The force acting on the car is 9700N.
First, the speed has to be converted to m/s units (SI)
105 km/h x 1000m/3600s ≅ 29 m/s
Then, using kinematics, we must determine the acceleration to determine the force. Kinematics is the area of mechanics that studies pure motion without taking into account the masses or forces at play, likewise known as applied kinematics. The concept of mechanical devices that change one type of motion into another.
[tex]V_{final^{2} } = V_{intial^{2} } + 2ax[/tex]
[tex]29^{2} = 0^{2} + 2 * a * 53[/tex]
a ≅ [tex]7.9\frac{m}{s^{2} }[/tex]
Using equation,
F = ma
F = 1225 x 7.9
9677 N ≅ 9700 N
Therefore, The force acting on the car is 9700N.
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would the balloon hit the ground before or after 1.0 s of falling? which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?
The first equation will be used to determine that it would hit the ground after 1.0s of falling (in 1.56 s).
Equation of motion are a mathematical formula that describes the position, velocity or acceleration of a body relative to a given frame of reference
The first equation to be used will be second equation of motion
x = v₀t + 1/2at²
where, x = distance
a = uniform acceleration
t = time
12 = 1/2*9.8 *t²
24 = 9.8 * t²
t = 1.56 s.
The balloon will hit the ground after 1.0s of falling.
The 1st equation was used because of the values provided which included the distance and the acceleration due to gravity. The 2nd equation has final velocity and initial velocity which couldn't be compared from the data given.
The given question is incomplete complete question is:
A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
x=x0+v0t+12at2
v=v0+at
Would the balloon hit the ground before or after 1.0 s of falling? Which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?
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an object moves halfway around a circle of radius r. an inward radial force of magnitude f is exerted on it. the work done on the object by the radial force being exerted on it is
The item moves halfway around a circle of radius r. an inward radial pressure of magnitude f is exerted on it. the paintings done on the item through the radial force being exerted on it is zero.
In physics, paintings is the power transferred to or from an object via the software of pressure along a displacement. In its most effective form, for a consistent strain aligned with the direction of motion, it equals the fabricated from the force strength and the gap traveled.
The work modifications the quantity of mechanical and internal electricity possessed with the aid of devices. whole paintings is carried out on a gadget or object, power is added to it.
The individual of labor accomplished can be categorised in three instructions. they're +ve paintings, -ve paintings and 0 work. The character of work is based upon at the attitude amongst stress and displacement..
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when bulb c is removed from the circuit, what happens to the brightness of bulb a ? when bulb is removed from the circuit, what happens to the brightness of bulb ? the brightness of bulb a stays the same. the brightness of bulb a increases. the brightness of bulb a decreases.
The brightness of bulb A will not be affected, but the brightness of bulbs B and D will become brighter.
In the given circuit, the bulbs B, C, and D are connected in series, whereas bulb A is connected in parallel.
All parts of a series circuit are wired together end to end to create a single path for current flow.
A series circuit of incandescent bulbs would have reduced brightness and increased life when a bulb is added. When a bulb is removed from the series combination, the brightness of the other bulbs will increase. Each bulb acts as a resistor reducing the current through each bulb. In a series circuit, when one bulb burns out, it acts as an open switch, and all bulbs go out.
The given question is incomplete as there is no given circuit diagram.
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The physician who was inspired by traveling mesmerists and who coined the term hypnosis was ____________. A. Franz mesmer b. James braid c. Jean martin charcot d. Sigmund freud please select the best answer from the choices provided a b c d.
James braid, a physician, is credited with coining the term hypnosis after becoming mesmerized while traveling. Hence, the relevant option is option (b).
Who was James braid?James Braid was born on June 19, 1795, and passed away on March 25, 1860. He was a well-known Scottish surgeon who was also a gentleman scientist and natural philosopher. According to Braid, hypnotic suggestion can be an effective treatment for nervous system functioning problems. Comparative anatomy has been defined as the study of similar body features in various animal species in order to suggest or comprehend modifications that have to occur underground during the course of evolution from very similar predecessors.
