A car travels for 0.5 hours and goes 25 miles. What is the car's speed? (Remember sad + t)

Answers

Answer 1

Answer:

s = 22.352 m/s

Explanation:

Given data:

Time taken = 0.5 hours

Distance cover = 25 miles

Car speed = ?

Solution:

First of all we will convert the units.

1 hour = 3600 sec

0.5 hr ×3600 sec / 1hr = 1800 sec

miles to meter:

25 mi × 1609 m/ 1 mi = 40233.6 m

Formula:

s =  d/t

s = speed

d = distance

t = time

Now we will put the values in formula.

s = 40233.6 m / 1800 sec

s = 22.352 m/s


Related Questions

SOMEONE PLZ HELP!!!!

Answers

Answer:

4.22mL

Explanation:

V=m/d

v= 18.45g/4.37g/mL

which of the following determines an object’s ability to float in water?

a. how much the object weighs
b. what the mass of the object is
c. how dense the object is
d. the volume of the object

Answers

Density of the object! :)
A. because it object is weighs

What is the value of E0 for the spontaneous reaction resulting from a suitable combination of these half reactions?
Standard Potentials E0
Fe2+ --> Fe3+ + e- -0.77 V
2Hg --> Hg2+ + 2e- -0.79 V
a. +0.02 V.
b. +0.36 V.
c. -1.56 V.
d. -0.02 V.
e. +1.56 V.

Answers

Answer:

+0.02 V

Explanation:

For the reaction to be spontaneous, iron must be the cathode and Mercury the anode

Given that the standard cell potential is obtained from;

E°=E° cathode - E° anode

Since;

E° cathode = -0.77V

E° anode = 0.79 V

E°cell = -0.77 -(-0.79)

E°cell = +0.02 V

A 25.00-mL aliquot of a nitric acid solution of unknown concentration is pipetted into a 125-mL Erlenmeyer flask and 2 drops of phenolphthalein are added. The above sodium hydroxide solution (the titrant) is used to titrate the nitric acid solution (the analyte). If 12.75 mL of the titrant is dispensed from a burette in causing a color change of the phenolphthalein, what is the molar concentration of the nitric acid solution? (Show all steps for calculating the answer.)
Answer: 0.0611 M HNO3​

Answers

Answer:

0.0611M of HNO3

Explanation:

The concentration of the NaOH solution must be 0.1198M

The reaction of NaOH with HNO3 is:

NaOH + HNO3 → NaNO3 + H2O

1 mole of NaOH reacts per mole of HNO3.

That means the moles of NaOH used in the titration are equal to moles of HNO3.

Moles HNO3:

12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.

In 25.00mL = 0.025L -The volume of the aliquot-:

0.00153 moles HNO3 / 0.025L =

0.0611M of HNO3

Convert
12 x 1025 kg/mL to fg/cm3

Answers

Answer:

[tex]1.2x10^{38}\frac{fg}{cm^3}[/tex]

Explanation:

Hello there!

In this case, for such unit conversion we need to realize that 1 kg is equal to 1000 g, 1 g is equal to 1x10⁹ and 1 mL equals 1 cm³, therefore we apply:

[tex]12x10^{25}kg*\frac{1000g}{1kg} *\frac{1x10^9fg}{1g} *\frac{1mL}{1cm^3} \\\\1.2x10^{38}\frac{fg}{cm^3}[/tex]

Best regards!

he concentration of H2S in a saturated aqueous solution at room temperature is approximately 0.1 M. Ka1=8.9x10-8 Ka2=1.0x10-19 Calculate the pH of the solution in 2 sig figs

Answers

Answer:

PH = 4.0

Explanation:

We are given;

Ka1 = 8.9 × 10^(-8)

Ka2 = 1.0 × 10^(-19)

From the 2 values of K given above, we can see that Ka2 is far smaller than Ka1.

Thus, Positive hydrogen ion (H+) will be majorly formed from first dissociation which is Ka1.

Now, the breakdown of the H2S solution is;

H2S⇌[H+] + [HS−]

Thus;

Ka1 = [[H+] × [HS2^(-)]]/(H2S)

HS2^(-) also has a positive hydrogen ion.

