A class has 25 students. In how many seats can four students be chosen as class leaders?

Answer:

Probably 95*

Step-by-step explanation:

If you look at the lines, the angle with Y looks equal to the bottom 95* angle.

Answer:

Area = 104

Step-by-step explanation:

In the middle, 8x10 = 80

We see that the two outside sides are both width of 3, height of 8.

We can do 8x3 = 24 to find both, so 80+24 = 104

Answer:

A = 104

Step-by-step explanation:

Answer:

x = 8

Step-by-step explanation:

8x - 20 = 44

8x - 20 + 20 = 44 + 20

8x = 64

8x ÷ 8 = 64 ÷ 8

x = 8

Answer:

28 bags but see below

Step-by-step explanation:

Start by subtracting 320 from 1700

1700 - 320 = 1680

Now he can buy any number of bags as long as he doesn't go over 1680 pounds. Let's see what that means

1680 / 60 = 28 bags of cement.

The answer to the math problem is 28 bags.

In real life, you likely want to trim it that close. What if you hit a bump. That would be very hard on the springs. I'd drop it down to 26 bags if I was actually transporting  concreate mix.

He could by any number of bags between 1 and 28 in a math class and a few less in actual practice.

Answer:

90 km

Step-by-step explanation:

Answer:

The answer is 3,200 oz.

Step-by-step explanation:

Because since 16 oz. is equal to 1 pound, you can multiply 16 and 200 and get a result of 3,200

Answer:

i think Muhammad

Step-by-step explanation:

Answer:

Look Down

Step-by-step explanation:

I believe its B Zoroastar

Answer:

Sebastian

Step-by-step explanation:

Answer:

It will fit

Step-by-step explanation:

165 / 15 = 11

So b = 11

12.5 can fit in 15

and 5.3 can fit in 11 so it will fit.

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

Since [tex]AB \neq BC \neq AC[/tex] and [tex]\cos B = 0[/tex], we conclude that given triangle is a right-angled and scalene.

Step-by-step explanation:

First, we determine the lengths of sides [tex]AB[/tex], [tex]BC[/tex] and [tex]AC[/tex] by the Equation of the Line Segment, which is based on the Pythagorean Theorem:

Line segment AB

[tex]AB = \sqrt{(4-1)^{2}+ (4-1)^{2}}[/tex]

[tex]AB = 3\sqrt{2}[/tex]

Line segment BC

[tex]BC = \sqrt{(6-4)^{2}+(2-4)^{2}}[/tex]

[tex]BC = 2\sqrt{2}[/tex]

Line segment AC

[tex]AC = \sqrt{(6-1)^{2}+(2-1)^{2}}[/tex]

[tex]AC = \sqrt{26}[/tex]

And the angles are found by means of the Law of Cosine:, where acute angles exist when [tex]0 < \cos \theta < 1[/tex], whereas obtuse angles exist for [tex]-1 < \cos \theta < 0[/tex].

Angle A

[tex]BC^{2} = AB^{2} + AC^{2} - 2\cdot AB\cdot AC \cdot \cos A[/tex] (1)

[tex]\cos A = \frac{BC^{2}-AB^{2}-AC^{2}}{-2\cdot AB\cdot AC}[/tex]

[tex]\cos A = \frac{8-18-26}{-2\dot (3\sqrt{2})\cdot (\sqrt{26})}[/tex]

[tex]\cos A = 0.832[/tex]

Angle B

[tex]AC^{2} = AB^{2} + BC^{2} - 2\cdot AB\cdot BC\cdot \cos B[/tex] (2)

[tex]\cos B = \frac{AC^{2}-AB^{2}-BC^{2}}{-2\cdot AB\cdot BC}[/tex]

[tex]\cos B = \frac{26-18-8}{-2\cdot (3\sqrt{2})\cdot (2\sqrt{2})}[/tex]

[tex]\cos B = 0[/tex]

Angle C

[tex]AB^{2} = AC^{2}+BC^{2}-2\cdot AC\cdot BC\cdot \cos C[/tex] (3)

[tex]\cos C = \frac{AB^{2}-AC^{2}-BC^{2}}{-2\cdot AC\cdot BC}[/tex]

[tex]\cos C = \frac{18 -26-8}{-2\cdot (\sqrt{26})\cdot (2\sqrt{2})}[/tex]

[tex]\cos C = 0.555[/tex]

Since [tex]AB \neq BC \neq AC[/tex] and [tex]\cos B = 0[/tex], we conclude that given triangle is a right-angled and scalene.

