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2055 Q. No. 10^-2
mole of KOH is dissolved in 10 litres of
water. What will be the pH of the solution?
12
Ans: pH = 11
Answers
Answer:
11
Explanation:
Moles of KOH = [tex]10^{-2}[/tex]
Volume of water = 10 liters
Concentration of KOH is given by
[tex][KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}[/tex]
[tex][KOH][/tex] is strong base so we have the following relation
[tex][KOH]=[OH^{-}]=10^{-3}\ \text{M}[/tex]
[tex]pOH=-\log [OH^{-}]=-\log10^{-3}[/tex]
[tex]\Rightarrow pH=14-3=11[/tex]
So, pH of the solution is 11
The density of gold is 19.3 g/cm³. Which of the following shows the mass of a gold bar that is 4.50 cm × 8.00 cm × 20.00 cm?
Answers
Answer:
13896g
Explanation:
volume = 4.50×8.00×20.00 = 720 cm³
mass = density × volume
mass= 19.3 × 720 = 13896g
Please help me ASAP I’ll mark Brainly
Answers
Answer:
Batteries hold chemical energy
Explanation:
The battery acid in a battery leads to chemical energy.
Element X has two naturally occurring isotopes, 65X (isotopic mass 65.0457 amu, abundance 20.53%) and 67X (isotopic mass 66.9704 amu, abundance 79.47%). Calculate the atomic mass of element X.
Answers
Answer:
66.5753 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A (⁶⁵X):
Mass of A = 65.0457 amu
Abundance of A = 20.53%
Isotope B (⁶⁷X):
Mass of B = 66.9704 amu
Abundance of B = 79.47%
Atomic mass of X =?
The atomic mass of X can be obtained as follow:
Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]
= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]
= 13.3539 + 53.2214
= 66.5753 amu
Therefore, the atomic mass of X is 66.5753 amu.
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
What is the average atomic mass?The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.
Element X has 2 isotopes:
⁶⁵X with an isotopic mass of 65.0457 amu and an abundance of 20.53% (0.2053).⁶⁷X with an isotopic mass of 66.9704 amu and an abundance of 79.47% (0.7947).We can calculate the average atomic mass of X using the following expression.
mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X
mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947
mX = 66.58 amu
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
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Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 3.00 molesmoles of aluminum sulfate, Al2(SO4)3Al2(SO4)3. Express the number of moles of AlAl, SS, and OO atoms numerically, separated by commas.
Answers
Answer:
[tex]n_{Al}=6.00molAl\\\\n_{S}=9.00molS\\\\n_{O}=36.0molO[/tex]
Explanation:
Hello!
In this case, when analyzing the moles of an element inside a compound, we need to keep in mind that a mole ratio should be set up; thus, for aluminum sulfate, we have the following ones:
[tex]\frac{2molAl}{1molAl_2(SO_4)_3} \\\\\frac{3molS}{1molAl_2(SO_4)_3} \\\\\frac{12molO}{1mol1molAl_2(SO_4)_3}[/tex]
Thus, starting by 3.00 moles of aluminum sulfate, the moles of each element turn out:
[tex]n_{Al}=3.00molAl_2(SO_4)_3*\frac{2molAl}{1molAl_2(SO_4)_3} =6.00molAl\\\\n_{S}=3.00molAl_2(SO_4)_3*\frac{3molS}{1molAl_2(SO_4)_3} =9.00molS\\\\n_{O}=3.00molAl_2(SO_4)_3*\frac{12molO}{1molAl_2(SO_4)_3}=36.0molO[/tex]
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what would be a logical explanation for why carbon dioxide increased over the time shown in the graph.
A. the area of land for crops incresed
b. the amount of plants eaten by animal increased
c. the amount of fossil fuels being burned increased
d. the amount of wood being burned by pepole increased
Answers
Answer:
c. the amount of fossil fuels being burned increased
Explanation:
Carbon dioxide gas concentration increased over the time due to burning of fossil fuels increased. Fossil fuels are organic compounds which releases carbondioxide gas as a result of burning of fossil fuels in the engines of vehicles and industries. With the passage of time, number of vehicles increases in the world which needs more fossil fuels and due to burning of that fossil fuels, more carbondioxide gas is released.
Nitrogen can exist as a solid, a liquid, or a gas. Which of the following lists the
phases of nitrogen in order of increasing density?
1. liquid, gas, solid
2. gas, liquid, solid
3. gas, solid, liquid
4. solid, liquid, gas
Answers
The phases of nitrogen in order of increasing density is solid, liquid, and gas.
Nitrogen is known to be odorless and colorless. Nitrogen makes up about 78% of the gases that we've in the atmosphere. It has an atomic number of 7 and is represented with the symbol N.It should be noted that nitrogen can be a solid, a liquid or a gas. When nitrogen is at ordinary pressure, it is known to be a gas. In a case whereby nitrogen is below 77°K, then it's a liquid and it's a solid when it's below 63°K.The density explains the mass per unit volume that nitrogen has when it's either at gaseous, solid or liquid state. It should be noted that the highest density is at its gaseous state.Therefore, the phases of nitrogen in order of increasing density will then be solid, liquid, and gas.In conclusion, the correct option is D.
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