Answer:
Distance = πr
Displacement = 2r
Explanation:
First we need to find the distance covered by the car. As the car is travelling on a circular path and it traveled to a diametrically opposite point on the circular path. Therefore, the distance covered by the car must be the half value of the circumference.
Distance = Circumference/2
Distance = 2πr/2
Distance = πr
Since, displacement is the straight line distance between two points. So, the displacement in moving from a point to its diametrically opposite point must be equal to the diameter of circle:
Displacement = Diameter
Displacement = 2r
What must be the acceleration of a train in order for it to stop from 12m/s in a distance of 541m?
Please help!!
Answer:
The acceleration of the train must be - 0.133 m/s²
Explanation:
A train in order for it to stop 12 m/s in a distance if 541 m
That means the initial velocity of the train is 12 m/s
Its final velocity is zero (stop)
The distance it covers is 541 m
P.S. This is part of the answer of another brainly user this is not my knowledge.
But Hope I helped you
Answer:
-0.133 m/s²
Explanation:
Given:
Δx = 541 m
v₀ = 12 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (12 m/s)² + 2a (541 m)
a = -0.133 m/s²
A basketball leaves a player's hands at a height of 2.20 m above the floor. The basket is 2.70 m above the floor. The player likes to shoot the ball at a 36.0 ∘ angle. Of the shot is made from a horizontal distance of 9.10 m and must be accurate to ±0.23m (horizontally), what is the range of initial speeds allowed to make the basket
Answer:
The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].
Explanation:
We must notice that basketball depicts a parabolic motion, which consists of combining a constant speed motion in x-direction and free fall motion in the y-direction. The motion is described by the following kinematic formulas:
x-Direction
[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \alpha[/tex]
y-Direction
[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \alpha +\frac{1}{2}\cdot g\cdot t^{2}[/tex]
Where:
[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial position of the basketball, measured in meters.
[tex]x[/tex], [tex]y[/tex] - Final position of the basketball, measured in meters.
[tex]v_{o}[/tex] - Initial speed of the basketball, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]\alpha[/tex] - Tilt angle, measured in sexagesimal degrees.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
If we know that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 2.20\,m[/tex], [tex]\alpha = 36^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], [tex]x = (9.10\pm0.23)\,m[/tex] and [tex]y = 2.70\,m[/tex], the system of equation is reduce to this:
[tex](9.10\pm 0.23)\,m = 0\,m + v_{o}\cdot t \cdot \cos 36^{\circ}[/tex]
[tex]9.10\pm 0.23 = 0.809\cdot v_{o}\cdot t[/tex] (Ec. 1)
[tex]2.70\,m = 2.20\,m + v_{o}\cdot t \cdot \sin 36^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}[/tex]
[tex]0.50 = 0.588\cdot v_{o}\cdot t-4.904\cdot t^{2}[/tex] (Ec. 2)
At first we clear [tex]v_{o}\cdot t[/tex] in (Ec. 1):
[tex]v_{o}\cdot t = \frac{9.10\pm 0.23}{0.809}[/tex]
[tex]v_{o}\cdot t = 11.248\pm 0.284[/tex]
(Ec. 1) in (Ec. 2):
[tex]0.5 = 0.588\cdot (11.248\pm 0.284)-4.904\cdot t^{2}[/tex]
Now we clear the time in the resulting expression:
[tex]4.904\cdot t^{2} = 0.588\cdot (11.248\pm 0.284)-0.5[/tex]
[tex]t = \sqrt{\frac{0.588\cdot (11.248\pm 0.284)-0.5}{4.904} }[/tex]
There are two solutions:
[tex]t_{1} = \sqrt{\frac{0.588\cdot (11.248- 0.284)-0.5}{4.904} }[/tex]
[tex]t_{1} \approx 1.101\,s[/tex]
[tex]t_{2} = \sqrt{\frac{0.588\cdot (11.248+ 0.284)-0.5}{4.904} }[/tex]
[tex]t_{2}\approx 1.131\,s[/tex]
The initial velocity is cleared within (Ec. 2):
[tex]v_{o}=\frac{0.50+4.904\cdot t^{2}}{0.588\cdot t}[/tex]
The bounds of the range of initial speed is determined hereafter:
[tex]t_{1} \approx 1.101\,s[/tex]
[tex]v_{o} = \frac{0.50+4.904\cdot (1.101)^{2}}{0.588\cdot (1.101)}[/tex]
[tex]v_{o} = 9.954\,\frac{m}{s}[/tex]
[tex]t_{2}\approx 1.131\,s[/tex]
[tex]v_{o} = \frac{0.50+4.904\cdot (1.131)^{2}}{0.588\cdot (1.131)}[/tex]
[tex]v_{o} = 10.185\,\frac{m}{s}[/tex]
The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].
Part A
Your GPS shows that your friend’s house is 10.0 km away (Figure 2). But there is a big hill between your houses and you don’t want to bike there directly. You know your friend’s street is 6.0 km north of your street. How far do you have to ride before turning north to get to your friend’s house?
8 km
Part B
Referring to the diagram in Part A, what is the sine of the angle
θ at the location of the friend's house?
Answer:
Part A
You have to ride 8.0 km before turning north to get to your friend’s house.
Part B
The sine of the angle θ at the location of the friend's house is 0.8
Explanation:
The remaining part of the question which is an image is attached below
Explanation:
Part A
To determine how far you will ride ride before turning north,
From the diagram, that is the distance of your street.
Let the distance of your street be [tex]A[/tex]
and the distance of your friend's street be [tex]B[/tex]
and let the displacement between your friends house and your house be [tex]C[/tex]
The relation in the diagram shows a right angle triangle.
The sides of the right angle triangle are represented as [tex]A,B[/tex] and [tex]C[/tex].
To find [tex]A[/tex], which is the distance of your street,
From Pythagorean theorem, 'The square of hypotenuse is the sum of squares of the other two sides'
That is,
[tex]/Hypoyenuse/^{2} = /Adjacent/^{2} + /Opposite/^{2}[/tex]
[tex]C[/tex] is the hypotenuse, which is the displacement between your friends house and your house,
Hence, [tex]C = 10.0 km[/tex]
[tex]B[/tex] is adjacent, which is the distance of your friends street
then, [tex]B = 6.0 km[/tex]
and [tex]A[/tex] is the opposite, which is the distance of your house
From Pythagoras theorem, we can then write that,
[tex]C^{2} = B^{2} + A^{2}[/tex]
Then, [tex]10.0^{2} = 6.0^{2} + A^{2}[/tex]
[tex]A^{2} = 100.0 - 36.0\\A^{2} = 64.0\\A = \sqrt{64.0}[/tex]
[tex]A = 8.0km[/tex]
Hence, you have to ride 8.0 km before turning north to get to your friend’s house.
Part B
To find the sine of the angle θ at the location of the friend's house,
In the diagram, the sine of the angle θ is given by
[tex]Sin\theta = \frac{Opposite}{Hypotenuse}[/tex]
Hence, [tex]Sin\theta = \frac{A}{C}[/tex]
Then,
[tex]Sin\theta = \frac{8.0}{10}[/tex]
[tex]Sin\theta = 0.8[/tex]
Hence, the sine of the angle θ at the location of the friend's house is 0.8
A. The amount of distance you have to ride before turning North to get to your friend’s house is 8 kilometers.
B. The sine of the angle (θ) at the location of your friend's house is 0.8.
Let your friend's house be a.Let your friend's street be b.Let the distance between your house and your friend be c.Given the following data:
Distance c = 10 kmDistance a = 6 kmA. To determine the amount of distance you have to ride before turning North to get to your friend’s house, we would apply Pythagorean's theorem:
Mathematically, Pythagorean's theorem is given by the formula:
[tex]c^2 = a^2 + b^2\\\\10^2 =6^2+b^2\\\\100=36+b^2\\\\b^2 =100-36\\\\b^2 =64\\\\b=\sqrt{64}[/tex]
b = 8 kilometers
B. To find the sine of the angle (θ) at the location of the friend's house:
Mathematically, the sine of an angle is given by the formula:
[tex]Sin\theta = \frac{opposite}{hypotenuse}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Sin\theta = \frac{8}{10} \\\\Sin\theta = 0.8[/tex]
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and aunt travels toward the right along a meter stick. if it starts at the 25.00 cm mark and then travels to the 80.00 cm mark, what is its displacement
Answer:
displacement = 55 cm
Explanation:
Initial position = 25 cm
Final position = 80 cm
Displacement = final position-finitial position
Putting values in above formula,
D = 80 cm - 25 cm
D = 55 cm
It means that the displacement of the ant is 55 cm.
Give an example of a situation in which you would describe an
object's position in
a. one dimension.
b. two dimensions.
three dimensions.
Which are best examples of projectile motion
Answer:
Please add the multiple choice awensers too then I'll get back to you when I can
Answer:
Answer is D
Explanation:
5.
An object with zero acceleration is not changing its velocity.
TRUE
FALSE
lol
idk what this is
Answer:
I know
Explanation:
Physics= hard
Compare the de Broglie wavelength of a golf ball moving at 70.0 miles per hour (31.3 m/s) to that of an alpha particle moving at 3.40E+7 miles per hour (1.52E+7 m/s) and a bullet with a speed of 700 miles per hour (313 m/s). Which region of the electromagnetic spectrum are each of these wavelengths near
Answer:
1. Golf ball is in the range of only particulate detectable range
2, alpha partcle is in ultraviolet range of wavelength
3.bullet is in xray range of wavelength
All in the EMW spectrum
What is the kinetic energy when the pendulum is at the halfway point
(height=1 m) when the total mechanical energy is 4 J
What is the mass of the cube
Density is 40 g/cm3
Length of the side= 2 cm
Answer:
80
Explanation:
because of the denstiy formula
When a piano tuner strikes both the A above middle C on the piano and a 440 Hz tuning fork, he hears 4 beats each second. The frequency of the piano's:____________.
A) 444 Hz
B) 880 Hz
C) 436 Hz
D) either 436 Hz or 444 Hz
Answer:
D) either 436 Hz or 444 Hz
Explanation:
frequency of the tuning fork, F₁ = 440 Hz
frequency of the piano, F₂ = ?
Beat frequency, F = 4 Hz
Beat frequency is given as the difference between the frequency of the two instruments and it is given by;
F = F₂ - F₁ or F = F₁ - F₂
F₂ = F + F₁ or F - F₁ = - F₂
F₂ = 4 Hz + 440 Hz or 4 - 440 = - F₂
F₂ = 444 Hz or - 436 = - F₂
F₂ = 444 Hz or F₂ = 436 Hz
Therefore, the frequency of the piano is 444 Hz or 436 Hz
A bird flies 3.7 meters in 46 seconds, what is its speed?
Answer:
Speed is 0.08 m/s.
Explanation:
Given the distance that the bird flies = 3.7 meters
The time is taken by the bird to fly the 3.7 meters = 46 seconds
We have given distance and time. Now we have to find the speed at which the bird flies. So, to calculate the speed of the bird we have to divide the distance by the time.
Below is the formula to find the speed.
Speed = Distance / Time
Now insert the given value in the formula.
Speed = 3.7 / 46 = 0.08 m/s
Car wheel's slip in mud. why?
Answer:
Because its wet
Explanation:
An excited squirrel starts from rest and accelerates towards a nut at 1.0 m/s2 for 2.0 seconds. What is the squirrel’s displacement?
Answer:
[tex]x=8m[/tex]
Explanation:
Hello,
In this case, the most suitable kinematic equation for the calculation of the squirrel's displacement is:
[tex]x=v_ot+\frac{1}{2}at^2[/tex]
Whereas the initial velocity is zero as it starts from rest, thus, we obtain:
[tex]x=\frac{1}{2}*1.0\frac{m}{s^2}*(2.0s)^2\\ \\x=8m[/tex]
Best regards.
