A copper telephone wire has essentially

A Copper Telephone Wire Has Essentially

Answers

Answer 1

Answer:

128.21 m

Explanation:

The following data were obtained from the question:

Initial temperature (θ₁) = 4 °C

Final temperature (θ₂) = 43 °C

Change in length (ΔL) = 8.5 cm

Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)

Original length (L₁) =.?

The original length can be obtained as follow:

α = ΔL / L₁(θ₂ – θ₁)

17×10¯⁶ = 8.5 / L₁(43 – 4)

17×10¯⁶ = 8.5 / L₁(39)

17×10¯⁶ = 8.5 / 39L₁

Cross multiply

17×10¯⁶ × 39L₁ = 8.5

6.63×10¯⁴ L₁ = 8.5

Divide both side by 6.63×10¯⁴

L₁ = 8.5 / 6.63×10¯⁴

L₁ = 12820.51 cm

Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

12820.51 cm = 12820.51 cm × 1 m / 100 cm

12820.51 cm = 128.21 m

Thus, the original length of the wire is 128.21 m


Related Questions

what is resistance ​

Answers

Answer:

Resistance is the measure of the opposition to current flow in an electrical circuit

Resistance refers to the opposition or hindrance that a material or object offers to the flow of electric current. It is a fundamental concept in the field of electrical engineering and physics.

Resistance is measured in ohms (Ω) and is denoted by the symbol "R."

In electrical circuits, resistance is caused by various factors, including the type of material, its dimensions, and its temperature.

The primary element contributing to resistance is the collisions between electrons and atoms within the material through which the current is passing.

When an electric current flows through a conductor, such as a wire, the electrons move along the path of the conductor. However, as they do so, they encounter resistance.

This resistance causes the electrons to collide with atoms, which generates heat and dissipates energy.

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If the sound level at a point is 98.0 dB, what is the intensity of sound at that point (Unit=W/m^2)? please help will give brainliest

Answers

Explanation:

The decibel scale is a logarithmic scale where each bel or 10 decibels correspondents to a factor of ten. A power intensity of 10^(-12) watts per square meter is the standard reference for a SPL of 0 db. So an SPL of 98 db corresponds to a power intensity of 10^(9.8)*10^(-12) or 10^(9.8–12) w/m^2.

0.006309573 w/m^2.

The kinetic energy of an object is equal to one half Its mass multiplied by its
speed
A squared
B cubed
C to the fourth power
D to the fifth power

Answers

the answer is B cubed

What is the Kinetic Energy of a 60 kg person on skis traveling 20 m/s?

(KE = ½ mv2)

Remember ENERGY is measured in JOULES!24,000 Joules


1,200 Joules


12,000 Joules


600 Joules

Answers

Explanation:

equating the parameters into the formula, it's gonna be

= ½ × 60 × 20²

= ½ × 60 × 400

= ½ × 24000

K.E = 12000J

The paper record of the earthquake data

Answers

a seismogram is the right answer.

A small rock is thrown straight up with initial speed V0 from
the edge of the roof of a building with height H. The rock travels upward
and then downward to the ground at the base of the building. Let
+y be upward, and neglect air resistance. (a) For the rock’s motion from
the roof to the ground, what is the vertical component Vav-y of its average
velocity? Is this quantity positive or negative? Explain. (b) What
does your expression for Vav-y give in the limit that H is zero? Explain.
(c) Show that your result in part (a) agrees with Eq. (2.10).

Hugh D. Young, Roger A. Freedman - University Physics with Modern Physics (15th Edition) Chap. 3 Ex. 73

Answers

Answer:

12 feet

Explanation:

The vertical component of the velocity v upwards will be v0sinθ, where the angle is formed with respect to the y axis.

What is velocity ?

Velocity of a moving object is the measure of its distance travelled per unit time. Velocity is a vector quantity having both magnitude and direction. Acceleration is the rate of change in velocity.

Here, the initial velocity is given V0. It is the product of acceleration g and time t. thus, u = gt.

The height travelled within the time t and acceleration g, is written as:

h = 1/2 gt²

The two components of velocity in the two axis are,

vertical component = v sinθ

Horizontal component = v cosθ.

Here, the vertical component along the y -axis with an angle θ being V0 sinθ. This velocity will be positive.

