Answer:
First, we need to calculate the amount of heat transferred when the frozen piece of alcohol melts and then heats up to the final temperature.
The heat transferred, Q, can be calculated using the formula:
Q = mcΔT
where:
m = mass of the frozen alcohol (10 g)
c = specific heat of the alcohol (0.57 cal/g°C)
ΔT = change in temperature (7°C - (-11°C) = 18°C)
Q = (10 g)(0.57 cal/g°C)(18°C) = 102.6 cal
Next, we need to calculate the amount of heat released by the liquid alcohol as it cools from 22°C to 7°C.
The heat released, Q, can be calculated using the formula:
Q = mcΔT
where:
m = mass of the liquid alcohol (150 g)
c = specific heat of the alcohol (0.57 cal/g°C)
ΔT = change in temperature (22°C - 7°C = 15°C)
Q = (150 g)(0.57 cal/g°C)(15°C) = 128.25 cal
Since the heat released by the liquid alcohol (128.25 cal) is greater than the heat absorbed by the frozen alcohol (102.6 cal), we can assume that the excess heat released by the liquid alcohol is due to the latent heat of fusion of the frozen alcohol.
The latent heat of fusion (L) can be calculated using the formula:
L = Q/m
where:
Q = excess heat released by the liquid alcohol (128.25 cal - 102.6 cal = 25.65 cal)
m = mass of the frozen alcohol (10 g)
L = 25.65 cal / 10 g = 2.565 cal/g
Therefore, the latent heat of fusion for this alcohol is 2.565 cal/g.
what is $12.7\ge s-5.3$ .
The solution of expression $12.7\ge s-5.3$ is $s \leq 18$.
The expression $12.7\ge s-5.3$ is an inequality, which means that it expresses a range of values for the variable $s$. The symbol $\ge$ means "greater than or equal to," and in this context it indicates that $12.7$ is greater than or equal to $s-5.3$.
To solve for $s$, we can start by adding $5.3$ to both sides of the inequality:
\begin{align*}
12.7 &\ge s-5.3 \
12.7+5.3 &\ge s-5.3+5.3 \
18 &\ge s
\end{align*}
So the solution is $s \leq 18$. This means that any value of $s$ that is less than or equal to $18$ will satisfy the inequality. For example, $s=15$ would satisfy the inequality, because $12.7 \ge 15-5.3$. However, $s=20$ would not satisfy the inequality, because $12.7 \ngeq 20-5.3$.
What are the variables?
A variable is a symbol or letter that represents a value that can vary or change in a given context or problem. Variables are used to write mathematical expressions, equations, and functions.
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Complete question is: $12.7\ge s-5.3$ is $s \leq 18$.
An operating lamp draws a current of 0. 50 ampere. The amount of charge passing through the lamp in 10. Seconds is
please help asap
An operating lamp draws a current of 0. 50 ampere. the amount of charge passing through the lamp in 10 seconds is 5.00 Coulombs.
The amount of charge (Q) passing through a conductor is given by the product of current (I) and time (t):
Q = I * t
In this problem, we are given the following information:
The current passing through the lamp is I = 0.50 A
The time for which the current flows is t = 10 s
Using the above formula, we can calculate the amount of charge passing through the lamp as:
Q = I * t
Q = 0.50 A * 10 s
Q = 5.00 C
Thus, the amount of charge is 5.00 Coulombs.
The ampere, often shortened to amp, is the unit of electric current in the International System of Units.Ampere meter, commonly known as Ammeter is an electrical instrument used to measure electrical current in Amperes.
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as a van travels along a level stretch of road with constant speed, most of the power developed by the engine is used to compensate for the energy transformations due to friction forces exerted on the van by the air and the road. if the power developed by the engine is 2.01 hp, calculate the total friction force acting on the van (in n) when it is moving at a speed of 28 m/s. one horsepower equals 746 w.
When travelling at a speed of 28 m/s, the van experiences a total amount of friction force of 748 N.
Calculate the van's overall friction force (measured in N) at a speed of 28 m/s with an engine that produces 2.01 horsepower.
Engine power is calculated as
P = 2.01 hp, or 2.01 x 746, or 1502.46 W.
Van's top speed is 28 m/s.
