Answer:
There are 8 dimes there.
Step-by-step explanation:
This question is solved used a system of equations.
I am going to say that:
x is the number of nickels.
y is the number of dimes.
19 coins
This means that x + y = 19.
A nickel is worth $0.05. A dime is worth $0.1. The total of these coins is $1.35. So
0.05x + 0.1y = 1.35
How many dimes are there?
We have to find y.
From the first equation: x = 19 - y.
Replacing in the second:
0.05(19 - y) + 0.1y = 1.35
0.95 - 0.05y + 0.1y = 1.35
0.05y = 0.4
y = 0.4/0.05
y = 8
There are 8 dimes there.
Sue Anne owns a medium-sized business. The probability model below describes the number of employees that may call in sick on any given day. What is the mean number of employees calling in sick each day?
probability model with number of employees sick in column 1. The probabilities are in column 2.
X
Number of
Employees Sick P(X)
0 0.05
1 0.40
2 0.30
3. 0.30
4. 0.05
Answer:
The mean is [tex]\mu = 2.1[/tex]
Step-by-step explanation:
The mean number of employees calling sick per day can be mathematically represented as
[tex]\mu = 0* 0.05 + 1 * 0.40 + 2 * 0.3 + 3 * 0.3 + 4*0.05[/tex]
[tex]\mu = 2.1[/tex]
In a small state, the license plate for a car begins with two letters, which may be repeated, and ends with three digits, which also may be repeated. How many license plates are possible in that state?
Answer:
676,000 possible license plate
Step-by-step explanation:
Each letter has 26 possible values (from A to Z), and each digit has 10 possible values (from 0 to 9).
So to find the number of license plates we can have, we just need to multiply the number of possible values for each letter and each digit, We have 2 letters and 3 digits, so we have:
Number of plates = 26 * 26 * 10 * 10 * 10 = 676000
We have 676,000 possible licence plates in this state.
The average manufacturing work week in metropolitan Chattanooga was 40.1 hours last year. It is believed that the recession has led to a reduction in the average work week. To test the validity of this belief, the hypotheses are
Answer:
The null and alternative hypothesis are:
[tex]H_0: \mu=40.1\\\\H_a:\mu< 40.1[/tex]
Step-by-step explanation:
If we want to test the claim that there is a reduction in the average work week, the null hypothesis should state:
- The alternative hypothesis should state the claim: there is a reduction in the average work week. This can be written as the true mean is less than 40.1
- The null hypothesis should state the oposite of the alternative hypothesis: that there is no significant reduction in the average work week. This can be written as the true mean is equal to 40.1.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=40.1\\\\H_a:\mu< 40.1[/tex]
The personnel department of a large manufacturing firm selected a random sample of 23 workers. The workers were interviewed and given several tests. On the basis of the test results, the following variables were investigated: X2 = manual dexterity score, X3 = mental aptitude score, and X4 = personnel assessment score. Subsequently, the workers were observed in order to determine the average number of units of work completed (Y) in a given time period for each worker. Regression analysis yielded these results: Y = -212 + 1.90X2 + 2.00X3 + 0.25X4, R2 = .75. (.050) (.060) (.20) What is the correct estimate for the number of units of work completed by a worker with a manual dexterity score of 100, a mental aptitude score of 80 and a personnel assessment score of 10?
Answer:
140.5 units of work
Step-by-step explanation:
The number of units of work by a worker is given as:
Y = -212 + 1.90X2 + 2.00X3 + 0.25X4
X2 = manual dexterity score=100
X3 = mental aptitude score=80
X4 = personnel assessment=10
Substituting these value for X2,X3 and X4 we have :
Y = -212 + 1.90(100) + 2.00(80)+ 0.25(10)
Y =-212 + 190 +160 +2.5= 140.5 units of work
The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities. Only eight of these facilities treated hazardous waste on-site.
Required:
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site? Interpret this result.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Answer:
(a) [tex]E(X) = 0.383[/tex]
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b) [tex]P(x = 4) = 0.000169[/tex]
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by
[tex]$ E(X) = \frac{n \times r}{N} $[/tex]
[tex]$ E(X) = \frac{10 \times 8}{209} $[/tex]
[tex]$ E(X) = \frac{80}{209} $[/tex]
[tex]E(X) = 0.383[/tex]
Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
[tex]$ P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $[/tex]
For the given case, we have
N = 209
n = 10
r = 8
x = 4
[tex]$ P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $[/tex]
[tex]$ P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $[/tex]
[tex]$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}[/tex]
[tex]P(x = 4) = 0.000169[/tex]
Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Determine whether the distribution is a probability distribution. x 0 1 2 3 4 5 P(x) StartFraction 1 Over 25 EndFraction one fifth one half three fourths StartFraction 1 Over 50 EndFraction StartFraction 1 Over 100 EndFraction Is the probability distribution a discrete distribution? Why? Choose the correct answer below. A. No comma because some of the probabilities have values greater than 1 or less than 0. B. Yes comma because the distribution is symmetric. C. Yes comma because the probabilities sum to 1 and are all between 0 and 1 comma inclusive. D. No comma because the total probability is not equal to 1. Click to select your answer and then click Check Answer.
Answer:
D. No comma because the total probability is not equal to 1.
Step-by-step explanation:
Given the distribution:
[tex]\left|\begin{array}{c|cccccc}x&0&1&2&3&4&5\\ P(x)&1/25&1/5&1/2&3/4& 1/50&1/100\end{array}\right|[/tex]
The sum of the probabilities
[tex]\sum P(x)=1/25+1/5+1/2+3/4+ 1/50+1/100\\\sum P(x) =1.52 \neq 1[/tex]
Therefore, the distribution is not a probability distribution because the total probability is not equal to 1.
The correct option is D.
The results of a survey of common allergies was organized into a Venn diagram. Circles D, C, and P overlap. Circle D contains 15. Circle C contains 18. Circle P contains 9. The overlap of circles C and D contains 7. The overlap of circles D and P contains 12. The overlap of C and P contains 10. The overlap of all 3 circles contains 1. Answer the questions about the following sets: D = {x | x is a person allergic to dogs}; C = {x | x is a person allergic to cats}; P = {x | x is a person allergic to pollen} How many people are not allergic to any of the three choices? How many people are allergic to all three choices? How many people are allergic to both dogs and cats but not allergic to pollen? How many people are allergic to cats only?
Answer:
first blank: 22
second blank: 1
third blank: 7
fourth blank: 18
Step-by-step explanation:
edge 2020
Answer: 22, 1, 7, 18
The results of a survey of common allergies was organized into a Venn diagram.
Circles D, C, and P overlap. Circle D contains 15. Circle C contains 18. Circle P contains 9. The overlap of circles C and D contains 7. The overlap of circles D and P contains 12. The overlap of C and P contains 10. The overlap of all 3 circles contains 1.
Answer the questions about the following sets:
D = {x | x is a person allergic to dogs}; C = {x | x is a person allergic to cats}; P = {x | x is a person allergic to pollen}
How many people are not allergic to any of the three choices?
✔ 22
How many people are allergic to all three choices?
✔ 1
How many people are allergic to both dogs and cats but not allergic to pollen?
✔ 7
How many people are allergic to cats only?
✔ 18
MY LAST 3 QUESTION WILL FOREVER BE GRATEFUL PLS HELP WILL GIVE BRANLIEST!! AT LEAST TAKE A LOOK!!!! PLS I AM BEGGING!!!
1. Curtis is trying to justify a step in his paragraph proof. What is the property that he should use? AB=BC therefore BC=AB
A) Equality of Congruence Property
B) Reflexive Property of Congruence
C) Symmetric Property of Congruence
D) Transitive Property of Congruence
2. All of the following would make a formal proof incomplete except what?
A) Incomplete sentences
B) Errors in logic
C) A lack of justifications
3. Which step in the proof has a flaw? IMAGE BELOW Given B is the midpoint of AC prove AB=BC
A) Step 2
B) No flaws.
