A first order reaction is 25% completed in 1h minutes. Calculate the time required for its 50% completion.

Answer:

the plot is about a crocodile who lives in a river.....

Explanation:

It is about a crocodile who lives in a river. He becomes friends with a monkey that lives on a tree on the river bank. Consequently, the monkey shares the fruits of the tree with his friend, the crocodile. Further, the crocodile takes a share for his wife.

it is D for sure im good with history

Answer: D

Explanation: Its just s that guy ca get brainlist :D

Answer:

the answer is a....,.......

Answer:

Gravity can pull soil, mud, and rocks down cliffs and hillsides.

Explanation:

Gravity is responsible for erosion by flowing water and glaciers. But gravity also causes erosion directly. This type of erosion and deposition is called mass wasting.

Answer:

Explanation:

Explanation:

This question is not feasible. There is no way to calculate the energy needed because the question is missing the final temperature

Question

what is the force exerted on a selectively permeable membrane beacuse water has moved from an area of higher concentration to an area of Lower concentration of water?

Answer

OSMOSIS

Explanation

Osmosis: This is the hydrostatic force acting to equalize the concentration of water on both sides of the membrane that is impermeable to substances dissolved in that water. Water will move along its concentration gradient.

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Answer: It is identified with color, texture, boiling point, melting point and freezing point

Explanation:

The rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium.

A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.

For a system subject to two opposite forces, the following exists;

Thus, we can conclude that the rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.

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Answer: part a is e

part b a  

Explanation:

I HOPE THIS HELPS

Answer:

Explanation:

To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).

Answer:

F = 0 N

Explanation:

The problem does not talk about any acceleration. We can just assume it always moves at a constant speed so the resultant force will be 0 newtons. Of course you could say that it accelerates for a certain amount of time, as the wind blows, but the problem doesn't tell us when to calculate the resultant force (if during the acceleration or after) + we don't have the mass of the jet.

42.9°

Explanation:

Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:

[tex]x:\;\;\;\;F - mg\sin{\theta} = 0\;\;\;\;[/tex]

[tex]\Rightarrow mg\sin{\theta} = F[/tex]

Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at [tex]\theta.[/tex] Solving for the angle, we get

[tex]\sin{\theta} = \dfrac{F}{mg}[/tex]

or

[tex]\theta = \sin^{-1}\left(\dfrac{F}{mg}\right)[/tex]

[tex]\;\;\;= \sin^{-1}\left[\dfrac{34\:\text{N}}{(5.1\:\text{kg})(9.8\:\text{m/s}^2)}\right][/tex]

[tex]\;\;\;=42.9°[/tex]

According to the law of superposition, the statement 'it is expected to find dinosaur bones below the K-T boundary but not above'' is TRUE. This boundary separates the Cretaceous and Tertiary periods.

The law of superposition is used by paleontologists to explain a sequence of sedimentary rock layers from the oldest layer at the base to reach the surface (newer).

Moreover, the K-T boundary is a boundary that separates sediments of the Cretaceous period from the Tertiary period.

This boundary (K-T boundary) dates approximately 65 million years (Mya) ago, i.e., the period in which dinosaurs became extinct.

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Answer:

The altitude of the satellite above the surface of the Earth is 1,528.48 km.

F=rmv2=R2GmMrv2=R2GMr=GMv2R2r=(6.67259×10−11)×(5.98×1024)(6900)2×(6,370,000)2r=4,841,516.6 mr=4,841.52 km

Answer:

Explanation:

parallel capacitances add directly

Series capacitances add by reciprocal of sum of reciprocals.

Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]

Ceq = [ C ] + [C / 2] + [C / 3]

Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]

Ceq = 11C/6

Answer:

[tex]0.2\; {\rm T}[/tex], assuming that the speed of the electron stays the same.

Explanation:

Let [tex]v[/tex] denote the speed of this electron. Let [tex]q[/tex] denote the electric charge on this electron. Let [tex]m[/tex] denote the mass of this electron.

Since the path of this electron is a circle (not a helix,) this path would be in a plane normal to the magnetic field.

