Answer:
[tex]power = \frac{(force \times distance)}{(time)} \\ power = \frac{(20 \times 10)}{4} \\ power = \frac{200}{4} \\ power = 50 \: watts[/tex]
A non -viscous incompressible fluid is pumped steadily into the narrow end of a long tapered pipe and emerges from the wide end . The pressure at the input is greater than at the output . A possible explanation is :
Answer:
v₂ =[tex]( \frac{r_1}{r_2})^2 \ v_1[/tex]
Explanation:
This phenomenon is explained by the continuity equation in fluids
v₁A₁ = v₂A₂
where the subscript 1 is for the input narrow part and the subscript 2 for the wide part
v₂ = [tex]\frac{A_1}{A_2} v_1[/tex]
consider the cross section at each point
A₁ = π r₁²
A₂ = π r₂²
we substitute
v₂ =[tex]( \frac{r_1}{r_2})^2 \ v_1[/tex]
therefore the exit velocity is less than the entrance velocity of the fluid.
We can also analyze the situation using Bernoulli's equation
P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y²
if we assume a horizontal system y₁ = y₂
P₁-P₂ = ρ g (v₂² - v₁²)
what force is required to accelerate to 10 kg object to 5.9 m/s/s?
Force required to accelerate 10 kg object to 5.9 m/s/s ?
Mass = 10 kg
Acceleration = 5.9 m/s^2
Force = Mass * Acceleration
Force = 10 kg * 5.9 m/s^2
Force = 59 kg m /s^2 = 59 N
2. An object's weight is proportional to its _ or _ from another object
Answer:
mass
gravitational pull