Answer:

The area of the parking lot is: 144cm^2

Step-by-step explanation:

Given

See attachment for polygon

Required

The area of the parking lot

The attached plot has 6 congruent triangles with the following dimension;

[tex]Base = 6cm[/tex]

[tex]Height = 8cm[/tex]

[tex]Area = \frac{1}{2} * Base * Height[/tex]

[tex]Area = \frac{1}{2} * 6cm * 8cm[/tex]

[tex]Area = 24cm^2[/tex]

The area of the 6 triangles is:

Area = 6 * Area of 1 triangle

[tex]Area = 6 * 24cm^2[/tex]

[tex]Area = 144cm^2[/tex]

Answer:

(-8,0)

Step-by-step explanation:

X=-8+y equation 1

-3x-3y=24 equation 2

-3(-8+y)-3y=24 sub x value in equation into x value of equation 2

24-3y-3y=24

-6y=0

y=0

solve for x

x=-8+y

x=-8+0

x=-8

check answer:

-3x-3y=24

-3(-8)-3(-0)=24

24-0=24

24=24

Answer:

128

Step-by-step explanation:

If the area of a figure is 32 square centimeters then the length/breadth could be 8cm and 4cm or 16cm and 2cm.

Let’s assume that the the sides of the figure are doubled, if that’s the case then we would arrive at 8*2 * 4*2 or 16*2 * 2*2 in which 16*8 or 32*4 which will both result to 128 as the answer.

answer 4

explanation

Nikki sold 4 more than Samantha number times 5

24-4=20

so Samantha number times five equals 20

20÷5=4

Samantha sold 4 boxes of cookies

Answer:

I'm not the best in math and honestly just goo gled this one when i had to do it paste, maybe that will help ill try another way if it does not

..

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

If you solve y = -x - 2 you can plot (-4,2)

Answer:

4

Step-by-step explanation:

multiplication is repeated addition

Answer:

4

Step-by-step explanation:

9+9+9+9= 36

36/9= 4

4×9= 9+9+9+9

Answer:

the first one is three and the second one is 12

Answer:

BC = 1.71

Step-by-step explanation:

SOHCAHTOA

Cosine = Adjacent over Hypotenuse

cos70 = ? / 5

? = 5*cos70

? = 1.7101

Answer:

0

Step-by-step explanation:

2x – 5x + 16 = –3(x – 6)

2x - 5x + 16 = -3x + 18

-3x + 16 = -3x + 18

0x = 1

x = 0

Answer:

x = ∅

Step-by-step explanation:

2x - 5x + 16 = - 3 (x - 6)

combine like terms

- 3x + 16 = - 3 (x - 6)

distribute

- 3x + 16 = - 3x + 18

subtract 3x from both sides

16 = 18

The equation is false and so x = ∅

Answer: a

Step-by-step explanation:

15.00x13.00=195

3x15.00=45.00

15x10.00=150.00

150.00+45.00=195.00

Answer:

Y=4x + 2 OB y= -x + 5 oC y=2x + 4 D. Y= -x+2

Step-by-step explanation:

The table below lists points of a linear function. X y-1 2 1 6 2 8 5 14

A.Y=4x + 2 OB y= -x + 5 oC y=2x + 4 D. Y= -x+2

The lateral surface area of the cone will be 65π square cm.

Let d be the diameter of the base circle, l be the slant height, and h be the height of the cone.

Then the lateral surface area of the cone will be

LSA = πrl

Then the slant height is given as

l² = r² + h²

l² = 5² + 12²

l² = 25 + 144

l² = 169

 l = 13 cm

Then the lateral surface area will be

LSA = π × 5 × 13

LSA = 65π cm²

More about the lateral surface area of a cone link is given below.

https://brainly.com/question/27492847

#SPJ2

Answer:

The volume of the prism is not equal to the volume of the cylinder.

Step-by-step explanation:

I took the test and it was right

If the base area of a triangular prism and a right cylinder are congruent then the volume of both can not be the same.

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

The cross-sectional areas of a triangular prism and a right cylinder are congruent.

The triangular prism has a height of 10 units, and the right cylinder has a height of 7 units.

The volume of the triangular prism will be

[tex]\rm Triangular \ prism \ volume = \dfrac{1}{2} \times a \times b \times 10\\\\\rm Triangular \ prism \ volume = 5ab[/tex]

Where a is the height of the triangle and b is the base of the triangle.

The volume of the right cylinder will be

[tex]\rm Right \ cylinder \ volume = \pi \times r^2 \times 7\\\\\rm Right \ cylinder \ volume = 22\ r^2[/tex]

Where r is the radius of the base circle.

If the base area of a triangular prism and a right cylinder are congruent then the volume of both can not be the same.

More about the geometry link is given below.

https://brainly.com/question/7558603

#SPJ2

Answer:

it sold 300 newspapers because you needed to multiply 25x 12

Step-by-step explanation: