The magnitude of the magnetic field at the center of the loop 6.28 × 10⁻⁵ T.
A magnetic field is a vector subject that describes the magnetic effect on moving electric charges, electric currents, and magnetic materials. A transferring price in a magnetic area stories a pressure perpendicular to its very own pace and to the magnetic discipline.
calculation:-
Given;
Number of turns n = 17 turns
radius = 11 cm = 0.11m
current i = 0.58 A
Magnetic field at the centre of the loop is
B = μ₀nI//2r
B = 4π × 10⁻⁷ × 17 × 0.58 / 2× 0.11
= 628.4 × 10⁻⁷ T
= 6.28 × 10⁻⁵ T
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric-powered currents, and magnetic substances. A transferring rate in a magnetic field story a pressure perpendicular to its own velocity and to the magnetic area.
The magnetic field is the place around a magnet wherein the impact of magnetism is felt. We use the magnetic discipline as a tool to explain how the magnetic force is shipped in the area around and inside something magnetic in nature.
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The electrochemical gradient that determines how a charged ion will move through a permeable membrane depends upon the electrical forces acting on that ion the difference in concentration of that ion on either side of the membrane the ratio between the charge on the ion and its atomic mass athe combined effects of electrical forces and concentration differences across the membrane Allof the choices for this question are correct
The combined effects of electrical forces and concentration differences across the membrane.
Since there are less positive ions within the cell due to the ion gradient, the interior is negative in comparison to the exterior forces. The ensuing membrane potential favors positively charged ions entering the cell and negatively charged ions exiting the cell. A combination of a concentration gradient and an electrical field gradient, the electrochemical gradient controls the direction in which ions will flow through an open ion channel. These two gradients may be taken into account individually. Energy can be released when the ions return down their electrochemical gradients, which primary active transport creates. The energy stored in these gradients is used in secondary active transport to move other materials against their own gradients.
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A coil 4.40 cm radius, containing 470 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×10−2 T/s )t+( 2.90×10−5 T/s4 )t4. The coil is connected to a 530-Ω resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.
Part A
Find the magnitude of the induced emf in the coil as a function of time.
E= 1.09×10−2 V +( 1.06×10−4 V/s3 )t3
E= 3.43×10−2 V +( 8.29×10−5 V/s3 )t3
E= 3.43×10−2 V +( 3.32×10−4 V/s3 )t3
E= 1.09×10−2 V +( 3.32×10−4 V/s3 )t3
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Correct
Part B
What is the current in the resistor at time t0 = 4.50 s ?
I =
The current in the resistor at time 4.50 s is 1.2179 X 10⁻⁴ A and the magnitude of induced EMF in the coil is (3.43 × 10⁻² V ) + ( 3.32 × 10⁻⁴ V/s³) t³.
Number of turns of coil = N = 470
Radius of the coil = R = 4.40 cm = 0.044 m
Magnetic field varying according to time = B = ( 1.20×10⁻² T/s )t +(2.90×10⁻⁵ T/s⁴ )t⁴
Resistance of the resistor = 530 Ω
Part A :
The flux over the coil is = φ =
= φ = nBA
= φ = 470 X B X (π X 0.044)
= φ = 2.85 (( 1.20 × 10⁻² T/s )t +(2.90×10⁻⁵ T/s⁴ )t⁴)
The magnitude of EMF is = E =
= E = dφ / dt
= E = 2.85 (1.20 × 10⁻² + 11.60 × 10⁻⁵ t³)
= E = (3.43 × 10⁻² V ) + ( 3.32 × 10⁻⁴ V/s³) t³
Part B:
The current in the coil = I =
= I = E / R
= I = (3.43 × 10⁻² V ) + ( 3.32 × 10⁻⁴ V/s³) t³ / 530
= I = 1.2179 X 10⁻⁴ A
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If you were to travel at a speed close to the speed of light, you could notice that your own.
As per the special theory of relativity, if the body moves with the speed of light, then the mass of the body increases, and the time decreases.
What happens if you travel close to the speed of light ?First off, reaching the speed of light causes your mass to expand infinity-times, which causes you to slow down. The more mass you have, the faster you move, according to relativity. Driving down a freeway on Earth functions the same way.
