A flywheel having constant angular acceleration requires 4.70 s to rotate through 164 rad . Its angular velocity at the end of this time is 101 rad/s . Find the angular velocity at the beginning of the 4.70 s interval. Find the angular acceleration of the flywheel.

Answer:

lol

Explanation:

From the diagram, the angular speed will increase clockwise, the sign of the angular acceleration will be negative and the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative. The correct answer is option B

Given that two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Counterclockwise is considered the positive rotational direction.

If m1 is 24 kilograms, m2 is 12 kilograms, and mbar is 10 kilograms, The moment of object m1 will be equal to the moment of object m2 without the Mbar

Let assume that the length L of the seesaw is 9 cm.

Anticlockwise moment = 24 x 9/3 = 72Nm

Clockwise moment = 12 x 2(9/3) = 72 Nm

With the consideration of mass of the bar Mbar, this will add to clockwise moment of the seesaw.

Therefore, the direction of rotation will be clockwise direction.

Angular acceleration is positive when object is speeding up and negative when slowing down. Also, angular acceleration is positive when speed increases in an anticlockwise direction and negative when speed increases in the clockwise direction.

From the diagram, since the angular speed increase clockwise, the sign of the angular acceleration will be negative.

We can conclude that the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative.

The correct answer is option B

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[tex] \large★·.·´¯`·.·★ {Answer}★·.·´¯`·.·★[/tex]

As we know that Kinetic Energy is the Energy that is possessed by a moving object. and if the object is at rest then it doesn't have velocity therefore there is no kinetic Energy.

In the numerical terms we can express it as : -

[tex]꧁  \:  \large \frak{Eternal \:  Being } \: ꧂[/tex]

20 seconds

Explanation:

Let [tex]x_a[/tex] be the distance traveled by the accelerating car and [tex]x_c[/tex] be the distance traveled by the car moving with a constant velocity. When they cover the same distance, we can write

[tex]x_a = x_c \Rightarrow v_{0a}t + \frac{1}{2}at^2 = v_ct[/tex]

where [tex]v_c[/tex] is the velocity of car moving at a constant rate and a is the acceleration of the accelerating car. Since the accelerating car started from rest, then [tex]v_{0a}[/tex] is zero so our equation above simplifies to

[tex]\frac{1}{2}at^2 = v_ct[/tex]

Note that the variable t cancels out so solving for t, we get

[tex]\frac{1}{2}at = v_c \Rightarrow t = \dfrac{2v_c}{a}[/tex]

Plugging in the given values,

[tex]t = \dfrac{2(20\:\text{m/s})}{2\:\text{m/s}^2} = 20\:\text{s}[/tex]

Answer:

200J

Explanation:

work done = force x distance

                  = 20 x 10

                  = 200J

Answer:

5 m/s

Explanation:

5000/1000=5 m/s

:))

Answer:

C

Explanation:

Pls brainliest

Answer:

I think the answer is (A)...

Hope this helps!

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

Answer:

im pretty sure the answer is C

Answer:

A straight wire in a magnetic field experiences a force of 0.022 N when the current in the wire is 1.1 A. The current in the wire is changed ...

1 answer

·

Top answer:

The magnetic force that acts on the wire in the first case can be written as

Explanation:

The pressure dropped by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.

Using the attached map below, in the morning of November 9, the pressure situated at the storm's center = 1000 MB isobar located at the center.

Meanwhile, on November 11, 0000z the pressure situated at the storm's center = 976 MB isobar  

The difference in this pressure is regarded as the pressure drop in the storm's center and it is determined as follows;

= 1000 MB - 976 MB

= 24 MB

Therefore, we can conclude that the pressure drop by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.

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Hi there!

We can use the equation:

d = v₀t + 1/2at²

Where:

v₀ = initial velocity downward

a = acceleration due to gravity

t = time

Plug in given values:

d = 4(12) + 1/2(9.8)(12²)

d = 48 + 705.6 = 753.6 m

Answer:

Explanation:

The answer:

https://www.chegg.com/homework-help/questions-and-answers/race-car-starting-rest-travels-around-circular-turn-radius-247-m-certain-instant-car-still-q402991

Total acceleration of car is 148.31 m/s².

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Given parameters:

Radius of the circular path: r = 22.5 m.

Angular speed: ω = 0.541 rad/s.

So, centripetal acceleration; α = ω²r = (0.541)² × 22.5 m/s² = 6.58 m/s².

Tangential acceleration: [tex]\alpha_t[/tex] = αr = 6.58 × 22.5 = 148.16 m/s².

Hence, total acceleration = √(α² + [tex]\alpha_t[/tex]²) = √(6.58² +148.16²) = 148.31 m/s².

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In 60 minutes or 3600 seconds, the tip of the minute hand traverses the circumference of a circle with radius 3.00 cm, so it moves with a tangential speed of

(3.00 cm)/(3600 s) ≈ 0.00083 cm/s = 8.3 μm/s

Answer:

A) 58 km

B) 30 mins

Explanation:

In pic details

graph in pic

Answer:

The speed of sound varies with the material in which the waves travel.