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What is the period of the wave motion for a wave with a frequency of 0.68 kHz?
____s

Answers

Answer:

T = 1.47 ms

Explanation:

We need to find the period of the wave motion for a wave of frequency 0.68 kHz.

Let the period be T. We know that,

T = 1/f

So,

[tex]T=\dfrac{1}{0.68\times 10^3}\\\\T=1.47\times 10^{-3}\ s\\\\T=1.47\ ms[/tex]

So, the period of the wave motion is 1.47 ms.

Which of these types of EM radiation has the most energy?*
Radio waves
UV waves
Microwaves
O X-rays

Answers

If you look at a em spectrum you see that it’s X-rays while radio waves have the least

A geosynchronous satellite orbits Mars (mass = 6.42 x 1023 kg) once every Martian day, 88640 s. At what radius does it orbit?

Answers

Answer:

angular speed ω = 2PI / T rad/sec  

ω^2*r = M*G/r^2

r = ³√ M*G/ω^2 = ³√6.42*10^23*6.67*10^-11*88640^2/39.5 = 2.04*10^7 m

Explanation:

A geosynchronous satellite orbits Mars once every Martian day, 88640 s then the radius of the orbit will be equal to 2.04 × 10⁷ m.

What is gravity?

The fundamental force of attraction operating on all matter is recognized as gravity, also spelled gravity, in mechanics. It has no impact on identifying the interior properties of common matter because it is the weakest force known to exist in nature.

As per the given data in the question,

Mass, m = 6.42 x 10²³ kg

Time, T = 88640 s

Use the formula of velocity for satellite,

v = 2πR/T

Where R represents the radius

Use the formula of centripetal acceleration,

[tex]a_c[/tex] = v²/R

Thus;

[tex]a_c[/tex] = (2πR/T)²/R

= 4π²R/T²

The formula for gravitational acceleration is:

[tex]a_g[/tex] = Gm/R²

G = 6.674 × 10⁻¹¹ m³/kg. s²

Now, the satellite's gravitational acceleration is what is responsible for its centripetal acceleration. Thus,

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Substitute the values in the above equation,

R = ∛((6.674 × 10⁻¹¹ × 6.42 x 10²³ × 88640²)/(4 × π²))

R = 2.04 × 10⁷ m

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A lever was used to life heavy rock. The input force was 150 N and the output force was 500 N. What was the mechanical advantage of the pulley?

Answers

MA = fo / fi = 500 N / 150 N = 3.3. So C.

Emma draws another diagram showing how adding energy affects this wave. How does her new diagram compare to this diagram?
A
Her diagram shows higher wavelengths.
B
Her diagram shows lower wave amplitudes.
С
Her diagram shows lower wave frequencies.
D
Her diagram shows higher wave amplitudes.

HELPPPP MEEE PLEASEEEE 55 POINTS!!!

Answers

Skansen ah w very video ne lol lay

What is the wavelength of a wave?

Answers

The wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.

If the initial velocity of a ball is sent straight upward at 10.5m/s from the ground what will its final velocity be when it hits the ground at the end of its flight?

Answers

Answer: -10.08 m/s

Explanation:

Here we only need to analyze the vertical problem.

When the ball is in the air, the only force acting on it will be the gravitational force, this means that the acceleration of the ball, is equal to the gravitational acceleration, then:

a(t) = -9.8m/s^2

Where the negative sign is because gravity pulls the ball down.

To get the velocity equation we need to integrate over time, we get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity, here it is v0 = 10.5 m/s

Then the velocity equation is:

v(t) =  (-9.8m/s^2)*t + 10.5 m/s

To get the position equation, we need to integrate again over time, we get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t + p0

Where p0 is the initial position, we know that the ball is sent upward from the ground, so p0 = 0m

Then the position equation is:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

Now we need to find the value of t such that the position is equal to zero (this means that the ball hits the ground again).

Then we need to solve:

p(t) = 0 =  (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

If we divide both sides by t, we get:

0 =   (1/2)*(-9.8m/s^2)*t + (10.5 m/s)

Now we can solve it:

(1/2)*(9.8m/s^2)*t = 10.5 m/s

t = (10.5 m/s)/((1/2)*(9.8m/s^2)) = 2.14 s

This means that after 2.14 seconds, the ball will hit the ground again.