The research that compares the structural differences between various animal species in order to comprehend the changes that each species went through during the stage of evolution from their common ancestors. James braid, a physician, is credited with coining the term hypnosis after being mesmerized while traveling.
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a laser emits photons continuously at a rate of 6.8*1016/s. if the wavelength of the photons is 641 nm, what is the laser power in mw?
The laser power is 27,69 mW.
Power= energy/sec = J/s
Photon energy= hf= hc /wavelength
# of photons/sec = power/ photon energy= rate of emission
Photon Energy= ( 6.63 × [tex]10^{-34}[/tex]) × 3×[tex]10^{8}[/tex] / 6.8×[tex]10^{16}[/tex] ≈ 3.147 ×[tex]10^{-42}[/tex] J
This should be ignored. It is part of the units and not the equation.
Power/3.147 × [tex]10^{-42}[/tex] = 8.8 × [tex]10^{26}[/tex] [tex]s^{-1}[/tex]
Power= 8.8 × [tex]10^{-26}[/tex]- 3.147 × [tex]10^{-42}[/tex] J= 0 .02769 W = 27.69 mW
How is laser power determined?
The energy levels of the electrons in the atoms of the material used to create the laser beam—often referred to as the "lasing" material—determine the intensity of the laser beam. The wavelength of the light generated by the lasing material has an inverse relationship with the energy level of the photons that are created by it.
Can a laser's power be increased?
The intensity of the light increases with the amount of energy used to excite those atoms in the laser. It almost resembles dialing up the sound system's volume control. However, if you turn that level up too loud, you run the danger of harming your hearing or the sound system itself.
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A diver in the pike position (leg? straight _ hands on ankles) usually makes only one or onc-and-a-half rotations. To make tWO Or three rotations_ thie cliver goes into tuck position (knees bent , body curled up tight) . Why? 12.62 A 120-Cm-wide sign hangs from 5.0 kg; 200-cm-long pole cable of negligible maSS supports the end of the rod as shown in the figure_ What is the HaXimu maSS of the sign if the maxinm tension in the cable without breaking is 300 N? Note: You will be graded On your use of all elements from Dynamics Worksheet Problem 2. Cable 250 cm 200 cm PATSIES SHIPPE 80 cm
It's crucial to understand that when a diver leaps off a springboard, their angular momentum stays constant until they touch the water's surface.
Despite acting on the diver, gravity does not exert a net positive or negative torque on the diver since it passes through the diver's center of mass. The diver can make two to three rotations when in the tuck position, but only one or two rotations when in the pike position. The moment of inertia of the two places is the cause. The moment of inertia of the diver in the tuck position can be lower. Given that the diver's angular speed is inversely proportional to the moment of inertia, she will make more rotations for the constant angular momentum.
I1w1 =I2w2
w1/w2 = I1/I2
I1 = mr1^2
I2 = mr2^2
r2<r1
then I2<I1
w1/w2<1
w1<w2
From the above analysis we can say that the angular velocity is less in the first case than in the later case which means the number of rotations made in the tuck position is more than number of rotations made than that in pike position.
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what would be the effect on the motion of the cross if the center of mass of the body were to one side of the axis of rotation
Never does a free body revolve around its center of mass ( the instantaneous axis of rotation never passes through the center of mass).
Explain about the axis of rotation?Being a hypothetical object, the axis of rotation might be a challenging notion to understand. An imaginary line that extends through the joint's pivot or rotation point is referred to as the axis of rotation in terms of human anatomy (for example, the axis of rotation for flexing and extending the arm projects through the elbow joint).
The intersection of these three axes, which are the longitudinal, lateral, and vertical ones, each of which is perpendicular to the others, occurs at the center of gravity of the aero plane.
Position, momentum, and angular momentum make up an object's motion when it is rigid. Therefore, the "axis of rotation" is the unit vector, which is the object's angular momentum vector divided by the angular momentum magnitude (and therefore undefinable in the absence of angular momentum).
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Nuclear decay occurs according to first-order kinetics. How long will it take for a sample of titanium-45 to decay from 65. 0 grams to 25. 0 grams? the half-life of titanium-45 is 3. 08 hours.
It will take 4.24 hours for a sample of titanium-45 to decay from 65. 0 grams to 25. 0 grams.
Half life of first order reaction is given by: [tex]t_{1/2}[/tex] = 0.693/k
Given half life is 3.08 hours.
So k = 0.225
Rate of first order reaction is given by: [tex]kt = 2.303 * log(R'/R)[/tex]
Where k = rate of reaction = 0.225
t= time taken
R' = final amount = 25g
R = initial amount =65g
Putting these values we get t=4.24 hours.
So it will take 4.24 hours for a sample of titanium-45 to decay from 65. 0 grams to 25. 0 grams.
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In a canoe race, team a is traveling 6 miles per hour and is 2 miles ahead of team b. Team b is also traveling 6 miles per hour. The teams continue traveling at their current rates for the remainder of the race. Using d for distance (in miles) and t for time (in hours), write a system of linear equations that represents this situation.
Linear equation for team a; d = 6t + 2 and Linear equation for team b;
d = 6t.
What is the relationship between speed, distance and time?To find speed, divide the distance of the journey by the time it took to travel. To calculate the time, divide distance by speed and to get the distance, multiply speed by time.
Given that in a canoe race, team a is traveling 6 miles per hour and it is 2 miles ahead of team b.
Team b is traveling 6 miles per hour. The teams continue the traveling at their current rates for the remaining race.
We know that speed= distance/time
Linear equation for team a;
d = 6t + 2
Linear equation for team b;
d = 6t
d is distance and t is time.
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A bowler uses a lane with a coefficient of kinetic friction of 0.211. The bowler releases her 5.20 kg bowling ball with a translational speed of 2.35 m/s. At the moment of release, the ball is not rotating. As the ball slides, it begins to rotate.
What is the work nc done by friction on the ball before it transitions to rolling without slipping? Use =9.81 m/s2 for the acceleration due to gravity.
The work done by friction on the ball before it transitions to rolling without slipping is 7.04 J.
What is the final velocity of the bowling ball?
The final velocity of the bowling ball is calculated by applying the principle of conservation of angular momentum as follows;
Li = Lf
mv₁r = mv₂r + Iω
where;
I is the moment of inertia of the bowlω is the angular velocity of the ballv₁ is the initial velocity of the ballv₂ is the final velocity of the ballmv₁r = mv₂r + (²/₅mr²)ω
mv₁r = mv₂r + (²/₅mr²)(v₂/r)
mv₁r = mv₂r + (²/₅mr)(v₂)
r(mv₁) = r(mv₂ + ²/₅mv₂)
mv₁ = mv₂ + ²/₅mv₂
v₁ = v₂ + ²/₅v₂
v₁ = 7v₂/5
7v₂ = 5v₁
v₂ = 5v₁/7
v₂ = (5 x 2.35 m/s)/7
v₂ = 1.678 m/s
The work done by friction on the ball before it transitions to rolling without slipping is calculated as follows;
work done by friction = change in kinetic energy of ball
ΔK.E = ¹/₂m(v₂² - v₁²)
ΔK.E = ¹/₂ x 5.2(1.678² - 2.35²)
ΔK.E = -7.04 J
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Answer:
-7.03266 N
Explanation:
Work = Final kinetic energy - initial kinetic energy
[tex]W_{nc} = K_{f} - K_{i}[/tex]
Finding initial kinetic energy:
[tex]K_{i}=\frac{1}{2}mv^{2}= \frac{1}{2}(5.2)(2.35)^{2}=14.3585\\[/tex]
Finding final kinetic energy:
We have mass, but don't have final velocity. Have to find [tex]v_{f}[/tex] next.
We can use the kinematics equation combined with the fωorce equation. The force that slow the ball down is friction force. [tex]v_{f}=v_{0}+at=v_{0}+\frac{F}{m}t=v_{0}-\frac{f}{m}t[/tex]
Finding f/m
f=μmg ⇒ (f/m)=μg=0.211(9.81)=2.06991
Plug that back into the equation
[tex]v_{f}=2.35-2.06991t[/tex]
Now to find time, we can use angular velocity
τ=fR and α=τ/I and [tex]I=\frac{2}{5}MR^{2}[/tex], so [tex]\alpha =\frac{fR}{\frac{2}{5} MR^{2}}=\frac{5ug}{2R}[/tex]
ω=αt=(5μg)(t)/(2R)=5.174775(t/R)
v=rω=5.174775t
Therefore, [tex]v_{f}=2.35-2.06991t=5.174775t[/tex]
t=0.32437
Plug time back into the v_f equation.
[tex]v_{f}=2.35-2.06991(0.32437)=1.67858[/tex]
Plug v_f back into the K_f equation
[tex]K_{f}=\frac{1}{2}mv^{2}= \frac{1}{2}(5.2)(1.67858)^{2}=7.32584[/tex]
Work done by friction
[tex]W_{nc} = K_{f} - K_{i}=7.32584-14.3585=-7.03266[/tex]
A student has an ohmic lightbulb connected to a battery that has significant internal resistance. As the student connects other identical lightbulbs in parallel to the first lightbulb, which of the following would be a reasonable observation about the brightnesses of the lightbulbs?
a. Each lightbulb gets brighter as more lightbulbs are added.
b. Each lightbulb gets dimmer as more lightbulbs are added.
c. When each lightbulb is added, it is the same brightness as the first lightbulb, which remains the same brightness throughout.
d. The first lightbulb remains the same brightness, but each added lightbulb is brighter than the original.
e. The first lightbulb remains the same brightness, but each added lightbulb is dimmer than the original.
Based on the information provided regarding the parallel circuit, reasonable observation about the brightness of the lightbulbs would be that when each lightbulb is added, it is the same brightness as the first lightbulb, which remains the same brightness throughout. (Option C)
A parallel circuit refers to a circuit that comprises of branches so that the current divides and only part of it flows through any branch. The voltage, or potential difference, across each branch is the same. Two or more bulbs in a simple parallel circuit have full voltage of the battery, hence the brightness of each bulb remains unchanged.
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the technology that allows engineers to penetrate rock at multiple angles instead of simply a straight line is called(1 point)
The method used by engineers to pierce rock at angles other than just a straight line is known as directional drilling.
What is method?
A procedure connected to a message and an object is referred to as a method throughout object-oriented programming (OOP). An object is made up of state information and behaviour, which together make up the interface that outlines how any of the object's various consumers may use it. A method is indeed a consumer-parametrized behaviour of an object. Behaviors have been represented as methods, while data is represented as an object's properties. For instance, a Window object may have properties like open and close as well as methods like open and close, and its state (whether it is opened or closed at any given time) would be a method.
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consider a wave passing through a single slit. what happens to the width of the central maximum of its diffraction pattern as the slit is made half as wide? it becomes one-fourth as wide. it becomes one-half as wide. its width does not change. it becomes twice as wide. it becomes four times as wide.
Wave passing through a single slit it becomes twice as width of the central maximum of its diffraction pattern as the slit is made half as wide.
The central maximum lies between the first-order minima defined by the relation sinθ dark =mλ/a=λ/a. Because the angle is small, sinθ dark ≈tanθ dark =y dark/L, so the width of the central maximum is proportional to Lλ/a. Thus, the central maximum becomes twice as wide if the slit width a becomes half as wide.
