A construction worker transfers 6000000 J in a n 8 hour day of work. What is their average power output? just need a quick answer with the working, thanks

Answers

Answer 1

Answer:

208.33 W

Explanation:

Using,

P = W/t.......................... Equation 1

P = Average power output, W = total work, t = total time.

From the question,

Given: W = 6000000 J, t = 8 hours = (8×60×60) = 28800 s

Substitute these values into equation 1

P = 6000000/28800

P = 208.33 W.

Hence the average power output is 208.33 W


Related Questions

PLEASE HELP—ITS PHYSICS AND I NEED ANSWERS ASAP

Answers

The answer is Point D.

If a motor is rated at 5.6KW, work done in 20minutes is equal to:​

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Answer:

given Power= 5.6×1000=5600watt

t=20min=20×60=1200sec. work done=?

P=w/t

w=pt=5600×1200=672×10^4Joule

The amount of work done by the motor is equal to 6.72 Megajoules.

Given the following data:

Time = 20 minutesPower = 5.6 Kilowatt = 5600 Watts.

Conversion:

1 minute = 60 seconds20 minutes = [tex]20 \times 60 = 1200[/tex] seconds.

To determine the amount of work done by the motor:

Mathematically, the work done by an object with respect to power and time is given by the formula:

[tex]Work\;done = power \times time[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 5600 \times 1200[/tex]

Work done = 6,720,000 Joules

Note: 1,000,000 Joules = 1 Megajoules.

Work done = 6.72 Megajoules.

Read more on work done here: https://brainly.com/question/13818347

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