The velocity of the ball when it hits the ground is equal to:

v(2.14s) = (-9.8m/s^2)*2.14s + 10.5 m/s = -10.08 m/s

What is the net force on a race car with a mass of 1200 kg if its acceleration is 32.0m/s2 West?

Answers

Answer:

38400N

Explanation:

F=mass×acceleration

=1200×32

=38400

A 1500 kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2500 kg SUV traveling from east to west. The two cars become enmeshed due to the impact and slide as one thereafter. On-the-scene measurements show that the coefficient of kinetic friction between the tires of these cars and the pavement is 0.750, and the cars slide to a halt at a point 5.48 m west and 6.37 in south of the impact point. How fast was sedan traveling just before the collision? How fast was SUV traveling just before the collision?

Answers

Answer:

v = 19.33 m / s   South

Explanation:

To solve this exercise we must use the conservation of momentum, for which we must define a system formed by the two cars, therefore the forces during the collision are internal and therefore the moment is conserved.

Since it is a vector quantity, we are going to work on each axis, the x axis is in the East-West direction

initial instant. Before the crash

        p₀ = m 0 + M v₂ₓ

final instant. Right after the crash

        p_f = (m + M) vₓ

        p₀ = 0_pf

        M v₂ₓ = (m + M) vₓ

In this case m is the mass of the car and M the mass of the SUV

        vₓ = [tex]\frac{M}{m+My}[/tex]  v₂ₓ            (1)

in the Y axis (North - South direction)

initial instant

       p₀ = m v_{1y} + M 0

final moment

       p_f = (m + M) v_y

       p₀ = p_f

       m v_{1y} + M 0 = (m + M) v_y

       v_y = [tex]\frac{m}{m+M} \ v_{1y}[/tex]       (2)

With these speeds we can use the relationship between work and the variation of kinetic energy, in this part the two cars are already united.

         W = ΔK

friction force work is

         W = - fr d

the friction force is described by the equation

         fr = μ N

Newton's second law

         N-W = 0

         N = W

         

we substitute

         W = - μ (m + M) g d

as the car stops the final kinetic energy is zero and

the initial kinetic energy is

         K₀ = ½ (m + M) v²

we substitute

         - μ (m + M) g d = 0 - ½ (m + M) v²

            μ g d = ½ v²

            v² = 2 μ g d

the distance traveled can be found with the Pythagorean theorem

        d = [tex]\sqrt{x^2+y^2}[/tex]

        d = [tex]\sqrt{5.48^2 + 6.37^2}[/tex]

        d = 8.40 m

let's calculate the speed

         v² = 2 0.75 9.8 8.40

         v = √123.48

         v = 11.11 m / s

this velocity is in the direction of motion so we can use trigonometry to find the angles

          tan θ = y / x

          θ = tan⁻¹ y / x

          θ = tan⁻¹ (-5.48 / -6.37)

          θ = 40.7º

Since the two magnitudes are negative, this angle is in the third quadrant, measured from the positive side of the x-axis in a counterclockwise direction.

          θ'= 180 + 40.7

          θ’= 220.7º

In the exercise they indicate the the sedan moves in the y-axis, therefore

          sin θ'= v_y / v

          v_y = v sin 220.7

          v_y = 11.11 sin 220.7

          v_y = -7.25 m / s

the negative sign indicates that it is moving south

To find the speed we substitute in equation 2

          v_y = [tex]\frac{m}{m+M} \ v_{1y}[/tex]

          v_{1y} = v_ y   [tex]\frac{m+M}{m}[/tex]

           

let's calculate

         v_{1y} = -7.25    [tex]\frac{1500+2500}{1500}[/tex]

         v_{1y} = - 19.33 m/s

therefore the speed of the sedan is v = 19.33 m / s with a direction towards the South

a tire rolls from rest to an angular velocity of 6 radians per second. the angle it turns through is 12 radians. what is the angular acceleration of the tire?