If 13 is added to a number, the result is 43 less than twice the number. Find the number,
Explanation:
13+x=43>2x
13+x=43>2x+43>2x
13+x=86>4x
x-4x=86-13
3x=73
x=73/3
x=24.333
x=24.4
Which atom is most likely to accept electrons to form an ionic bond? a mercury ion with a negative 2 charge a potassium ion with a negative 1 charge radon, a noble gas with 8 valence electrons sulfur, a nonmetal with 6 valence electrons
Sulfur, a nonmetal with 6 valence electrons atom is most likely to accept electrons to form an ionic bond option (D) correct.
What is an ionic bond?Ionic bonds, also known as electrovalent bonds, are a type of connection created in a chemical molecule by the electrostatic attraction of ions with opposing charges.
As we know,
It has been shown that the top of the electronegativity scale is defined by the fundamental atomic particles F>O>N.
Ionic bonds need an electron, often a nonmetal, and an electron, typically a metal. Metals display ionic bonding because there aren't many-electron in outer orbitals.
Thus, sulfur, a nonmetal with 6 valence electrons atom is most likely to accept electrons to form an ionic bond option (D) correct.
Learn more about the ionic bond here:
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Please help me slow this I don't understand how this works
Answer:
[tex]A=90^0-B\\B+C=180^0-90^0=90^0\\C=90^0-B\\A=C[/tex]
Explanation:
6
Following an inelastic collision, what can kinetic energy be converted into? Check all that apply.
heat
impulse
momentum
potential energy
sound
Mark this and return
Save and Exit
Next
Submit
Answer:
Heat, potential energy, and sound.
Explanation:
Edgenuity says so
The characteristics of the inelastic shocks allow to find the correct answers of in which the kinetic energy can be transformed are:
Heat Potential energy Sound.
In a collision the total momentum of the system is conserved, this is an important principle of physics, we have two types of collisions:
Elastic. In this case the kinetic energy of the system is conserved. Inelastic. In this case the initial kinetic energy is not conserved.
In inelastic collision, part of the energy of the movement is transformed into potential energy of configuration of the system.
Let's analyze the different answers:
a) Heat.
True. Heat is a form of energy that, due to the change in the relative friction motion of bodies, is one of the greatest sources of transformation of energy into configuration power energy.
b) Impulse.
False. The impulse is the change of the momentum of the system and this is conserved, therefore the momentum is also conserved.
c) Momentum
False. Momentum is preserved in all crashes.
d) Potential energy.
True. Power energy is a configuration energy, therefore kinetic energy can be transformed into potential energy.
e) The sound.
True. Sound is a wave that carries energy, therefore kinetic energy can be transformed into traveling sound waves.
In conclusion, using the characteristics of inelastic shocks, we can find the correct answers that the kinetic energy can be transformed into are:
Heat Potential energy Sound.
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the force which slow down a paper aeroplane moving through the air is called
The paper plane slows down when flying in the air due to air resistance or the friction due to the air around it. As the paper plane have flat surfaces and more surface area, the air resists it's motion more than before. If the paper plane is moving towards left, then friction acts towards left.
The friction always act opposite to the direction of paper plane and resists its motion. Hence, we can say that paper plane slows due to Frictional Force [tex]\red{\bullet}[/tex]
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4. Two people each have a mass of 55 kg. They are both in an
elevator that has a mass of 240 kg. When the elevator
begins to move, the people and the elevator have an upward
acceleration of 1.00 m/s2. What is the net force that acts on
the elevator as it accelerates upward at 1.00 m/s2?
Answer:
350 N
Explanation:
F=ma
[tex]f = force \\ m = mass \\ a = acceleration[/tex]
[tex]m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} } [/tex]
Force = 350 Newtons
The net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2.
What is Newton's second law?
