A city continuously disposes of effluent from a wastewater treatment plant into a river. The minimum flow in the river is 130 m3/s, and the discharge from the treatment plant is 37 m3/s. Upstream from the outfall, the background concentration is 0.69 mg/L. The maximum allowable concentration in the river is 1.1 mg/L. What is the maximum concentration that of the pollutant (in mg/L) that can be safely discharged from the wastewater treatment plant

Answers

Answer 1

Answer:

[tex]2.54\ \text{mg/L}[/tex]

Explanation:

C = Allowable concentration = 1.1 mg/L

[tex]Q_1[/tex] = Flow rate of river = [tex]130\ \text{m}^/\text{s}[/tex]

[tex]Q_2[/tex] = Discharge from plant = [tex]37\ \text{m}^3/\text{s}[/tex]

[tex]C_1[/tex] = Background concentration = 0.69 mg/L

[tex]C_2[/tex] = Maximum concentration that of the pollutant

The concentration of the mixture will be

[tex]C=\dfrac{Q_1C_1+Q_2C_2}{Q_1+Q_2}\\\Rightarrow C_2=\dfrac{C(Q_1+Q_2)-Q_1C_1}{Q_2}\\\Rightarrow C_2=\dfrac{1.1(130+37)-130\times 0.69}{37}\\\Rightarrow C_2=2.54\ \text{mg/L}[/tex]

The maximum concentration that of the pollutant (in mg/L) that can be safely discharged from the wastewater treatment plant is [tex]2.54\ \text{mg/L}[/tex].


Related Questions

Which salt preparation uses a burette and a pipette

Answers

potassium chloride from potassium hydroxide and hydrochloric acid

Titrations provide a method of quantitatively measuring the concentration of an unknown solution.

a. Trueb. False

Answers

Answer: True

Explanation:

Titration is a quantitative technique where a solution of known concentration is used to determine the concentration of an unknown solution. The titrant (the known solution) is added from a burette to a known quantity of the the unknown solution until the reaction is complete.

By knowing the volume of titrant,  we can determine the concentration of the unknown.

Thus the statement Titrations provide a method of quantitatively measuring the concentration of an unknown solution is True .

A sample of chlorine gas has a volume of 0.30 L at 273 K and 1 atm pressure. What temperature (in ∘C) would be required to increase the volume to 1.0 L ?

Answers

Answer:

[tex]T_2=637\°C[/tex]

Explanation:

Hello there!

In this case, considering this problem as pressure constant, since the change is exhibited in temperature and volume only, it is possible for us to use the Charles' law as shown below:

[tex]\frac{V_2}{T_2}=\frac{V_1}{T_1}[/tex]

Thus, by solving for the final temperature, we obtain:

[tex]T_2=\frac{T_1V_2}{V_1}\\\\T_2=\frac{273K*1L}{0.30L}\\\\T_2=910K-273\\\\T_2=637\°C[/tex]

Best regards!

g At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H 2 (g) Br 2 (g) 2HBr (g) A mixture of 0.682 mol of H 2 and 0.440 mol of Br 2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.516 mol of H 2 present. At equilibrium, there are ________ mol of Br 2 present in the reaction vessel.

Answers

Answer: At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]

Explanation:

Moles of  [tex]H_2[/tex] = 0.682 mole

Moles of  [tex]Br_2[/tex] = 0.440 mole

Volume of solution = 2.00 L

Initial concentration of [tex]H_2[/tex] = [tex]\frac{0.682}{2.00}=0.341 M[/tex]

Initial concentration of [tex]Br_2[/tex] =  [tex]\frac{0.440}{2.00}=0.220 M[/tex]

Equilibrium concentration of [tex]H_2[/tex] = [tex]\frac{0.516}{2.00}=0.258 M[/tex]

The given balanced equilibrium reaction is,

             [tex]H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)[/tex]

Initial conc.   0.341 M    0.220 M        0 M    

At eqm. conc.   (0.341-x) M   (0.220-x) M   (2x) M

Given : (0.341-x) M = 0.258 M

x= 0.083 M

Thus equilibrium concentartion of [tex]Br_2[/tex] = (0.220-0.083) M = 0.137 M

Thus moles of [tex]Br_2[/tex] at equilibrium = [tex]0.137M\times 2.00L=0.274mol[/tex]

At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]

Suppose that scientists want to study a feature of the galaxy that is very far away. They decide to use a telescope that observes high-energy gamma rays. Explain why this would be a good choice.

Answers

Answer & Explanation:

Gamma rays are the most energetic form of electromagnetic radiation. By observing the distant galaxy at gamma-rays, scientists can search for new physics, test theories, and perform experiments that are not possible in earth-bound laboratories.

