A chemist titrates 50.0 mL of a 0.1333 M benzoic acid (HCH,CO2) solution with 0.2560M NaOH solution at 25 °C. Calculate the pH at equivalence. The
PK, of benzoic acid is 4.20.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.
DH-0
5
?

Answers

Answer 1
Oh okie gosh lol I don’t know what

Related Questions

Knowing that Boyle's Law is P1V1 = P2V2, How would we rearrange the formula if we needed to solve for P1?
A. P1 = V1 -P2
B. P1 = P2V2 - V1
C. P1 = P2V2/V1
D. P1= V1/V2

Answers

i think the answer would be D i’m sorry if it’s wrong

Answer:

your answer is C

Explanation:

because when u make P1 the subject formula then P2 V2 will be divided with V1

How many moles of gold atoms do 3.45x10^24 gold atoms constitute?

Answers

Answer:

3.45E24

Explanation:

calculator I'm not that great at math but I'm good at science but that isn't really science but it's aix between it tho

1. Which kingdom is made up of only autotrophs?
A. Protista
I
B. Animalia
C. Plantae
D. Phylum

Answers

Answer: I believe it's C

Hope this helped<3

Can you please make my answer brainly

Which contributes to the polarity of a water molecule?

Oa linear shape along with strong covalent bonds

O deflection of hydrogen atoms by lone pairs of electrons

O no difference in the electronegativity of oxygen and hydrogen

Ohydrogen bond formation between water molecules​

Answers

Answer:

B

Explanation:

Answer:

B

Explanation:

Edge 2022

Which of the following is the Brønsted-Lowry definition of an acid?​

Answers

Answer:

A Brønsted-Lowry acid is any species that can donate a proton (H +) to another molecule. A Brønsted-Lowry base is any species that can accept a proton from another molecule. In short, a Brønsted-Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).

Convert 25.6 L of a gas at STP to molecules

Answers

25.6L / 22.4 L=1.14 moles

Beth heats a pot of water to cook pasta. What may happen as a result of adding heat

Answers

Answer:

the pasta will soften

Explanation:

the pasta will boil and will soften up as a result of it being regular pasta

what are the three components of a chemical formula?​

Answers

Answer:

The three components of a chemical formula are the empirical formula, the molecular formula, and the structural formula.Hope this answer helps.

Question #37.P.2A.2
Which statement about the periodic table is true?
a. Elements in the same column share similar properties.
b. Elements in the same row share similar properties.
c. Elements on the left have a larger nucleus than elements on the right.
d. Elements at the top of each column have the highest atomic mass in that column.

Answers

a. Elements in the same column share similar properties.

This is because they have the same number of valence electrons, so they react and bond similarly.

What is one way that minerals crystallize from materials dissolved in water?

Answers

Answer:

From solutions that evaporate

From hot water solutions when the solution cools

Explanation:

The substances that can form minerals can be dissolved in the water to form a solution. Solution can be described as as a mixture in which a solute is dissolved in a solvent. When a particular dissolved solute evaporates from the solution, crystals of minerals might form. The mineral halite was formed when seas evaporated over a period of time.

The minerals can also be formed when a hot water solution gets cooled.

someone help i will give branliest:)

Answers

Answer:

i think answer is B negative effects and benefits

Calculate how many moles of NO2 form when each
quantity of reactant completely reacts.
2 N2O5(9) + 4NO2(g) + O2(9)
Part B
6.4 mol N205
Express your answer using two significant figures.
VALO
n =
Submit
Request Answer
Part C
16.2 g N205
Express your answer using three significant figurer

Answers

Answer:

partB: n=2N205

partc:17.20

Which of the following apply to concentration?

Answers

Answer:Concentration of products can vary.

As more solute dissolves, more ions form; but the volume in which they are contained does not change.

Concentration of the solid phase does not change.

Explanation:

Which of the following is the correct definition of "weathering"? *

The movement of rocks

The breakdown of rocks.

The dropping off of rocks

All of the above

Answers

I think that it would be the breakdown. Hope this helps!
the breakdown of rocks is the answer!

what energy is stored

Answers

Answer: potential energy is stored

Explanation:

Consider the addition of an electron to the following atoms from the fourth period. Rank the atoms in order from the most negative to the least negative electron affinity values based on their electron configurations. Atom or ion Electron configuration BrBr 1s22s22p63s23p64s23d104p51s22s22p63s23p64s23d104p5 GeGe 1s22s22p63s23p64s23d104p21s22s22p63s23p64s23d104p2 KrKr 1s22s22p63s23p64s23d104p61s22s22p63s23p64s23d104p6 Rank the electron affinity from most negative to least negative. To rank items as equivalent, overlap them. View Available Hint(s)

Answers

Answer:

Br>Ge>Kr

Explanation:

Electron affinity is the energy change that results from adding an electron to a gaseous atom(Khan Academy). It is also defined as "the amount of energy released when an electron is attached to a neutral atom or molecule in the gaseous state to form a negative ion" (Wikipedia).

Electron affinity increases from left to right in the periodic table. However, the noble gases possess a complete outermost electron shell.

Hence, electron affinity can be raked from the most negative to the least negative for the three atoms as follows; Br>Ge>Kr

What is  the correct name of the acid corresponding to the BrO3- oxoanion  ​

Answers

Answer:

hello

Bromate is a bromine oxoanion and a monovalent inorganic anion. It is a conjugate base of a bromic acid.

Explanation:

thanks

_BaS + _PtF2 → _BaF2 + _Pts

Answers

[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]

_BaS + _PtF2 → _BaF2 + _Pts

Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.

=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS

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HOPE IT HELPS

PLEASE MARK ME BRAINLIEST☺️

When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing point of pure . On the other hand, when of sodium chloride are dissolved in the same mass of , the freezing point of the solution is lower than the freezing point of pure . Calculate the van't Hoff factor for sodium chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Answers

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=8.2^0C[/tex] = Depression in freezing point

[tex]K_f[/tex] = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =[tex]\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9[/tex]

[tex]8.2^0C=1\times K_f\times 1.9[/tex]

[tex]K_f=4.32^0C/m[/tex]

Now Depression in freezing point for sodium chloride is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=20.0^0C[/tex] = Depression in freezing point

[tex]K_f[/tex] = freezing point constant  

m= molality = [tex]\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45[/tex]

[tex]20.0^0C=i\times 4.32^0C\times 2.45[/tex]

[tex]i=1.9[/tex]

Thus vant hoff factor for sodium chloride in X is 1.9

8. A liquid boils when the vapor pressure of the liquid equals the atmospheric pressure on the surface
of the liquid. Using Reference Table H, determine the boiling point of water when the atmospheric
pressure is 90. kPa

Answers

Answer:

It is 98 degrees C.

Explanation:

HELP ANYONE THERE
At a research lab, a scientist carelessly pours cultures of living microbes down the drain. Which type of pollution is this?

Question 4 options:

toxic


sediment


nutrient


bacterial

Answers

A scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.

What is bacterial pollution?

Bacterial pollution refers to the uncontrolled proliferation of bacteria in the surrounding environment and ecosystems.

Bacterial pollution can be a subject of concern because bacteria may be pathogenic microorganisms.

Bacterial pollution may cause serious harm to the public health and the well-being of a population.

In conclusion, a scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.

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https://brainly.com/question/24704410

what components of static electricity theory does Electrostatic Precipitator make use of

Answers

Answer:

Electrostatic smoke precipitators work by forcing dirty flue gas (the gas escaping from a smokestack) past two electrodes (electrical terminals), which take the form of metal wires, bars, or plates inside a pipe or smokestack

Explanation:

#8 explain and answer

Answers

Answer:

B. The limiting reactant determines the maximum amount of product that can be formed.

explanation and answer and you’ll get brain list

Answers

Answer:

Option B.