Answer:
1. C
2. A
3. A
Step-by-step explanation:
1. It is the Symmetric Property of Congruence because the definition is literally what it says.
2. Incomplete sentences don't matter as long as you have the right stuff.
3. Step 2 is wrong because it should be Definition of Midpoint.
If Curtis is attempting to defend a step in his proof paragraph. He should apply the symmetric property of congruence so that he can demonstrate that AB=BC and that BC=AB. It's best to choose C.
What is geometry?It is defined as the branch of mathematics that is concerned with the size, shape, and orientation of two-dimensional figures.
A)If Curtis is trying to justify a step in his paragraph proof. Symmetric Property of Congruence that he should use as a result he can show AB=BC therefore BC=AB. Option C is correct.
B)All of the following would make a formal proof incomplete except Incomplete sentences. Option A is correct.
C)Step 2 in the proof has a flaw Because it is not a symmetric property while they show congruency because it must be a midpoint definition. Option A is correct.
Thus, if Curtis is trying to justify a step in his paragraph proof. Symmetric Property of Congruence that he should use as a result he can show AB=BC therefore BC=AB. Option C is correct.
Learn more about geometry here:
brainly.com/question/16836548
#SPJ2
4x - 23
(8x + 3x + 5x2)
Answer:
Let's simplify step-by-step.
[tex]4x^4-2x^3-(8x^4+3x^3+5x^2)[/tex]
Distribute the Negative Sign:
[tex]4x^4-2x^3+-1(8x^4)+-1(3x^3)+-1(5x^2)[/tex]
[tex]4x^4+-2x^3+-1(8x^4)+-1(3x^3)+-1(5x^2)[/tex]
[tex]4x^4+-2x^3+-8x^4+-3x^3+-5x^2[/tex]
Combine Like Terms:
[tex]4x^4+-2x^3+-8x^4+-3x^3+-5x^2[/tex]
[tex](4x^4+-8x^4)+(-2x^3+-3x^3)+(-5x^2)[/tex]
[tex]-4x^4+-5x^3+-5x^2[/tex]
Answer:
[tex]-4x^4-5x^3-5x^2[/tex] This is the answer
I hope this help you :)
8. Suppose Betty saves $200 each month in her 401(k) account. How much less will her monthly take-home pay be? (Assume a combined 20% state and federal income tax rate, as in the example.)
Note: Check the file attached below for the complete question
Answer:
Betty's monthly take home is $20 less
Step-by-step explanation:
Betty's monthly income = $2300
Betty's monthly savings = $200
Amount left after savings = $2300 - $200
Amount left after savings = $2100
Federal and State Income tax rate = 20% = 0.2
Tax amount paid = $420
Monthly take home = $2100 - $420
Monthly take home = $1680
Compared to $150 per month savings, Betty's monthly take home is $20 less
describe this diagram help please
Answer:
U are finding the slope. so the vertical line is ur rise(x value) and the horizontal line is ur y value. Hopefully that helped
Error Analysis A problem on a test says that 70% of people enjoy the beach. The students are
asked to use the simulation numbers below to estimate the probability that exactly one person says
he or she enjoys the beach. Let the numbers 0-6 represent a person who enjoys going to the beach
and let 7-9 represent a person who does not. One student says that the probability is about 100%.
Estimate the probability that exactly one person enjoys the beach. What error might the student have
made?
(5,8) (2,7) (0,9) (0,2) (9,0) (1,9) (4,7) (0,3) (6,7) (7,5)
Use the simulation to estimate the experimental probability that exactly one person enjoys the beach
is 40%
Enter your answer in the answer box and then click Check Answer
pan
rema
Answer:
Probability that exactly one person says he or she enjoys the beach = 80%
Check Explanation for how to get this and which error the studemt that made the 100% claim must have made.