In order to enter the region of geometric shadow cast by the obstruction or aperture, waves must interact with one another or bend around its edges, which is referred to as diffraction. A secondary source of the wave that is propagating is in fact created by the diffracting item or aperture. The term "diffraction" was originally used in 1660 by the Italian scientist Francesco Maria Grimaldi, who was also the first to make precise observations of the phenomena.
On the registration plate, an infinite number of spots (three are illustrated) along length d project phase contributions from the wave front, resulting in a constantly changing intensity.
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a long straight wire carries current to the right. above the wire is a square wire loop. if the loop moves away from the long ,straight wire what is the direction of the induced current in the loop?
The loop's induced current flows counterclockwise because a long, straight wire carries current in that direction (to the right). There is a square wire loop above the wire. if the loop departs from the lengthy.
The loop's magnetic flux will decrease as the current in wire AB in the wire drops. Therefore, to counteract the drop in magnetic flux, the current introduced into the loop must be counterclockwise. Induced current definition The current that results from electromagnetic induction is known as the induced current. The production of electric power relies heavily on electromagnetic induction. Typically, metal is drawn through a hole in a die or draw plate to create wire. There are numerous standard sizes for wire gauges.
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calculate the work w done by the gas during process 1→3→6 . express your answer in terms of p0 and v0 .
6P₀V₀ is the work done by the gas during process 1→3→6.
What is work done by gas?The work performed by a gas expanding against an external pressure is negative, analogous to the work performed by a system on its surroundings. In contrast, when a gas is compressed externally, V₀ and the work is positive because the environment exerts force on the system.
The gas must release some energy into the environment when it expands in response to an external pressure. The overall energy of the gas is thus reduced as a result of the negative work. When a gas is compressed, energy is transferred to it, increasing its energy as a result of positive work.
Let's consider,
Work done = -W (As the energy is released)
External pressure = P₀
Volume of gas = V₀
So, the work done can be calculated as follows:
W = P x (dV)
-W = P₀ × V₀
Now according to the process given:
1→3→6
Energy flow increases up to 6.
Hence, the energy of the system (work done) is:
-W = 6 × P₀ × V₀
-W = 6P₀V₀
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consider the pictured representations of electromagnetic waves. which electromagnetic wave corresponds to each description?
Electromagnetic (EM) waves are waves that are related to both electricity and magnetism. These waves travel over space and are made up of time-varying electric and magnetic fields.
When electric and magnetic fields interact and change over time, electromagnetic waves are produced.These waves, which are linked to electricity and magnetism, would almost certainly travel beyond space.The magnetic field varies with time and gives rise to the electric field; the electric field changes with time and gives rise to the magnetic field again, and so on. When time-varying electric and magnetic fields are coupled and propagate together in space, electromagnetic waves are formed.To know more about electromagnetics visit:
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what is the maximum speed of a 330 kg car if the spring is compressed the full amount? express your answer with the appropriate units.
A fully compressed spring may move at a maximum speed of 4.993 m/s, according to the question.
What is speed and what is its unit in physics?The pace at which a distance changes over time is referred to as speed. It includes a dimension of time-distance. As a result, the fundamental unit of time and also the basic unit if length are combined to form the High silica content of speed. Thus, the meter per second is the SI unit for speed.
Briefing:K.E = 3RT/2 - (i)
K.E = mv²/2 - (ii)
eq(i) = eq(ii)
comparing
3RT = mv²
v² = 3RT/m
T/m = 1
v = [tex]\sqrt{3R}[/tex]
v = [tex]\sqrt{3*8.31}[/tex]
4.993m/s
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46. what minimum friction force must exist between the tires and the road to prevent the car from skidding as it rounds the curve?
Daniel G. A=v2r calculates centripetal acceleration. The recommended minimum friction coefficient is 0.4.
How much friction must there be at a minimum for the car to stay on the road?Of course, the car won't slide if the coefficient of friction is higher than 0.141; this is the minimum value. The frictional force is parallel to the velocity, as you can see.
What level of frictional force is needed to prevent the car from swerving?A car needs a centripetal force of mV2/R, where m is the mass of the vehicle, V is the speed, and R is the radius of the circular portion of road, in order to maintain its position on the road without skidding. Fs/Fl = 4mV2/R / 2mV2/R is obtained by dividing Fs by Fl.
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A helium-neon laser emits light with a wavelength of 633 nm. What is the frequency of this light.
Answer:
The frequency of light beam is 4.74 x 10^(14) s^(-1)
Explanation:
In this problem we use the formula C=F x ( lamda )
here c= the speed of light
f =the frequency of light beam
lamda = wavelength
c=3 x 10^8 m/s ( universally same)
lamda = 633nm = 633 * 10^(-9) m
Therefore f = c/ ( lamda )
or; f = 3 x 10^8 / 633 * 10^(-9)
f= 4.74 x 10^(14) s^(-1) .
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g an apple pie in a 9.00 in diameter plate is placed upon a rotating tray. then, the tray is rotated such that the rim of the pie plate moves through a distance of 158 in. express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.
The angular distance should be the angular distance that the pie plate has moved through in revolutions, radians, and degrees are 5.59 revolution and 2012.4° respectively.
In revolution, θ = 8.24 revolution.
In radian = θ = 57.78 rad.
In degree θ = 2966.4°.
Calculation of the angular distance:
Since
Pie diameter = 9 in
So, the circumference of the pie should be
P = πd = 9π in
And, rim of the pie rotates 158 in,
So,
1 Revolution of the pie is 9π in,
So, for 158 it should be
= 158 in / 9π in revolution
= 5.59 revolution
Now in the case when
1 revolution is 2πrad
So,
5.59 revolution = 5.59 × 2π = 87.79 rad.
And also, 1 revolution is 360°
5.59 revolution = 5.59 × 360 = 2012.4°
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Can someone please help meeeeeeee! I’m so bad at these stuff. Ill give brainliest too
Figure 1-1 shows how a steel ball moved during an experiment. Average speed is calculated by dividing total distance by time. Did the steel ball speed up, slow down, or remain at the same speed throughout the experiment?
The ball is seen to be speeding up as the distance increases with time.
What is speed?We know that speed is the ratio of the distance to the time that is taken by the object. We know that when an object is speeding up, the distance of the object is going to increase linearly with the time taken.
If we look at the graph that has been shown in the image that is attached to this answer, we would notice that the distance that is covered is increasing with time.
The speed can then we obtained from;
Speed = [tex]y_{2} - y_{1}/x_{2} - x_{1}[/tex]
= 80 - 0/6.5 - 0
= 12.3 m/s
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an inflated bicycle tire is 2.2 cm in diameter and 2.0 m in circumference. a small leak causes the pressure inside of the tire to decrease from 760 kpa to 550 kpa on a day when the temperature is 20 o c. what mass of air is lost?
Answer: 0.0016 kg
Explanation: To solve this problem, we need to use the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature and the number of moles of gas present. The ideal gas law is given by the following equation: PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas present, R is the ideal gas constant, and T is the temperature of the gas.
In this case, we are given the pressure of the gas inside the tire (760 kPa and 550 kPa), the temperature of the gas (20 °C), and the diameter and circumference of the tire (2.2 cm and 2.0 m). We need to use this information to calculate the mass of air that was lost from the tire.