Explanation:

2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂

First we convert 9.90 g of Pb(NO₃)₂ into moles, using its molar mass:

9.90 g ÷ 331.2 g/mol = 0.0299 mol Pb(NO₃)₂

Then we convert moles of Pb(NO₃)₂ into moles of PbO, using the stoichiometric coefficients:

0.0299 mol Pb(NO₃)₂ * [tex]\frac{2molPbO}{2molPb(NO_3)_2}[/tex] = 0.0299 mol PbO

Now we convert 0.0299 mol PbO into grams, using its molar mass:

0.0299 mol PbO * 223.2 g/mol = 6.67 g PbO

So 6.67 g is the theoretical yield. With that in mind we calculate the percent yield:

% yield = 5.51 / 6.67 * 100 % = 82.6%

So the correct answer is option B.

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m2 at 500C. Assume a diffusion coefficient of 1.0 108 m2 /s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained

Answers

This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained

Answer:

the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

Explanation:

Given the data in the question;

thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

concentration high pressure side C[tex]_A[/tex] = 2.4

concentration low pressure side C[tex]_B[/tex] = 0.6 kg

from the question, we calculate the concentration gradient

dc/dx = (C[tex]_A[/tex] -  C[tex]_B[/tex])/dt

so we substitute

dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )

dc/dx = -360

now, mass of hydrogen per hour that diffuse through a pd sheet

M = -∝AT(dc/dx)

where time t is 1 hour ( 3600 sec )

we substitute

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per one hour

Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.

Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.

According to the question, given data is:

Thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

Concentration high pressure side [tex]C_A[/tex] = 2.4

Concentration low pressure side[tex]C_B[/tex]= 0.6 kg

from the question, we calculate the concentration gradient,

[tex]dc/dx = (C _A- C_B)/dt[/tex]

so, we substitute the values,

[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)

[tex]dc/dx = -360[/tex]

Now, mass of hydrogen per hour that diffuse through a Palladium sheet,

M = -∝[tex]AT(dc/dx)[/tex]

where time t is 1 hour (3600 sec)

We substitute,

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per hour.

Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.

Learn more about purification here:

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

A student said, "You can't see the full Moon during the day because it rises close to sunset."
Which diagram supports this statement? (Diagrams are not to scale. You are looking down from
a north polar view fisa person standing on Earth at sunset.)
Oq. Ooo
Ooo
OD
ОА
OB
ОС
OD

Answers

Answer:

I think it would be B.

Explanation:

What are Renewable Resoures?

Answers

Answer:

resources that you can use more than 1 time like rechargeable battery or solar energy

Explanation:

Recourses that can be renewed, the world will never run out of them. Such as wind for wind turbines, sun for solar power, etc

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 100 cm3, the pressure is 150 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?

Answers

Answer:

The volume is decreasing at a rate of 30 cm³/min.

Explanation:

From the question given above, pressure (P) and volume (V) are related by the following equation

PV = C

C => constant

If we make P the subject of the above, we shall have:

P = C/V

From the equation above (i.e P = C/V),

We can say that P is inversely proportional to V. This implies that as P is increasing, V will be decreasing and also, as P is decreasing, V will be increasing.

Considering the question given above, the pressure (P) is increasing at a rate of 30 kPa/min. Therefore, the volume will be decreasing at a rate of 30 cm³/min.

Explain about Bose-Einstein condensate​.

Answers

A Bose-Einstein condensate is a group of atoms cooled to within a hair of absolute zero. When they reach that temperature the atoms are hardly moving relative to each other; they have almost no free energy to do so. At that point, the atoms begin to clump together, and enter the same energy states.

Answer:

A Bose-Einstein condensate or BEC in simple words is a group of atoms cooled near absolute zero.

Name the SI base units that are important in chemistry.

Answers

Units of the SI System

There are seven base units in the SI system:

the kilogram (kg), for mass

the second (s), for time

the kelvin (K), for temperature

the ampere (A), for electric current

the mole (mol), for the amount of a substance

the candela (cd), for luminous intensity

the meter (m), for distance

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