Let [tex]B[/tex] denote the strength of this magnetic field. The size of the magnetic force on this electron would be:

[tex]F = q\, v\, B[/tex].

Assuming that there is no other force on this electron. The net force on this electron would be [tex]F = q\, v\, B[/tex]. By Newton's Second Law of motion, the acceleration of this electron would be:

[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{q\, v\, B}{m}\end{aligned}[/tex].

On the other hand, since this electron is in a circular motion with a constant speed:

[tex]\begin{aligned} a = \frac{v^{2}}{r} \end{aligned}[/tex].

Combine the two equations to obtain a relationship between [tex]r[/tex] (radius of the path of the electron) and [tex]B[/tex] (strength of the magnetic field:)

[tex]\begin{aligned}\frac{q\, v\, B}{m} = \frac{v^{2}}{r}\end{aligned}[/tex].

Simplify to obtain:

[tex]\begin{aligned}r &= \frac{m\, v^{2}}{q\, v\, B} \\ &= \frac{m\, v}{q\, B} \\ &= \left(\frac{m\, v}{q}\right)\, \frac{1}{B}\end{aligned}[/tex].

In other words, if the speed [tex]v[/tex] of this electron stays the same, the radius [tex]r[/tex] of the path of this electron would be inversely proportional to the strength [tex]B[/tex] of the magnetic field. Doubling the radius of this path would require halving the strength of the magnetic field (to [tex]0.2\; {\rm T}[/tex].)

Answer:

Explanation:

Ignoring friction, the initial kinetic energy will convert to maximum potential energy at its highest point.

PE = KE

mgh = ½mv²

    h = v²/2g

    h = 36.4²/ (2(9.81))

    h = 67.53109...

    h = 67.53 m

Mass the air mattress support before sinking will be M = 97.2 kg

Given that

mass of mattress m=2.8 kg

Length = 2.00 m  

width =0.5 m  

The mattress can support a total weight that is equal to the weight of water that the air mattress displaces.

The volume of the air mattress will be equal to

[tex]V= (2\times 0.5\times 0.1)[/tex]

[tex]V= 0.1 m^{3}[/tex]

This volume is equal to the maximum amount of water that the mattress can displace in the water before it begins sinking.

We know the density of water is 1000 kg / m²

We can calculate the weight of the maximum amount of water that mattress will displace

[tex]V\times density of water\times g=0.1\times 1000\times 9.81=981N[/tex]

Let M represent the mass that the mattress is supporting.

The total weight of the mattress and the supported mass is:

[tex](2.8+M)\times9.81[/tex]

Setting this weight equal to the weight of the water displaced gives:

[tex](2.8+M)\times9.81=981[/tex]

[tex]2.8+M=100[/tex]

m = 97.2 kg

Hence Mass the air mattress support before sinking will be M = 97.2 kg

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[tex] \: \: \: [/tex]

[tex] \pink{false}[/tex]

Answer:

False

Explanation:

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The average momentum of Cart 1 during the entire time shown before the collision is 0.24 kgm/s.

The given parameters:

The average velocity of the cart 1 before collision is calculated as follows;

[tex]v = \frac{\Delta x}{\Delta t} \\\\v = \frac{0.55 - 0.31}{0.5 - 0} \\\\v = 0.48 \ m/s\\\\[/tex]

The average momentum of Cart 1 during the entire time shown before the collision is calculated as follows;

[tex]P = mv\\\\P = 0.5 \times 0.48\\\\P = 0.24 \ kgm/s[/tex]

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Answer:

Speed of light =m/s

wavelength = m

frequency = ?

we have

Speed = frequency × wavelength

[tex]3* 10^8[/tex] = frequency × [tex]5 * 10^{-7}[/tex]

 Frequency = [tex]\frac{3*10^8}{5*10^{-7}}=6*10^{14}[/tex]hz

Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.

First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f× λ

All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.