Thus, we can rewrite as;

Ka1 = [[H+] × [H+]]/(H2S)

Ka1 = (H+)²/(H2S)

Concentration of H2S is given as 0.1M. Thus;

8.9 × 10^(-8) = (H+)²/0.1

(H+)² = 0.1 × 8.9 × 10^(-8)

(H+) = √(0.1 × 8.9 × 10^(-8))

(H+) = 0.00009433981

Now, PH is gotten from;

PH = -log (H+)

Thus;

PH = -log 0.00009433981

PH ≈ 4.0

When methylcyclobutane is treated with chlorine gas and heated, the total number of monochlorinated products, including stereoisomers, is

Answers

Answer:

5

Explanation:

The image attached shows the different monochlorination products obtained when chlorine gas is heated with methylcyclobutane.

We must keep in mind that the reaction occurs by free radical mechanism as shown in the image attached. The proportion in which the products are formed depends on the stability of the free radical intermediate leading to that particular product.

Image credit: askiitians

What concentration of NO−3NO3− results when 897 mL897 mL of 0.497 M NaNO30.497 M NaNO3 is mixed with 813 mL813 mL of 0.341 M Ca(NO3)2?

Answers

Answer:

Explanation:

NaNO₃  = Na⁺  + NO₃⁻¹

.497 M                 .497 M

moles of NO₃⁻¹ = .897 x .497 = .4458 moles

Ca( NO₃)₂  = Ca + 2 NO₃⁻¹

.341 M                    2 x .341 M = .682 M

moles of NO₃⁻¹ = .813 x .682 = .5544 moles

Total moles =  .4458 moles  +  .5544 moles

= 1.0002 moles

volume of solution = 897 + 813 = 1710 mL

= 1.710 L

concentration of nitrate ion = 1.0002 / 1.710 M

= .585 M

Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color.

Determine the genotypes of offspring 1-8.
1
2
3
4
5
6
7
8
A 4-column table has 4 rows. The labels of the columns are Upper B Upper E, Upper B e, b Upper E, b e. The labels of the rows are Upper B Upper E, Upper B e, b Upper E, Upper B b Upper E e. The first column has entries 1, Upper B Upper B Upper E e, 4, Upper B b Upper E e. The second column has entries Upper B Upper B Upper E e, 3, Upper B b Upper E e, 7. The third column has entries Upper B b Upper E Upper E, Upper B b Upper E e, 5, b b Upper E e. The fourth column has entries 2,Upper B b e e, 6, 8.

Answers

Answer:

the answer is simple

Explanation:

jnnn B upper up of the eye color

Answer:

1. BBEE

2. BbEe

3. BBee

4. BbEE

5. bbEE

6. bbEe

7. Bbee

8.bbee

Calculate the pH of a 0.02 M solution of ascorbic acid ( K a1 = 7.9 × 10 –5; K a2 is 1.6 × 10 –12).
a.
2.9
b.
8.2
c.
11.8
d.
11.1
e.
5.8

Answers

Answer:

C

Explanation:

3. Does matter increase in
mass when mixed with
another substance?
a Yes
b. No

Answers

Answer:

b. No

Explanation:

The question above is related to "The Law of Conservation of Mass." This law states that mass is neither created nor can it be destroyed. Even if a particular matter will be mixed with another substance or it undergoes chemical reaction, the mass of the matter will remain the same. Even with a change in phase, the mass of the matter will remain the same.

3. Which of the following molecules would want except to have a nonpolar covalent bond

Answers

Answer:

polar bonds are caused by different kind of atoms, because almost every atoms have different powers to attract electrons.

the answer will be the two same atoms, F2

1.191 mol N2O3 is put into a 2.00 L flask at 25°C where it decomposes into NO2(g) and NO(g). What is the equilibrium constant (to 4 decimal places) if the reaction mixture contains 0.300 mol NO2 at equilibrium?

Answers

Answer:

K = 0.0505

Explanation:

Based on the equilibrium:

N2O3 ⇄ NO2 + NO

K, equilibrium constant, is defined as:

K = [NO2] [NO] / [N2O3]

Where [] are the equilibrium concentration of each species in the mixture.

The initial molarity of N2O3 is:

1.191mol / 2.00L = 0.5955M

In equilibrium, 0.5955M of N2O3 reacts producing X Molar of NO2 and X Molar of NO:

[N2O3] = 0.5955M - X

[NO2] = X

[NO] = X

As equilibrium concentration of NO2 is 0.300mol/2.00L = 0.15M; X = 0.15M:

[N2O3] = 0.5955M - 0.15M = 0.4455M

[NO2] = 0.15M

[NO] = 0.15M

And K is:

K = [0.15M] [0.15M] / [0.4455M]

K = 0.0505

What is the momentum of a 1kg ball moving at 5m/s?

