A car's horn produces a constant frequency of 350 Hz as it passes by Suzy. What is the best estimate of the
frequency Suzy hears after the car passes her?
330 Hz
350 Hz
360 Hz
700 Hz

Answer:

C. Do bubbles form when the element is mixed with an acid?

Explanation:

all the other options are incorrect because they are

"Does a magnet attract the element?" is the question that can be used to identify a physical property of an element, because the magnetic behavior of any material is purely a physical property of that material.

Therefore, the correct answer is option A.

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

Since the magnetic behavior of any substance is solely a physical feature of that material, the question "Does a magnet attract the element?" can be used to determine a physical attribute of an element.

Thus, the correct answer is option A.

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[tex]\sf{m_1}[/tex] = 8kg

[tex]\sf{m_2}[/tex] = 4kg

g = 10m/s²

→Acceleration of block

→Tension in strings

Let, the two equation will be ,

[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)

[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)

Putting the value of equation no (1) and (2) we get,

[tex]\implies[/tex] 4g = 12a

[tex]\implies[/tex] 4 × 10 = 12a

[tex]\implies[/tex] 40 = 12a

[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]

[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]

Again, we have to putting the value of a in the equation no (2) we get,

[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]

[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40

[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]

[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N

[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².

And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N

mass = 30kg

frictional force = coefficient of friction * (mass * g)

g = 9.8 m/s^2

So:

60N = x * 294 N

x = 60 N / 294 N = 0,2

Answer: 2 m/s

Explanation:

Divide 10 meters by 5 seconds

Answer:

800 mL

Explanation:

D*V=M

You pick out the numbers as well as what it is they represent from the word problem/explanation, then from there plug them in to the equations. Once you do that, you get your product and have the answer.

10*80= 800

Answer: To determine the speed of an object, you need to know the distance traveled and the Time = 4.0 seconds The speed of the cheetah in miles per hour is 63 mph 5. How far can a person run in 15 minutes if he or she runs at an average .

Explanation: I hope that was helpful !

Answer:

C more than 1 second

Explanation:

it will take time since its 4.9 meters and how hard you throw it down

Answer & Explanation:

Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.

Answer:

0

Explanation:

F1 = G•2.2•4.66/3² (pointed right)

F2 = G•2.2•4.66/3² (pointed left)

subtract the two to get zero

The gravitational force on the 2.20 Kg mass is 7.53 × 10⁻¹¹ N to the right and and the same to the left. The same forces are in opposite direction and thus balances each other.

The gravitational force is the force by which an object attracts other object into its center of mass. The gravitational force depends on the masses of the objects and distance between them by the equation written below:

g = G m1 m2/r²

where G is the universal gravitational constant equal to 6.67 × 10⁻¹¹ N

Given the mass at the  origin = 2.20 kg

mass in right side = 4.66 Kg.

distance = 3 m.

then g = 6.67 × 10⁻¹¹ N × (2.20 × 4.66 kg)/3² =  7.53 × 10⁻¹¹ N

However, the equal force acts from the equal distance by the same mass from the left side also. Therefore, both forces cancel each other in magnitude and the net gravitational force will be zero.

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Answer:

I once yelled out in zoom "I WANNA KISS A ANIME BOY" Cause of a silly dare

Explanation:

Everyone laughed and I was kicked

Answer:

my brother was pushing the cart at target and the front like got my ankles and I fell in front of everyone and he was just laughing.

[tex]w = F * S[/tex]

[tex]F = 20\\S = 10\\F * S = 20 * 10 = 200[/tex] Joules <- 1st answer

[tex]w = F * S[/tex]

[tex]1234 = F * 100[/tex]

[tex]F = \frac{1234}{100}[/tex]

[tex]F = 12.34 N[/tex]  <- 2nd answer

Answer:

57,6N

Explanation:

To find the component  of a force on the x-axis we can simply do:

F * cos(36) = 72N * 0.8 = 57,6N

Answer:

392.4

Explanation:

40*9.81=392.4

Answer:

Explanation:

The acceleration it's the difference of speed (final speed - initial speed)  divided by the time. So:

a = Δv/t

In this case the initial speed is equal to 0. The final speed is equal to 80 miles/hour. The time is 10s.

a = 80 miles/hour divided by 10 = 8 miles/hour

Answer:

8

Explanation:

Because as you can see 80/10= 8

Answer is 8

Answer:

It would break because how fast and how tall the fall is because at a certain hight water can act like a solid and break your body/bones or you could die

its a do or die situation

Explanation:

Answer:

1. The stone will strike the ground 49.46 m from the base of the cliff

2. A) Approximately 0.542 seconds

B)  Approximately 3.69 m/s

3. A) The time the ball spends in the air is approximately 4.0775 s

B) The horizontal range is approximately  141.25 m.

