a dog is sitting in a boat which is floating in a pond. if the dog drinks some water from the pond. then:

The first person credited with achieving fission of uranium-235 is Enrico Fermi. In 1942, Fermi and his team successfully initiated the first nuclear chain reaction in a pile of uranium and graphite at the University of Chicago as part of the Manhattan Project. This achievement led to the development of the atomic bomb.

The credit for first achieving fission of uranium-235 goes to a team of scientists led by Enrico Fermi. Fermi and his colleagues conducted an experiment in a converted squash court beneath the bleachers of Stagg Field at the University of Chicago on December 2, 1942. They successfully initiated the first self-sustaining nuclear chain reaction by using graphite as a moderator and uranium as fuel. The experiment was called the Chicago Pile-1, and it marked a critical moment in the development of the atomic bomb during World War II.

Fermi was an Italian physicist who fled fascist Italy in 1938 and eventually settled in the United States. He was one of the leading scientists of the Manhattan Project, the secret American-led effort to build an atomic bomb during World War II. His achievement of the first nuclear chain reaction paved the way for further advancements in nuclear technology and helped shape the course of history.

To know more about   fission of uranium- click this link -

brainly.com/question/8991357

#SPJ11

The volume of the air when released into the atmosphere would be 3.717 m³.

To determine the volume of the air when released into the atmosphere, we can use the Ideal Gas Law equation: (P1V1/T1) = (P2V2/T2), where P1, V1, and T1 represent the initial pressure, volume, and temperature respectively, and P2, V2, and T2 represent the final pressure, volume, and temperature respectively.
Given values:
P1 = 860 kPa, V1 = 0.460 m³, T1 = 291 K
P2 = 101 kPa, T2 = 303 K
We need to find V2, so we can rewrite the equation as:
V2 = (P1V1/T1) * (T2/P2)
Plugging in the values
V2 = (860 * 0.460 / 291) * (303 / 101)
V2 = 3.717 m³

Summary: When the compressed air is released into the atmosphere at 101 kPa and 303 K, it will occupy a volume of 3.717 m³.

Learn more about volume click here:

https://brainly.com/question/463363

#SPJ11

I. Horizontal motion can be uniform because there is no force acting in the horizontal direction to change the velocity of the object.

II. Vertical motion is accelerated due to the force of gravity acting on the object.

III. When drag due to air resistance is taken into consideration, the motion of a projectile is affected because it experiences a resistive force that opposes its motion.

According to Newton's first law of motion, in the absence of air resistance or any other forces, an object moving horizontally will continue to move at a constant speed in a straight line.

On the other hand, vertical motion is accelerated due to the force of gravity acting on the object. Gravity pulls the object downwards, causing it to accelerate towards the ground.

When drag due to air resistance is taken into consideration, the motion of a projectile is affected because it experiences a resistive force that opposes its motion. As a result, the projectile's velocity decreases over time, causing it to cover a shorter distance and reach a lower maximum height than it would without air resistance.

Learn more about horizontal motion here: https://brainly.com/question/29095581

#SPJ1

If you were to observe a steady stream of X-rays emitted from a central void in space, you would most likely be observing an active galactic nucleus (AGN) or a supermassive black hole.

If you were to observe a steady stream of X-rays emitted from a central void in space, you would most likely be observing an active galactic nucleus (AGN) or a supermassive black hole. AGNs are powered by the accretion of matter onto a supermassive black hole at the center of a galaxy. As matter falls into the black hole, it forms an accretion disk, generating intense gravitational forces and emitting high-energy X-rays. These X-rays can be detected by observing instruments in space, such as X-ray telescopes. The presence of a central void emitting a steady stream of X-rays indicates the presence of a highly energetic and active region associated with AGNs or supermassive black holes.

Learn more about X-rays here:

https://brainly.com/question/8611796

#SPJ11

The maximum safe speed of the sports car on the banked road is 31.3 mph.

The maximum safe speed of the car can be calculated using the formula V = sqrt(μs * g * rho * tan(theta)), where V is the maximum safe speed, μs is the coefficient of static friction between the tires and the road, g is the acceleration due to gravity, rho is the radius of curvature of the road, and theta is the angle of inclination of the banked road. Substituting the given values, we get V = sqrt(0.1 * 32.2 ft/s^2 * 500 ft * tan(30 deg)) = 31.3 mph, where acceleration due to gravity is taken 32.2ft/s^2.

