A current of 5 a flows in a copper wire for 20 s. how many coulombs of charge passed through the wire in this time?

Answers

Answer 1

Answer:

I think so too

Explanation:

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Related Questions

Why is it important for equipment for sport to be strong? To protect us

Answers

Answer:

To protect us.

Explanation:

For ex. your dunking on a basketball hoop if that wasn't strong you would fall on your back and get injured.

Which of the following is form of energy:
a) Power
b) Light
C) pressure
d) None​

Answers

Answer:

Explanation:

b) light

A child moving at constant velocity carries a 2 N ice-cream cone 1 m across a level surface. What is the net work done on the ice-cream cone?

Answers

Answer:

2 Joule

Explanation:

Work=force *dISPLACMENT

2N*1M

2 JOUL

24. A anvil with a mass of 60 kg falls from a height of 9.5 m. How fast is it going right
before it hits the ground?

V= I*R

V = voltage (measured in volts) V

I = current (measured in amperes) A

R = resistance (measured in Ohms) Ω

Answers

So they give us this

V=IR

V= 1.8

I=0.4

R=?

So we insert the thing that we know.

1.8=0.4*R

We need to leave our unknown value alone. So if our value of 0.4 is multiplying the unknown value it passes to the other side dividing.

So we have this.

Lastly we solve.

R=4.5ohms

The formula to find R is V=IR

V/I=R

So the resistance will be the Voltage divided by the Current

g a mass of 1.3 kg is pushed horizontally against a massless spring with a spring constant of 58 n/m until the spring compresses 19.5 cm if the mass is then released what is the kinetic energy of the mass when it is no longer in contact with the spring ignore friction

Answers

Answer: [tex]1.102\ J[/tex]

Explanation:

Given

Mass [tex]m=1.3\ kg[/tex]

Spring constant [tex]k=58\ N/m[/tex]

Compression in the spring [tex]x=19.5\ cm\ or\ 0.195\ m[/tex]

When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.

[tex]\Rightarrow \dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}\cdot 58\cdot (0.195)^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}mv^2=1.102\ J[/tex]

The kinetic energy of the mass is 1.102 J.

Two parallel slits are illuminated by light composed of two wavelengths, one of which is 657 nm. On a viewing screen, the light whose wavelength is known produces its third dark fringe at the same place where the light whose wavelength is unknown produces its fourth-order bright fringe. The fringes are counted relative to the central or zeroth-order bright fringe. What is the unknown wavelength

Answers

Answer:

     λ = 5.75 10⁻⁷ mm

Explanation:

This is a slit interference exercise, we analyze each wavelength separately                    

            λ = 657 nm                                     indicate that the third dark pattern

          a sin θ = (m + ½) lam

          a sin θ = (3 + ½) 657 10⁻⁹

          a sin θ = 2299.5 10⁻⁹ nm

for the other wavelength in the same place we have m = 4 bright

          a sin θ = m lam

           

we substitute

           2299.5 10⁻⁹ = 4 λ

           λ = [tex]\frac{2299.5 \ 10^9 }{ 4}[/tex]

           λ = 5.75 10⁻⁷ mm

There are three 20.0 Ω resistors connected in series across a 120 V generator

Answers

Answer:

That is equal to R1 + R2. If three or more unequal (or equal) resistors are connected in series then the equivalent resistance is: R1 + R2 + R3 +…, etc. One important point to remember about resistors in series networks to check that your maths is correct.

g Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit

Answers

Answer:

d = 1.19 x 10⁻⁴ m = 0.119 mm

Explanation:

This problem can be solved by using Young's double-slit experiment formula:

[tex]Y = \frac{\lambda L}{d}[/tex]

where,

Y = fringe spacing = 32 mm = 0.032 m

L = slit to screen distance = 6 m

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

d = slit width = ?

Therefore,

[tex]0.032\ m = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{d}\\\\d = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{0.032\ m}[/tex]

d = 1.19 x 10⁻⁴ m = 0.119 mm

A 0.413 kg block requires 1.09 N
of force to overcome static
friction. What is the coefficient
of static friction?
(No unit)

PLEASE HELP!

Answers

Answer:

static friction=0.126

1. Pam has a mass of 48.3 kg and she is at rest on
smooth, level, frictionless ice. Pam straps on
a rocket pack. The rocket supplies a constant
force for 27.3 m and Pam acquires a speed of
62 m/s.
What is the magnitude of the force?
Answer in units of N.