We wouldn't even be able to recognise our surroundings at close to light speed. Similarly, the Doppler effect would make things so bright that we couldn't tell what they were at all.
A thing would have infinite mass if it ever managed to travel faster than light. The energy needed to move the object would then have to be infinite as well, which is impossible.
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The student decides to build a model transformer.
The transformer is a step-up transformer which doubles the input voltage.
Describe how they could build this step-up transformer in a science laboratory.
Answer:
hhh
Explanation:
3. What photonic energy would be required to move an electron from energy level:
a.
1 to 5?
b.
1 to 3?
c.
d.
e.
2 to 3?
2 to 4?
2 to 6?
Answer:
Energy of nth orbit of H-atom, E
n
=−
n
2
13.6
eV
∴ ΔE=E
5
−E
1
=−13.6(
5
2
1
−
1
2
1
) eV
∴ ΔE=13.6×
25
24
=13.056 eV
how, if at all, does the ground state energy change if these electrons are subject to a uniform magnetic eld of strength b?
The ground state energy does not change when the electrons are subject to a uniform magnetic field of strength b. This is because the ground state energy is determined only by the number of electrons and the Coulomb repulsion between them, which is not affected by the magnetic field.
What is magnetic field?
The magnetic influence on moving electric charges, pulsed electrical, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is moving through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts as well as repels other magnets. Paramagnetism, diamagnetism, as well as antiferromagnetism are three additional magnetic effects that a nonuniform magnetic field can have on "nonmagnetic" materials, though these forces are typically so minute that they can only be discovered by laboratory equipment. Electric currents, such as those found in electromagnets, as well as electric fields that change in time produce magnetic fields that surround magnetised materials.
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suppose you are on a ship in the north pacific ocean. you notice that the wind is blowing out of the west toward the east. if you look over the edge of the ship, to which direction would the net ekman transport be directed?
To south direction would the net ekman transport be directed when the wind is blowing out of the west toward the east.
When the wind is coming from the north, upwelling happens along the western coasts of the Northern Hemisphere because the net transport of near-surface water is away from the shore. Along the eastern shores of the Northern Hemisphere, winds from the south cause upwelling. Ekman transport occurs when wind-induced friction forces on ocean surface waters have an impact. The top 10-100 meters of the water column are pulled along by the friction force that the wind creates as it blows on the ocean's surface.
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in an air-free chamber, a pebble is thrown horizontally, and at the same instant a second pebble is dropped from the same height. which pebble is traveling faster when it reaches the ground? responses
They hit at the same time.
Correct answer is C.
What happens to velocity when a ball is thrown horizontally?
Gravity produces a downward vertical acceleration with a magnitude of 9.8 m/s/s, but a projectile's horizontal velocity is constant (a value that never changes). The vertical velocity of a projectile varies by 9.8 m/s per second and is independent of its horizontal motion.
When a ball is thrown horizontally and another is dropped which will be faster?
Since both balls experienced the same acceleration, their time to reach the ground should have been the same. same vertical speed, thus. It goes without saying that a ball thrown horizontally will move quicker.
What is Acceleration?
Acceleration is the term used to describe how quickly a velocity varies over time.
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I understand that the question you are looking for
In an air-free chamber, a pebble is thrown horizontally, and at the same instant a second pebble is dropped from the same height. which pebble is traveling faster when it reaches the ground?
A) The thrown pebble hits first.
B) The dropped pebble hits first.
C) They hit at the same time.
D) We cannot tell without knowing which pebble is heavier.
a car is traveling at 104 km/h when the driver sees an accident 80 m ahead and slams on the brakes. what minimum constant deceleration is required to stop the car in time to avoid a pileup? (round your answer to two decimal places.)
Answer:
below
Explanation:
104 km/hr = 104 000 / 3600 = 28.889 m/s
average velocity = 28.9 / 2 = 14.44 m/s
80 m / 14.4 m/s = 5.538 seconds to stop
vf = 0 = vo + at
= 28.9 + a (5.538) shows a = - 5.22 m/s^2
a puuck of mass m pslides across a horizontal surafe cand collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations ap physics
surafe cand collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations with angular velocity ω=MpVpL/(1/12 ML²+MpL²)
The moment of inertia of a rod rotated about one end is 1/12 ML².