Answers

Answer:

[tex]\alpha =1.5\ rad/s^2[/tex]

Explanation:

Given that,

Initial angular velocity, [tex]\omega_i=0[/tex]

Final angular speed, [tex]\omega_f=6\ rad/s[/tex]

Angular displacement, [tex]\theta=12\ rad[/tex]

We need to find the angular acceleration of the tire. We can find it using the third equation of rotational kinematics. So,

[tex]\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{\omega_f^2-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{6^2-0^2}{2\times 12}\\\\\alpha =1.5\ rad/s^2[/tex]

So, the angular acceleration of the tire is equal to [tex]1.5\ rad/s^2[/tex].

True or False. In a parallel circuit, the voltage is the same anywhere in the circuit.

Answers

true! hope this helps:)

Answer:

true

Explanation:

in a parallel circuit, the voltage is the same

Tell me, Is universe created due to big bang???? Plz I want a bunch of para​

Answers

Answer:

shreya Sister's answer is correct hope it's help you have a good day

explain Heat with its unit

Answers

Answer:

As a form of energy, heat has the unit joule (J) in the International System of Units (SI). However, in many applied fields in engineering the British thermal unit (BTU) and the calorie are often used. The standard unit for the rate of heat transferred is the watt (W), defined as one joule per second

Explanation:

Hope it helps

What is the angular displacement In radians of a wagon that moves 270 around a circle path

Answers

Answer:

dont go to link they will track u

Explanation:

Where is the moon? Please help?

Answers

In space, because of its in space
The moon is in space and it orbits around earth

PLEASE HELP ME WITH THIS ONE QUESTION
A tuning fork of 500 Hz is struck in a room with a speed of sound of 340 m/s. What is the distance between a point of rarefaction and the next compression point, in the resulting sound?

Answers

Answer:

Wavelength = 0.68 meters.

Explanation:

Wavelength gives the distance between a point of rarefaction and the next compression point, in the resulting sound.

Given the following data;

Frequency = 500 Hz

Speed of sound = 340 m/s

To find the wavelength;

Wavelength = speed/frequency

Wavelength = 340/500

Wavelength = 0.68 meters

While riding a horse, the horse suddenly comes to an abrupt stop. You fly forward and
fall over the front of the horse.
What is the Newton law?

Answers

Answer:

For every action there is an opposite reaction.

Explanation:

A 10.0 kg mass is lifted 5.0 m above the ground.
Find the change in gravitational energy.

Answers

Answer:

500 J

Explanation:

formula of Energy is: E=mass*height*g, where g≈10 (m/s²).

according to the formula above: E=10*5*10≈500 (J)

PLEASE HELP!!!!!!




Is this correct?

Answers

The answer is A the wavelength of the waves do in fact change
change your awnser!! to a

STUDY QUESTIONS
1. (a) You are provided with a 15 cm long steel strip,
By using a permanent bar magnet explain how
you will magnetise the steel strip​

Answers

Answer:

The blade of sharpener is made up of iron. Iron is a magnetic material because of this pencil sharpener gets attracted by the poles of a magnet although the body is made up of plastic.

A form of energy NOT associated with the particles of objects is
thermal energy
mechanical energy
nuclear energy
chemical energy

Answers

Answer:

mechanical energy

Explanation:

because except mechanical energy all posseses particles

state two precautions to be taken when using a density bottle​

Answers

Explanation:

(i) The density bottle must be held by the neck to avoid expansion. (ii). The outside must be wiped clean. (iii).

Answer:

The density bottle must be held by the neck to avoid expansion The outside must be wiped clean

Explanation:

hope this help

Which statement best defines constructive interference? O Energy reflects back toward the source of its power. O Two waves with identical crests and troughs meet. thing O A wave appears to be at a standstill and vibrates in place O The trough of one wave matches the crest of another.​

Answers

Answer:

when the trough of one wave matches the crest of another

Explanation:

just took the test

Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader

Answers

Answer:

7.55 g

Explanation:

Heat of fusion = 333kj/kg

Heat capacity, c = 4190 j/kg /k

Heat capacity in j/g /k = 0.4190

Let the Number of grams of ice that will melt = n

Number of grams * heat of fusion = heat capacity * temperature change

n * 0.333 = 0.419 * (6-0)

0.333n = 2.514

n = 2.514 / 0.333

n = 7.5495

n = 7.55 gram

Hence, the number of gram of ice that will melt is 7.55 grams