In this case, you know:

Replacing in the definition of propagation speed:

3×10⁸ m/s = f× 5×10⁻⁷ m

Solving:

3×10⁸ m/s ÷ 5×10⁻⁷ m= f

f= 6×10¹⁴ Hz

In summary, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.

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[tex]\huge \bf༆ Answer ༄[/tex]

The Correct choice is ~ A

A covalent bond would form because the electron would be shared so both hydrogens have a full, stable shell.

A covalent bond would form between two hydrogens because the electron would be shared so both hydrogens have a full, stable shell.

Equal shares of electrons from the two involved atoms result in the formation of a covalent bond. This sort of bonding's electron pair is known as the shared pair or bonding pair. Molecular bonds are another name for covalent bonds. The atoms will reach stability in their outer shell, analogous to the atoms of noble gases, thanks to the sharing of bonding pairs.

The simplest material with a covalent bond is the hydrogen molecule. Two hydrogen atoms, each with one electron in a 1s orbital, combine to produce it. The two electrons in the covalent bond are shared by both hydrogen atoms, and each one takes on an electron configuration like that of helium.

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Answer:

An electron tube from which all air has been removed. The vacuum ensures transparency inside the tube for electric fields and moving electrons. Most electron tubes are vacuum tubes; cathode-ray tubes, which include television picture tubes and other video display tubes, are the most widely used vacuum tubes

Explanation:

hope it help

Explanation:

Downstream: you just sum the magnitude of the velocity vectors:

3km/h + 4km/h = 7km/h

Upstream: difference of the magnitudes of the velocity vectors, in absolute value:

|3km/h - 4km/h| = 1km/h

Answer:

(a) 91 kg (2 s.f.)    (b) 22 m

Explanation:

Since it is stated that a constant horizontal force is applied to the block of ice, we know that the block of ice travels with a constant acceleration and but not with a constant velocity.

(a)

                                                   [tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2} at^{2} \\ \\ a \ = \ \displaystyle\frac{2(s \ - \ ut)}{t^{2}} \\ \\ a \ = \ \displaystyle\frac{2(11 \ - \ 0)}{5^{2}} \\ \\ a \ = \ \displaystyle\frac{22}{25} \\ \\ a \ = \ 0.88 \ \mathrm{m \ s^{-2}}[/tex]

     Subsequently,

                                                  [tex]F \ = \ ma \\ \\ m \ = \ \displaystyle\frac{F}{a} \\ \\ m \ = \ \displaystyle\frac{80 \ \mathrm{kg \ m \ s^{-2}}}{0.88 \ \mathrm{m \ s^{-2}}} \\ \\ m \ = \ 91 \mathrm{kg} \ \ \ \ \ \ (2 \ \mathrm{s.f.})[/tex]

*Note that the equations used above assume constant acceleration is being applied to the system. However, in the case of non-uniform motion, these equations will no longer be valid and in turn, calculus will be used to analyze such motions.

(b) To find the final velocity of the ice block at the end of the first 5 seconds,

                                                    [tex]v \ = \ u \ + \ at \\ \\ v \ = \ 0 \ + \ (0.88 \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \\ \\ v \ = \ 4.4 \ \mathrm{m \ s^{-1}}[/tex]

     According to Newton's First Law which states objects will remain at rest

     or in uniform motion (moving at constant velocity) unless acted upon by

     an external force. Hence, the block of ice by the end of the first 5

     seconds, experiences no acceleration (a = 0) but travels with a constant

     velocity of 4.4 [tex]m \ s^{-1}[/tex].

                                                    [tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2}at^{2} \\ \\ s \ = \ (4.4 \ \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \ + \ \displaystyle\frac{1}{2}(0)(5^{2}) \\ \\ s \ = \ 22 \ \mathrm{m}[/tex]

      Therefore, the ice block traveled 22 m in the next 5 seconds after the

      worker stops pushing it.

Explanation:

Force= mass× acceleration

Force= 4×2

= 8N

Doubling the force, 8×2= 16N

16= 4 × a

a= 16/4

= 4m/s²

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

Answer:

a

Explanation:

you will find out that an object that has more weight requires more energy to move than the one with less weight