The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.
Write the expression of the conservation of the angular momentum.
.L1=L2
MpVpL=(1/12 ML²+MpL²)ω
ω=MpVpL/(1/12 ML²+MpL²)
Thus, the angular velocity is ω=MpVpL/(1/12 ML²+MpL²)
The rotational axis is the direction in which the angular velocity is moving. The angular velocity of an object rotating counterclockwise is along the axis of rotation, away from you. The angular velocity of an object rotating counterclockwise points in your direction along the axis of rotation.
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The average kinetic energy of gas molecules is ________ proportional to the absolute temperature.
The average Kinetic energy of the molecules of a gas is directly proportional to the absolute temperature.
How is K.E proportional to absolute temperature?We know that Kinetic energy is given by the equation ,
[tex]K = \frac{1}{2} mv^{2}[/tex]
where ,
K = kinetic energy
m = mass
v = velocity
Since the square of a particle's velocity is precisely proportional to the kinetic energy of a gas, kinetic energy likewise rises when temperature rises.As a result, the relationship between a gas's kinetic energy and absolute temperature is linear.The kinetic energy of the gas molecules increases as the temperature rises, increasing their rate of motion.The speed of the gas molecules' motion, or their kinetic energy, falls as the temperature drops.A gas's average molecular kinetic energy is inversely related to its absolute temperature.What is absolute temperature?The Kelvin scale, where 0 represents absolute zero, is used to measure absolute temperature. The temperature at which matter's particles move the least and cannot cool down is known as the zero point (minimum energy). A thermodynamic temperature reading does not include a degree symbol because it is "absolute" in nature.
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the filament of a light bulb has a temperature of 2580oc and radiates 60 w of power. the emissivity of the filament is 0.36. what is the surface area of the filament?
The surface area of the filament of a light bulb is 0.159×10⁻⁴m².Surface area is inversely to emissivity and directly proportional to power.
Every body in this universe emits some radiations whether it will be large or small.
We know that surface area of filament of bulb=Power radiated by the body/Emissivity of the body, or
=>A=P/I
Now, Power radiated by the body is given(P)=σAT⁴,where
σ is Stefan constant having value 5.67040×10⁻⁸ w/m²-K⁴.
A is the surface area
and T is the temperature of body.
Now, temperature is given in degree celsius.
So, on converting temperature into kelvin, we get
K=C+273
=>K=2580+273
=>K=2853Kelvin
Value of T⁴ is =(2853)⁴ =(8139609×8139609)K⁴
On putting values of power, area and temperature, we get
=>A=P/σT⁴
=>A=60 / [(5.67040×10⁻⁸)×(8139609×8139609)
=>A=60/(5.67040×10⁻⁸)×(66.21×10¹²)
=>A=60/375.48×10⁴
=>A=0.159×10⁻⁴m²
Hence, surface area is 0.159×10⁻⁴m².
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light that is incident upon the eye is refracted several times before it reaches the retina. as light passes through the eye, at which boundary does the majority of the overall refraction occur?
Eye refraction is the dimension of the specified energy for a person’s eyeglasses or touch lenses. This is calculated through a refraction test (additionally called a vision test).
Where and how refraction occurs maximum?
Most of the refraction takes place on the outer floor of cornea whilst mild enters the attention. Refraction is described as bending of mild from its authentic direction whilst mild travels from one medium to some other. Refraction additionally relies upon at the refractive index of the medium. More the distinction in refractive index of mediums, extra might be the refraction. So while mild enters the attention maximum distinction in refractive index is gift among the air and outer floor of cornea. Here most refraction takes place. Whereas the internal components of the attention, the distinction of refractive index isn't always plenty in comparison to that of air.
Around 80% of general refraction takes place on the cornea and ultimate 20% takes place inner the attention. Since it's far a herbal phenomena, refraction of mild can not be stopped. The eye is likewise full of aqueous humor which additionally performs a essential position for refraction. There is any other component in the attention which plays refraction is the lens. The lens converges mild rays to retina to shape an image. The quantity of refraction right here continues to be much less than on the cornea.