To learn more about speed, click here:
https://brainly.com/question/30462853

#SPJ11

The distance from the proton when the electron comes to a stop due to the electrical interaction with the proton is approximately [tex]1.18 x 10^-10 m.[/tex]

To solve this problem, we can use Coulomb's law, which states that the force between two charged particles is given by:

[tex]F = k * q1 * q2 / r^2[/tex]

where F is the force, k is Coulomb's constant, q ₁and q₂ are the charges of the particles, and r is the distance between them.

In this case, the charges are [tex]q1 = -1.6 x 10^-19 C[/tex] (charge of the electron) and q2 = [tex]1.6 x 10^-19 C[/tex] (charge of the proton). The initial velocity of the electron is 250 m/s, and we can assume that the distance between the particles is very large compared to their sizes, so we can neglect their sizes.

The force on the electron due to the proton is given by:

[tex]F = k * q1 * q2 / r^2[/tex]

We can equate this force to the initial kinetic energy of the electron:

[tex]F = ma = 1/2 * mv^2[/tex]

where m is the mass of the electron, v is its initial velocity, and a is the acceleration due to the force.

Solving for r, we get:

[tex]r = √(k * q1 * q2 / (1/2 * m * v^2))[/tex]

Plugging in the values, we get:

r = √(([tex]9 x 10^9 N m^2/C^2[/tex]) * ([tex]1.6 x 10^-19 C)[/tex][tex]^2[/tex] / (1/2 * 9.1 x[tex]10^-31 kg *[/tex] (250 [tex]m/s)^2)[/tex])

[tex]r = 1.18 x 10^-10 m[/tex]

Therefore, the distance from the proton when the electron comes to a stop due to the electrical interaction with the proton is approximately [tex]1.18 x 10^-10 m.[/tex]

Learn more about initial velocity,

https://brainly.com/question/28395671

#SPJ4

The transverse tubule (T-tubule) system of the sarcolemma in striated muscles is an invagination of the plasma membrane that runs perpendicular to the myofibrils. The T-tubules are important in transmitting action potentials deep into the muscle fiber, allowing for synchronous contraction.

The T-tubules are closely associated with the sarcoplasmic reticulum (SR), which is a specialized smooth endoplasmic reticulum that stores calcium ions (Ca2+) and releases them upon muscle stimulation. The SR surrounds each myofibril, and the T-tubules form triads with the two SR cisternae flanking each T-tubule.

During muscle contraction, the action potential traveling down the T-tubule activates voltage-gated Ca2+ channels in the adjacent SR membrane, leading to the release of Ca2+ into the cytoplasm. The Ca2+ binds to troponin, triggering a conformational change in the thin filaments and allowing myosin to bind to actin, leading to muscle contraction.

Therefore, the close association of the T-tubule system and the SR is essential for the initiation and regulation of muscle contraction.

you know more about sarcolemma in striated muscles pls visit-

https://brainly.com/question/10898378

#SPJ11

The wires in a three conductor ribbon cable all have a diameter of 8 mils by a distance of 50 mils. -0.999 × 10⁻⁷ H/m is the mutual inductance between the generator and receptor conductors

To calculate the per unit length mutual inductance between the generator and receptor conductors in a three-conductor ribbon cable, we need to use the formula:
M = (μ₀/4π) × [(2a/π) × ln(2a/b) - 1]
Where:
μ₀ = 4π × 10⁻⁷ H/m is the permeability of free space
a = 8 mils is the radius of each conductor
b = 50 mils is the center-to-center separation distance between the conductors
Plugging in the values, we get:
M = (4π × 10⁻⁷ H/m/4π) × [(2 × 8 mils/π) × ln(2 × 8 mils/50 mils) - 1]
M = (10⁻⁷ H/m) × [0.0087 - 1]
M = -0.999 × 10⁻⁷ H/m
Therefore, the per unit length mutual inductance between the generator and receptor conductors in a three-conductor ribbon cable is approximately -0.999 × 10⁻⁷ H/m. Note that the negative sign indicates that the mutual inductance is in the opposite direction of the current flow.

Learn more about conductor here

https://brainly.com/question/30197898

#SPJ11

It is important to look up density information prior to performing a liquid-liquid extraction to ensure proper layer formation and separation.

