Answer:
0.2231 = 22.31% of customers having to hold more than 4.5 minutes will hang up before placing an order
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
The length of waiting time was found to be a variable best approximated by an exponential distribution with a mean length of waiting time equal to 3 minutes.
This means that [tex]m = 3, \mu = \frac{1}{3}[/tex]
What proportion of customers having to hold more than 4.5 minutes will hang up before placing an order?
This is:
[tex]P(X > 4.5) = e^{-\frac{1}{3}*4.5} = e^{-\frac{4.5}{3}} = e^{-1.5} = 0.2231[/tex]
0.2231 = 22.31% of customers having to hold more than 4.5 minutes will hang up before placing an order
Can some one please help me find the solution of the question
Answer:
x=16°
Step-by-step explanation:
tanθ=opposite/adjacent
tan(<CAB)=BC/AB
<CAB=tan⁻¹(21/29)=35.9097308°
tanθ=opposite/adjacent
tan(<DAB)=BD/AB
<DAB=tan⁻¹((21/2)/29)=19.90374954°
<CAB=<DAB+x
x=<CAB-<DAB
=35.9097308-19.90374954
x=16.00598126°
What is the answer pls it’s for a grade
ab" that goes through points (0,9)
Write an exponential function in the form y
and (5,2187)
9514 1404 393
Answer:
y = 9(3^x)
Step-by-step explanation:
We assume you want a function in the form ...
y = a(b^x)
that passes through points (0, 9) and (5, 2187).
Filling in the given point values, we have ...
9 = a(b^0) = a
2187 = a(b^5) = 9(b^5) . . . . using the above value of 'a'
Dividing the second equation by 9 and taking the 5th root, we find b.
(2187/9) = b^5
243^(1/5) = b = 3
The exponential function is ...
y = 9(3^x)
Assume we cut the last piece of the pie into two sections (1 and 2) along ray BD
such that m∠ABD = 2x+3, m∠CBD = 4x+7, and m∠ABC = 40°. Based on this information,
would you ask for section 1 or section 2 (you have to pick one) for dessert? Provide numerical
evidence to back up your choice. Explain your reasoning and your methods.
Answer:
Section 2
Step-by-step explanation:
I will pick the section with the largest angle.
Let's determine the size of the angle of each section.
Given:
m∠ABD = 2x+3,
m∠CBD = 4x+7,
m∠ABC = 40°
Thus:
m<ABD + m<CBD = m<ABC (angle addition postulate)
Substitute
2x + 3 + 4x + 7 = 40
Add like terms
6x + 10 = 40
6x + 10 - 10 = 40 - 10
6x = 30
6x/6 = 30/6
x = 5
✔️m∠ABD = 2x+3
Plug in the value of x
m<ABD = 2(5) + 3 = 13° (section 1)
✔️m∠CBD = 4x+7
m∠CBD = 4(5) + 7
m∠CBD = 27° (section 2)
✅I will pick section 2 because it is the section with the largest angle, which means it is the biggest.
Evaluate each expression for the given value(s) of the variables(s).
Answer:
9. [tex] \frac{1}{10,000} = 0.0001 [/tex]
10. [tex] \frac{1}{81} [/tex]
Step-by-step explanation:
9. [tex] x^{-4} [/tex]
Evaluate when x = 10.
Substitute x = 10 into the expression
[tex] 10^{-4} [/tex]
Apply the negative exponent rule ([tex] a^{-n} = \frac{1}{a^n} [/tex])
Thus:
[tex] = \frac{1}{10^4} [/tex]
[tex] = \frac{1}{10^4} = \frac{1}{10,000} = 0.0001 [/tex]
10. [tex] 2a^{-1}b^{-3} [/tex]
Evaluate when a = 6 and b = 3
Substitute
[tex] (2*6^{-1})(3^{-3}) [/tex]
Apply the negative exponent rule
[tex] (2*\frac{1}{6})(\frac{1}{3^3}) [/tex]
[tex] (\frac{2}{6})(\frac{1}{27}) [/tex]
[tex] \frac{2*1}{6*27} [/tex]
[tex] \frac{1}{81} [/tex]
[tex]\huge{ \mathfrak{ \underline{ Answer }\: \: ✓ }}[/tex]
Question : 9plugging the value of x as 10, we get
[tex]\longrightarrow\: \: x {}^{ - 4} [/tex]
[tex]\longrightarrow\: 10 {}^{ - 4} [/tex]
[tex]\longrightarrow \dfrac{1}{10 {}^{4} } [/tex]
[tex] \longrightarrow\dfrac{1}{10000} [/tex]
[tex]\longrightarrow0.0001[/tex]
Question : 10plugging the value of
a as 6b as 3[tex]\longrightarrow2 {a}^{ - 1} b {}^{ - 3} [/tex]
[tex]\longrightarrow2 \times 6 {}^{ - 1} \times 3 {}^{ - 3} [/tex]
[tex]\longrightarrow \dfrac{2}{6 \times 27} [/tex]
[tex]\longrightarrow \dfrac{2}{162} [/tex]
[tex]\longrightarrow \dfrac{1}{81} [/tex]
_____________________________
[tex] \\ \\ \mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]
A manufacturer that specializes in hamburgers made 200 hamburger patties. The manufacturer claims that the weights of these patties are approximately normally distributed with a mean of 8 ounces and a standard deviation of 0.54 ounces. You go to a store and buy 5 randomly selected hamburgers and find that the mean weight of your 5 hamburgers is only 7.6 ounces.