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What is the energy, in J, of light that must be absorbed by a hydrogen atom to transition an electron from n = 3 to n = 6? Submit an answer to three signficant figures.
It takes [tex]1.815 * 10^{-19}[/tex] Joules of energy for a hydrogen atom to transition an electron from n=3 to n=6.
Energy absorbed by photon (eV)
[tex]E = 13.6 Z^{2} ( \frac{1}{n_{1} ^{2} } -\frac{1}{n_{2} ^{2} } )[/tex]
where Z is the atomic number
[tex]n_{1}[/tex] lower energy state
[tex]n_{2}[/tex] higher energy state
[tex]E =13.6* 1^{2} ( \frac{1}{3 ^{2} } -\frac{1}{6 ^{2} } )\\\\E = 13.6 (\frac{1}{9} -\frac{1}{36} )= \frac{13.6 *3}{36}[/tex]
E = 1.133 eV
To convert energy into J from eV
Multiply it by [tex]1.602 * 10^{-19}[/tex]
E = [tex]1.133 *1.602 * 10^{-19}[/tex]
E = [tex]1.815 * 10^{-19}[/tex] J
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what is the approximate age of the universe indicated by that erroneous value of h0 ? express your answer in years to one significant figure.
With the Hubble's constant H₀, the estimated age of the universe would be:
T = 8,332,452,617.49 years.
How to get the age of the universe?
We know that the age of the universe is something near to the time the galaxies needed to reach their current distance:
T = D/V
And by Hubble's law, we know that:
V = H₀*D
Then we can write:
T = D/(H₀*D) = 1/H₀
So, we can say that the age of the universe is something near the inverse of Hubble's constant.
Then we have
T = 1/(36 km/s*Mly) = (1/36) s*Mly/km
Now we need to perform the correspondent change of units.
1 Mly = 1 million light-years
Such that:
1 ly = 9.461*10^12 km
Then 1 million light-years over km is equal to:
1 Mly/km = 1,000,000*(9.461*10^12 km)/km = 9.461*10^18
Then we can replace it:
T = (1/36) s*Mly/km = (1/36)*9.461*10^18 s
T = 2.628*10^17 s
This is the age in seconds, but we want it in years.
We know that:
1 year = 3.154*10^7 s
Then to change the units, we compute:
T = (2.628*10^17 s/3.154*10^7 s)* 1 yea
T = 8,332,452,617.49 years.
Therefore, the age of universe according to Hubble's constant will be 8,332,452,617.49 years.
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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Suppose that Hubble's constant were H0 = 36 km/s/Mly (which is not its actual value). What would the approximate age of the universe be in that case? Express your answer in years to two significant figures.]
in the past, asteroids striking the earth have produced disastrous results. if we discovered an asteroid on a collision course with the earth, we could, in principle, deflect it and avoid an impact by focusing a laser on the surface. intense surface heating from the laser could cause surface material to be ejected into space at high speed.
By focusing a laser on the surface of a asteroid, the intense surface heating from the laser could cause surface material to be ejected into space at high speed due to change in the momentum
Since the surface material is ejected into space at high speed, it has significant momentum. And since the asteroid and all of its component are considered as an isolated system, the total momentum is conserved according to law of conservation of momentum.
So, as the surface material is ejected with momentum, this causes a change in the momentum of the asteroid in the opposite direction. This change reduces the speed of the asteroid gradually decreasing its momentum, or it gives the asteroid a speed in a different direction causing it to be deflected from its path.
The given question is incomplete. The complete question is:
In the past, asteroids striking the earth have produced disastrous results. If we discovered the asteroid on a collision course with the earth, we could, in principle, deflect it and avoid an impact by focusing a laser on the surface. Intense surface heating from the laser could cause surface material to be ejected into space at high speed. How would this deflect the asteroid?