The van's total work is equal to its change in kinetic energy, according to the work-energy theorem.
Hence, total work completed = Change in kinetic energy (K) -Change in kinetic energy (K)
= [tex](1/2) m (vf_2 - vi_2)[/tex] = [tex](1/2) m v^2[/tex]
where m is the van's mass
([tex]v_f[/tex]) = The van's final speed
([tex]v_i[/tex] )= The van's initial speed
As a result, the van is subject to a 748 N friction force (approx.). So, at a speed of 28 m/s, the van experiences a total friction force of 748 N.
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A metal cube with a negative charge -Q_1−Q
1
minus, Q, start subscript, 1, end subscript is brought into contact with a cylinder of a negative charge -Q_2−Q
2
minus, Q, start subscript, 2, end subscript, where |Q_1| > |Q_2|∣Q
1
∣>∣Q
2
∣vertical bar, Q, start subscript, 1, end subscript, vertical bar, is greater than, vertical bar, Q, start subscript, 2, end subscript, vertical bar
The metal cube will transfer some of its charge to the cylinder, causing both objects to have a net positive charge. This is because when two objects with opposite charges are brought into contact, they will exchange charges until they have the same magnitude and the same sign.
In this case, the cube with a greater charge will transfer charge until both objects have a positive charge.When an object has more electrons than protons is called a negative charge. A positive charge occurs when an atom has more protons than electrons. Electrons have a negative charge and protons have a positive charge. The unit of charge is the coulomb(C). Like charges repel each other.
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Question:
A metal cube with a negative charge -Q_1−Q 1 minus, Q, start subscript, 1, end subscript is brought into contact with a cylinder of a negative charge -Q_2−Q 2 minus, Q, start subscript, 2, end subscript, where
|Q_1| > |Q_2|Q1∣>∣Q 2∣vertical bar, Q, start subscript, 1, end subscript, vertical bar, is greater than, vertical bar, Q, start subscript, 2, end subscript, vertical bar.
What is the difference between energy transfer and energy store? I need proper explanation please!?
Energy transfer is the movement of energy from one location to another. ... Energy transformation is when energy changes from one form to another – like in a hydroelectric dam that transforms the kinetic energy of water into electrical energy.
Energy transfer in physics refers to the movement of energy from one object or system to another. Energy can take various forms such as kinetic energy, potential energy, thermal energy, electromagnetic radiation, and chemical energy, among others. The transfer of energy can occur through different mechanisms such as work, heat, and radiation.
Work is the transfer of energy that occurs when a force acts on an object and causes it to move a certain distance. Heat transfer is the flow of energy from a hotter object to a cooler object, driven by a temperature difference between the two objects. Radiation is the transfer of energy in the form of electromagnetic waves or particles. Energy transfer is a fundamental concept in physics as it governs many natural phenomena such as heat flow, electrical power generation, and energy conversion in machines.
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a football is kicked from the ground with a speed of 28.65 m/s at an angle of 37.18 degrees. what is the horizontal displacement of the football when it lands back on the ground?
49.87 m. is the horizontal displacement of the football when it lands back on the ground.
The horizontal displacement of the football can be determined using the formula
x = vxt,
where vx is the initial x-component of the velocity, and t is the time the football is in the air.
The initial x-component of the velocity (vx) can be calculated using the formula
vx = vcos(θ),
where v is the initial velocity, and θ is the angle of projection.
Therefore, vx = 28.65cos(37.18) = 25.36 m/s
The time the football is in the air (t) can be calculated using the formula t = 2vsin(θ)/g, where g is the acceleration due to gravity (9.81 m/s2).
Therefore, t = 2(28.65sin(37.18))/9.81 = 1.97 seconds
Finally, the horizontal displacement (x) can be calculated using the formula x = vxt.
Therefore, x = 25.36*1.97 = 49.87 m.
Therefore, the horizontal displacement of the football when it lands back on the ground is 49.87 m.
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a stationary source of sound has a fundamental frequency of 500 hz. what frequency will you hear when you are approaching the source of sound at 20 m/s? the speed of sound is 340 m/s.
The frequency you will hear when you are approaching a stationary source of sound at 20 m/s is 537 Hz.
What is the fundamental frequency of sound?
