 1.8000

44°F =  6.6666666667°C

-56°F = -48.888888889°C

So, if u want whole number as the answer

it is something like 6.6666666667°C +  48.888888889°C = 55.5555555557 °C

so, so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)