Answer:
The answer is "Parameter: 8 ounces and Statistics: 7.6 ounces"
Step-by-step
Amount of restaurant hamburger packers = 200
Mean weight of its patties = 8 ounces
Specification Patty Deviation=0.54 ounces
Those who went to the supermarket and bought five hamburgers picked randomly.
The important weight of hamburgers = 7.6 ounces
For this case, we need to classify the sample population and test statistics.
The group comprises all elements that may probably be predefined, while a small number of findings from this wider group are taken from either the sample. The restaurants achieved a list of 200 hamburgers. Consequently, the population is made up of 200 patties. From 200 hamburgers accessible, I visit the shop or pick 5 hamburgers. So, five hamburgers arbitrarily selected are samples.
parameters:
The parameter is known for just about any value or metric representing or reflecting the entire nation. They know from the information that the average weight of 200 burger patties is eight pounds. Because as mean(center) of a whole population is 8 ounces, this is a parameter.
Statistics:
The statistic is any quality or measure defining or representing its specimen. We purchased 5 randomly selected hamburgers, which meant 7.6 ounces for mean weight. 7.6 is a statistic, thus.
1
When rolling two number cubes, what is the probability of rolling at least one 6?
А
12
36
С
6
36
B
11
36
D
1
36
Answer:
The answer is D.
If you deposit $300 in an account with a 6% interest rate, how much will be in your account after 1 year? If you leave this money in the account, how much will be in your account after 2 years?
Answer:
I only know the first question, If you leave that money for 1 year it would equal $480 basically, $300 x 1.6 = $480.
Step-by-step explanation:
The required amount in your account after 2 years will be $337.08.
What is compound interest?Compound interest is the interest on deposits computed on both the initial principal and the interest earned over time.
Here,
If you deposit $300 in an account with a 6% interest rate, the amount in your account after 1 year can be calculated as follows:
Find the interest earned after one year:
Interest earned = (6/100) x 300 = $18
Add the interest earned to the original amount:
Total amount after 1 year = $300 + $18 = $318
Therefore, the amount in your account after 1 year will be $318.
If you leave this money in the account for another year, the amount in your account after 2 years can be calculated as follows:
Find the interest earned after two years:
Interest earned in year 1 = $18
Interest earned in year 2 = (6/100) x $318 = $19.08
Add the interest earned to the original amount and the interest earned in year 1:
Total amount after 2 years = $300 + $18 + $19.08 = $337.08
Therefore, the amount in your account after 2 years will be $337.08.
Learn more about compound interest here: https://brainly.com/question/14295570
#SPJ7
z(x) is a function as defined below:
z(x) = x + 1
If you input a 3 into z(x), what do you get for the output?
What are the center and radius of a circle whose equation is:
(x−A)2+(y−B)2=C
Question options:
a)
Center: (−A,−B), radius = C
b)
Center: (−A,−B), radius =C −−√
c)
Center: (A, B), radius = C
d)
Center: (A, B), radius =C −−√
Answer:
d)
Step-by-step explanation:
Equation of circle with center at point (h, k) and radius, r.
[tex] (x - h)^2 + (y - k)^2 = r^2 [/tex]
This problem:
(x − A)^2 + (y − B)^2 = C
The center is (A, B).
The radius is sqrt(C).
Answer: d)
a) Find the slope, x-intercept, y-intercept of the line (L):
3x+4y-6= 0 and draw its graphs.
b) Find the equation of a line perpendicular to the line (L) in part (a) and
passing through the point (1, -2).