Density information is crucial in liquid-liquid extraction because it determines the order of layer formation and the ease of separation. If two liquids of vastly different densities are mixed, they will not form distinct layers and will make separation difficult. Additionally, if the density of the solvent is not properly considered, it may cause improper layer formation and the target compound may be lost in the wrong layer.

Therefore, by knowing the density of the two liquids being used, one can accurately predict the order of layer formation and ensure a clean separation. This will help in obtaining a pure compound, improving the yield and overall success of the extraction.

Learn more about density here:

https://brainly.com/question/30568551

#SPJ11

Susan's average velocity for the entire race was 2.47 yards per second.

To find Susan's average velocity for the entire race, we need to know the total distance and the total time taken. The total distance is 50 yards, and the total time taken is the sum of the time taken for each leg of the race:

Total time = 10.01 s + 10.22 s = 20.23 s

To find the average velocity, we divide the total distance by the total time:

Average velocity = total distance / total time

Average velocity = 50 yd / 20.23 s

Average velocity = 2.47 yd/s

Note that we could also convert this to other units of velocity, such as meters per second or miles per hour, if desired.

To learn more about velocity click on,

https://brainly.com/question/18453227

#SPJ4

A 1.4 kg model rocket is launched vertically from rest, experiencing a constant thrust. In this scenario, the rocket's mass (1.4 kg) plays a crucial role in determining its acceleration due to the applied force. The constant thrust ensures that the force propelling the rocket upwards remains consistent throughout the launch phase.

This force counteracts the gravitational force acting on the rocket, enabling it to ascend vertically. As the rocket's acceleration increases, so does its velocity, allowing it to gain altitude over time.

In summary, the 1.4 kg model rocket's vertical launch is characterized by its mass and the constant thrust applied, which work together to overcome gravity and propel the rocket upwards.

you know more about 1.4 kg model rocket pls visit-

https://brainly.com/question/28598885

#SPJ11

The sample contains [tex]2.76 \times 10^{22[/tex] nuclides, the decay constant of the element is [tex]2.22 \times 10^{-11} s^{-1[/tex], and the half-life is [tex]3.13 \times 10^{10[/tex] seconds or approximately 991 years.

Part A: To determine the number of nuclides in the sample, we need to use Avogadro's number and the molar mass of the element with mass number 105. The molar mass of this element can be calculated as follows:

Molar mass = (105 atomic mass units) × ([tex]1.661 \times 10^{-27[/tex] kg/atomic mass unit) = [tex]1.745 \times 10^{-25[/tex] kg

The number of atoms in the sample can then be calculated by dividing the mass of the sample by the molar mass and multiplying by Avogadro's number:

Number of atoms = (8.00 g / [tex]1.745 \times 10^{-25[/tex] kg/mol) × [tex]6.022 \times 10^{23[/tex]atoms/mol = [tex]2.76 \times 10^{22[/tex] atoms

Therefore, there are [tex]2.76 \times 10^{22[/tex] nuclides in the sample.

Part B: The decay constant (λ) of the element can be determined using the following formula:

Activity (A) = λN,

where A is the activity of the sample in becquerels (Bq), N is the number of nuclides in the sample, and λ is the decay constant. Rearranging this equation, we can solve for λ:

λ = A/N

Substituting the given values, we get:

[tex]\lambda = \frac{6.14\times 10^{11} \text{ Bq}}{2.76\times 10^{22}}[/tex] nuclides = [tex]2.22 \times 10^{-11} s^{-1[/tex]

Therefore, the decay constant of the element is [tex]2.22 \times 10^{-11} s^{-1[/tex].

Part C: The half-life (t1/2) of the element can be calculated using the following formula:

[tex]t_{1/2} = \frac{\ln(2)}{\lambda}[/tex]

Substituting the decay constant we calculated in part B, we get:

[tex]t_{1/2} = \frac{\ln(2)}{2.22\times 10^{-11}\,\text{s}^{-1}} = 3.13\times 10^{10}\,\text{s}[/tex]

Therefore, the half-life of the element is [tex]3.13 \times 10^{10[/tex] seconds or approximately 991 years. This means that after 991 years, half of the original sample will have decayed, and after another 991 years, half of the remaining sample will have decayed, and so on.