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = ma
As given in the problem two people each have a mass of 55 kg. They are both in an elevator that has a mass of 240 kg. When the elevator begins to move, the people and the elevator have an upward acceleration of 1.00 m/s2, then we have to find the net force acting on the elevator,
The net force acting on the elevator,
F = ma
F =(2×55 + 240)×1
= 350 Newtons
Thus, the net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2
Learn more about Newton's second law, here
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Question 3
A box is being pulled by a rope that makes a 25 degree angle with the ground. The
pulling force is 100.0 N
along the rope. Find the horizontal and vertical components of the force vector.
A. 90.63 N, 42.26 N
B. 86.87 N, 32.17 N
C. 60.87 N, 75,63 N
D. 80.9 N, 45.5 N
What is the answer A,B,C or D?
Answer:
A
Explanation:
A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turns on, causing an acceleration of 0.250 m/s2 in the x direction. The acceleration lasts for 45.0 s, at which point the thruster turns off. (a) What is the magnitude of the satellite's velocity when the thruster turns off
Answer:
a) The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.
b) The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.
Explanation:
Statement is incomplete. The complete description is now described below:
A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turns on, causing an acceleration of 0.250 m/s2 in the x direction. The acceleration lasts for 45.0 s, at which point the thruster turns off.
(a) What is the magnitude of the satellite's velocity when the thruster turns off
(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis. ° counterclockwise from the +x-axis
Let be x and y-directions orthogonal to each other and the satellite is accelerated uniformly from rest in the +x direction and moves at constant velocity in the +y direction. The velocity vector of the satellite ([tex]\vec{v}_{S}[/tex]), measured in meters per second, is:
[tex]\vec{v}_{S} = (v_{o,x}+a_{x}\cdot t)\,\hat{i}+v_{y}\,\hat{j}[/tex]
Where:
[tex]v_{o,x}[/tex] - Initial velocity in +x direction, measured in meters per second.
[tex]a_{x}[/tex] - Acceleration in +x direction, measured in meter per square second.
[tex]t[/tex] - Time, measured in seconds.
[tex]v_{y}[/tex] - Velocity in +y direction, measured in meters per second.
If we know that [tex]v_{o,x} = 0\,\frac{m}{s}[/tex], [tex]a_{x} = 0.250\,\frac{m}{s^{2}}[/tex], [tex]t = 45\,s[/tex] and [tex]v_{y} = 21.4\,\frac{m}{s}[/tex], the final velocity of the satellite is:
[tex]\vec{v}_{S} = \left[0\,\frac{m}{s}+\left(0.250\,\frac{m}{s^{2}} \right)\cdot (45\,s) \right]\,\hat{i}+\left(21.4\,\frac{m}{s} \right)\,\hat{j}[/tex]
[tex]\vec{v_{S}} = 11.25\,\hat{i}+21.4\,\hat{j}\,\,\left[\frac{m}{s} \right][/tex]
a) The magnitud of the satellite's velocity can be found by the resource of the Pythagorean Theorem:
[tex]\|\vec {v}_{S}\| = \sqrt{\left(11.25\,\frac{m}{s} \right)^{2}+\left(21.4\,\frac{m}{s} \right)^{2}}[/tex]
[tex]\|\vec{v}_{S}\| \approx 24.177\,\frac{m}{s}[/tex]
The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.
b) The direction of the satellite's velocity when the thruster turns off is determined with the help of trigonometric functions:
[tex]\tan \alpha = \frac{v_{y}}{v_{x}} = \frac{21.4\,\frac{m}{s} }{11.25\,\frac{m}{s} }[/tex]
[tex]\tan \alpha = 1.902[/tex]
[tex]\alpha = \tan^{-1}1.902[/tex]
[tex]\alpha \approx 62.266^{\circ}[/tex]
The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.
Part A
What is the magnitude of the momentum of a 0.0073-kg marble whose speed is 0.65 m/s?
Express your answer to two significant figures and include appropriate units.
Part B
What is the speed of a 0.136-kg baseball whose momentum has a magnitude of 3.14 kg⋅m/s?
Express your answer to two significant figures and include appropriate units.
Answer:
(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.
