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Answer:
I play!!!!!!!!
Explanation:
Every element in group one has ______________ electron in its outer shell. Every element in group two has _______________ electrons in its outer shell.
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A weather balloon with a volume of 3.40774 L
is released from Earth’s surface at sea level.
What volume will the balloon occupy at an
altitude of 20.0 km, where the air pressure is
10 kPa?
Answer in units of L.
Answer: The volume occupied at an altitude of 20.0 km is 34.5289 L
Explanation:
Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
[tex]P\propto \frac{1}{V}[/tex] (At constant temperature and number of moles)
where,
[tex]P_1[/tex] = initial pressure of gas = 101.325 kPa ( sea level)
[tex]P_2[/tex] = final pressure of gas = 10 kPa
[tex]V_1[/tex] = initial volume of gas = 3.40774 L
[tex]V_2[/tex] = final volume of gas = ?
Now put all the given values in the above equation, we get the final pressure of gas.
[tex]101.325\times 3.40774=10\times V_2[/tex]
[tex]V_2=34.5289L[/tex]
Therefore, the volume occupied at an altitude of 20.0 km is 34.5289 L
In the electron dot diagram for sulfur monoxide, each atom of sulfur will have how many unshared pairs of electrons an each atom of oxygen will have how many unshared pairs of electrons.
Answer:
Both sulphur and oxygen have two unshared pairs of electrons
Explanation:
The compound sulphur monoxide has the formula S=O. It is quite analogous to the diatomic molecules of the group 16 elements.
We must remember that each group element has six electrons in their outermost shell. Two of these are lone pairs leaving only two electrons available for bond formation.
These two electrons are used to form the sigma and pi bonds in S=O, leaving two lone pairs on each of sulphur and oxygen atoms.
Calculate the mass of zinc that reacts with 16.23 g of hydrochloric acid to form 15.2 g of zinc chloride and 18.97 g of hydrogen gas
Answer:
17.94 g
Explanation:
23.1 g of HCl (a strong acid) is added to water to make 1250 mL of solution. Calculate [H3O+] and pH of the solution
Answer:
Following are the solution to this question:
Explanation:
[tex]\to HCl \ mol = \frac{23.1 \ g}{36.5 \frac{g}{mol}} = 0.633 \ mole\\\\\\\to HCl \ molarity = \frac{ 0.633 \ mole }{1.25 L} \\\\[/tex]
[tex]=0.5064 \ m[/tex]
[tex]HCl +H_2O \longrightarrow H_3O^{+} + Cl^{-}\\\\\\[/tex]
[tex][H_3O^{+}] =[HCl] \\\\\to [H_3O^{+}] =0.5064 \ m \\\\\to PH =-\log [H_3O^{+}] \\\\[/tex]
[tex]= -\log (0.5064)\\\\= 0.295 \\\\=0.3[/tex]
Draw the product or products that are obtained from the reaction of HCl with 1-butene and with 2-butene. Show the relative stereochemistry if the product has two or more stereocenters.
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Which of the following are not decomposition reactions?
A. KCIO3 → KCI + O2
B. CaO + H2O + Ca(OH)2
C. 2Mg + O2 + 2Mgo
O D. NaOH + Na2O + H2O
The following are not decomposition reactions :
B. CaO + H2O ⇒ Ca(OH)2
C. 2Mg + O2 ⇒ 2MgO
Further explanationThe decomposition reaction is a chemical reaction shows the decomposition of a compound into its constituent elements or compounds
General formula :
AB⇒A+B
A. KCIO3 → KCI + O2
decomposition reaction
B. CaO + H2O ⇒ Ca(OH)2
synthesis/combination reaction
C. 2Mg + O2 ⇒ 2MgO
synthesis/combination reaction
D. 2NaOH ⇒ Na2O + H2O
decomposition reaction
Suppose you light a Bunsen burner and notice that the flame is very yellow and too short. To get a blue flame, you should ________further. To increase the size of the flame, you should _____________the _____________further.
Answer:
In the given case, to get a blue flame, one should open the air inlet further. To increase the size of the flame one should open the gas regulator further. When one opens the air inlet, more amount of oxygen goes within, and thus, one can get a more intense form of blue flame.
When one opens the gas regulator more concentration of gas goes and the larger the size of flame one gets.
To regulate a bunsen burner follow this procedure
To get a blue flame, you should rotate the wheel of the burner anticlockwise further to reduce the level of oxygen flow.
To increase the size of the flame, you should rotate the wheel clockwise further
The bunsen burner is an apparatus in the laboratory used to carry out experiment when heating of substance is required, hence it is used to add heat to substances, it has a wheel used to regulate the flow of air which is required for combustion, it has a hose which is used to tap gas to the burner
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Which statement describes an example of a chemical property of a metal statue?
O It is metal.
O It can tarnish.
OIt is solid.
OIt is shiny.
Answer:
The answer is "it can tarnish"
Explanation:
The statement describes an example of a chemical property of a metal statue is that it can tarnish.
Chemical properties are defined as those properties which become evident during or after a chemical reaction has taken place.
These properties cannot be determined externally just by viewing the substance ,these change immensely after a substance undergoes a chemical change.These are used for identification of unknown substances and used for building up chemical classifications.
The major chemical properties include flammability,toxicity,reactivity,acidity and heat of combustion.For a chemical property to be apparent , it is necessary that the structure of the substance is altered.
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Which cannot be chemically broken down into simpler substances?
O compound
O element
O solution
O mixture
Answer:
an element.
Explanation:
it is the purest form
Answer:
b
Explanation:
How many atoms are in 1.4 mol of phosphorus trifluoride (PF3)?
Number of atoms in 1.4 mol of Phosphorus trifluoride (PF₃) : 8.428 x 10²³
Further explanationThe mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
1.4 mol of Phosphorus trifluoride (PF₃), number of atoms :
[tex]\tt N=1.4\times 6.02\times 10^{23}\\\\N=8.428\times 10^{23}[/tex]
What are three ways that we can identify when a chemical reaction is occurring?
Which of the following belong to a category called the main group of elements
A halogens
B nonmetals
C alkaline metal
D transition elements
Answer:
C. Alkaline Metal ok thanks
A student pipets 5.00 mL of a 5.103 M aqueous NaOH solution into a 250.00 mL volumetric flask and dilutes up to the mark with distilled water. What is the final molarity of the dilute solution?
Answer:
0.102 M.
Explanation:
From the question given above, the following data were obtained:
Volume of stock solution (V1) = 5 mL
Molarity of stock solution (M1) = 5.103 M
Volume of diluted solution (V2) = 250 mL
Molarity of diluted solution (V2) =?
The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:
M1V1 = M2V2
5.103 × 5 = M2 × 250
25.515 = M2 × 250
Divide both side by 250
M2 = 25.515 / 250
M2 = 0.102 M
Thus, the molarity of the diluted solution is 0.102 M.
The dilution of the NaOH results in the dilution of the molarity of the solution. The molarity of the final NaOH solution is 0.102 M.
What is molarity?Molarity is the concentration unit that defines the amount of solute present in a liter of solution.
The dilution of the solution results in a change in the molarity. It can be accessed as:
[tex]\rm M_1V_1=M_2V_2[/tex]
The initial molarity of the solution is, [tex]\rm M_1=5.103\;M[/tex]
The initial volume of the NaOH is, [tex]\rm V_1=5\;mL[/tex]
The final volume of the NaOH is, [tex]\rm V_2=250\;mL[/tex]
Substituting the values for the calculation of final molarity, [tex]\rm M_2[/tex]:
[tex]\rm 5.103\;\M\;\times\;5.0\;mL=M_2\;\times\;250\;mL\\\\M_2=\dfrac{5.103\;\M\;\times\;5.0\;mL}{250\;mL} \\\\M_2=0.102\;M[/tex]
The molarity of the NaOH solution after dilution is 0.102 M.
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A solid substance was tested in the laboratory. The test results are listed below: 1.) dissolves in water 2.) is an electrolyte 3.) melts at a high temperature. Based on these results, the solid substance could be
Answer:
NaCl may be i guess so....
Balance the following equation.
C3H8(g) + O2(g) → CO2(g) + H2O(l)
Explanation:
C3H8+5O2----->3CO2+4H2O
Answer:
C3H8+5O2----->3CO2+4H2O
Explanation:
Mr. Juan is husband of Maria, before they get married Maria knows that her husband cannot make a baby since he cant produce sperm. But during their 2 years in marriage, Maria got pregnant. Is Juan can file a case to Maria? What it is? Support your answer?
Answer:
yes but first he need to check himself
Explanation:
bcoz if he cannot produce a sperm than she might have cheated him and the baby might be of someone other.
3. Theoretically how many grams of magnesium is required to produce to 5.0 g of
Magnesium oxide?
Answer:
3grams
Explanation:
The reaction for the production of Magnesium dioxide will be
Mg + O2 → MgO
we have 5g of MgO (molar mass 40g)
no of moles of MgO = 5/40 = 0.125
Using unitary method we have
1 mole of Mg require 1 mole of MgO
0.125 Mole of MgO = 0.125mole of Mg
n = given mass /molar mass
0.125 = mass / molar mass
mass = 0.125* 24 = 3grams
A 50.0 mL solution of Ba(OH)2 is combined with a 150 mL solution of 0.20 M HCl. If the resulting solution has a hydroxide ion concentration of 0.12 M, what was the concentration of Ba(OH)2 in the original solution?
Answer:
0.54M of Ba(OH)2
Explanation:
When Ba(OH)2 reacts with HCl, BaCl2 and H2O are produced as follows:
Ba(OH)2 + 2HCl → BaCl2 + 2H2O
The remanent hydroxide ion is because not all Ba(OH)2 reacts. Thus, we need to find moles of Ba(OH)2 that doesn't react and moles of Ba(OH)2 that reacts. The ratio between total moles and volume of the Ba(OH)2 solution = 0.050L is the molarity of the original solution
Moles of Ba(OH)2 that doesn't react:
50mL + 150mL = 0.200L * (0.12 mol OH- / L) = 0.024 moles OH-
2 moles of OH- are in 1 mole of Ba(OH)2:
0.024 moles OH- * (1mol Ba(OH)2 / 2 mol OH-) = 0.012 moles Ba(OH)2
Moles of Ba(OH)2 that react:
0.150L * (0.20mol / L) = 0.030 moles HCl
2 moles of HCl react per mole of Ba(OH)2:
0.030 moles HCl * (1mol Ba(OH)2 / 2 mol HCl) = 0.015 moles Ba(OH)2
Total moles:
0.012mol + 0.015mol = 0.027mol Ba(OH)2 in 50mL
0.027mol Ba(OH)2 / 0.0500L =
0.54M of Ba(OH)2
In chemical reaction atoms are what?
Answer:
In chemical reaction atoms are reactantsif you a boy answer this question because............. idk
Answer:
no
Explanation:
What is the difference between Mega and Milli symbols?
Answer:
Mega = 10^6
Milli = 10^-3
Explanation:
Mega is whatever times 10 to 6th power.
Milli is whatever times 10 to the -3rd power.
What is the answer? Please
Answer:
Cell
Explanation:
I just passed this unit a month ago.
Answer:
It is 6. Cell
Explanation:
Cells make up the smallest level of a living organism such as yourself and other living things. The cellular level of an organism is where the metabolic processes occur that keep the organism alive. That is why the cell is called the fundamental unit of life.
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in which beakers are the particles moving the most slowly
Answer:
A and D
Explanation:
How many atoms of phosphorus are in 5.70 mol of copper(II) phosphate?
Answer:
Cu3 (PO4)2 contains a total of 2 atoms of phosphorus in just one molecule. (2.10 mol)(6.02214 x 10^23 atoms / mol)(2 phosphorous) = 2.53 x 10^24 atoms of phosphorous per molecule of copper i
Explanation:
1. How many atoms are in 0.25 moles of carbon?
2. How many atoms are in 12.3 grams of sodium?
3. How many grams are there in 0.52 moles of boron?
4. How many grams are there in 2.0 moles of HCl?
5. How many moles are in 3.4 grams of HBr?
6. How many grams are there in 4.5x10^10 atoms of NaCl?
7. How many atoms are there in 45.1 grams of MgO?
Answer 1 mole = 6.02 × 1023 atoms
0.25 moles × (6.02 × 1023) = 1.5 × 1023 atoms Carbon
for the first one
Which statement about atoms is not correct
Answer:
Atoms are not able to exist independently.
Explanation:
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A solution is made by adding 5.01 g of iron sulfate to 75.3 g of water. What is the mass percentage of iron sulfate in this solution?
Answer:
6.24 % of FeSO₄
Explanation:
Solute mass: 5.01 g of FeSO₄
Solvent mass: 75.3 g of water
Solution mass = solute mass + solvent mass
5.01 g + 75.3 g = 80.31 g
We can apply a rule of three. Mass percentage means the mass of solute which is contained in 100 g of solution. Then,
In 80.31 g of solution we have 5.01 g of solute
In 100 g solution, we may have (5.01 . 100)/ 80.31 = 6.24 g of solute.
This is the mass percentage: 6.24%
Suppose you are titrating vinegar, which is an acetic acid solution, of unknown strength with sodium hydroxide according to the equation HC2H3O2 + NaOH → H2O + NaC2H3O2 If you require 32.17 mL of 0.116 M NaOH solution to titrate 10.0 mL of HC2H3O2 solution, what is the concentration of acetic acid in the vinegar? (M)
Answer:
0.373 M
Explanation:
The reaction is
HC₂H₃O₂ + NaOH → H₂O + NaC₂H₃O₂So 1 mol of acetic acid reacts with 1 mol of sodium hydroxide.
First we calculate the moles of NaOH:
0.116 M * 32.17 mL = 3.732 mmol NaOHBecause the stoichiometric ratio is 1:1 :
3.732 mmol NaOH = 3.732 mmol Acetic AcidNow we calculate the concentration of acetic acid, dividing the moles by the volume:
3.732 mmol Acetic Acid / 10.0 mL = 0.373 M32.17 mL of 0.116 M NaOH are required to titrate 10.0 mL of 0.373 M acetic acid.
What is titration?Titration is a common laboratory method of quantitative chemical analysis to determine the concentration of an identified analyte.
Let's consider the neutralization reaction between acetic acid and sodium hydroxide.
HC₂H₃O₂ + NaOH → H₂O + NaC₂H₃O₂
We can calculate the concentration of acetic acid in vinegar using the following expression.
Ca × Va = Cb × Vb
Ca = Cb × Vb / Va
Ca = 0.116 M × 32.17 mL / 10.0 mL = 0.373 M
where,
Ca is the concentration of the acid.Va is the volume of the acid.Cb is the concentration of the base.Vb is the volume of the base.32.17 mL of 0.116 M NaOH are required to titrate 10.0 mL of 0.373 M acetic acid.
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