The fundamental frequency of sound is the lowest frequency produced by a vibrating object or sound source.
What is the speed of sound? The speed of sound is the distance covered by a sound wave per unit of time.
The given values are as follows:
frequency of sound = 500 Hz
speed of sound = 340 m/s
velocity of the observer = 20 m/s
Formula to find the frequency heard by the observer
The formula for finding the frequency of a sound wave observed by a moving observer is:
[tex]f\prime = \frac{f \times (v + v_o)}{(v - v_S)}[/tex]
Where, f' is the frequency observed
v is the speed of sound
f is the frequency of the sound source
[tex]v_S[/tex] is the velocity of the sound source
v₀ is the velocity of the observer
Substituting the given values into the above formula, f' = [tex]\frac{500 \times (340 + 20)}{(340 - 20)}
Hence, f' = 537 Hz
Therefore, when you are approaching the source of sound at 20 m/s, you will hear a frequency of 537 Hz.
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*100 points* How does the bending of light depend on the two media and what is the mystery medium A? (This is a project where you have to find what medium A is, and use Snells law to calculate it)
The bending of light as it passes from one medium to another is governed by Snell's law, which depends on the indices of refraction of the two media and the angle of incidence
The bending of light as it travels from one medium to another is described by Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction of the two media:
n1 sin(theta1) = n2 sin(theta2)
where n1 and n2 are the indices of refraction of the two media, theta1 is the angle of incidence (the angle between the incident ray and the normal to the interface between the two media), and theta2 is the angle of refraction (the angle between the refracted ray and the normal).
The index of refraction of a medium is a measure of how much the speed of light is reduced when it travels through that medium compared to its speed in a vacuum.
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Pls help! Could you guys verify if the correct answer is B because of the v^2? See the attached image below :)
Answer:
It could either be b, or d, Your choice! (hint: I know the answer but pick one)
How much work is done by an engine to accelerate an
800 kg vehicle from 10 m/s to 20 m/s?
We are unable to directly determine the work performed by the engine because the distance over which the force acts is unknown.
What work is involved in accelerating an 800 kg automobile from 5 meters per second to 10 meters per second?This indicates that the effort expended to increase the car's speed will be equivalent to the change in kinetic energy of the vehicle. Thus, 30 kJ of effort must be performed.
What is the recipe for getting stuff done?The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.
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Use the diagram and the drop-down menu to answer the question.
If bulb C burns out, what will happen to bulbs A and B
Answer: They both will go out
Explanation:
In a physics lab experiment, a 6kg box is pushed across a flat table by a horizontal force F . What the magnitude of force F if the box is speeding up with a constant acceleration of 0.18ms^-2?
Answer:
The F's accelerated
where m is the box's mass, an is its acceleration, and F net is the net force.
The net force in this situation is equal to the applied force less any potential frictional forces. The net force is just the force applied to the box, assuming the table is smooth and there is no friction:
F net = F
Thus, the equation can be rewritten as follows:
F = m * a
Inputting the values provided yields:
F = 6 kg times 0.18 m/s2 to get 1.08 N
As a result, 1.08 N of force F is needed to accelerate a 6 kilogramme box at a constant rate of 0.18 m/s2.
the mechanical advantage of a pulley that requires 20 N of force to lift a 90 N box. here the answer choices 45, 4.5 , and 0.2
Answer:
Explanation:
The mechanical advantage (MA) of a pulley is defined as the ratio of the output force (the force exerted by the pulley system) to the input force (the force applied to the pulley system).
In this case, the input force is 20 N, and the output force (the force needed to lift the box) is 90 N. Therefore, the mechanical advantage of the pulley can be calculated as:
MA = output force / input force
MA = 90 N / 20 N
MA = 4.5
So the mechanical advantage of the pulley is 4.5. This means that for every 1 N of force applied to the pulley system, the pulley system can lift 4.5 N of weight.
The ratio of the output force to the input force is used to calculate the mechanical advantage of a pulley system. In this case, the Mechanical Advantage of the pulley used to lift a 90N box with 20N of force is 4.5.
Explanation:The Mechanical Advantage (MA) of a machine is calculated by the ratio of output force (the force exerted by the machine) to the input force (the force applied on the machine). In this case, the output force is the weight of the box which is 90N, and the input force is the force required to lift the box which is 20N. Therefore, the mechanical advantage is calculated as MA = Output Force/Input Force = 90N/20N = 4.5. So, the Mechanical Advantage of the pulley system used to lift the box is 4.5.
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Jodi made a list about electric current to help her study for a test. 1) Movement of electrons is continuous in a current. 2) Electrons move from areas of low to high electric potential. 3) Voltage causes current to flow. 4) Rate at which current flows is measured in amperes. Which best describes Jodi’s error?
The best description of Jodi's error is "The electrons move from areas of low to high electric potential." because the electrons actually move from areas of high to low electric potential. thus option 2 is the answer.
Jodi's error is in statement 2, which says that electrons move from areas of low to high electric potential. In reality, electrons move from areas of high to low electric potential. This is because electric potential represents the energy per unit charge, and electrons are negatively charged particles that naturally move from higher energy levels to lower ones. The direction of electron flow determines the direction of electric current, which is the flow of electric charge. The other statements on Jodi's list are generally correct, including the fact that voltage (or potential difference) is what drives current flow, and that current is measured in amperes.
However, it's important to note that the movement of electrons in a current is not always continuous, as they can be impeded by resistance, which causes them to lose energy and generate heat.
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The correct question Is:
Jodi made a list about electric current to help her study for a test.
1) Movement of electrons is continuous in a current.
2) Electrons move from areas of low to high electric potential.
3) Voltage causes current to flow.
4) Rate at which current flows are measured in amperes.
Which best describes Jodi’s error?
The movement of electrons is not always continuous.
Electrons move from areas of high to low electric potential.
Resistance causes current to flow.
The rate at which current flows is measured in ohms.
Stopping Distance Activity
Background: This activity involves observing the effect of original car speed upon the
skid distance. The simulation involves a toy car rolling down a hill, hitting a box, and
skidding to a stop. The height from which the car is released can be modified. The
speed of the car at the bottom of the hill (prior to contact with the box) is reported. The
distance that the car (and box) skid before stopping can be measured. Before answering
the questions, it would be useful to first run the simulation for each of the provided
heights and to record the corresponding pre-collision car speed and the stopping
distance. The background grid on the simulation screen can be used to determine the
stopping distance. Each square on the grid is 10 cm in length along its edge.
Data:
Initial Height Pre-Collision Speed Skid Distance
(m/s)
(cm)
(cm)
10. 0
20. 0
30. 0
40. 0
50. 0
60. 0
70. 0
80. 0
By using the formula:- [tex]mgh= \frac{1}{2} mv^{2} , v = \sqrt{2gh}[/tex], as the release height of the car increase the speed of the car increases.
As the release height of the car increases, the skid distance of the car increaseincrease due to increased velocity.
The directional speed of an object in motion, as measured by a specific unit of time and witnessed from a specific point of reference, is what is referred to as velocity.
Velocity can be defined as the rate at which something travels in a specific direction. Like the speed of a vehicle travelling north on a highway or the speed of a rocket after launch, for instance.
Less momentum with increased height. Less height, more speed. The rate at which it is exchanging height for velocity at any given moment in the fall is therefore equal to the velocity divided by the gravitational constant. As a result, at the top when its velocity is low, it loses only a tiny amount of height with each increase in velocity.
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complete question:-
Help as fast as you can please
Therefore, the components of vector M are approximately Mx = 3.98 and My = 3.02.
How to calculate vector of components ?
The vector M has a magnitude of 5.0 and a direction of 37.0° with respect to the x-axis, as seen in the attached figure.
The cosine of the angle between vector M and the x-axis can be used to determine the x-component of vector M:
Mx = 5.0 cos(37.0°) 3.98, where Mx = M cos(37.0°)
The sine of the angle between vector M and the x-axis can be used to calculate the y-component of vector M:
M sin(37.0°) = 5.0 sin(37.0°) 3.02; My = M sin(37.0°)
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The 0. 20 kg puck on the frictionless, horizontal table in the figure is connected by a string through a hole in the table to a hanging 1. 20 kg block. With what speed must the puck rotate in a circle of radius r = 0. 40 m if the block is to remain hanging at rest?
The puck must rotate with a speed of 3.44 m/s to keep the hanging block at rest.