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A wiring device (switch or receptacle) is mounted on one yoke (strap). The number of conductors to be deducted from the maximum permitted conductor fill for the box as indicated in 314.16(B) is: _________two conductors
For a wiring device installed on a single yoke (strap), two conductors must be subtracted from the maximum permissible conductor fill.Section 314.16(B) of the National Electrical Code outlines this requirement (NEC).
A regionally adopted standard for the secure installation of electrical wiring and equipment in the United States is the National Electrical Code (NEC), often known as NFPA 70.
The National Fire Protection Organisation (NFPA), a private trade association, publishes the National Fire Code series, which includes this document.
The National Electrical Code (NEC), published by the National Fire Protection Association (NFPA®), provides guidance on how electrical equipment and systems should be installed and used in buildings and other structures in order to assist safeguard people and property from potential risks.
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Determine which the following are defined Whenever they occur denctes multivariable function and denotes vector field both of which are twice continuously differentiable on common domain_ (Select all that apply.) V . (F . Vf) V. (V x Vf) V x (V . F) V x (V x f) V x (V x F) V . (V x F)
Yes, all of these are defined whenever they occur, and they denote multivariable functions and vector fields that are twice continuously differentiable on a common domain.
What is multivariable function?
The extension with one calculus to calculus with functions of multiple variables, or the differentiation as well as integration of functions involving different variables as opposed to just one, is known as multivariable function(also recognised as multivariate calculus). Calculus with multiple variables can be seen as an introduction to more complex calculus. Check out calculus on Euclidean space for advanced calculus. The term "vector calculus" refers to the special particular instance of calculus throughout three dimensional space.
For example, V . (F . Vf) denotes a multivariable function and vector field that is twice continuously differentiable. This expression can be interpreted as the dot product of the vector V and the product of the function F and the vector field Vf.
Similarly, V x (V x f) denotes a multivariable function and vector field that is twice continuously differentiable. This expression can be interpreted as the cross product of the vector V and the cross product of the vector V and the function f.
Likewise, V x (V x F) and V . (V x F) denote multivariable functions and vector fields that are twice continuously differentiable. These expressions can be interpreted as the cross product of the vector V and the cross product of the vector V and the function F, and the dot product of the vector V and the cross product of the vector V and the function F, respectively.
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calculate the braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s
The braking distance traveled by the car is 73.5 m.
What is the braking distance of the car?The braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s at a deceleration rate of 3 m/s² is calculated as follows.
v² = u² - 2as
where;
v is the final velocity of the car, when it stops = 0u is the initial velocity of the car = 21 m/sa is the deceleration of the car = 3 m/s²s is the braking distance of the carSubstitute the given parameters and solve for the braking distance of the car as shown below.
0 = u² - 2as
2as = u²
s = (u²) / (2a)
s = (21²) / (2 x 3)
s = 73.5 m
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The complete question is below:
calculate the braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s, when the car is decelerating at 3 m/s².
A carbon atom usually has 6 protons and 6 neutrons. Carbon-14 is a type of carbon with atoms that contain 6 protons and 8 neutrons. Carbon-14 can be used to find the age of certain fossils. Carbon-14 is an example of a(n).
Carbon-14 is an example of an Isotopes.
Isotopes can be defined as variants of chemical elements that have the same number of protons and electrons but different numbers of neutrons.
In other words, isotopes are variants of elements that differ in the number of nucleons (the total number of protons and neutrons) due to the difference in the total number of neutrons in their respective nuclei.A carbon atom usually has 6 protons and 6 neutrons.
Also, Carbon-14 contains an atomic nucleus of 8 neutrons along with 6 protons.
Both the carbon atoms have the same number of protons, but different number of neutrons, hence they can be termed as the isotopes.
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describe the sizes of stars along the main sequence. what are stars like near the top of the main sequence, the middle, and the bottom
The sizes of stars Super Giant Stars, Giant Stars ,Main Sequence White Dwarf Stars .Based on their temperature, the stars are categorized, with O being the hottest and M being the coldest. O-B-A-F-G-K-M
What are stars known as?Any big, large celestial mass that is personality and produces light from its own internal renewable resources is referred to be a star. Only a very small portion of the hundreds of milliards of trillions of in the observable cosmos are visible.