2. What is Pam’s final kinetic energy?
Answer in units of J.

3. A child and sled with a combined mass of 55.7
kg slide down a frictionless hill that is 11.3 m
high at an angle of 29 ◦
from horizontal.
The acceleration of gravity is 9.81 m/s

3. If the sled starts from rest, what is its speed
at the bottom of the hill?
Answer in units of m/s

Answers

Answer:

1. F = 3400 N = 3.4 KN

2. [tex]K.E_f=92832.6\ J = 92.83\ KJ[/tex]

3. v = 14.9 m/s

Explanation:

1.

First, we will calculate the acceleration of Pam by using the third equation of motion:

[tex]2as = v_f^2-v_i^2[/tex]

where,

a = acceleration = ?

s = distance = 27.3 m

vf = final speed = 62 m/s

vi = initial speed = 0 m/s

Therefore,

[tex]2a(27.3\ m) = (62\ m/s)^2-(0\ m/s)^2\\\\a = 70.4\ m/s^2[/tex]

Now, we will calculate the force by using Newton's Second Law of Motion:

F = ma

F = (48.3 kg)(70.4 m/s²)

F = 3400 N = 3.4 KN

2.

Final kinetic energy is given as:

[tex]K.E_f = \frac{1}{2}mv_f^2\\\\K.E_f = \frac{1}{2} (48.3\ kg)(62\ m/s)^2[/tex]

[tex]K.E_f=92832.6\ J = 92.83\ KJ[/tex]

3.

According to the law of conservation of energy:

[tex]Potential\ Energy\ at\ top = Kinetic\ Energy\ at\ bottom\\mgh = \frac{1}{2}mv_2 \\\\v = \sqrt{2gh}[/tex]

where,

v = speed at bottom = ?

g = acceleration due to gravity = 9.81 m/s²

h = height at top = 11.3 m

Therefore,

[tex]v = \sqrt{(2)(9.81\ m/s^2)(11.3\ m)}[/tex]

v = 14.9 m/s

Light travels at 300,000,000 m/s. This is an example

Answers

Answer:

ook soooooo

Explanation:

A 35.0 g bullet strikes a 5.3 kg stationary wooden block and embeds itself in the block. The block and bullet fly off together at 7.1 m/s. What was the original speed of the bullet? (WILL GIVE BRAINLIEST)​

Answers

Answer:

= 1200m/s or 1.2 x [tex]10^{3}[/tex] m/s

Explanation:

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What is the longest wavelength that forms an intensity maximum in the fifth order

Answers

Answer:

377 nm

Explanation:

Number of lines per meter is, [tex]N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}[/tex]

Grating element is, [tex]d=\frac{1}{N}[/tex]

[tex]=1.8868 \times 10^{-6} \mathrm{~m}[tex]

Order is, n=5

Condition for maximum intensity is, [tex]d \sin \theta=n \lambda[/tex]

 [tex]\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\ &=0.377 \times 10^{-6} \mathrm{~m} \\ &=377 \mathrm{~nm}[/tex]

An old fashioned string of 80 Christmas lights is wired in series. Each bulb has a resistance of 2 Ohms and the entire string is plugged into a 120V outlet. What is the current passing through each of the bulbs?

Answers

The sum of the resistance = 2 ohms x 80 lights = 160 ohms.

Current = Total voltage / total resistance:

Current = 120V / 160 ohms

Current = 0.75 Amps

If an electromagnetic wave has a frequency of 6×10^5 hz, what is its wavelength? ​ what is its wavelength? A. 2 x 10^12m, B. 5 x 10^14m, C. 5 x 10^2m, 2 x 10^-3m

Answers

Answer:

5*10^2

Explanation:

A p e x

The illustration shows ?
A)open circuit
B)broken circuit
C)series circuit
D)parallel circuit

Answers

Answer:

D)parallel circuit

Explanation:

the components are placed parallel from eachother

D. Parallel circuit

A magnetic field of 0.27 T exists in the region enclosed by a solenoid that has 599 turns and a diameter of 9.29 cm. Within what period of time must the field be reduced to zero if the average magnitude of the induced emf within the coil during this time interval is to be 12.8 kV

Answers

Answer: [tex]8.54\times 10^{-5}\ s[/tex]

Explanation:

Given

The initial magnetic field is [tex]B=0.27\ T[/tex]

No of turns [tex]N=599\ \text{turns}[/tex]

Diameter of the solenoid [tex]d=9.29\ cm[/tex]

Induced EMF [tex]E=12.8\ kV[/tex]

Induced emf is the product of no of turns and rate of change of flux.