To learn more about decay constant

https://brainly.com/question/29473809

#SPJ4

Complete question:

Suppose that an 8.00 g of an element with mass number 105 decays at a rate of 6.14 × 1011 Bq.

Part A How many nuclides are in the sample?

Part B What is the decay constant of the element?

Part C What is its half-life?

The magnitude of the electric field at the center, P, is 1.77 N/C (to two decimal places), with a maximum acceptable error of 5%.

E = k * (Q / r²)

l = (1/2) * 2 * π * 6.3 = 6.3 * π

Therefore, the charge on the arc is:

Q = λ * l = (5.9 × [tex]10^{-9[/tex]C/m) * (6.3 * π m) = 1.17 × [tex]10^{-7[/tex] C

The distance from the center of the arc to the center, P, is also 6.3 meters. So the electric field at point P is:

E = k * (Q / r²) = (9 × [tex]10^{-9[/tex] N·m²/C²) * (1.17 × [tex]10^{-7[/tex] C / (6.3 m)²)

E = 1.77 N/C

The electric field is a fundamental concept in electromagnetism that describes the force that a charged particle experiences due to the presence of other charges in its vicinity. It is defined as the force per unit charge experienced by a small test charge placed in the electric field. Mathematically, it is represented by the vector field E, which describes the direction and strength of the force at each point in space.

The electric field can be created by stationary charges, such as electrons and protons, or by changing magnetic fields. It is responsible for a wide range of phenomena, from the attraction and repulsion of charged particles to the functioning of electronic devices. The electric field is related to the concept of potential energy, which is the energy associated with the position of a charged particle in an electric field.

To learn more about Electric field visit here:

brainly.com/question/8705524

#SPJ4

Answer:

The rest energy of a feather can be calculated using the equation E=mc^2, where E is the energy, m is the mass, and c is the speed of light. Since the feather is at rest, its kinetic energy is zero, so its rest energy is equal to its total energy.

The mass of the feather is 8.2x10^-6 kg. The speed of light is 299,792,458 m/s.

E = (8.2x10^-6 kg) x (299,792,458 m/s)^2

E = 7.4 x 10^-4 joules

Therefore, the magnitude of the rest energy of the feather is 7.4 x 10^-4 joules.

The energy range of photons of wavelength 390 nm to 740 nm is between 2.68 x 10⁻¹⁹ J and 5.08 x 10⁻¹⁹ J, and the energy range of photons of wavelength 390 nm to 740 nm is between 1.67 eV and 3.17 eV.

To calculate the energy range of photons of wavelength 390 nm to 740 nm, we use the formula;

E = hc/λ

where E is energy, h is Planck's constant (6.626 x 10⁻³⁴ J.s), c is the speed of light (2.998 x 10⁸ m/s), and λ is wavelength.

For 390 nm, we have;

E = (6.626 x 10⁻³⁴ J.s)(2.998 x 10⁸ m/s)/(390 x 10⁻⁹ m)

= 5.08 x 10⁻¹⁹ J

For 740 nm, we have;

E = (6.626 x 10⁻³⁴ J.s)(2.998 x 10⁸ m/s)/(740 x 10⁻⁹ m)

= 2.68 x 10⁻¹⁹ J

So, the energy range of photons of wavelength 390 nm to 740 nm is between 2.68 x 10⁻¹⁹ J and 5.08 x 10⁻¹⁹ J.

To convert the energy range of photons from joules to electronvolts (eV), we use the conversion factor 1 eV = 1.602 x 10⁻¹⁹ J.

So, for the lower energy limit of 2.68 x 10⁻¹⁹ J, we have:

2.68 x 10⁻¹⁹ J x (1 eV/1.602 x 10⁻¹⁹ J)

Therefore, the energy range of photons of wavelength 390 nm to 740 nm is between 1.67 eV and 3.17 eV.

= 1.67 eV

And for the higher energy limit of 5.08 x 10⁻¹⁹ J, we have;

5.08 x 10⁻¹⁹ J x (1 eV/1.602 x 10⁻¹⁹ J)

= 3.17 eV.

To know more about photons here

https://brainly.com/question/28134171

#SPJ4

The statement (t ^ s) v (~t ^ ~s) is always true. Assuming t and s are Boolean variables, "~" represents the negation operator (i.e., NOT), "^" represents the conjunction operator (i.e., AND), and "v" represents the disjunction operator (i.e., OR).

The true value of this statement depends on the truth values of t and s.

Assuming t and s are Boolean variables, "~" represents the negation operator (i.e., NOT), "^" represents the conjunction operator (i.e., AND), and "v" represents the disjunction operator (i.e., OR).

If t is true and s is true, then the statement simplifies to:

(true ^ true) v (~true ^ ~true)

= true v false

= true

If t is false and s is false, then the statement simplifies to:

(false ^ false) v (~false ^ ~false)

= false v true

= true

In all other cases, the statement simplifies to:

(false) v (true)

= true

Therefore, the statement (t ^ s) v (~t ^ ~s) is always true.

To learn more about Negation operators click here

https://brainly.com/question/30654833

#SPJ11

The temperature of the cosmic microwave background radiation (CMBR) is only 3 Kelvin (K) because the universe has expanded and cooled significantly since the Big Bang. As the universe expanded, the energy of the CMBR photons also decreased, leading to a decrease in temperature. This process is known as cosmic redshift, and it is a result of the expansion of the universe stretching the wavelengths of light.

Additionally, the universe went through a period of rapid cooling known as the recombination epoch, during which electrons and protons combined to form neutral atoms. This process reduced the number of free electrons in the universe, making it more transparent to the CMBR and causing the temperature to decrease further. Overall, the combination of cosmic redshift and the recombination epoch has led to the CMBR having a temperature of only 3 K today.
The Cosmic Microwave Background (CMB) radiation's temperature is now only 3 K because it has cooled down over time since the Big Bang. As the universe expands, the CMB radiation also stretches and its energy decreases, leading to a drop in temperature. This cooling process is a natural consequence of the universe's expansion and the laws of thermodynamics.

To know more about cosmic redshift visit:

https://brainly.com/question/1351911

#SPJ11

(a) The relativistic kinetic energy of a 1000-kg car moving at 30.0 m/s can be calculated using the equation:

K = [(γ - 1) * m * c^2] - mc^2

where K is the relativistic kinetic energy, γ is the Lorentz factor, m is the mass of the car, and c is the speed of light. If the speed of light were only 45.0 m/s, then the Lorentz factor can be calculated as:

γ = 1 / sqrt(1 - (v/c)^2) = 1 / sqrt(1 - (30/45)^2) ≈ 1.155

Substituting the values, we get:

K = [(1.155 - 1) * 1000 kg * (45.0 m/s)^2] - (1000 kg * (45.0 m/s)^2) ≈ 240 kJ

(b) The ratio of the relativistic kinetic energy to classical kinetic energy can be calculated as:

Krel/Kcl = [(γ - 1) / (v^2/c^2)] + 1

where Krel is the relativistic kinetic energy and Kcl is the classical kinetic energy. Substituting the values, we get:

Krel/Kcl = [(1.155 - 1) / (30.0 m/s)^2/(45.0 m/s)^2] + 1 ≈ 1.12

Therefore, the relativistic kinetic energy is about 1.12 times greater than the classical kinetic energy.

Learn more about the speed of light here:- brainly.com/question/394103

#SPJ11

The minimum distance between the two dots that can be distinguished by the person's eye is approximately 1.22 × [tex]10^-3 cm.[/tex]

The limiting angle of resolution of the human eye is the smallest angle between two points that can be distinguished as separate. It is given by the formula:

sinθ = 1.22 λ/D

where θ is the limiting angle of resolution, λ is the wavelength of light, and D is the diameter of the pupil.

In this case, we can assume the wavelength of light to be 550 nm, and the diameter of the pupil to be 5 mm. Substituting these values in the above equation, we get:

sinθ = 1.22 × 550 × [tex]10^-9[/tex] / 5 × [tex]10^-3[/tex]= 1.34 × [tex]10^-5[/tex]

Next, we can use trigonometry to calculate the minimum distance between the two dots that can be distinguished by the person's eye. Let x be the minimum distance between the dots. Then, we have:

x/43.4 = tanθ

Substituting the value of θ, we get:

x = 43.4 × tan(1.34 × [tex]10^-5[/tex]) = [tex]1.22 × 10^-3 cm[/tex]

Therefore, the minimum distance between the two dots that can be distinguished by the person's eye is approximately 1.22 × [tex]10^-3 cm.[/tex]

Learn more about wavelength

https://brainly.com/question/31143857

#SPJ4

The constant c relating the moment of inertia to the mass and radius (I) of the circular object is 0.00025 [tex]Nm^2/kg^2.[/tex]

The constant c relating the moment of inertia to the mass and radius (I) of a circular object can be calculated using the following formula:

[tex]c = (G * m * r^2) / I[/tex]

Where G is the gravitational constant, m is the mass of the object, r is the radius of the object, and I is the moment of inertia of the object.