Why is a star created?When light element atoms are compressed put under a lot compression allowing their nuclei to fuse, a star is created. All stars are still the consequence of an equilibrium of forces gravity pulls interstellar gas's atoms together until fusion reactions start.
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what would happen to your percent recovery of a solid on filter paper if you do not take account for the mass of the filter paper?
The percent recovery will be larger than expected.
How does a gravity filter work?The process of utilizing gravity to force liquid through a filter to remove contaminants from solutions is known as gravity filtration. Gravity and vacuum/suction filtration are the two basic types employed in laboratories. Gravity filtration is frequently employed in chemical laboratories to remove residual reactants, unacceptable side products, drying agents, and precipitates from precipitation operations. Vacuum filtration is most frequently utilized for this purpose, while it can also be used to filter out powerful compounds.Transport and attachment are two processes in the removal of suspended materials. When particles pass through the filter paper and migrate to a different location, this mode happens.It is simple to remove precipitation or solid contaminants from an organic liquid using gravity filtering.To learn more about filter, refer to
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some of the light also reflects off the surface of the water. if the incident light is initially unpolarized, the reflected light will be
Whereas if incident light is originally updates, the diffraction pattern will be slightly horizontally polarized, according to the stated assertion.
What exactly are incident and reflected light?The light that strikes the object as incident light from the source but also reflects off it is alluded to as refract. It makes no difference what the flashlight is or what you are photographing. When light strikes anything, it will always be transformed and reflected.
How does incident light behave?A portion of the light is dispersed when incident light hits a sample. Rayleigh scattering is the process wherein most of the dispersed light shares the same frequency as the incoming light. A portion of the light is dispersed around a different wavelength; this is called Raman scattering.
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A force of 5. 0 n moves a 6. 0 kg object along a rough floor at a constant speed of 2. 5 m/s. (a) how much work is done in 25 s? (b) what power is being used? (c) what force of friction is acting on the object?.
Total work done by 5N force is 312.5 J and power used is 12J/s
Speed of object = 2.5 m/s
Time the object moves = 25 s
Since no acceleration is given,
Distance = Speed * Time
Distance = 2.5 * 2.5
Distance = 6.25
i.e. Distance travelled by the block is 62.5m.
F= Force on object = 5N
Work done = Force * Displacement
W = F * S
W = 5 * 62.5
W = 312.5 J
Total work done by 5N force is 312.5 J.
We know that: Power = Work/time
i.e. Power = 312.5/25 = 12 J/s
So power being used is 12 J/s
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7. A raindrop has a mass of 0.003 kg
a) Assume the raindrop takes 15 s to reach its terminal velocity of 7 m/s. Calculate
the average acceleration of the raindrop.
b) Determine the average air resistance force on the raindrop.
(a) The average acceleration of the raindrop is 0.467 m/s².
(b) The average air resistance force on the raindrop is 1.4 x 10⁻³ N.
What is the average acceleration of the raindrop?The average acceleration of the raindrop is calculated as follows;
Mathematically, the formula for average acceleration is given as;
a = Δv/Δt = v/t
where;
v is the velocity of the raindropt is the time of motion of the raindropa = (7 m/s) / (15 s)
a = 0.467 m/s²
The average air resistance force on the raindrop is calculated as follows;
F = ma
where;
m is mass of the raindropa is the acceleration of the raindropF = 0.003 x 0.467
F = 1.4 x 10⁻³ N
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a tuning fork produces a steady 400 hz tone. when struck and held near a vibrating guitar string, twenty beats are counted in 5 seconds. what are the possible frequencies produced by the guitar string? 380 hz or 420 hz 396 hz or 404 hz 395 hz or 405 hz 400 hz click here to check your answer 12.5 pts.100% 25% try penalty
Frequency = 404 Hz
Frequency of tuning Fork V0 = 400HZ
beat frequency= 20 / 5= 4hz
= possible frequency = V0 - 4 = 396 Hz or V0 + 4 = 404 Hz
In physics, the term frequency refers back to the number of waves that skip a hard and fast factor in unit time. It also describes the number of cycles or vibrations undergone for the duration of one unit of time by using a frame in periodic motion.