Answers

Answer:

5Ns

momentum= mass *velocity

=1*5

=5Ns

Please help! I'm confused on a few of these, 100 points!

Answers

I cannot see the picture
reupload ^^ there’s no picture

ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the ee of this solution

Answers

Complete Question

You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?

Answer:

The value is  [tex]k  = 96 %[/tex]

Explanation:

From the question we are told that

   The  percentage of  enantiomer A is  A =  98%

    The  percentage of  enantiomer B is  B =  2%

Generally the enantiomeric excess is mathematically represented as

      [tex]k  =  \frac{A -B}{A+B}  *  100[/tex]

=>   [tex]k  =  \frac{98 -2}{98+2}  *  100[/tex]

=>   [tex]k  = 96 %[/tex]

Two elements in the same period have the same number of _____ _____ in their electron clouds.

Answers

Answer:

outer electrons

Explanation:

Answer:

Energy levels

Explanation:

2. Determine the possible traits of the calves of : Da red (RR) bull is mated with a red (RR) cow 1 a red * (RR) bullis mated with a white (WW) Cow 2 Da roan * (RW) is mated with a red(RR)Cow 3 3. Illustrate your answers using a Punnett square. 4. Write your answers on the paper.​

Answers

1st square - all 4 red babies
2nd square - all 4 roan babies
3rd square - 2 red, 2 roan babies

Which condition produces an anion?
A. more neutrons than electrons
B. more protons than electrons
C. more electrons than neutrons
D. more electrons than protons

Answers

B. An anion is an ion where an element loses an atom. Num Protons = Num Electrons and it loses an ion so more protons than electrons.

Consider the diagram below.
What does C represent?
A) enthalpy of reaction
B) activation energy
C) activated complex
D) energy of the reactants

Answers

Answer:

A) enthalpy of reaction

Explanation:

The region C signifies the enthalpy of reaction.

This diagram is the energy profile of an endothermic reaction. In such reaction, heat is absorbed from the surrounding. At the end of the reaction, the heat of product is lesser than that of the reactants.

Enthalpy changes are heat changes accompanying a physical and chemical change. An enthalpy is the difference between the sum of the heat contents of products and sum of the heat contents of reactants.

it is indeed A) enthalpy of reaction

A certain first-order reaction has a rate constant of 2.10×10−2 s−1 at 19 ∘C. What is the value of k at 58 ∘C if Ea = 82.0 kJ/mol ?

Answers

Answer:

K₂ = 1.12s⁻¹

Explanation:

Based on Arrhenius equation:

ln K₂/K₁ = -Ea/R (1/T₂ - 1/T₁)

Where K is rate constant,

R is gas constant (8.314J/molK),

T is absolute temperature (In K) Of 1, initial state and 2, final state.

ln K₂/K₁ = -Ea/R (1/T₂ - 1/T₁)

ln K₂/2.10x10⁻²s⁻¹ = -82000J/mol/8.314J/molK (1/(273.15 + 58) - 1/(273.15 + 19))

ln K₂ / 2.10x10⁻²s⁻¹ = 3.976

K₂ / 2.10x10⁻²s⁻¹ = 53.3

K₂ = 1.12s⁻¹

PLS PLS PLS PLS PLS PLS PLS help ASAP!!!!! Scientists call all of the compounds that contain carbon and are found in living things Organic because ________.

WILL DO BRAINLIEST!

Answers

carbon mark brainliest please

Someone plz hello me ASAP it would be appreciated on question 7 btw

Answers

Answer:

Kinetic Energy is the correct Answer.

Explanation:

At the highest point on the roller coaster (assuming it has no velocity), the object has a maximum quantity of gravitational potential energy. As the object begins moving down to the bottom, its gravitational potential energy begins to decrease and the Kinetic Energy starts to increase.

if you wanted to measure in irregular object's volume, which device would you use?

Answers

Answer:

a beaker

Explanation:

The density of wind-packed snow is estimated to be 0.35 g/cm^3. A flat roof that is 35 by 43 feet has 28 inches of snow on it. How many pounds of snow are on the roof?