Atoms in the same GROUP have the same...

A . Size
B. Temperature
C. Number of energy levels
D. Reactivity

Answers

Answer:

reactivity

Explanation:

for example atoms in group 7 react by gaining 1 electron to become stable but they do not have the same number of energy levels

why is space cold ???

Answers

Because the space is ultimate thermos.

visible light travels from place to place as a

Answers

Answer:

Light can travel in three ways from a source to another location: (1) directly from the source through empty space; (2) through various media; (3) after being reflected from a mirror.

Explanation:

Hydrogen chloride dissolved in water yields hydrochloric acid. What is the
molar concentration of HCl if 3.65 g of hydrogen chloride is dissolved in 500 mL of
water?

Answers

Answer:

1500ml

Explanation:

molarity=3.65⋅g36.5⋅g⋅mol−1500⋅mL×10−3⋅L⋅mL−1=0.200⋅mol⋅L−1

A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
mass.
Question 1: The empirical formula for this compound is :

Question 2: The molar mass for this compound is 82.98 g/mol.
The Molecular formula for this compound is:

Answers

Answer: 1. The empirical formula is [tex]PNF_2[/tex]  

2. The molecular formula is [tex]PNF_2[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P =[tex]\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles[/tex]

Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles[/tex]

Moles of F =[tex]\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = [tex]\frac{1.20}{1.20}=1[/tex]

For N = [tex]\frac{1.20}{1.20}=1[/tex]

For F =[tex]\frac{2.41}{1.20}=2[/tex]

The ratio of P: N: F= 1: 1: 2  

Hence the empirical formula is [tex]PNF_2[/tex]

The empirical weight of [tex]PNF_2[/tex]= 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1[/tex]

The molecular formula will be=[tex]1\times PNF_2=PNF_2[/tex]

Considering change of state descriptions, select the name of the change of state for when energy is absorbed. Group of answer choices sublimation freezing condensation deposition

Answers

Answer: Sublimation

Explanation:

Sublimation : It is a process in which a solid directly changes to gaseous phase by providing heat.

Freezing is a process in which a liquid changes into solid phase when allowed to cool.

Condensation is a process in which a gas changes into liquid phase when allowed to cool.

 Deposition is a  process in which a gas deposits as solid phase when allowed to cool.

Thus change of state where energy is absorbed is sublimation.

A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrate the excess complexing reagent after the addition of 70.00 mL of 0.009005 M EDTA to a 20.00 mL aliquot of the Co2 solution.

Answers

Answer:

85.952 ml [tex]Zn^2^+[/tex]  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of [tex]CoSO_4[/tex] =[tex]\frac{Given mass }{molar mass}[/tex]

                                                       =[tex]\frac{1.817}{155}[/tex]

                                                          =0.01172

Molarity = [tex]\frac{no. of moles}{volume of solution}[/tex]

           =[tex]\frac{0.01172}{20}[/tex]

        =0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

                            = 0.009005 - 0.000586

                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 [tex](Zn^2^+)[/tex]

           [tex]0.008419\times100ml=0.009795\times V2[/tex]

           [tex]V2=\frac{0.008419\times100}{0.009795}[/tex]

             V2 =85.952 ml

Therefore , 85.952 ml [tex]Zn^2^+[/tex] needed to titrate the excess complexing reagent .

What is orbit? A. An increase in centripetal motion and mass friction. B. Resistance of an object to avoid friction. C. Gravity causing a curved path as an object tries to go straight. D. How well an object floats.

Answers

Answer:

C. gravity causing a curved path as an object tries to go straight.

Reaction of Nitrile with Grignard Grignard reagents react with nitriles to give an intermediate imine anion that is hydrolyzed by the addition of water to yield a ketone. The mechanism is similar to the reduction of a nitrile to an amine except that only one nucleophilic addition occurs instead of two, and the nucleophile is a carbanion rather than a hydride ion.

Required:
Draw curved arrows to show the movement of electrons. in this step of the mechanism. Arrow-pushing Instructions

Answers

Answer:

its a.

Explanation:

A student in the lab accidentally poured 45 mL of water into a graduated cylinder containing 15 mL of 3.0 M HCL. What is the concentration of the new solution?

Answers

Answer:

The correct approach is "1 M".

Explanation:

The given values are:

Volume of HCL,

V₁ = 45 ml

In prepared solution,

V₂ = 15 ml

Concentration,

C₁ = ?