Frequency is expressed in units of hertz (Hz), which is equivalent to 1 event consistent with 2d. The corresponding period is the time length of one cycle in a repeating collection of events, so the length is the reciprocal of the frequency.
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What is the fastest motion that can be measured in any frame of reference? (1 point).
Speed of light is the fastest motion that can be measured in any frame of reference.
A frame of reference is a reference point combined with a set of directions.A frame of reference is similar to the idea of a reference point. A frame of reference is defined as a reference point combined with a set of directions.Something is in motion if it is changing position. It could be a fast-moving airplane, a leaf swirling in the wind, or water trickling from a hose.For example, when you see a ball roll down a street, you can tell the ball is moving because the frame of reference is the streets, whatever may be on the side of the roads, or the Earth.To know about Frame of reference visit:
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two particles of mass m and 3m are moving with the same speed v in a vacuum at right angles with the particle of mass m moving in the x-direction and the particle of mass 3m moving in the negative y-direction. a
If the two particles are moving at the same speed in a vacuum, then their kinetic energy will be the same. The kinetic energy of a particle is given by the equation:
KE = (1/2)mv^2
Where KE is the kinetic energy of the particle, m is its mass, and v is its speed.
In this case, the kinetic energy of the particle with mass m will be:
KE = (1/2)m*v^2
And the kinetic energy of the particle with mass 3m will be:
KE = (1/2)3mv^2 = (3/2)mv^2
Since the particles have the same kinetic energy, we can set the two equations equal to each other and solve for v:
(1/2)mv^2 = (3/2)mv^2
(1/2)*v^2 = (3/2)*v^2
1/2 = 3/2
This equation does not have a valid solution, which means that the two particles cannot be moving at the same speed in a vacuum if one has a mass of m and the other has a mass of 3m.
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a sled of mass 1375 kg has four identical rockets. with all four rockets burning, the sled initial acceleration is 45.0 m/s2. assume that the force of friction opposing the motion is 450 n, what is the force exerted by the rockets?
The force exerted by the rockets is 62,325 N.
What is the force exerted by the rockets?
The force exerted by the rockets is determined by applying Newton's second law of motion.
According to Newton's second law of motion, the force exerted by an ob ject is directly proportional to the product of mass and acceleration of the object.
F(net) = ma
where;
F(net) is the net force on the objectm is the mass of the objecta is the acceleration of the objectF - Ff = ma
where;
F is the force exerted by the rocketsFf is the force of frictiona is the acceleration of the sledF - 450 = (1375 x 45)
F = 61,875 + 450
F = 62,325 N
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A red wagon with a mass of 7\, {\text{kg}}7kg7, start text, k, g, end text is moving with a velocity of 4\,\dfrac{\text{m}}{\text{s}}4
s
m
4, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction straight toward a blue wagon at rest. The red wagon’s mass is 777 times the mass of the blue wagon. The final velocity of the red wagon is 3\,\dfrac{\text{m}}{\text{s}}3
s
m
3, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction .
What is the velocity of the blue wagon immediately after the red wagon collides with it?
The velocity of the blue wagon immediately after the red wagon collides with it is 7 m/s
How do I determine the velocity of the blue wagon after collision.?From the law of conservation of linear momentum, we understood that momentum before collision is equal to momentum after collision as shown below:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where
m₁ and m₂ are the masses of the two objectsu₁ and u₂ are the initial velocities of the two objectsv₁ and v₂ are the final velocities of the two objectsWith the above formula, we can obtain the velocity of the blue wagon as follow:
Mass of red wagon (m₁) = 7 KgInitial velocity of red wagon (u₁) = 4 m/sMass of blue wagon (m₂) = m₁ / 7 = 7 / 7 = 1 KgFinal velocity of red wagon (v₁) = 3 m/sFinal velocity of red wagon (v₂) = ?m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(7 × 4) + (1 × 0) = (7 × 3) + (1 × v₂)
28 = 21 + v₂
Collect like terms
v₂ = 28 -21
v₂ = 7 m/s
Thus, the velocity of the blue wagon after collision is 7 m/s
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