Answer: 2, 1.5 , -0.75
(b) [tex]4x-3y-10=0[/tex]
Step-by-step explanation:
Given
line is [tex]3x+4y-6=0[/tex]
Converting it into intercept form
[tex]\Rightarrow 3x+4y=6\\\\\Rightarrow \dfrac{3x}{6}+\dfrac{4y}{6}=\dfrac{6}{6}\\\\\Rightarrow \dfrac{x}{2}+\dfrac{y}{1.5}=1[/tex]
So, the x-intercept is [tex]2[/tex] and y-intercept is [tex]1.5[/tex]
The slope is given by
[tex]-\dfrac{\frac{1}{2}}{\frac{1}{1.5}}=-0.75[/tex]
(b) the line perpendicular to the above line and passing through [tex](1,-2)[/tex]
The slope of the required line
[tex]m=-\dfrac{1}{-0.75}\\\\m=\dfrac{4}{3}[/tex]
Equation of the line is given by
[tex]\Rightarrow \dfrac{y-(-2)}{x-1}=\dfrac{4}{3}\\\\\Rightarrow 3y+6=4x-4\\\Rightarrow 4x-3y-10=0[/tex]
A bag contains 2 red marbles and 3 black marbles. If Abby picks a marble without looking, returns it to the bag, and
a then draws a second marble, what is the probability that both marbles are red? Give the answer as a fraction in
simplest form.
Answer: I think it would be 1/2, 2/2 or 2/5. If i'm wrong then i'm sorry.
Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form. 3, 5,7
Answer:
3, 12, 48 ... =
3(4)^0, 3(4)^1, 3(4)^2 ... =
3(1), 3(4), 3(16) ....
3, 12, 48 ...
it's geometric with common ratio of 4. each term is 4 times the prior termStep-by-step explanation:
Rachel cut a whole banana into 6 pieces and then ate all the pieces. She put a point on a number line to show how much she ate.
0
Which fraction is equal to the point shown on the number line?
what is x • x³
[tex]x \times x ^{3} [/tex]
Answer:
x^4
Step-by-step explanation:
any variable when multiplied by the same variable will result in the exponent to increase.
help me plissssss. “
Answer:
letter A because it's representing 100% plus some so it is increasing.
What is 28% of 250 Takis?
Answer:
28% of 250 is 70
Step-by-step explanation:
If you turn 28% into a decimal it will turn into 0.28 so then multiply that by 250 and you'll get 70
The answer is 70.......
The volume of a cylinder is 1761 square
centimeters and the height is 11
centimeters. Find the radius.
Answer:
7.14cm
Step-by-step explanation:
find the value for x y and z
Answer:
All triangles add up to 180 degrees so...
180 - 43 - 59 = 78 degrees.
So x - 78 degrees.
x and y are supplementary angles so...
180 - 78 = 102.
So y = 102.
180 - 102 - 49 = 29 degrees
So z = 29 degrees
Hope this helps!
Tina has eight packs of paper each of her packs contain 50 sheets. Caz has three packs of paper each of his packs contain 125 sheets. Juan has 350 sheets of paper which statement is true
Answer:
i think the question is incomplete but
Tina at an average contains each package of
50 sheets ÷ 8 pack
6.205 of sheet in each pack
125 sheets ÷ 3 packs
caz contain at average 41.60 sheet average
but where the juan packs of paper that's why question is incomplete
. (0.5 point) We simulate the operations of a call center that opens from 8am to 6pm for 20 days. The daily average call waiting times are reported below for these 20 simulated days: 24.16 20.17 14.60 19.79 20.02 14.60 21.84 21.45 16.23 19.60 17.64 16.53 17.93 22.81 18.05 16.36 15.16 19.24 18.84 20.77 Due to a budget cut, the call center has now to downsize and the simulation model is used to predict the effect. We again simulate the call center for 20 days and now the daily average call waiting times are: 19.81 18.39 24.34 22.63 20.20 23.35 16.21 21.73 17.18 18.98 19.35 18.41 20.57 13.00 17.25 21.32 23.29 22.09 12.88 19.27 Compute a 95% t-confidence interval to decide if the change in the call waiting time is statistically significant.
