A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are
the total distance and total displacement of the boat?
OA. The total distance is 105 kilometers and the total displacement is 45 kilometers east.
OB. The total distance is 60 kilometers and the total displacement is 60 kilometers east.
OC. The total distance is 105 kilometers and the total displacement is 15 kilometers east.
OD. The total distance is 60 kilometers and the total displacement is 45 kilometers east.
Answer:1) the total distance is the sum of the two distances
60 km + 45 km = 105 km
2) The displacement is the net movement, or the difference between the initial position and the final position
Call x the initial position, then the final position is x + [60km - 45km]
And the displacement is x + (60km - 45km) - x =60km -45 km = 15 km
Explanation:
32. For each of the listed parts of a power plant, make a selection to indicate in what
type(s) of power station the part is found. Place your answer in in the blank space!
I. part of a coal-fired power plant
II. part of a nuclear power plant
III. part of a coal-fired power plant and part of a nuclear power plant
a. boiler. ( insert answer)
b. combustion chamber(
c. condenser(
d. control rod(
generator(
f. turbine(
From a to f choice which of the following from I, II, III is appropriate from a to F
Answer: a. boiler - I. part of a coal-fired power plant.
b. combustion chamber - I. part of a coal-fired power plant.
c. condenser - III. part of a coal-fired power plant and part of a nuclear power plant.
d. control rod - I. part of a coal-fired power plant.
e. generator- III. part of a coal-fired power plant and part of a nuclear power plant.
f. turbine - III. part of a coal-fired power plant and part of a nuclear power plant.
Explanation:
a. Boiler: It is used in the coal power plant to heat the water used for producing electricity. The boiler keeps the temperature of water or steam at a desired level.
b. Combustion chamber: It is used for combustion of coal and using thermal energy for electricity generation.
c. Condenser; It is used in both nuclear and coal power plants. It condense and receive from the turbine.
d. Control rod: It is used in the nuclear power plant for controlling the nuclear fission and fusion reactions of heavy metals.
e. Generator: It converts the thermal energy into electrical energy.
f. Turbine: The turbine blades move with the effect of steam or any form of energy and the energy so produce is used for generating electricity in generator.
The energy a wave carries is measured by its ____. Question 15 options: wavelength frequency amplitude speed
Answer: frequency is the answer to this question
Answer:
frequency
Explanation:
c a n v a s / a p e x :))
May I please get some help?
A unicorn running on a beach at 8 m/s changes speed at a constant rate of 2.7
m/s2 over a period of 2 seconds. What is the unicorn's velocity at the end of this
time?
Answer:
13.4 m/s
Explanation:
Write down what you have, so:
V0=8 m/s
a=2.7 m/s^2
t=2 seconds
We are trying to find final velocity, so we will use vf = v0 + at
From there, we plug in the given values.
vf = 8 m/s + (2.7 m/s^2 x 2 seconds)
vf = 13.4 m/s
Answer:
about 13s
Explanation:
How much momentum will a dumbbell of mass 10kg transfer to the floor if it falls from a height of 80cm (assume that the dumbbell stops after hitting the ground) ? Take g=10m/s^2
(Point stealers will be reported so better dont do it)
Answer: momentum = 40kgm/s
Explanation:
Given that the
Mass M = 10kg
Height H = 80 cm = 0.8m
g = 10m/s^2
The velocity of the dumbbell as it fall can be calculated by using the formula;
V^2 = U^2 + 2gH
Since the dumbbell fell from rest, initial velocity U = 0
Substitute g and H to get final velocity V
V^2 = 0 + 2 × 10 × 0.8
V^2 = 16
V = sqrt(16)
V = 4 m/s
Momentum is the product of mass and velocity. That is,
Momentum = MV
Substitute mass M and V into the formula
Momentum = 10 × 4 = 40kgm/s
Therefore, 40 kgm/s momentum will be transferred as the dumbbell fall to the floor.
The woman was standing on a cliff 30 meters above where she landed. There was a safety fence 4 meters from the cliff edge that would have prevented her from taking a long distance to run and leap off the cliff. She landed 12 meters away from the base of the cliff. Her launch speed was calculated to be 4.86 m/s, meaning that to travel those 12 meters, she had to be traveling at 10.87 miles per hour (or moving faster than a runner at a 5.5 minute mile pace) as she left the cliff. Put all this information together. Why did forensic scientists determine that the woman’s body was thrown instead of concluding that she jumped off the cliff?
Answer:
Forensic scientists determined that the woman’s body was thrown off the cliff because after considering the velocity and angle of the projectile needed in relationship to the cliff she could not have reached those speeds and cleared the safety fence 4m away from the cliff’s edge. She would have been going faster than a 5.5 minute mile pace and she was not an athletic person.
** Just make sure to change the format and/or wording. Hope I was helpful :-)
The woman’s body was thrown instead of concluding that she jumped off the cliff as there has more initial speed than regular which is provided during throw.
What is projectile motion?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.
Given: She landed 12 meters from the cliff's base.
And when she jumped off the cliff, her estimated launch speed was 10.87 miles per hour. She could have avoided having to go a considerable distance in order to jump over the cliff by using the safety barrier that was 4 meters away.
Hence, Instead of drawing the conclusion that the woman leaped from the cliff, the body of the woman was flung since throwing provides more initial speed than usual.
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How did the angel of the pendulum affect the period
Answer:The starting angle of a pendulum does not affect its period for .
Explanation: however, the period increases with increasing . The starting angle of a pendulum does not affect its period for.