In this case, the mass of the object is given as 10 kg, the radius is given as 0.5 m, and the translational velocity at the bottom is given as 7.0 m/s. To find the moment of inertia, we can use the formula:

[tex]I = (1/2) * m * r^2[/tex]

Plugging in the given values, we get:

I = (1/2) * 10 kg * 0.5 [tex]m^2[/tex]

I = 25 k[tex]g^2/[/tex][tex]m^2[/tex]

Substituting this value of I into the formula for c, we get:

[tex]c = (G * 10 kg * 0.5 m^2) / 25 kg^2/m^2[/tex]

[tex]c = (6.67 * 10^-11 Nm^2/kg^2 * 0.5 m^2) / 25 kg^2/m^2[/tex]

[tex]c = 0.00025 Nm^2/kg^2[/tex]

Therefore, the constant c relating the moment of inertia to the mass and radius (I) of the circular object is 0.00025 [tex]Nm^2/kg^2.[/tex]

Learn more about translational velocity

https://brainly.com/question/31660439

#SPJ4

(a) The speed of reference frame S′ relative to frame S is 5.1 m/s.

Using the formula for velocity addition in special relativity, we can calculate the velocity of reference frame S′ relative to S as v = (v' + u) / (1 + v'u/c^2), where v' is the velocity of S′ relative to an unprimed frame S'', u is the velocity of S'' relative to S, and c is the speed of light. Since S'' is at rest in S, we have u = 0. The velocity of S′ relative to S'' is v' = 5.1 m/s (given in the problem). Substituting these values, we get v = (5.1 m/s + 0 m/s) / (1 + (5.1 m/s x 0 m/s) / (299792458 m/s)^2) = 5.1 m/s.
(b) In frame S, the position of the first explosion is x=10m and the position of the second explosion is x=22m.
In frame S, the positions of the explosions are given by the coordinates (x, t) = (10 m, 1.0 s) and (22 m, 5.0 s). To find the positions of the explosions in frame S′, we use the Lorentz transformation equations for position: x' = γ(x - vt) and t' = γ(t - vx/c^2), where γ = 1/√(1 - v^2/c^2) is the Lorentz factor. Since the explosions occur at the same location in S', we have x'_1 = x'_2 = x'. Solving the two equations simultaneously, we get x' = (10 m + 5.1 m/s x 1.0 s) / √(1 - (5.1 m/s / 299792458 m/s)^2) = 13.4 m, which is the position of both explosions in frame S'. To find the positions in frame S, we use the inverse Lorentz transformation: x = γ(x' + vt') and t = γ(t' + vx'/c^2), where v is the velocity of S' relative to S. Substituting the values from parts (a) and (b), we get x_1 = γ(13.4 m + 5.1 m/s x 1.0 s) = 14.3 m and x_2 = γ(13.4 m + 5.1 m/s x 5.0 s) = 31.3 m. Thus, the positions of the explosions in frame S are x_1 = 10 m and x_2 = 22 m.

To learn more about speed, click here:

https://brainly.com/question/30462853

#SPJ11

The  angle of the second dark fringe is 2.48 degrees.

The angular position of the second dark fringe in a single-slit diffraction pattern can be found using the formula:

sin(θ) = (mλ)/(w)

Where θ is the angle of the fringe, m is the order number of the fringe (in this case, m = 2 for the second dark fringe), λ is the wavelength of the light, and w is the width of the slit.

First, we need to calculate the width of the slit. The distance between the second dark fringe and the central maximum is given as 3.20 cm, which corresponds to the distance between two dark fringes. Therefore, the distance between the central maximum and the first dark fringe is half of this value, or 1.60 cm.