To keep the hanging block at rest, the tension in the string must be equal to the weight of the block. We can start by finding the tension in the string using the weight of the hanging block:
T = mg = (1.20 kg)(9.81 m/s^2) = 11.77 N
The tension in the string provides the centripetal force that keeps the puck moving in a circle. The centripetal force is given by:
F = ma = m(v^2/r)
where m is the mass of the puck, v is its speed, r is the radius of the circle, and a is the centripetal acceleration.
Solving for v, we get:
v = sqrt(ra) = sqrt(r(T/m)) = sqrt((0.40 m) × (11.77 N)/(0.20 kg)) = 3.44 m/s
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What is the dewpoint when the air temperature is 28°C and the relative humidity is 47%?
The dewpoint when the air temperature is 28°C and the relative humidity is 47% is 15.9°C.
What is temperature?Temperature is a physical property of matter that quantitatively expresses hot and cold. It is measured with a thermometer, which may work through the bulk behavior of a thermometric material, detection of thermal radiation, or particle kinetic energy. Temperature is one of the principal parameters of thermodynamics. Temperature is also important in all fields of natural science, including physics, geology, chemistry, atmospheric sciences, medicine and biology.
The dewpoint is the temperature at which the air has reached its saturation point. At this point, water vapor will begin to condense into liquid droplets, forming dew.
To calculate the dewpoint when the air temperature is 28°C and the relative humidity is 47%, we use the formula:
Dewpoint (°C) = (Air Temperature (°C) * Relative Humidity) / 100 + (112 - Relative Humidity) / (x + 0.444)
Where x = (17.27 * Air Temperature (°C)) / ( Air Temperature (°C) + 237.3 ).
In this example, x = (17.27 * 28) / (28 + 237.3) = 0.39.
Plugging the values into the formula gives us:
Dewpoint (°C) = (28 * 47) / 100 + (112 - 47) / (0.39 + 0.444) = 15.9°C.
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A horizontal pipe of diameter 0.945 m has a smooth constriction to a section of diameter 0.567 m. the density of oil flowing in the pipe is 821 kg/m° if the pressure in the pipe is 8940 n/m° and in the constricted section is 6705 n/m?, what is the rate at which oil is flowing?
If the pressure in the pipe is 8940 n/m° and in the constricted section is 6705 n/m, the rate at which oil is flowing through the pipe is 2.74 m^3/s.
The volume flow rate (Q) can be expressed as:
Q = Av
We can use the continuity equation to relate the velocities at the two different cross-sectional areas:
A1v1 = A2v2
Where:A1 and A2 are the cross-sectional areas at the two different points in the pipe
v1 and v2 are the fluid velocities at the two different points in the pipe
We can rearrange this equation to solve for v1 in terms of v2:
v1 = (A2/A1) * v2
Now we can use Bernoulli's equation to relate the pressure and velocity at the two different points in the pipe:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
We can rearrange this equation to solve for v2:
v2 = sqrt(2(P1 - P2) / ρ + v1^2)
Now we can plug in the given values to find v2:
v1 = ?
A1 = (π/4)(0.945 m)^2 = 0.664 m^2
A2 = (π/4)(0.567 m)^2 = 0.100 m^2
ρ = 821 kg/m^3
P1 = 8940 N/m^2
P2 = 6705 N/m^2
v2 = sqrt(2(8940 - 6705) / 821 + ((0.100/0.664) * v1)^2)
We can simplify this equation by assuming that the velocity at the wider section of the pipe (v1) is much smaller than the velocity at the constriction (v2), due to the principle of continuity. Therefore, we can neglect the second term in the equation, giving:
v2 = sqrt(2(8940 - 6705) / 821) = 11.98 m/s
Now we can use the continuity equation to find the volume flow rate:
Q = A1v1 = A2v2 = (π/4)(0.945 m)^2 * 11.98 m/s =2.74 m^3/s
Therefore, the rate at which oil is flowing through the pipe is 2.74 m^3/s.
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At which location is contact metamorphism least likely to occur?
Contact metamorphism is least likely to occur in low-temperature areas with sedimentary rocks, such as the Earth's oceanic crust.
Contact metamorphism occurs due to heating, with or without burial, of rocks that lie close to a magma intrusion. It is characterized by low P/T gradients, as strong thermal gradients between an intruding magma and adjacent country rock are best established at shallow crustal level. It is a type of metamorphism where rock minerals and texture are changed, mainly by heat, due to contact with magma. Regional metamorphism is a type of metamorphism where rock minerals and texture are changed by heat and pressure over a wide area or region.
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how is scientifical learn done and disuss
Answer:
The six steps of the scientific method include: 1) asking a question about something you observe, 2) doing background research to learn what is already known about the topic, 3) constructing a hypothesis, 4) experimenting to test the hypothesis, 5) analyzing the data from the experiment and drawing conclusions, and 6) communicating the results to others.
A pipe, 30 cm long, is open at both ends. Which harmonic mode of the pipe resonates with a 1. 1 kHz source? Speed of sound in air = 330 m/s
The harmonic mode of the pipe that resonates with a 1. 1 kHz source is second harmonic.
The length of the pipe is given as 30 cm = 30/100 m = 0.3 m
Speed of light is known to be 330 m/s
Frequency of the source is given as 1.1 kHz = 1100 Hz
We know the relation between frequency, harmonic mode and length as,
vn = n v / 2 l
where,
n is number of harmonic mode
v is speed of light
l is length
vn is frequency of nth harmonic in an open pipe
Putting in the values, by making n as subject we have,
n = vn × 2 l/v = 1100 × 2 × 0.3/330 = 2
Thus, the harmonic mode of the pipe is calculated to be 2nd harmonic mode.
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Two cars are moving in the same direction. If the velocity of the first car is 55m/s & that of the second car is 40 m/s, calculate the relative velocity of the first car second car. If they were moving in the opposite direction, what would be the relative with respect to the velocity? Calculate.
(a) The relative velocity of the second car with respect to the first car is -15 m/s.
(b) The relative velocity of the second car with respect to the first car is 95 m/s when they are moving in opposite directions.
What is the relative velocity of the cars?When two objects are moving in the same direction, the relative velocity of the second object with respect to the first object is the difference between their velocities:
Relative velocity = Velocity of the second car - Velocity of the first car
Relative velocity = 40 m/s - 55 m/s
Relative velocity = -15 m/s
When the two cars are moving in opposite directions, the relative velocity of the second car with respect to the first car is the sum of their velocities:
Relative velocity = Velocity of the first car + Velocity of the second car
Relative velocity = 55 m/s + 40 m/s
Relative velocity = 95 m/s
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please help me
sub -physics, topic-laws of motion
The maximum angular speed of the turntable to avoid slipping is option (2), √(µg/x).
How to determine angular speed?The maximum angular speed of the turntable can be found by equating the centrifugal force with the frictional force acting on the block.
At maximum angular speed, the centrifugal force acting on the block is given by F = mRω², where R = x is the distance of the block from the center and ω is the angular speed of the turntable.
The frictional force acting on the block is f = µN, where N is the normal force on the block.
At maximum angular speed, the normal force N is equal to the weight of the block, N = mg.
Equating the centrifugal force and the frictional force:
mRω² = µN
mRω² = µmg
ω² = µg/R
ω = √(µg/R)
Substituting R = x:
ω = √(µg/x)
Therefore, the maximum angular speed of the turntable so that the block does not slip is given by √(µg/x).
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a particle with charge 18 nc travels from an equipotential line with 46 volts to another equipotential with 10 volts as part of miss frizzle's science experiment of the day for her students. what is the change in potential energy of the system during this time interval? answer in nj (nano-joules) to the nearest nj.
The change in potential energy of the system during this time interval is -648 nJ.
The change in potential energy of a particle with charge q that moves from a point with potential V1 to a point with potential V2 is given by:
ΔPE = q x (V2 - V1)
where q is the charge of the particle, and
V2 and V1 are the potentials at the final and initial positions.
Therefore, the charge of the particle is 18 nC, and it moves from a point with potential V1 = 46 V to a point with potential V2 = 10 V.
Therefore, the change in potential energy is:
ΔPE = q x (V2 - V1) = 18 nC x (10 V - 46 V) = -648 nJ
The negative sign indicates that the potential energy of the particle has decreased, which means that the particle has lost potential energy as it moved from the point with higher potential to the point with lower potential.
