Answer:
18.392 N
Explanation:
Given that,
Smaller force acting on the car, F₁ = 3.8 N
Radius of smaller radius, r₁ = 10 cm = 0.1 m
The radius of the larger piston, r₂ = 0.22 m
We need to find the force exerted on the larger piston. Let it is F₂.
Using the relation,
[tex]\dfrac{F_1}{F_2}=\dfrac{A_1}{A_2}\\\\\dfrac{F_1}{F_2}=\dfrac{\pi r_1^2}{\pi r_2^2}\\\\\dfrac{F_1}{F_2}=\dfrac{r_1^2}{r_2^2}\\\\F_2=\dfrac{F_1r_2^2}{r_1^2}\\\\F_2=\dfrac{3.8\times (0.22)^2}{(0.1)^2}\\\\F_2=18.392\ N[/tex]
Hence, the force exerted on the larger piston is 18.392 N.
a hiker walks westward 2 meters and then eastward 7 meters. for this motion the distance moved is?
Answer:
d = 9 [m]
Explanation:
This is a problem where we must be clear about the concept of distance, which tells us that it is a measure of the space traveled on a trajectory.
Therefore:
d = 2 + 7
d = 9 [m]
The directions are not taken into account, as it is the sum of the displacements traveled, regardless of their directions.
A popular ride at an amusment park lifts
customers up to a height of 50 m and then
drops them threw a displacement of 50 m
before slowing them to a stop. How fast
are the customers going at the 50 m
mark?
Answer:
[tex]31.32\ m/s[/tex]
Explanation:
[tex]We\ are\ given\ that:\\Height\ to\ which\ there're\ lifted=50m\\Displacement\ during\ the\ descent=50m\\Now,\\In\ order\ to\ find\ the\ velocity\ of\ the\ customers\ at\ 50\ m,\\We\ can\ use\ the\ Third\ Equation\ Of\ Motion,\ which is:\\2as=v^2-u^2\\As\ we\ know\ that,\\Acceleration\ due\ to\ gravity=9.81\ m/s^2\ or\ roughly\ 10\ m/s^2\\Displacement=50\ m\\Initial\ velocity=0\ m/s^2\\ [As\ they\ stop\ when\ they\ reach\ the\ maximum\ height\ of\ 50\ m\\ and\ begin\ their\ descent][/tex]
[tex]By\ reconstructing\ the\ Third\ Equation\ Of\ Motion,\ we\ have:\\2gs=v^2\\Hence,\\v^2=2*9.81*50 \\v^2=981\ m^2/s^2 \\v=\sqrt{981\ m^2/s^2} \\v=31.32\ m/s[/tex]
A carousel at the local carnival rotates once every 45 seconds.
(a) What is the linear speed of an outer horse on the carousel, which is 2.75 m from the axis of rotation?
(b) What is the linear speed of an inner horse that is 1.75 m from the axis of rotation?
Answer:
We know that the carousel does a complete rotation in 45 seconds.
Then the frequency of this carousel will be f = 1/45 seconds.
And the angular frequency will be 2*pi times the frequency, then we have:
angular frequency = w = 2*3.14*(1/45s) = 0.1396 s^-1
Now, the linear speed of an object that rotates with a radius R, and an angular frequency W is:
S = R*W
then:
a) in this case the radius is 2.75m, then the linear speed is:
S = 2.75m*0.1396 s^-1 = 0.3839 m/s
b) in this case the radius is 1.75m, then the linear speed here is:
S = 1.75m*0.1396 s^-1 = 0.2443 m/s
(a) The linear speed of an outer horse on the carousel is 0.384 m/s.
(b) The linear speed of an inner horse on the carousel is 0.244 m/s.
Given data:
The time interval for the rotation of carousel is, t = 45 s.
The distance of the outer horse from the axis of rotation is, r = 2.75 m.
The distance of an inner horse from the axis of rotation is, r' = 1.75 m.
