a cylinder is filled with 10. 0 L of gas and a piston is put into it. The initial preasure of the gas is measured to be 138 kPa. The piston is now pushed down compressing the gas until the gas has a final volume of 8.30 L calculate the final pressure of the gas be sure your answer has the correct number of significant digits.​

Answers

Answer 1

Answer:

First you need to convert the cylinder to a boot, then you can successfully compress the water into the tip of the boot, preventing it from busting.

Explanation:

To convert a cylinder to a boot, simply multiply the circumference of the cylinder by 1.3125768927, or 1.31. The .31 is the extra space taken in by the tip of the boot.


Related Questions

What type of reaction is 3Mg + N2 → Mg3N2 ?

Answers

Reducing: Mg is a reducing agent, N 2 is an oxidizing agent.

A cylinder container is filled with air. Its radius is 6.00cm and its height is 3.50 cm. What is the volume of air inside in milliliters?

Answers

Answer:

Volume Cylinder = 396cm³

Explanation:

We can find the volume of a cylinder (The container is cylindric) using the general expression:

volume cylinder = π*(radius)²*height

As the container has a radius og 6.00cm and a height of 3.50cm:

volume cylinder = π*(6.00cm)²*3.50cm

Volume Cylinder = 396cm³

1.the volume of air in a mountain bicycle tire is constant. the initial pressure and temperature are 3.14 atm and 26 degrees celsius.

a) as the bike is ridden friction with the road causes the tire to heat up. at what kelvin temperature will the gas in the tire have a pressure of 3.96 atm

b) explain why your answer makes sense at the particle level. use the words collisions, force, and frequency in your responde.

Answers

Answer:

Explanation:

Givens

P1 = 3.14 atm

T1 = 26 + 273 = 299

P2 = 3.96

T2 = ?

Equation

P1 / T1 = P2 / T2

Solution

3.14 / 299 = 3.96 / x                   Cross multiply

3.14 x = 299 * 3.96                     Divide by 3.14

x = 299*3.96 / 3.14

x = 1184.04/3.14

x = 377.08 oK                             Take off 273 to get the degrees Centigrade.

x = 104.08 oC

Part B

If you want the temperature to increase, the relationship is a direct  one. That means as the temperature goes up, the pressure will as well. So for a bicycle, it makes sense that the volume remains constant. That makes the formula above without volume because the volume would cancel out on both sides of the equation.

So as the pressure increases, the particles making up the air begin to respond by the molecules moving faster. Temperature really is the a measurement of how fast molecules are moving. So the momentum is increasing. When the particles hit something, it is with a much greater force and that increases the apparent pressure.


If the nucleus of an atom
contained 6 protons and 7
neutrons, what would be its
mass

Answers

Answer:

13

Explanation:

1 proton/neutron has an atomic mass of 1. We ignore the electrons because they are too small. Protons and Neutrons have the same atomic mass, therefore the answer s 6+7=13

. Apply a coat of ____ to keep a wooden ladder structurally sound and functioning well. A. metallic paint B. oil-based paint C. linseed oil D. ​

Answers

Answer:

oil based paint

Explanation:

A solution is prepared by dissolving 16.90 g of ordinary sugar (sucrose, C12H22O11, 342.3 g/mol) in 40.90 g of water. Calculate the boiling point of the solution. Sucrose is a nonvolatile nonelectrolyte.

Answers

Answer:

Explanation:

The boiling point will increase due to dissolution of sugar in water . Increase in boiling point ΔT

ΔT = Kb x m , where Kb is molal elevation constant water , m is molality of solution

Kb for water = .51°C /m

moles of sugar = 16.90 / 342.3

= .04937 moles

m = moles of sugar /  kg of water

= .04937 / .04090

= 1.207

ΔT = Kb x m

= .51 x 1.207

= .62°C .

So , boiling point of water = 100.62°C .

Boyle's Law represents the relationship of volume as pressure is changed. The constants of Boyle's Law are

temperature and number of molecules of gas

Answers

Answer:

True.

Explanation:

Hello!

In this case, according to the ideal gas equation:

[tex]PV=nRT[/tex]

It turns out possible for us to obtain the Boyle's law, as a directly proportional relationship between pressure and volume, considering that both moles and temperature remain constant; in such a way, we write the following:

[tex]PV=k[/tex]

Therefore, for an initial (1) and final state (2) we are able to write:

[tex]P_2V_2=P_1V_1[/tex]

Regards!