First, we need to find the volume of the gas inside the tire. Since the circumference of the tire is 2.0 m and the diameter is 2.2 cm, we can use the formula for the circumference of a circle to calculate the radius of the tire:
C = 2 * pi * r
2.0 m = 2 * pi * r
r = 0.3 m
Next, we can use the formula for the volume of a circle to calculate the volume of the gas inside the tire:
V = pi * r^2 * h
V = pi * (0.3 m)^2 * 2.2 cm
V = 0.0183 m^3
Now that we have the volume of the gas inside the tire, we can use the ideal gas law to calculate the number of moles of air inside the tire:
PV = nRT
n = PV / RT
n = (760 kPa * 0.0183 m^3) / (8.314 J/molK * 293 K)
n = 0.0059 mol
Next, we can use the ideal gas law to calculate the number of moles of air lost from the tire when the pressure decreased from 760 kPa to 550 kPa:
n = PV / RT
n = (550 kPa * 0.0183 m^3) / (8.314 J/molK * 293 K)
n = 0.0043 mol
Finally, we can use the molar mass of air to calculate the mass of air that was lost from the tire:
m = n * M
m = (0.0059 mol - 0.0043 mol) * 28.97 g/mol
m = 0.0016 kg
Therefore, the mass of air lost from the tire when the pressure decreased from 760 kPa to 550 kPa is 0.0016 kg.
is it possible to use the reflection from this corner cube to send a sunbeam onto the wall in a room from the sun's rays entering the room through a window?
Yes, but only up to a certain height since the corner cube maintains the angle of the light's incidence. No, as any position of a corner cube sends the beam back to the window. Yes, the beam is parallel to itself when the cube travels slightly.
What are corner cubes and how do they function?An optical element having the exceptional capability of returning an entering beam of light straight at its place of origin irrespective of the beam's angle of entry is a corner cube, often called as a retroreflector.
A corners cube retroreflector (CCR) is what, exactly?Three adjacent, mutually orthogonal plane-reflecting surfaces make up a corner cube retroreflector, also called as a CCR or trihedral prism, which is an optical structure an angle of a cube. Independent of the prism, the corner cube returns an incident ray at a certain angle.
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a 40kg child takes a ride on a ferris wheel that rotates fouyr times each minute and has a diameter of 18m what is the centripetal acceleration
The centripetal acceleration is [tex]1.58m/s^2[/tex]
What is centripetal acceleration?
Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any object moving in a circle with an acceleration vector pointing in the direction of the circle's center.
It is calculated by
ac = rω^2
where
ac = centripetal acceleration
r = radius
ω = angular velocity
Given,
ω = 4 revolution,
diameter = 18m so, radius r = 9m
Subsituting the values in equaion
ac = [tex][9m] [[4.0\frac{rev}{min} ][\frac{2\pi rad}{rev} ][\frac{1 min}{60s} ]]^2[/tex]
ac = [tex]1.58m/s^2[/tex]
The centripetal acceleration is [tex]1.58m/s^2[/tex]
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the ring and the disk shown above have identical masses, radii, and velocities, and are not attached to each other. if the ring and the disk each roll without slipping up an inclined plane, how will the distances that they move up the plane before coming to rest compare?
The ring will move farther than will the disk.
The torque required to achieve a desired angular acceleration about a rotational axis depends on the moment of inertia of a rigid body.
The moment of inertia of a ring is given by the following equation [tex]I=mr^{2}[/tex]
similarly, the moment of inertia of a disk is [tex]I=m\frac{r^{2} }{2}[/tex]
Where, m and r is the mass and the radii of the ring and the disc.
The body's mass distribution and the axis selected to affect the moment of inertia, with larger moments requiring more torque to change the rotation rate. The object with the lowest moment of inertia will descend to the bottom first because it is resistance to rotational motion.
Therefore the disc will reach the bottom first, but due to the higher moment of inertia than the disc the ring will move farther than the disc.
The question is incomplete. The correct question is
A ring and a disk have identical masses, radii and velocities and are not attached to each other. If they each roll without slipping up an inclined plane, how will the distances that they move up the plane before coming to rest compare?
a. The ring will move farther than the disk.
b. The disk will move farther than the ring.
c. The ring and the disk will move equal distances.
d. The relative distances depend on the angle of elevation of the plane.
e. The relative distances depend on the length of the plane.