Step-by-step explanation:
The simulation presented is that for a series of two people sample.
Numbers 0 to 6 represents that the beach-goer enjoys going to the beach and numbers 7 to 9 represents that the beach-goer doesn't enjoy going to the beach.
So, the simulation is then obtained to be
(5,8) (2,7) (0,9) (0,2) (9,0) (1,9) (4,7) (0,3) (6,7) (7,5)
Using the simulation, estimate the probability that exactly one person says he or she enjoys the beach
From the simulation, the ones with exactly one of the two numbers ranging from 0 to 6 to indicate enjoying going to the beach include
(5,8) (2,7) (0,9) (9,0) (1,9) (4,7) (6,7) (7,5)
The probability of an event is defined and expressed as the number of elements in that event divided by the total number of elements in the sample space.
Probabilty that exactly one person says he or she enjoys the beach = (8/10) = 0.80 = 80%
The student claims that this probability is 100%, but the other two simulations that did not satisfy the condition of exactly one person saying that he or she enjoys the beach include
(0,2) and (0,3), which show that in the two cases, the two participants both expressed enjoying going to the beach.
The student's error must have been in counting these two simulations as part of 'exactly one person saying he or she enjoys the beach' which is indeed an error.
Hope this Helps!!!
Which graph represents the function y=2x-4
Answer:
Step-by-step explanation:
pls find below
hope this helps
Answer:
C
Step-by-step explanation:
took the test
Jimmie invested $57,500 at 9.38% compounded continuously. What will Jimmie's account balance be in 42 years?
Answer:
$6,259,057.84
Step-by-step explanation:
hello,
compounding continuously means that we have to multiply by
[tex]e^{0.0938*t}[/tex]
t is the number of years
so the account balance in 42 years is
[tex]57,500e^{0.0938*42}=6,259,057.84....\\[/tex]
so it gives
$6,259,057.84
hope this helps
Find the x intercept of the line 2x-3y=-19
Answer:
See below.
Step-by-step explanation:
Recall that the x-intercept is basically: (x,0).
In other words, we just need to substitute y with 0 in order to find the x-intercept.
Thus, we will have:
[tex]2x-3(0)=-19[/tex]
[tex]2x=-19[/tex]
[tex]x=-19/2[/tex]
One solution to the problem below is 10. what is the other solution?
b^2-100=0
Answer:
the same
Step-by-step explanation:
Answer:
The two solutions can be +10 and -10
Step-by-step explanation:
b^2 - 100 = 0
b^2 = 100
Take the root of both sides
b = +- 10
b = +10 , b = -10
The number 41,849 written to 4 significant figures is?
Answer:
41,850
Step-by-step explanation:
The 4th digit from the left is in the 10s place, so you need to round to that place. This requires rounding up, since the 1s digit is more than 4.
41,850 . . . . to 4 significant figures
If mACD = 100°, then mACE = [?]
Answer:
ACE = 80
Step-by-step explanation:
ACD and ACE form a straight line so they add to 180 degrees
ACD + ACE = 180
100 + ACE = 180
Subtract 100 from each side
100-100 + ACE = 180-100
ACE = 80
Which would be appropriate compatible numbers to use to estimate (19 4/5) (4/6) A. 16(1/3) B. 19(2/3) C. 20(1/2) D. 20(1)
Answer:
C. 20(1/2)
Step-by-step explanation:
Let's find the value of the expression before looking for the nearest estimate
(19 4/5) (4/6) = 19 *(4/5)(4/6)
(19 4/5) (4/6) = 19(16/30)
(19 4/5) (4/6) = 19(8/15)
(19 4/5) (4/6) = (19*8)/15
(19 4/5) (4/6) = 152/15
(19 4/5) (4/6) = 10(2/15)
A. 16(1/3) =5.33
B. 19(2/3) = 12.667
C. 20(1/2) = 10
D. 20(1)= 20
The nearest to the expression is C. 20(1/2)
Parking at a large university has become a very big problem. University administrators are interested in determining the average parking time (e.g. the time it takes a student to find a parking spot) of its students. An administrator inconspicuously followed 250 students and carefully recorded their parking times. Identify the population of interest to the university administration.