How many moles of iron are needed to produce 10 moles of Fe2O3

Answers

Answer:

20 moles of Iron are needed

Explanation:

In 1 mole of Iron (III) oxide, Fe₂O₃, there are 2 moles of Iron, Fe. The equation that we can write is:

2 moles Fe = 1 mole Fe₂O₃

To find the moles of iron that are needed to produce 10 moles of Fe₂O₃ we must use this equation as follows:

10 moles of Fe₂O₃ * (2 moles Fe / 1mole Fe₂O₃) =

20 moles of Iron are needed

I’m confused and I don’t understand this, can someone help?

Answers

Wilma- tt

Wilbur- TT

c) 100% chance

d) 100% chance

it has been a while since I've done this so it could be wrong but im pretty sure its correct

Wilbur's family claims it is pure so they have TT

and his wife simply has big eyes so its tt

so the chances of their children having either eye shape is 100%

I'm sorry- im not too good at explaining it ><

Is earth an inertial frame of reference? justify your answer

Answers

Answer:

Earth is not an inertial reference frame because the Earth rotates and is accelerated with respect to the Sun.

The following data were obtained by gas-liquid chromatography on a 40-cm packed column:

Compound tR, min W, min
Air 1.9 —
Methylcyclohexane 10 0.76
Methylcyclohexene 10.9 0.82
Toluene 13.4 1.06

Calculate:
a. an average number of plates from the data.
b. the standard deviation for the average in (a).
c. an average plate height for the column.

Answers

Answer:

a)

For Methylcyclohexane  N₁ = 2770

For Methylcyclohexene N₂ = 2827

For Toluene N₃ = 2557

b) the standard deviation for the average in (a) is 143.31

c)

For Methylcyclohexane; H₁ = 0.01444 cm

For Methylcyclohexene; H₂ = 0.01415 cm

For Toluene; H₃ = 0.01564 cm

Explanation:

Given the data in the question;

Gas-liquid chromatography on a 40-cm packed column:

Compound                   tR, min                           W, min

Air                                   1.9                                    —

Methylcyclohexane      10.0                               0.76

Methylcyclohexene      10.9                               0.82

Toluene                        13.4                                1.06

a)

an average number of plates from the data;

To get the Number of plates N, we use the following expression;

N = 16( tR / W )², we use it for Methylcyclohexane, Methylcyclohexene and Toluene

-

For Methylcyclohexane  N₁ = 16( 10 / 0.76 )² = 16( 173.13 ) = 2770.08 ≈ 2770

-

For Methylcyclohexene N₂ = 16( 10.9 / 0.82 )² = 16( 176.7 ) = 2827.2 ≈ 2827

-

For Toluene N₃ = 16( 13.4 / 1.06 )² = 16( 159.8078 ) = 2556.9 ≈ 2557

b) standard deviation for the average in (a).

First we get the mean;

Mean N" = ( N₁ + N₂ + N₃ ) / 3 = ( 2770 + 2827 + 2557 ) / 3 = 8154 / 3 = 2718

Next we determine the deviation

d₁² = (N₁ - N")² = (2770 - 2718)² = (52)² = 2704

d₂² = (N₂ - N")² = (2827 - 2718)² = (109)² = 11881

d₃² = (N₃ - N")² = (2557 - 2718)² = (-161)² = 25,921

∴ ∑d²[tex]_i[/tex] = 40506

Standard Deviation S = √( ∑d²[tex]_i[/tex]  / ( n-1 ) )

Standard Deviation S = √( 40506 / ( 3-1 )

Standard Deviation S = √( 40506 / 2 )

Standard Deviation S = √( 20253 )

Standard Deviation S = 143.31

Therefore, the standard deviation for the average in (a) is 143.31

c)

an average plate height for the column

Given that; Gas-liquid chromatography on a 40-cm packed column, L = 40 cm

-

For Methylcyclohexane; H₁ = L/N₁ = 40 / 2770 = 0.01444 cm

-

For Methylcyclohexene; H₂ = L/N₂ = 40 / 2827  = 0.01415 cm

-

For Toluene; H₃ = L/N₃ = 40 / 2557 = 0.01564 cm

Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.

Answers

Answer:

mass of sucrose = 17.115 grams

Explanation:

Given that:

mass = 2000 grams

molar mass of sucrose = 342.3 g/mol

2.5% of the sucrose soltion.

Let assume we are given 1 M of the sucrose solution;

2.5% of 1 M = 0.025 M

Molarity = ( mass/molar  mass )(1000/V)

mass = (0.025 * 342.3 * 2000)/(1000)

mass of sucrose = 17.115 grams

What is the mass of 1.2 x 1023 atoms of arsenic?