Answers

Answer:

There are 76728.2 pounds of snow on the roof

Explanation:

To determine how many pounds of snow are on the roof,

First we will determine the mass of the snow in grams.

From the question,

Density of snow = 0.35 g/cm³

From

Density = Mass / Volume

To determine the mass, we will first find the volume.

From the question, a flat roof that is 35 by 43 feet has 28 inches of snow on it, that is, the height of the snow on the roof is 28 inches.

Area of the roof = 35 ft × 43 ft = 1505 ft²

Volume of the snow = Area of the roof × Height of the snow

Height of the snow = 28 inches

12 inches = 1 foot

∴ 28 inches = 28/12 feet = 2.3333 ft

Hence,

Volume of the snow = 1505 ft² × 2.3333 ft = 3511.62 ft³

Volume of the snow = 3511.62 ft³

This is the volume of the snow in cubic feet

Now, we will convert cubic feet (ft³) to cubic centimeter (cm³)

1 ft = 30.48 cm

and 1 ft³ = 30.48³ cm³ = 28316.84659 cm³.

If 1 ft³ =  28316.84659 cm³

∴ 3511.62 ft³ will be 3511.62 × 28316.84659 cm³ = 99438004.83 cm³

Hence, Volume of snow = 99438004.83 cm³

Now, we can determine mass of snow in grams

From

Density = Mass / Volume

Mass = Density × Volume

Mass = 0.35 g/cm³ × 99438004.83 cm³

Mass = 34803301.69 g

Now, we will convert the mass from grams to pounds

1 pound = 453.592 grams

If 453.592 grams = 1 pound

Then, 34803301.69 g will be 34803301.69 / 453.592 pounds = 76728.2 pounds

Hence, there are 76728.2 pounds of snow on the roof.

Which of the following is NOT an example of deposition?
sand dune
river delta
cave crystal
valley
This science btw

Answers

Answer:

Cave Crystal

Explanation:

I believe it's cave crystal because sand dunes, river deltas, and valleys are all examples of deposition.

Which is one way that minerals crystallize from materials dissolved in water?

from the air
from solutions that evaporate
from hot water solutions when water boils
from the soil

Answers

Answer:

the second answer its science behind it

Answer:

b

Explanation:

explain the reason each step of the separation is performed with three portions of the solvent rather than with a single poriton of solvent

Answers

Answer:

Several extractions is more effective than a single extraction.

Explanation:

When extraction is carried out multiple times, for instance, in this case, the extraction was carried out with three portions of the solvent rather than with just a single portion of the solvent, the amount of material left in the residue will be lower, because the extraction is more complete.

Several extractions with smaller volumes of solvent are more effective than a single extraction with a large volume of solvent.

what is the relationship between the atomic number and the melting and boiling point

Answers

Answer:

As the atomic number of elements increases, the melting point increases because there are more electrons around the nucleus, which creates a stronger negatively-charged force. With stronger forces, the melting point rises. 3. Non-metals usually have low melting points.

Explanation:

The melting point rises as the atomic number of elements increases because there are more electrons surrounding the nucleus, creating a stronger negatively charged force. The melting point rises as the forces become stronger.

What is nucleus?The nucleus is made up of protons, which are positively charged, and neutrons, which are electrically neutral. Quarks are particles that make up protons and neutrons. The nucleus (plural, nuclei) is a positively charged region in the atom's center. It is made up of two types of subatomic particles that are tightly packed together. Protons, which have a positive electric charge, and neutrons, which have a neutral electric charge, are the particles. The nucleus is the most important component of the cell (plural: nuclei). It is derived from a Latin word that means "nut kernel." Definition of Nucleus: A nucleus is a double-membraned eukaryotic cell organelle that contains genetic material.

To learn more about nucleus, refer to:

https://brainly.com/question/14110259

#SPJ2

How many moles of each substance is produced when 7 moles of ammonium carbonate decompose?

(NH4)2CO3(s) ⟶ NH3(g) + CO2(g) + H2O(g)

Answers

Answer:

1. 14 moles of NH3 were produced.

2. 7 moles of CO2 were produced.

3. 7 moles of H2O were produced.

Explanation:

We'll begin by writing a balanced equation for the decomposition of ammonium carbonate, (NH4)2CO3.

This is illustrated below:

(NH4)2CO3(s) —> NH3(g) + CO2(g) + H2O(g)

There are 2 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NH3 as shown below:

(NH4)2CO3(s) —> 2NH3(g) + CO2(g) + H2O(g)

Now the equation is balanced.