Therefore, the change in potential energy of the system during this time interval is -648 nJ
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A cheetah stalking her prey is moving at 1 m/s. She accelerates to a speed of
25 m/s to catch the zebra. Her acceleration is 10 m/s². Calculate the time
caken to reach her top speed.
The time taken to reach zebra's top speedis 2.4 second by the cheetah.
How to calculate time?using the suvat formulav=u+at 25=1+10t because of this, t=2.4 secondsWhat is the formula for Suvat?V = U + A T. It belongs to the family of equations known as the SUVAT. Their namesake motion in a straight line with constant acceleration involves the following variables: displacement (S), starting velocity (U), final velocity (V), acceleration (A), and time (T).The majority of the suvat equations are rather simple to construct once you realize that acceleration (, assumed constant) is the derivative of velocity () with respect to time and velocity is the derivative of position (), likewise with respect to time.Physics frequently mentions Issac Newton. For more information on suvat equation kindly visit to
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Exercise 2: Julie, the clown, carries two balloons that rub against a circus
elephant, causing the balloons to separate. Each balloon acquires 2. 0 x107 C of
in charge. How large is the electric force between them when they are separated by
a distance of 0. 50 m?
When the spheres are separated by 0.5 m, the electric force between them is 1.44 x [tex]10^{20}[/tex] N.
To determine the electric force between two balloons, we can use Coulomb's law:
F = k * (q₁ * q₂) / r²
where F is the electric force, k is Coulomb's constant (9 × [tex]10^{9}[/tex] N·m²/C²), q1 and q2 are the charges on the balloons (2.0 x [tex]10^{7}[/tex] C), and r is the distance between the balloons (0.5 m).
Plugging in these values, we get:
F = 9 × [tex]10^{9}[/tex] * (2.0 x [tex]10^{7}[/tex])² / (0.5)²
F = 1.44 x [tex]10^{20}[/tex] N
Therefore, the electric force between the balloons is 1.44 x [tex]10^{20}[/tex] N when they are separated by a distance of 0.5 m.
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Describe a complex (non-electrical) machine that you enjoy using? What makes it a complex machine, rather than a simple machine?
A simple machine is that a complex machine is made up of multiple simple machines that work together to perform a complex task.
One example of a complex machine is a car. A car is a complex machine because it consists of many simple machines that work together to perform a complex task. The simple machines in a car include the wheel and axle, pulleys, gears, levers, and inclined planes.
The engine in a car is a complex machine that converts the chemical energy of gasoline into the kinetic energy needed to move the car. The engine is made up of many simple machines, including pistons, cylinders, valves, and crankshafts. The transmission is another complex machine in a car that uses gears and levers to transfer power from the engine to the wheels.
Other components of a car, such as the steering system, brakes, and suspension, are also complex machines that use multiple simple machines to perform their functions.
What distinguishes a complex machine from a simple machine is that a complex machine is made up of multiple simple machines that work together to perform a complex task. In contrast, a simple machine performs a single task using only one or two basic mechanisms, such as the lever or the inclined plane.
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need help asap pleasee
Answer:
I think it's moving towards the reference point
mike has a linear production possibilities frontier that shows maximum production of trucks or computers of 10 million each. debra also has a linear production possibilities curve that shows maximum production of 9 million trucks or 3 million computers.
Mike and Debra both have linear production possibilities frontiers (PPF), which show the maximum amount of two goods that can be produced given their resources and technology. However, their PPFs are different because they have different maximum production levels for trucks and computers.
Mike's PPF shows that he can produce a maximum of 10 million trucks or 10 million computers. This means that if he allocates all of his resources to producing trucks, he can produce 10 million of them, and if he allocates all of his resources to producing computers, he can produce 10 million of them. Debra's PPF, on the other hand, shows that she can produce a maximum of 9 million trucks or 3 million computers. This means that if she allocates all of her resources to producing trucks, she can produce 9 million of them, and if she allocates all of her resources to producing computers, she can produce 3 million of them.
Overall, Mike and Debra's PPFs show the trade-offs they face when deciding how to allocate their resources between producing trucks and computers. They must decide how much of each good to produce in order to maximize their production and meet their needs.
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