Explanation:

1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)

∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds

The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m

The stone will strike the ground 49.46 m from the base of the cliff

2. A) The time the ball spends in the air = t = √(h/(1/2 × g)

∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds

B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s

The initial horizontal velocity ≈ 3.69 m/s

3. A) The time the ball spends in the air is given by the following equation;

t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s

t ≈ 4.0775 s

B) The horizontal range, R, of the  ball is given by the equation for the range of a projectile as follows;

[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]

Substituting the known values, gives;

[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]

The horizontal range ≈ 141.25 m.

Answer:

biosphere

Explanation:

pretty sure bc it is ground

Answer:

Q=it

I=2.5A

T=600 seconds

Q=2.5*600

= 1,500 C

Answer:

Explanation:

Explanation is attached.

Answer: yes it is

Explanation: A biotic factor is something that is living. this also apply to plants animals and people. A dinosaur was once a living being so it would be classified as a biotic factors. An abiotic factor is something that is not living .so that would be tables chairs and clothes.

Answer:

The faster car has more kinetic energy because kinetic energy increases with speed.

Explanation:

-

-- The distance the force moved through

-- How long the force lasted

The other thing we need to calculate the power is the "Velocity".

The relation can be shown as:

→ [tex]P= Fv[/tex]

where,

Thus the above is the right response.

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Answer:

i. Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

  Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii. cyclist B overtake cyclist A 6 km from the same starting point X.

Explanation:

From the question,

- Cyclist A and B cycled at an average speed of 15 km/h and 20 km/h respectively.

- Cyclist B started his journey 6 mins after cyclist A had started.

Let the cyclist A time be t.

Then, we can write that

For Cyclist A

Speed = 15 km/h

Time = t mins

For Cyclist B

Speed = 20 km/h

Time = (t - 6) mins

i) To determine the distances travelled by cyclist A and B 1h cyclist A had started his journey,

For Cyclist A

Speed = 15km/h

Time = 1h = 60 mins

From the formula

Speed = Distance / Time

Then,

Distance = Speed × Time

Putting the values into the equation,

Distance = 15km/h × 1h

Distance = 15 km

∴ Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

For cyclist B

Speed = 20km/h

Time = 1h - 6mins = 60mins - 6mins = 54mins = 54/60 hour = 0.9 h

Also, from

Distance = Speed × Time

Putting the values into the equation

Distance = 20km/h × 0.9h

Distance = 18 km

∴ Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii) To determine the distance cyclist B overtake cyclist A, that is, when the distance covered by cyclist A equals that covered by cyclist B.

First, we will determine the time at which the distances covered by both cyclists were equal.

From

For Cyclist A

Speed = 15 km/h

Time = t hour  

Distance = Speed × Time

Distance = 15t km

For Cyclist B

Speed = 20 km/h

Time = (60t - 6) mins = (t - 0.1) hour

Distance = 20 × (t - 0.1) = (20t - 2) km

Equate the distances

15t = 20t - 2

15t - 20t = -2

-5t = -2

5t = 2

t = 2/5

t = 0.4 hour

Hence, cyclist B overtake cyclist A 0.4 hour after cyclist A had started.

For the distance cyclist B overtake cyclist A,

From

Distance = (20t - 2) km

Distance = (20×0.4 - 2) km

Distance = (8 - 2) km

Distance = 6 km

Hence, cyclist B overtake cyclist A 6km from the same starting point X.

Answer:

The neutral wire is often confused with ground wire, but in reality, they serve two distinct purposes. Neutral wires carry currents back to power source to better control and regulate voltage. Its overall purpose is to serve as a path to return energy.

Explanation:

Given:

v₀ = 0 m/s

a = 3 m/s²

t = 4 s

Find: Δx and v

Δx = v₀ t + ½ at²

Δx = (0 m/s) (4 s) + ½ (3 m/s²) (4 s)²

Δx = 24 m

v = at + v₀

v = (3 m/s²) (4 s) + 0 m/s

v = 12 m/s

Answer:

The anwser is b

Explanation:

Answer:

the answer is B

I know  because i just did it