Answer:
The 95% t-confidence interval for the difference in mean is approximately (-2.61, 1.16), therefore, there is not enough statistical evidence to show that there is a change in waiting time, therefore;
The change in the call waiting time is not statistically significant
Step-by-step explanation:
The given call waiting times are;
24.16, 20.17, 14.60, 19.79, 20.02, 14.60, 21.84, 21.45, 16.23, 19.60, 17.64, 16.53, 17.93, 22.81, 18.05, 16.36, 15.16, 19.24, 18.84, 20.77
19.81, 18.39, 24.34, 22.63, 20.20, 23.35, 16.21, 21.73, 17.18, 18.98, 19.35, 18.41, 20.57, 13.00, 17.25, 21.32, 23.29, 22.09, 12.88, 19.27
From the data we have;
The mean waiting time before the downsize, [tex]\overline x_1[/tex] = 18.7895
The mean waiting time before the downsize, s₁ = 2.705152
The sample size for the before the downsize, n₁ = 20
The mean waiting time after the downsize, [tex]\overline x_2[/tex] = 19.5125
The mean waiting time after the downsize, s₂ = 3.155945
The sample size for the after the downsize, n₂ = 20
The degrees of freedom, df = n₁ + n₂ - 2 = 20 + 20 - 2 = 38
df = 38
At 95% significance level, using a graphing calculator, we have; [tex]t_{\alpha /2}[/tex] = ±2.026192
The t-confidence interval is given as follows;
[tex]\left (\bar{x}_{1}- \bar{x}_{2} \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}[/tex]
Therefore;
[tex]\left (18.7895- 19.5152 \right )\pm 2.026192 \times \sqrt{\dfrac{2.705152^{2}}{20}+\dfrac{3.155945^2}{20}}[/tex]
(18.7895 - 19.5125) - 2.026192*(2.705152²/20 + 3.155945²/20)^(0.5)
The 95% CI = -2.6063 < μ₂ - μ₁ < 1.16025996668
By approximation, we have;
The 95% CI = -2.61 < μ₂ - μ₁ < 1.16
Given that the 95% confidence interval ranges from a positive to a negative value, we are 95% sure that the confidence interval includes '0', therefore, there is sufficient evidence that there is no difference between the two means, and the change in call waiting time is not statistically significant.
please please i neeed help
Answer:
i have made it in above picture
hope it helps
An automobile manufacturer has developed a new compact automobile. A random sample of 64 of the new automobiles showed that the automobiles had a sample mean mileage of 28.75 miles per gallon and a sample standard deviation of 3.4 miles per gallon. a) Find the 95% confidence interval for the population mean mileage, and state your conclusion. b) Find the 98% confidence interval for the population mean mileage, and state your conclusion.
Answer:
The 95% confidence interval for the population mean mileage is
(27.917, 29.593)
The 98% confidence interval for the population mean mileage
(27.737, 29.762)
Step-by-step explanation:
Step(i):-
Given that the random sample size 'n' = 64
Given that the mean of sample x⁻ = 28.75miles
Given that the standard deviation of the sample (S) = 3.4 miles
Degrees of freedom = n-1 = 64-1 =63
t₀.₀₅ = 1.9983
Step(ii):-
95% confidence interval for the population mean mileage is determined by
[tex](x^{-} - t_{0.05} \frac{S}{\sqrt{n} } , x^{-} + t_{0.05} \frac{S}{\sqrt{n} })[/tex]
[tex](28.75-1.99\frac{3.4}{\sqrt{64} },28.75 + 1.99 \frac{3.4}{\sqrt{64} } )[/tex]
(28.75 - 0.845 , 28.75 + 0.845)
(27.917 , 29.593)
Step(iii):-
98% confidence interval for the population mean mileage is determined by
[tex](x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02} \frac{S}{\sqrt{n} })[/tex]
[tex](28.75-2.3824\frac{3.4}{\sqrt{64} },28.75 + 2.3824 \frac{3.4}{\sqrt{64} } )[/tex]
(28.75 - 1.01252 , 28.75 + 1.01252)
(27.737 , 29.762)
Final answer:-
98% confidence interval for the population mean mileage is
(27.737 , 29.762)
What is the value of the expression (−2 4/5)÷(−1.4)
Answer:
2
Step-by-step explanation:
please help and explain how you got the answer:)
using cos to get x
cos -1 of 13/20
= 49.45
then y = 40.54° using sin y= opp /hyp =13\15
then the sin-1 of 13/20 =40.54 •
Help me guyssssss skeks
Answer:
19
Step-by-step explanation:
|-8 -11|=19
Answer:
3
Step-by-step explanation:
when you have 2 negitives it makes a positive which cancelles it out and it equals 3
find the Total surface area of given figure)
nuem
1
20cm 24cm 14cm
Answer:
where is the figure? to calculate the surface area
Mandy and Randy are each playing with a beach ball. Mandy's ball has a diameter of 12 inches. Randy's ball has a diameter that is twice as large as Mandy's ball. How much larger is the volume of Randy's ball? Show and explain your reasoning.
Answer:
Randy's ball is 904.78 larger than Mandy's.
Step-by-step explanation:
Using math, we find that Mandy's ball is 904.78 inches in volume and if Randy's is twice the size that's, 904.78 x 2 = 1809.56. so Randy's ball is 904.78 larger than Mandy's
Which number rounds to 700 when rounded to the nearest hundred?
Answer:
C.
Step-by-step explanation:
Hope this helps! have a great day!

A science teacher is preparing test tubes for an experiment.
She places 0.69 g of baking soda into each test tube. What is
the greatest number of test tubes the teacher can prepare for
the experiment if she has 41.4 g of baking soda
Answer: 60 test tubes
Step-by-step explanation: 41.4/60 = 0.69