Explanation:

knowledge and research

It can be concluded as per the given table that the speed of sound varies with the material in which the waves travel. The correct option is A.

Speed is the pace at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

It has a dimension of time-distance. As a result, the fundamental unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.

According to the given table, it can be inferred that the material in which the waves travel affects the speed of sound.

Thus, the correct option is A.

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Answer:

In space we feel weightlessness because the earth's gravity has less effect on us. The Earth's gravitational attraction at those altitudes is only about 11% less than it is at the Earth's surface. If you had a ladder that could reach as high as the shuttle's orbit, your weight would be 11% less at the top.

Explanation:

Hope this helps:)

Answer:

Option c.

Explanation:

Answer:

Heat Loss = 5 kg * 700 deg K * 220 J / (kg*deg K) = 7.70E5 J

Since there are 4.186 J/cal

Heat Loss = 7.70E5J / 4.186 J/cal = 1.84E5 cal

Heat Gain = 2000 g * 85 deg K / cal / (deg K g) + M * 540 cal/g

Heat Gain = 1.70E5 cal + M * 540 cal/g

M = (1.84 - 1.70) E5 g / 540

25.9 g

25.9 g or 25.9 cm^3 or .0259 L   of water will boil away

Answer:

$13.31

Explanation:

We know that the bill comes to $93.17 and that 7 people will split the bill equally

We can just use the equation

bill = $93.17/7

bill = $13.31

Answer:

Cement, iron, and steel all work great!

Answer:

v down exponenet 1 brainlest

Explanation:

Answer:

v0 [vee nought] is the initial velocity when time=0

Answer:

14. scolded

15. supporter

16. i am not sure but I think it is removes

17. comfortable

18. outdated

19. drink

20. it can be fantastic or wealthy

Answer:

14. Reicon's parents admonished him for breaking their antique collection,

15. I am an advocate of anti-corruption movement in the country.

16. The hotel abolishes its rice-all-you-can policy to avoid wastage of food.

17. The country has a very tropical climate where it only has dry and wet

seasons similar to other countries in Southeast Asia

18. The obsolete books and other references in the library resulted to the

removal in the shelves and inventory.

19. Beverages, such as juices, milk, beers and sodas, have increased in,due to low supply and importation issues.

20. The luxurious life of my cousin in an exclusive subdivision in Ta makes me inspired to dream and work hard for me to escape this unp.

Answer:Climate change, emerging diseases, and increased exposure to ultraviolet radiation (due to ozone depletion) are all additional factors that could be contributing to falling amphibian populations. ... Instead, amphibians are disappearing thanks to a complex mixture of factors, including: Alien Specie

Explanation:

just look it up........

Answer:

Explanation:

20 n is an unknown amount

If that is supposed to be 20 N(ewtons)

then W = Fd = 20(15) = 300 J

Answer: it will be 300 newton meters

Explanation:

The distance r between the pions when the criteria are satisfied is 1.45 × 10⁻¹⁶ m

If we consider the potential energy (U) between the pions, then (U) can be expressed as:

[tex]\mathbf{U = \dfrac{kq^2}{r} ---- (1)}[/tex]

Given that at some instance, the potential energy becomes negligible compared to the final K.E.

As such the conservation of the total energy in the system can be given as:

Again, if we consider the ratio of the potential energy to the kinetic energy to be about 0.01, then:

[tex]\mathbf{\dfrac{U}{K}= 0.01} \\ \\ \mathbf{U = 0.01 K----(2)}[/tex]

∴

Equating both equations (1) and (2) together, we have:

[tex]\mathbf{\dfrac{kq^2}{r} = 0.01 K}[/tex]

[tex]\mathbf{\dfrac{kq^2}{r} = 0.01 \Bigg [ m_{o \pi}c^2 \Big [\dfrac{1}{\sqrt{1 - \dfrac{v_{\pi}^2}{c^2} }} \Big ] \Bigg] }[/tex]

[tex]\mathbf{r =\dfrac{kq^2}{ 0.01 \Bigg [ m_{o \pi}c^2 \Big [\dfrac{1}{\sqrt{1 - \dfrac{v_{\pi}^2}{c^2} }} \Big ] \Bigg] }}[/tex]

where:

Replacing their values in the  above equation, the distance (r) between the pions is calculated as:

[tex]\mathbf{r =\dfrac{(9\times 10^9 \ N.m^2/C^2) (1.6022 \times 10^{-19} \ C)^2}{ 0.01 \Bigg [ (2.5 \times 10^{-28\ kg } )\times (3\times 10^8 \ m/s)^2 \Big [\dfrac{1}{\sqrt{1 - \dfrac{(2.97 \times 10^8 \ m/s)^2}{(3 \times 10^8 \ m/s)^2} }} \Big ] \Bigg] }}[/tex]

distance (r) = 1.45 × 10⁻¹⁶ m

Therefore, we can conclude that the distance r between the pions when the criteria are satisfied is 1.45 × 10⁻¹⁶ m

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