C₂ = 3.0 M

As we know,

⇒  [tex]V_1C_1=V_2C_2[/tex]

or,

⇒      [tex]C_1=\frac{V_2C_2}{V_1}[/tex]

On substituting the values, we get

⇒           [tex]=\frac{15\times 3}{45}[/tex]

⇒           [tex]=\frac{45}{45}[/tex]

⇒           [tex]=1 \ M[/tex]

A 1.om sample of dry air at
at 25°c at 786mmHg contains 0.925g Nitrogen Plus other gases including oxygen, argon and carbon dioxide. what is the partial pressure of Na with the air sample.

Answers

Answer:

Is the question not supposed to be what is the partial pressure of Nitrogen not Sodium

Use the following Balanced Equation to complete the question: 2 Al + 6 HBr → 2 AlBr3 + 3 H2

If you have 10 moles of Al how many moles of H2 can be produced?


*Will give Brainly!*

Answers

Here is the answer enjoy

what blood vessels and chambers of the heart does a molecule of glucose absorbed through the gut passes on its way to an active muscle in the leg

Answers

Answer:

Blood capillaries

Explanation:

The walls of capillaries are just one cell thick. Capillaries therefore allow the exchange of molecules between the blood and the body's cells - molecules can diffuse across their walls. This exchange of molecules is not possible across the walls of other types of blood vessel.

gases are really _______ and molecules are full of _______, bouncing around constantly

Answers

Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.

Answer:Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.

Explanation:

A gas has a volume of 10 L at 200 K and a pressure of 1.5 atm . What would the volume of the gas be at 300 K and 2atm of pressure ?

Answers

Answer:

jeyjeyjetnetney

Explanation:

thmrhmrhmrum

What's the bond between two atoms of hydrogen?​

Answers

Answer:There is a iin dipole attraction between two hydrogen atom

Explanation:

The same atoms have the ion dipole attraction between them the same atoms repel each other

The process of breaking a compound down into its elements is called
rearrangement
recombination
decomposition
dessication

Answers

I believe it’s decomposition

Plzz help me well mark brainliest if you are correct

Answers

Answer:

A. non renewable energy sources cannot be used over again and renewable energy sources can be used again

Answer:

A. Nonrenewable energy sources cannot be used over again. Renewable energy sources can be used again.

Explanation:

In what industry do fertilizers and pesticides wash off and contaminate water supplies?Construction Oil Transportation Agriculture

Answers

Answer:

The answer is agriculture.

Explanation:

Answer: Agriculture

Explanation:

I got it right on my exam

What is the value of the equilibrium constant K ?

Answers

Answer:

K = 0.0209

Explanation:

K = [tex]\frac{[H_{2}][I_{2}]}{[2HI]^{2}}[/tex]

K = [tex]\frac{[4.35 x 10^{-2} ][2.79 x 10^{-2} ]}{[0.241]^{2} }[/tex]

K = 0.0208958

K = 0.0209

When P4O10(s) reacts with H2O(l) to form H3PO4(aq) , 453 kJ of energy are evolved for each mole of P4O10(s) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.

Answers

Answer:

P4O10 + 6H2O → 4H3PO4         ΔH = 453 kJ

Explanation:

A thermochemical reaction is one in which the amount of heat gained/evolved is written as part of the reaction equation.

A thermochemical equation helps us to judge whether an equation is endothermic or exothermic. For an endothermic reaction, ΔH  is positive while for an exothermic reaction ΔH is negative.

Since, the reaction of one mole of P4O10(s)  with H2O(l) to form H3PO4(aq) evolves 453 kJ of energy for each mole of P4O10(s) that reacts. Then we can write;

P4O10 + 6H2O → 4H3PO4         ΔH = 453 kJ

What is it called when a gas turns into a liquid

Answers

Answer:

condensation

Explanation:

The process of a gas becoming a liquid is called condensation.

☁️ Answer ☁️

Condensation

"Condensation is the name of the process through which gas turns into a liquid. Three common states of matter exist: solids, liquids and gases. Matter, however, can change its state with the addition or subtraction of energy. The energy is usually in the form of heat. "

Hope it helps.

Have a nice day noona/hyung.

how many ions does magnesium phosphite have? how many of those are anions? please explain thought process.

Answers

Answer:

We can simply refer to the cation in the ionic compound as magnesium. Phosphorus, Pstart text, P, end text, is a group 15 element and therefore forms 3- anions.

Explanation:

Because it is an anion, we add the suffix -ide to its name to get phosphide as the name of the ion.

Convert 5.28 x 1019 molecules of C6H1206 to grams.

Answers

Answer:

[tex]m=0.0158g[/tex]

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

[tex]m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g[/tex]

Best regards!

__Zn+__HCI → _ZnCl2 + __H2

Answers

Answer:

1Zn+ 2HCI → 1ZnCl2 + 1H2

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