Answer:
The population of interest is all the students at the University, to find their parking times.
Step-by-step explanation:
Sampling
This is a common statistics practice, when we want to study something from a population, we find a sample of this population.
For example:
I want to estimate the proportion of New York state residents who are Buffalo Bills fans. So i ask, lets say, 1000 randomly selected New York state residents wheter they are Buffalo Bills fans, and expand this to the entire population of New York State residents.
Here, the population of interest is all New York state residents.
An administrator inconspicuously followed 250 students and carefully recorded their parking times.
Sample of 250 students at the University.
So the population of interest is all the students at the University, to find their parking times.
Please answer this correctly
Answer:
1/2
Step-by-step explanation:
There are two sides of a coin, therefor you have 1/2 a chance of getting heads or tails. 1/2=50%
Answer:
50%
Step-by-step explanation:
There are 2 sides of a coin which have an equal chance of landing on the visible side. In other words, they each have half of the chance, or 50%.
Let I (x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements. (a) Jerry does not have an Internet connection. (b) Rachel has not chatted over the Internet with Chelsea. (c) Jan and Sharon have never chatted over the Internet. (d) No one in the class has chatted with Bob. (e) Sanjay has chatted with everyone except Joseph. (f) Someone in your class does not have an Internet connection. (g) Not everyone in your class has an Internet connection. (h) Exactly one student in your class has an Internet connection. (i) Everyone except one student in your class has an Internet connection. (j) Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class. (k) Someone in your class has an Internet connection but has not chatted with anyone else in your class. (l) There are two students in your class who have not chatted with each other over the Internet. (m) There is a student in your class who has chatted with everyone in your class over the Internet. (n) There are at least two students in your class who have not chatted with the same person in your class. (o) There are two students in the class who between them have chatted with everyone else in the class
Answer:
Step-by-step explanation:
L(x) means that Student X has an internet connection
C(x,y) means that students X and Y have chatted over the internet
The domain for variables X and Y comprise all students in your class. We now use quantifiers or algebraic functions to express each of the statements:
(A) Jerry does not have an internet connection
L(x) = 0
Where X represents Jerry
(B) Rachel has not chatted over the internet with Chelsea
C(x,y) = 0
Where X and Y represent Rachel and Chelsea
(C) Jan and Sharon have never chatted over the internet
L(x) + L(y) = 0
Where X and Y represent Jan and Sharon. If they have NEVER chatted over (the question didn't say they have never "with each other", it says they have never chatted at all) the internet, then they've probably never had an internet connection!
(D) No one in the class has chatted with Bob
Let Y represent Bob and X1, X2, ..., Xn represent everyone else in the class.
The value of Y is not significant here (because it is raised to the power of zero and that makes it equal to 1 and when 1 is multiplied by any X value, the X value or student remains the same) but we have to put it, to represent Bob.
The quantifier here is C (X1Y°, X2Y°, X3Y°, ..., XnY°)
Stereo speakers are manufactured with a probability of 0.100.10 being defective. TwentyTwenty speakers are randomly selected. Let the random variable X be defined as the number of defective speakers. Find the expected value and the standard deviation.
Answer:
The expected value of X is 2 with a standard deviation of 1.34.
Step-by-step explanation:
For each speaker, there are only two possible outcomes. Either it is defective, or it is not. The probability of a speaker being defective is independent of other speakers. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Stereo speakers are manufactured with a probability of 0.1 of being defective
This means that [tex]p = 0.1[/tex]
Twenty speakers are randomly selected.