(B). The speed of baseball is 23.0 m/s
Explanation:
Given that,
Mass of marble = 0.0073 kg
Speed = 0.65 m/s
(A). We need to calculate the magnitude of the momentum of the marble
Using formula of momentum
[tex]p = mv[/tex]
Where, m = mass
v = velocity
Put the value into the formula
[tex]p=0.0073\times0.65[/tex]
[tex]p=0.004745\ kg m/s[/tex]
(B). Mass of baseball = 0.136 kg
Momentum of baseball = 3.14 kg m/s
We need to calculate the speed of baseball
Using formula of momentum
[tex]p=mv[/tex]
[tex]v=\dfrac{p}{m}[/tex]
Put the value into the formula
[tex]v=\dfrac{3.14}{0.136}[/tex]
[tex]v=23.0\ m/s[/tex]
Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.
(B). The speed of baseball is 23.0 m/s
How does an electrometer differ from a voltmeter? What is meant by an electrical ground? What must you do before each measurement in this experiment and why?
Answer:
n an electrometer, it is built in such a way that its resistance in parallel is extremely high
Ground in a circuit is a reference point from which voltages are measured
all the instruments must be grounded and we must ground ourselves
Explanation:
When you build a voltmeter you have a resistance in parallel with the galvanometer, therefore when measuring the voltage of a circuit, so that there is no effect (load effect) by the voltmeter, a resistance must be much greater than the resistance where it is is measuring.
In an electrometer, it is built in such a way that its resistance in parallel is extremely high in the order of 10¹²Ω, so its load effect is very small and can be measured with high resistance mu
Electric ground in home and industrial installations is a protection system consisting of a metal piece connected to a buried ground electrode.
Ground in a circuit is a reference point from which voltages are measured and is common to all parts of the circuit
In an experiment where an electrometer is used, all the instruments must be grounded and we must ground ourselves, since it must be an instrument where very small voltages are measured at high impedances.
Jesse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is 0.600 m and Miguel has a mass of 11.0 kg, what is the centripetal force on Miguel? Round to the nearest whole number. N
Answer:
224.6 N
Explanation:
We can use first the formula to calculate the centripetal acceleration, given by:
[tex]a_c=\frac{v_t^2}{R}[/tex]
where the Vt is the tangential velocity, and R is the radius of the circular motion.
Then, for our case we have:
[tex]a_c=\frac{v_t^2}{R}=\frac{3.5^2}{0.6}\approx 20.42\,\,\frac{m}{s^2}[/tex]
And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:
[tex]F_c=11 \,*\,20.42\,N = 224.6\,\,N[/tex]
Answer:
225 N
Explanation:
Just answered the question
what is the mass of an object that is experiencing a net force of 200N and an acceleration of 500m/s2
Answer:
F=200N
a=500m/s2
Mass=?
Explanation:
F=ma
200=m*500
200/500=m
Mass=0.4kg
What is an example of intellectual development?
Answer:
learning new activities like riding a bike and playing sports. and also having the ability to collect information and remember them (memory). <3
Earth's atmosphere is constantly bombarded by cosmic ray protons that originate somewhere in space. If the protons all passed through the atmosphere, each square meter of Earth's surface would intercept protons at the average rate of 1800 protons per second. What would be the electric current in amperes intercepted by a 41 × 107 km2 area on the planet
Answer:
Electric current in amperes = 1.1808 A
Explanation:
Given:
Intercept protons rate = 1800 protons per second
Area = 41 × 10⁷ km²
Find:
Electric current in amperes
Computation:
Current density = Intercept protons rate × 1.6 × 10⁻¹⁹
Current density = 1800 × 1.6 × 10⁻¹⁹
Current density = 2.88 × 10⁻¹⁶
1 km² = 10⁶m²
So,
Electric current in amperes = 2.88 × 10⁻¹⁶ × 41 × 10⁷ × 10⁶
Electric current in amperes = 1.1808 A
What do we know has to be TRUE about the action and reaction force below?
the boot kecked the ball which is frictinal force