[tex]\Rightarrow E=-N\cdot \dfrac{\Delta \phi }{\Delta t}\\\\\Rightarrow E=-N\cdot \dfrac{\Delta (B\cdot A)}{\Delta t}\\\\\Rightarrow E=-NA\cdot \dfrac{\Delta B}{\Delta t}\\\\\text{Insert the values}\\\\\Rightarrow 12.8=-599\times \pi r^2\cdot \dfrac{(0-B)}{\Delta t}\\\\\Rightarrow \Delta t=\dfrac{599\times \pi \times (4.64\times 10^{-2})\times 0.27}{12.8\times 10^3} \\\\\Rightarrow \Delta t=854.71\times 10^{-7}\ s\\\\\text{Taking absolute value}\\\Rightarrow \Delta t=8.54\times 10^{-5}\ s[/tex]

True False: Marke each statement as true or false.
shift
1. Light intensity affects the rate of photosynthesis.
in
2. Energy is required by all organisms for life.
3. The ability of a plant to repair tissue depends on respiration.
4. The gas needed for photosynthesis is carbon dioxide (CO2).
5. Plants only carry on photosynthesis, not respiration.
6. Respiration can occur without photosynthesis.

Answers

Answer:

1) true 2) true 3) true 4) true 5) false 6) false

Explanation:

A chemist measures the flow of charged ions through a circuit. Which of these would increase the current? Select all that apply.

Answers

2,3 and 5 should be right

The diagram below shows a person swinging a hammer.

Which position has the least amount of kinetic energy?

A-1
B-2
C-3
D-4


Answers

4 because its not yet moving. It has kinetic energy, it just hasn’t been used yet.

Moving current has electrical energy.

Answers

Yes, that’s true it has electrical energy

is it possible to have rainbows during the fine sunny day? Explain your answer.​

Answers

Answer:

As long as there is rain, a rainbow is possible. Rain is possible on a sunny day, and is known as a sunshower.The rainbow can be observed in a sunny day if the water droplets are present in air and the sun rays pass through it reaches the eye of the observer. In this situation, the observer can see a rainbow.

or

If you happened to look up at the sky this past weekend, you might have noticed a rare and beautiful sight: iridescent rainbow clouds, but not a drop of rain in sight. This phenomenon is known, fittingly, as cloud iridescence or irisation. The effect is not unlike seeing a rainbow painted on the clouds.

Help


An object’s mass 300 kg is observed to accelerate at the rate of 4 m/s^2. Calculate the force required to produce this acceleration. *


1. 1000 N
2 .75 N
3. 1200 N
4. 1250 N

Answers

The answer for this is 1200N

Which of the following means that an
image is real?
A. +do
B. +di
c. -di
D.-do

Answers

Answer:

B

Explanation:

paano matutugunan o matutulungan ng pamahalaan at ng mga guro yubg mga estudyanteng nakararanas nag stress at anxiety.

Answers

Answer: how the government and teachers can address or help students experiencing stress and anxiety.

Explanation:

4- What force must be applied to a surface area of 0.0025m , to create a pressure ol
200.000Pa?​

Answers

Force = area * pressure
F = 0.0025 m * 200000 pa
F = 500 N

An electrical insulator is a material that:
A) contains no charge
B) does not allow electrons to flow
C) has more protons than electrons
D) must be a crystal

Answers

Answer:

Option B is appropriate for this question

Help me with this please

Answers

Answer:

check out of phase

Explanation:

this is my answer


9. Cellular respiration occurs in what types of cells?

Answers

Answer:

Cellular respiration takes place in the cells of all organisms. It occurs in autotrophs such as plants as well as heterotrophs such as animals. Cellular respiration begins in the cytoplasm of cells. It is completed in mitochondria

Explanation:

Cellular respiration takes place in the cells of all organisms. It happening in autotrophs such as plantas as well as heterotrophs such as animals. Cellular respiration starts in the cytoplasm of cells.

It is finished in mitochondria.

A boat that can travel at 4.60 km/h in still water crosses a river with a current of 1.80 km/h. At what angle must the boat be pointed upstream to travel straight across the river

Answers

Answer:

The angle the boat must be pointed upstream is 69⁰

Explanation:

Check the image uploaded for the diagram;

Given;

speed of the boat on still water, = 4.6 km/h

speed of the boat on a river with current, = 1.8 km/h

The angle the boat must be pointed upstream is calculated as follows

[tex]tan(\theta) = \frac{4.6}{1.8} \\\\tan(\theta) = 2.556\\\\\theta = tan^{-1}(2.556)\\\\\theta = 68.63^0\\\\\theta = 69^0[/tex]

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