A 14 kilogram beam is hinged at one end. A 6.0-kilogram triangular object and a 7.5-kilogram capital I-shaped object are placed as shown in the figure. The dots indicate the individual centers of gravity of the beam and objects. The center of mass of the entire system must be:
Answer: 1.3 m
Explanation:
From the figure attached, 3 materials are involved. A 14 kilogram beam hinged at one end, a 6.0-kilogram triangular object and a 7.5-kilogram capital I-shaped object.
Let take the moment at the hinge axis.
The moment for the beam will be
14 × ( 0.36 + 0.53 ) = 12.6
The moment of the triangle object will be 6 × 0.36 = 2.16
The moment of capital I shape will be
7.5 × ( 0.36 + 0.53 + 1.92 ) = 21.075
The total moment = 12.6 + 2.16 + 21.075
The total moment = 35.835
The total mass = 14 + 6 + 7.5 = 27.5
The center of mass of the entire system must be:
X = total moment ÷ total mass
Substitute both in the formula
X = 35.835/27.5
X = 1.3 m.
Therefore, The center of mass of the entire system must be 1.3m
In a weak acid solution, _____.
A.) all ions in the acid compound form water
B.) many ions in the acid compound form a base
C.) no ions separate from the acid compound
D.) few ions separate from the acid compound
Answer:
A)
Explanation:
PLS HELP!
Raymond Cattell created the 16PF self-inventory assessment by first taking 4,504 personality traits and removing all of the __________.
A. nouns
B.homonyms
C.synonyms
D.antonyms
Raymond Cattell created the 16PF self-inventory assessment by taking 4,504 personality traits and removing all of the synonyms.
What is Synonym?This is defined as a word or phrase which has a close or near meaning to the other.
Raymond Cattell created the 16PF self-inventory assessment by removing the synonyms from the personality traits.
Read more about Synonyms here https://brainly.com/question/76433
What is the net displacement of the particle between 0 seconds and 80 seconds?
Velocity (m/s)
chhi NSON WAO
20
40
80
280
100
Кузорил
Time (s)
OA.
160 meters
OB.
80 meters
OC.
40 meters
OD.
20 meters
OE.
0 meters
Answer: 80
Explanation:
The question is incomplete, There is no specific time for the specific velocity, which is not provided in this question instead of giving the total time interval from 0sec to 80 sec. According to my assumption, I think the net displacement will be 20 m. The correct answer will be option D.
What is net displacement?Net displacement is the total change in the position of an object, taking into account both the magnitude and direction of its motion. It is a vector quantity and is expressed in terms of distance and direction.
In other words, it is the final position of an object relative to its initial position, irrespective of the path taken. It is calculated by finding the vector difference between the final and initial positions of the object.
For example, if an object moves 10 meters to the east and then 5 meters to the north of its starting position, then its net displacement would be the vector sum of these two displacements, which is the diagonal distance between its starting and final positions.
Here in the Question,
To calculate the net displacement of the particle between 0 seconds and 80 seconds based on the given options, we can use the fact that the net displacement is the same as the final position minus the initial position.
Let's assume that the initial position is zero.
Option A. If the net displacement is 160 meters, the final position would be 160 meters. However, looking at the velocities given, we can see that the particle goes back and forth, so it does not make sense for the net displacement to be larger than the maximum displacement in one direction.
Option B. If the net displacement is 80 meters, the final position would be 80 meters. This option could be possible if the particle moves in one direction for a while and then moves back to its initial position. This is incorrect.
Option C. If the net displacement is 40 meters, the final position would be 40 meters. This option is also possible if the particle moves in one direction for a shorter period of time. This is not relevant to the question.
Option D. If the net displacement is 20 meters, the final position would be 20 meters. This option could be possible if the particle moves in one direction for a very short period of time. This is most relevant to the Question.
Option E. If the net displacement is 0 meters, the final position would be the same as the initial position, which is zero. This option could be possible if the particle moves back and forth such that the positive displacements cancel out the negative displacements.
Therefore, based on the given options, the correct answer for the net displacement of the particle between 0 seconds and 80 seconds is option D: 20 meters.
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The shape of a lens affects the _____. A. direction light is bent B. color of light moving through it C. medium in which the light travels D. speed of light traveling through it
Answer:
A.The direction in which light is bent
Explanation:
That why I the topic thin lenses we learn how to draw Ray's of light
Answer:
a
Explanation:
which of the following are good conductors under normal conditions? A. Penny B.copper wire C. a dime D.plastic E.aluminum foil F.water
Answer:
see explanation
Explanation:
A,B,C,E
B.
Because its copper
A projectile is fired vertically upwards and reaches a height of 78.4 m. Find the velocity of projection and the time it takes to reach its highest point.
Answer:
1.) U = 39.2 m/s
2.) t = 4 seconds
Explanation: Given that the
height H = 78.4m
The projectile is fired vertically upwards under the acceleration due to gravity g = 9.8 m/s^2
Let's assume that the maximum height = 78.4m. And at maximum height, final velocity V = 0
Velocity of projections can be achieved by using the formula
V^2 = U^2 - 2gH
g will be negative as the object is moving against the gravity
0 = U^2 - 2 × 9.8 × 78.4
U^2 = 1536.64
U = sqrt( 1536.64 )
U = 39.2 m/s
The time it takes to reach its highest point can be calculated by using the formula;
V = U - gt
Where V = 0
Substitute U and t into the formula
0 = 39.2 - 9.8 × t
9.8t = 39.2
t = 39.2/9.8
t = 4 seconds.