Answers

Answer:

14.93 g

Explanation:

First we convert 1.2 x 10²³ atoms of arsenic (As) into moles, using Avogadro's number:

1.2 x 10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.199 mol As

Then we can calculate the mass of 0.199 moles of arsenic, using its molar mass:

0.199 mol * 74.92 g/mol = 14.93 g

Thus, 1.2x10²³ atoms of arsenic weigh 14.93 grams.

Using stoichiometry, you predict that you should be able to use 314.0 g of Al to produce 1551 g of AlCi3. In your lab
exercise you actually produced 1400.0 g of aluminum chloride. What is your % yield for this reaction?
CORRECT ANSWER IS: 90.26% but what are the steps on how to get this answer ?

Answers

Answer:

90.26%

Explanation:

From the question given above, the following data were obtained:

Theoretical yield of AlCl₃ = 1551 g

Actual yield of AlCl₃ = 1400 g

Percentage yield =?

The percentage yield of the reaction can be obtained as follow:

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 1400 / 1551 × 100

Percentage yield = 140000 / 1551

Percentage yield = 90.26%

Thus, the percentage yield of the reaction is 90.26%

What is the molarity of a solution that contains 152 g NaCl in 4.00 L solution?

Answers

Answer:

200.0lg

Explanation:

please give a brainliest

The diagram above shows repeating groups of atoms that make up to samples. Will the properties of the two samples likely be the same or different? (Examples of properties are smell, color, and the temperature at which a substance melts)

Answers

Answer:

I would need to see the diagram in order to answer properly

A piece of wood has a mass of 36g and measures 3cm X 6cm X 4cm. What is the density of the wood? Would the piece of wood float or sink in water?

Answers

Answer:

Explanation:

The density is  

1.1 g c m 3 .

What could have caused the size of the moon jelly population to increase? Claim 1: A change to the zoo plankton population caused births to increase in the moon jelly population. Claim 2: A change to the sea turtle population caused deaths to decrease in the Moon jellies population

Answers

Answer:

i think is claim 1

Explanation:

moon jellies eat zooplankton and the zooplankton population increased

Answer:It’s important to know WHY. Great explanations are what makes Brainly awesomeExplain everything. Imagine that the person who was asking, knows nothing at all so you need to start from the very beginningAlways include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their ownShow all the calculation if it is a numerical question.

Explanation:

A percent is a ratio expressed per 100 units. If you have 20 balls, and 1 is blue, you can say that 5% (or 5 out of 100 balls) is blue. Similarly, if a solution is 5% KI by mass, you can say that 5 g per 100 g solution is KI. When mass percent is used as a conversion factor, it can be expressed in the units required to solve the problem provided that the ratio remains constant. If the numerator is divided by 100, the denominator must also be divided by 100. Two examples are: express the grams of solute per 100 grams of solution, or express the centigrams (cg) of solute per 1 g of solution The latter example works because 100 cg is equivalent to 1 g. Complete the following statements regarding how many grams of KI are found in either 100 g or 1 kg of a 2.5% solution of KI.

a. A 2.5% (by mass) solution concentration signifies that there is ______ of solute in every 100 g
b. Therefore, when 2.5% is expressed as a ratio of solute mass over solution mass, that mass ratio would be ________
c. A solution mass of 1 kg is _______ times greater than 100 g, thus one kilogram (1 kg) of a 2.5% KI solution would contain ____________of

Answers

Answer:

a. 2.5 g

b. 0.025

c. i. 10 times ii 25 g of KI

Explanation:

a. A 2.5% (by mass) solution concentration signifies that there is ______ of solute in every 100 g

Since % by mass = mass of solute, m/mass of solvent,M × 100 %

2.5 % = m/M × 100%

since M = 100 g,

2.5 % = m/100 × 100 %

m/100 = 2.5/100

m = 2.5 g

b. Therefore, when 2.5% is expressed as a ratio of solute mass over solution mass, that mass ratio would be ________

The mass ratio = mass of solute/mass of solvent

= m/M

= 2.5 g/100 g

= 0.025

c  A solution mass of 1 kg is _______ times greater than 100 g, thus one kilogram (1 kg) of a 2.5% KI solution would contain ____________of

i. A solution mass of 1 kg is _______ times greater than 100 g

Since 1 kg = 1000 g, 1 kg/100 g = 1000 g/100 g = 10

So,1 kg is 10 times greater than 100 g.

ii. Thus one kilogram (1 kg) of a 2.5% KI solution would contain ____________of KI

So, if M = 1 kg = 1000 g, we find m

Since % by mass = mass of solute, m/mass of solvent,M × 100 %

2.5 % = m/M × 100%

since M = 1000 g,

2.5 % = m/1000 × 100 %

m/1000 = 2.5/100

m = 2.5/100 × 1000 g

m = 2.5 × 10 g

m = 25 g

The exhaust from car engines spreads throughout our atmosphere and adds to pollution. What is this an example of?