From the balanced equation above,

1 mole of (NH4)2CO3 decompose to produce 2 moles of NH3, 1 mole of CO2 and 1 mole of H2O.

1. Determination of the number of mole of NH3 produced.

From the balanced equation above,

1 mole of (NH4)2CO3 decompose to produce 2 moles of NH3.

Therefore, 7 moles of (NH4)2CO3 will decompose to produce = 7 × 2 = 14 moles of NH3.

Therefore, 14 moles of NH3 were produced.

2. Determination of the number of mole CO2 produced.

From the balanced equation above,

1 mole of (NH4)2CO3 decompose to produce 1 mole of CO2.

Therefore, 7 moles of (NH4)2CO3 will also decompose to produce 7 moles of CO2.

Therefore, 7 moles of CO2 were produced.

3. Determination of the number of mole of H2O produced.

From the balanced equation above,

1 mole of (NH4)2CO3 decompose to produce 1 mole of H2O.

Therefore, 7 moles of (NH4)2CO3 will also decompose to produce 7 moles of H2O.

Therefore, 7 moles of H2O were produced.

Other Questions
Which of the following best describes the Articles of Confederation?AA document outlining how the British government ignored the colonies' rightsBThe first plan for the government of the original thirteen statesCJohn Locke's writings on the separation of government powerDJames Madison's document outlining the principles of the US government What can cause an infectious disease when they enter your body and multiply?A.) phagocytes B.) antibodies C.) pathogens D.) T cellsPlease explain why. Which of these sequences of transformations would not return a shape to its original position?Group of answer choices1. Translate 3 units up, then 3 units down.2. Reflect over line p, then reflect over line p again.3. Translate 1 unit to the right, then 4 units to the left, then 3 units to the right.4. Rotate 120 counterclockwise around center C, then rotate 220 counterclockwise around C again. How does a calorie on a food label relate to a calorie that is produced in cellular respiration?? Please help Evaluate the function f(x) = 2x+ 8 when x= 6 Andy wants to install a new Internet connection. He wants to take the fastest he can get. What are the maximum speeds for the following Internet access technologies? King George III hoped the Proclamation of 1763 would stop ....Question 7 options:immigrationfuture Native American attacks on the coloniststradingalliances A segment has endpoints A (-1, 1) and B (8, 4) .If the segment is divided into four equal parts, the coordinates of the point closest to point A are _____? Which question must be answered to complete the table below?A 3-column table with 3 rows. Column 1 is labeled alpha decay with entries alpha particles, plus 2 and low. Column 2 is labeled Beta Decay with entries no entry, electron negative 1 positron positive 1, and medium. Column 3 is labeled Gamma decay with entries gamma rays, 0 and high.a. What kind of shielding will block beta decay?b. What is the penetrating power of beta decay?c. What kind of particles are produced by beta decay?d. How massive are the particles in beta decay? what is an expression equivalent to m^238/m^-79 in the form m^v, where v is an integer? How many 2/3 cup servings are in 28/3 cups of yogurt The "umbrella statement" for all parts of an argument in a speech is called theO claim.O reason.O evidence.O rhetoric. What is the y-intercept of a line that has a slope of 3 and passes through point (0, 7)? The Pompeii worm was discovered near _______. a. a hydrothermal vent b. a sea mount c. Hawaii d. the great barrier reef Please select the best answer from the choices provided A B C D What do you think it means to be a responsible citizen ? what percentage is equal to 32/100 In a lab investigation, one group of students (group A) measures the speed of a .1 kg toy car to be 2.5 m/s at the bottom of a ramp. Another group of students (group B) measures the speed of a car to be 3 m/s at the bottom of a ramp. The car's starting position at the top of the ramp is 1 m high. What is the potential energy of the car at the beginning of the experiment before its speed is measured? M= 1/2 M= 2M= -1/2M=-2 In order to create an aerial perspective, a painter can:O A. show a scene from the perspective of God looking down onhumanity.B. make humans and animals larger than other objects.C. reduce the size of objects in the background to make them seemfarther away.O D. use shadows to highlight certain features of the composition. A quarterback dropped back 5 yards behind the lone of scrimmage. Then, he passed the ball 14 yards. How far past the line of scrimmage did the ball travel? (Write an equation to represent this problem)