This means that [tex]n = 20[/tex]
Let the random variable X be defined as the number of defective speakers. Find the expected value and the standard deviation.
[tex]E(X) = np = 20*0.1 = 2[/tex]
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.1*0.9} = 1.34[/tex]
The expected value of X is 2 with a standard deviation of 1.34.
The following are the ages (years) of 5 people in a room: 14, 14, 18, 18, 22 A person enters the room. The mean age of the 6 people is now 16. What is the age of the person who entered the room?
Answer:
[tex]\boxed{\sf \ \ age = 10\ \ }[/tex]
Step-by-step explanation:
Hello,
let's write the mean computation, we note x the age of the additional person
[tex]\dfrac{14+14+18+18+22+x}{6}=16[/tex]
[tex]<=> 14+14+18+18+22+x = 6*16=96\\\\<=> x = 96 - ( 14+14+18+18+22)= 10[/tex]
So the age of the person is 10
hope this helps
Consider the functions f (x )equals negative 9 x plus 3 and g (x )equals negative one ninth (x minus 3 ). (a) Find f(g(x)). (b) Find g(f(x)). (c) Determine whether the functions f and g are inverses of each other.
Answer:
[tex](a) f(g(x)) = x\\(b) g(f(x)) = x[/tex]
(c) Yes, the functions f and g are inverses of each other.
Step-by-step explanation:
Given the functions:
[tex]f(x) = -9x+3\\g(x) = -\dfrac{1}{9}(x-3)[/tex]
(a) [tex]f(g(x))=?[/tex]
[tex]put\ x = -\dfrac{1}{9}(x-3)\ in\ (-9x+3):[/tex]
[tex]f(g(x))= -9(-\dfrac{1}{9}(x-3)) +3\\\Rightarrow (-\dfrac{-9}{9}(x-3)) +3\\\Rightarrow (\dfrac{9}{9}(x-3)) +3\\\Rightarrow 1(x-3) +3\\\Rightarrow x-3 +3\\\Rightarrow x\\\Rightarrow f(g(x) )=x[/tex]
(b) [tex]g(f(x))=?[/tex]
[tex]put\ x = (-9x+3)\ in\ -\dfrac{1}{9}(x-3):[/tex]
[tex]f(g(x))= (-\dfrac{1}{9}((-9x+3)-3))\\\Rightarrow (-\dfrac{1}{9}(-9x+3-3))\\\Rightarrow (-\dfrac{1}{9}(-9x))\\\Rightarrow (-\dfrac{-9}{9}x)\\\Rightarrow g(f(x))=x[/tex]
(c) Yes, f and g are the inverse functions of each other.
As per the property of inverse function:
If [tex]f^{-1}(x)[/tex] is the inverse of [tex]f(x)[/tex] then:
[tex]f(f^{-1}(x)) = x[/tex]
And here, we have the following as true:
[tex]f(g(x)) = x\\ g(f(x)) = x[/tex]
[tex]\therefore[/tex] f and g are inverse functions of each other.
70 points !!!!!!! Help
Answer:2
Step-by-step explanation:
v= is the midpoint of xn and wy
Answer:
Option 1
Step-by-step explanation:
The line XZ and line WY parallelogram have a midpoint or center. That is point V.
The lines are the two diagonals of a parallelogram.
Since the diagonals XZ and WY divide each other into equal segments, the diagonals bisect each other. Since the diagonals XZ and WY bisect each other at point V, point V is the midpoint of each diagonal. That is the definition of midpoint.
In the interval 0° < x < 360°, find the values of x for which tan x = 2.7475
Give your answers to the nearest degree,
1
Answer:
[tex]70^\circ, 250^\circ[/tex]
Step-by-step explanation:
Given that:
[tex]tan x= 2.7475[/tex]
and [tex]0^\circ < x < 360^\circ[/tex] i.e. [tex]x[/tex] lies in the interval [tex]0^\circ[/tex] to [tex]360^\circ[/tex] or [tex]0\ to\ 2\pi[/tex].