A.

An increase in enthalpy


B.

An increase in thrust


C.

An increase in thermodynamics


D.

An increase in entropy

(D is the correct answer!)

Answers

Answer: When exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

Explanation:

A degree of randomness in the molecules of a substance is called entropy.

When exhaust from car engines spreads throughout our atmosphere then it means the molecules are moving at a faster speed due to which they spread into the atmosphere rapidly.

This means that the entropy of exhaust is increasing.

Thus, we can conclude that when exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

An increase in entropy

Determine how many pennies are in the stack on the left in the photograph at the beginning of this module. Create a conversion factor to calculate how many pennies are in the photo, knowing that there are 12 stacks of pennies.

Answers

Answer:

I had the answer

Explanation:

Moles to particles Now suppose you want to determine how many particles of sucrose are ... Driving Question Board Have students revisit the DQB to remind themselves of the Unit and Module questions.

Convert a pressure of 250 torr to atm a) 0.266 atm b) 0.279 atm c) 0.329 atm d) 0.297 atm

Answers

Answer:

C

Explanation:

1atm=760torr

X=250torr

Cross multiply

760torrX=250torr*atm

Divide both sides by 760torr

X=250torr*atm/760torr

X=0.32895atm

X=0.329atm

Option C is collect

The masses of carbon and hydrogen in samples of four pure hydrocarbons are given above. The hydrocarbon in which sample has the same empirical formula as propene, C3H6

Sample Mass of carbon Mass of hydrogen
A 60g 12g
B 72g 12g
C 84g 10g
D 90g 10g

a. Sample A
b. Sample B
c. Sample C
d. Sample D

Answers

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

30. Which of the following atoms would form
a trivalent anion?
A. Aluminium
B. Oxygen
C. Lithium
D. Nitrogen​

Answers

Aluminium and Nitrogen!

I think the answer is D. nitrogen .

The chemical equation below is unbalanced.
NaOH + H3PO4 -> Na3PO4 + H2O
When the equation is correctly balanced, what will be the coefficient of H2O?

Answers

Answer:

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

Explanation:

This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.

When the equation is balanced, and the coefficient of H₂O is 3.

To balance the chemical equation:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + H₂O

The number of atoms of each element is the same on both sides of the equation.

Balance the hydrogen atoms. There are three hydrogen atoms on the left side and two hydrogen atoms on the right side. To balance the hydrogen atoms, multiply H₂O by a coefficient of 3:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + 3H₂O

If the oxygen (O) atoms are balanced. There are four oxygen atoms on the right side, but only two oxygen atoms on the left side. To balance the oxygen atoms, we need to multiply NaOH by a coefficient of 2.

To learn more about the chemical equation, follow the link:

https://brainly.com/question/28792948

#SPJ6

what's the difference between ionic bond and molecular or covalent bond?
pls be serious and help me understand​

Answers

Answer:

It's all about understanding the concept, see my explanation.

Explanation:

A ionic bond is formed between a metal element and a non metal element always. On the other hand, a molecular bond or covalent bond is formed between 2 elements which are both non metals. A ionic bond is made when there is a electron transfer occurring meaning that one element is giving it's electron to another to ethier become a postive or negative ion. Whereas a molecular bond is made when two non metals elements share there electrons.

• An example of a ionic bond would be MgCl2 as we know magnesium is a metal and chlorine is a non metal.

• An example of a molecular bond would be NF

which we know are both non metals.

3. Suppose you had titrated your vinegar sample with barium hydroxide instead of sodium hydroxide:

Ba(OH)2(aq)+2CH3COOH(aq)⟶Ba(CH3COO)2(aq)+2H2O(l)

Consider a 0.586 M aqueous solution of barium hydroxide,

What volume (in mL) of 0.586 M Ba(OH)2 solution are required to neutralize 10 ml of vinegar containing 2.78 g of acetic acid?

Answers

Answer:

39.6 mL

Explanation:

Step 1: Write the balanced neutralization reaction

Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)

Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH

The molar mass of CH₃COOH is 60.05 g/mol.

2.78 g × 1 mol/60.05 g = 0.0463 mol

Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH

The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.

Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂

0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL

4-ethylbenzoyl chloride structure

Answers

Answer:

Ethylbenzoyl chloride | C9H9ClO

If 56.8 g of FeCl, are formed, how many grams of Fe reacted?
(Explain or show work plz)

Answers

Answer:

the molar mass for Fe and Cl

Help please...balance the equations. Extra points!

Answers

A:2KClO3=2KCl+3O2 hope it helps ! Don't know the rest
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