Using the small angle approximation (sin(θ) ≈ θ), we can find the angle of the first dark fringe:

θ = (1.60 cm) / (6.43 m) = 0.002485 radians

Now we can use this value to find the width of the slit:

w = (mλ) / sin(θ) = (2)(698 nm) / sin(0.002485) = 0.0565 mm

Finally, we can use the formula to find the angle of the second dark fringe:

θ = (2)(698 nm) / (0.0565 mm) = 0.0433 radians

Converting to degrees, we get:

θ = 2.48 degrees (rounded to two decimal places)

Therefore, the angle of the second dark fringe is 2.48 degrees.

Visit to know more about Fringe:-

brainly.com/question/27548790

#SPJ11

5 compressions per second is the frequency of a 10 meter longitudinal wave when 25 compressions pass a point in a medium in 5 seconds

What is a definition of frequency?

The number of waves that pass a fixed point in a unit of time is known as frequency. It is also known as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. Hertz is the name of the frequency's SI unit.

A waveform signal's wavelength is defined as the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or along a wire.

The relationship between frequency and wavelength is inversely proportional. The wavelength of the wave with the highest frequency is the shortest. Half the wavelength corresponds to twice the frequency. The wavelength ratio is therefore the inverse of the frequency ratio.

Frequency will be 25 / 5 i.e. 5 compressions per second

To learn more about wavelength use:

https://brainly.com/question/10750459

#SPJ4

Answer: 660 N.

Explanation: Force on a free falling body is F=mg.

Therefore, Force =66×10 =660

(g is gravitational acceleration, taking it as 10)

You continuously move a block across a table for 1.9 seconds at a speed of 1.5 m/s. The two items have a 0.60 coefficient of kinetic friction. The mass of the block is 8.95 kg. Here option 3 is correct.

To solve this problem, we need to use the equation for work done by a force:

W = Fd

where W is the work done, F is the force applied, and d is the distance over which the force is applied.

In this case, the force is the force of friction between the block and the table. Since the block is moving at a steady velocity, we know that the net force on the block is zero. Therefore, the force of friction must be equal in magnitude to the force applied to the block.

We can use the equation for kinetic friction to find the force of friction:

Ffriction = μkN

where μk is the coefficient of kinetic friction, and N is the normal force, which is equal in magnitude to the force of gravity on the block (since the block is not accelerating in the vertical direction).

The normal force is given by:

N = mg

where m is the mass of the block, and g is the acceleration due to gravity.

We can use the equation for velocity to find the distance traveled by the block:

d = vt

where v is the velocity of the block, and t is the time for which the force is applied.

Now we have all the pieces we need to solve for the mass of the block. We start by using the equation for kinetic friction to find the force of friction:

Ffriction = μkN = μkmg = 0.60 × m × 9.81 = 5.886 m

We know that the work done is 150 J, and the distance over which the force is applied is d = vt = 1.5 m/s × 1.9 s = 2.85 m. Therefore:

W = Fd = 5.886 m × 2.85 m = 16.761 J

Since the work done by the force of friction must equal the work performed, we have:

16.761 J = 150 J

Solving for the mass of the block, we get:

m = 150 J / 16.761 m = 8.95 kg

To learn more about kinetic friction

https://brainly.com/question/30886698

#SPJ4

The minimum energy (in electron volts) that is required to remove the electron from the ground state of a singly ionized helium atom (He+, Z = 2) is 54.4 electron volts (eV).

To answer your question, we need to calculate the ionization energy required to remove the electron from the ground state of a singly ionized helium atom (He+). In this case, the ionization energy can be calculated using the formula:

Ionization energy (eV) = 13.6 * Z² / n²

where Z is the atomic number (for He+, Z = 2), and n is the principal quantum number of the ground state (n = 1 for the ground state).

Ionization energy (eV) = 13.6 * (2²) / (1²) = 13.6 * 4 = 54.4 eV

So, the minimum energy required to remove the electron from the ground state is 54.4 electron volts (eV).

More on energy: https://brainly.com/question/31779681

#SPJ11

The rate of radiation emitted by an identical surface at 35°C can be calculated using the Stefan-Boltzmann law. The rate is approximately 117 W.