To find: The possible values for x in the interval [tex]0^\circ[/tex] to [tex]360^\circ[/tex] = ?
First of all, let us learn something about [tex]tan\theta[/tex].
In a right angled triangle the value of [tex]tan\theta[/tex] can be calculated as follows:
[tex]tan\theta = \dfrac{Perpendicular}{Base}[/tex]
i.e. [tex]tan\theta[/tex] is equal to the ratio of Perpendicular to Base in a right angled triangle.
We are given that:
[tex]tan x= 2.7475[/tex]
[tex]\Rightarrow x = tan^{-1}(2.7475)\\\Rightarrow x = 70^\circ[/tex]
So, the value of x in first quadrant is [tex]70^\circ[/tex].
It is also known that value of tangent is positive in the first and third quadrant.
We are given a positive value of tangent here,
So, another value of [tex]x = 180^\circ+70^\circ = 250^\circ[/tex]
Hence, the correct answers are: [tex]x=70^\circ, 250^\circ[/tex]
According to an airline, flights on a certain route are on time 85% of the time. Suppose 20 flights are randomly selected and the number of on-time flights is recorded.
(a) Explain why this is a binomial experiment
(b) Find and interpret the probabdity that exadly 15 flights are on time.
(c) Find and interpret the probability that fewer than 15 flights are on time.
(d) Find and interpret the probability that at least 15 flights are on time.
(e) Find and interpret the probability that between 13 and 15 flights, inclusive, are on time.
(a) Identify the statements that explain why this is a binomial experiment. Select all that apply.
A. Each trial depends on the previous trial
B. There are three mutually exclusive possibly outcomes, arriving on-time, arriving early, and arriving late.
C. The experiment is performed unti a desired number of successes is reached
D. The trials are independent.
E. The probability of success is the same for each trial of the experiment.
F. There are two mutually exclusive outcomes, success or failure.
G. The experiment is performed a fixed number of times.
Answer:
See the answers below. Thanks!
Step-by-step explanation:
(a). Option F is the correct choice. "There are two mutually exclusive outcomes, success or failure."
(b). P(X=15) = 0.1702
(c). P(X<15) = 0.0673
(d). P(X>=15) = 1 - P(X<15) = 0.9327
(e). P(13<=X<=15) = 0.1482
Best Regards!
Of the 3,400 widgets produced at the wacky widgets factor today, 12% are defective. How many widgets are defective? which steps would be used to find 12% of 3,400 check all that apply
Answer:
408 widgets
Step-by-step explanation:
Data provided in the question
WP = Total number of widgets produced = 3,400 widgets
DP = Defective percentage = 12%
Based on the above information, the number of widgets that are defective is
[tex]= WP \times DP[/tex]
[tex]= 3,400\ widgets \times 12\%[/tex]
= 408 widgets
We simply multiplied the total number of widgets produced by the defective percentage so that the defective widgets could come
Answer:
The answers are B,D,F
The number of hits on a certain website during a one-minute interval follows a Poisson distribution with a mean rate of four hits per minute. What is the probability that there is at least one hit in a 30-second period (that is the probability of one or more hits)
Answer:
86.47% probability that there is at least one hit in a 30-second period
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Mean rate of four hits per minute.
This means that [tex]\mu = 4n[/tex], in which n is the number of minutes.
What is the probability that there is at least one hit in a 30-second period
30 seconds is 0.5 minutes, so [tex]\mu = 4*0.5 = 2[/tex]
Either the site doesn't get a hit during this period, or it does. The sum of the probabilities of these events is 1. So
[tex]P(X = 0) + P(X \geq 1) = 1[/tex]
We want [tex]P(X \geq 1)[/tex]
Then
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353[/tex]
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1353 = 0.8647[/tex]
86.47% probability that there is at least one hit in a 30-second period