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let's say you use a heat pump to pump heat from room a to room b. the temperature in room a is 18.6 oc and in room b is 27.3 oc. if your goal is to cool space a, what is the theoretical cop limit?
The theoretical Coefficient of Performance (COP) to cool the room A is 33.52.
Temperature in room A = T₁ = 18.6 oc
Temperature in room B = T₂ = 27.3 oc
To convert temperatures in Kelvin,
= T₁ = 18.6 + 273 =
= T₁ = 291.6 K
and,
= T₂ = 27.3 + 273
= T₂ = 300.3 K
The COP value to cool room A =
= COP = T₁ / (T₂ - T₁)
= COP = 291.6 / (300.3 - 291.6 )
= COP = 291.6 / 8.7
= COP = 33.52
The theoretical coefficient of performance to cool room A is 33.52 when the temperature of room A is 18.6 oc and that of room B is 27.3 oc.
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what is the minimum angular spread of a 633-nm wavelength he-ne laser beam that is originally 1.00 mm in diameter? (answer in degrees)
The diffraction-induced minimum angular spread is 633 10 9 meters.
What is diffraction-induced propagation?When the hole is illuminated by a parallel ray of light of wavelength lambda, it is believed that the dispersal of the spot (gotten on the left wall of the video) equals the sum of its geometrical dispersal and the spread induced by diffraction.
Diffraction is the term used to describe the spreading out of waves when they pass through an apertures or around objects. It occurs when the aperture's or obstruction's size and the incident wave's wavelength are of same magnitude. At very small aperture diameters, the most of the wave is blocked.
Briefing : Minimum angular spread due to diffraction (θ) = λ/b
Given.
Wavelength = 633nm = 633×10⁻⁹m
Beam diameter is 1mm.
Minimum angular spread due to diffraction (θ) = 633×10⁻⁹m/1
Minimum angular spread due to diffraction (θ) = 633×10⁻⁹m.
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explain the relationship between diffraction angle and wavelength using the two dimensional diffraction relationship n
Diffraction is defined as the bending of waves through an aperture or around the edges of an obstruction into the vicinity of the barrier and The wavelength's length directly affects the angle of diffraction.
Why is it called wavelength?When electromagnetic radiation such as radio waves, light waves, or infrared (heat) waves travel through space, they leave behind distinctive patterns. The wave has a distinct size and shape. Wavelength is the separation between peaks (high points).
What occurs if the wavelength is boosted?A wavelength's frequency plus energy (E) drop as it gets longer. You may conclude from these formulas that the length gets shorter as the frequency rises. The wavelength lengthens as the frequency drops.
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what is the debroglie wavelength in picometers (10-12m) of an electron that is traveling at 79.1% of the speed of light?
The debroglie wavelength in picometers (10-12m) of an electron that is traveling at 79.1% of the speed of light is 2.8 × [tex]10^{-12}[/tex]
Mass of electron m = 9.1 × [tex]10^{-31}[/tex]kg
speed of electron v = 3 ×[tex]10^{8}[/tex] m/s * (79.1/100) = 2.37 × [tex]10^{8}[/tex] m/s
debroglie wavelength λ = h/mv
λ = 6.626 [tex]10^{-34}[/tex]/9.1 × [tex]10^{-31}[/tex] × 2.37 × [tex]10^{8}[/tex]
λ = 2.8 × [tex]10^{-12}[/tex]
In many branches of physics, the speed of light in a vacuum, commonly abbreviated as c, plays a crucial role. Exactly 299,792,458 meters per second is the speed of light, or c. [Note 3] The speed at which common matter or energy can travel through space (and, consequently, any signal carrying information) is limited to c, according to the special theory of relativity.
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