According to the Stefan-Boltzmann law, the rate at which an object emits thermal radiation is proportional to the fourth power of its absolute temperature. Given that an identical surface at 27°C emits radiation at a rate of 100 W, we can use this law to determine the rate of radiation emitted by the surface at 35°C. By applying the formula P' = P * (T'/T)^4, where P is the initial rate of radiation emitted (100 W), T is the initial temperature (27°C + 273.15 = 300.15 K), and T' is the final temperature (35°C + 273.15 = 308.15 K), we can calculate P' to be approximately 117 W. Hence, an identical surface at 35°C emits radiation at a rate of approximately 117 W.

To determine the wavelength of the maximum amount of radiation emitted by the surface at 27°C, we can employ Wien's displacement law. This law states that the wavelength of maximum emission (λ_max) is inversely proportional to the temperature of the object. By using the equation λ_max = b / T, where b is Wien's constant (approximately 2.898 × 10^(-3) m·K) and T is the temperature in Kelvin, we can substitute T = 27°C + 273.15 = 300.15 K into the equation. The calculation yields λ_max to be approximately 9.65 × 10^(-6) m or 9.65 μm. Thus, the surface at 27°C emits the maximum amount of radiation at a wavelength of approximately 9.65 μm.

Learn more about Stefan-Boltzmann law : brainly.com/question/30763196

#SPJ11

In a simplified nuclear fusion reaction where 4 hydrogens convert to helium, the energy released is 6.0 × 10⁻¹⁴ J (Option C).

In a simplified nuclear fusion reaction, 4 hydrogen nuclei (H) combine to form one helium nucleus (He). However, the mass of four hydrogen nuclei (4 x 1.007 = 4.028) is slightly greater than the mass of one helium nucleus (4.0026). This difference in mass is converted into energy according to Einstein's famous equation E=mc², where E is the energy released, m is the mass difference, and c is the speed of light.

Using the given mass of hydrogen (1.67 x 10⁻²⁷ kg), we can calculate the mass difference as:

(4 x 1.007 - 4.0026) x 1.67 x 10⁻²⁷ kg

= 2.385 x 10⁻²⁹ kg

Plugging this into the equation E=mc², we get:

E = (2.385 x 10⁻²⁹ kg) x (3.00 x 10⁸ m/s)²

= 2.1465 x 10⁻¹² J

However, this is the energy released by one fusion reaction. The question asks for the energy released when 4 hydrogens convert to helium. Therefore, we need to multiply by 4 to get:

4 x 2.1465 x 10⁻¹² J

= 8.586 x 10⁻¹² J

This is the energy released when 4 hydrogens convert to helium. However, the answer choices are in scientific notation. Converting to scientific notation, we get:

8.586 x 10⁻¹² J

= 8.586e⁻¹² J

= 6.0 x 10⁻¹⁴ J (to two significant figures)

Learn more about nuclear fusion reaction: https://brainly.com/question/10104286

#SPJ11

The average momentum of the sprinter is 532.85 kg·m/s.

To calculate the average momentum, we first need to find the average velocity of the sprinter.

Average velocity equals distance divided by time. In this case, the distance is 100 meters, and the time is 10.35 seconds. So, the average velocity is 100 / 10.35 = 9.66 m/s.

Momentum equals mass multiplied by velocity, so the average momentum is 55 kg * 9.66 m/s = 532.85 kg·m/s.

Summary: The average momentum of a 55-kg sprinter running a 100-m dash in 10.35 s is 532.85 kg·m/s.

Learn more about momentum click here:

https://brainly.com/question/1042017

#SPJ11

The current in the solenoid would be 31.4 amps.

To calculate the current in the solenoid in amps, we can use the formula for the magnetic field produced by a solenoid, which is given by B = μnI, where B is the magnetic field, μ is the permeability of free space, n is the number of turns per unit length, and I is the current.
Using the given values of the solenoid's length (1.4 m) and number of turns (8,404), we can calculate the number of turns per unit length, which is n = N/L = 8,404/1.4 = 6,003 turns/m.
Substituting this value of n and the given magnetic field (1.4 T) into the formula, we get:
1.4 T = 4π * 10^-7 Tm/A x 6,003 turns/m x I
Solving for I, we get:
I = \frac{1.4 T }{ (4π x 10^-7 Tm/A x 6,003 turns/m)} = 31.4 A
Therefore, the current in the solenoid would be 31.4 amps.

learn more about current Refer: https://brainly.com/question/4289257

#SPJ11