(a)
The linear speed in this problem can be obtained from the concept of rotational mechanic, in which the ratio of the circumference and the time gives required linear speed. So,
v = 2 π r/t
Solving as,
v = 2 π (2.75) / 45
v = 0.384 m/s
Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.384 m/s.
(b)
Now similarly the linear speed of an inner horse is calculated as,
v' = 2 π r' / t
Solving as,
v' = 2 π (1.75) / 45
v' = 0.244 m/s
Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.244 m/s.
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The average speed of a car that drives 140 kilometers in 2 hours
Answer:
240 kilometer
Explanation:
ur just mutipling the number by 2
Your average speed was 70.0 Kilometers per hour (km/h)
What is the steady state rate of heat flow through a pane of glass that is 40.0 cm by 30.0 cm with a thickness of 4.00 mm when the outside temperature of the glass is −10.0℃ and its inside temperature is 25.0℃? The thermal conductivity of glass is 0.105 W/(m⋅K); the specific heat of glass is 0.180 cal/(g⋅℃); and 1 cal = 4.190 J.
Answer:
110.25 watt/s
Explanation:
The rate of heat transfer is given by the formula
R = k*A(T1 - T2) / d, where
k = thermal conductivity, 0.105 (W/(m*K)
d = thickness, 4 mm = 0.004 m
T1 = inside temperature, 25° C
T2 = outside temperatures, -10° C
A = area 0.3 * 0.4 = 0.12 m²
Now, applying the given data to the formula, we have
Rate = 0.105 * 0.12 (25 - -10) / 0.004
Rate = 0.105 * 0.12(35) / 0.004
Rate = 0.105 * 4.2 / 0.004
Rate = 0.441 / 0.004
Rate = 110.25 Watt/s
Therefore, the steady state rate of heat flow is 110.25 watt/s
According to Steinberg, which of the following statements is true about creative people
They appreciate art and music.
They always take popular stands.
They accept ideas at fàce value.
They accept their limitations,
A ball is dropped from rest. Its energy is transformed from ________.
Answer:
gravitational potential energy
When the ball falls, some of its gravitational potential energy is converted to other forms of energy, such as kinetic energy and rotational energy. When it rebounds, these other forms of energy is converted back to gravitational potential energy.
Explanation:
Define conductor and insulator, including how the resistance is different in the two, and give at least one example of each.
Answer:
Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.
Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.
Example of conductor is copper
Example of insulator is plastic
A metal wire is uncharged. Explain how it is possible for a current to flow through it.
Answer:
Most conductors are fully charge neutral when carrying current, since their atomic structure is not altered, and electrons are in their normal state of jumping from atom to atom all the time.
It is just that this movement gets a direction under an external electric field, which causes a net charge flow (current) in conductor. So the conductor remains uncharged.
It is however possible for a capacitor plate to be charged (charged capacitor), and at the same time the plate can be a part of current carrying circuit through two points on it. In this case, charge on plate is independent of current and unrelated with it.
I have made foil type capacitors with such construction where the capacitor was a part of filter circuit in a signal carrier circuit, and connections were made from both ends of each foil.
WILL MARK BRAINLIEST JUST PLEASE HELP
Answer:
40N in either direction is the answer
Pure sodium metal explodes when it makes contact with water, and chlorine, in its natural state, is a deadly, poisonous gas. When these two chemicals combine, they form a harmless, white powder known as sodium chloride or table salt. Which of the following statements does this information support?
A.The properties of substances change during chemical reactions but then later go back to their original condition.
B.Heat must be added in order to change the chemical properties of substances.
C.When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.
D.When substances are chemically combined, the properties of the new substances that are formed are the same as the properties of the original substances.
Answer: When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.
Explanation:
An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 28.3 m/s. It then flies a further distance of 48900 m, and afterwards, its velocity is 45.5 m/s. Find the airplane's acceleration (m/s^2) and calculate how much time elapses (s) while the airplane covers those 40500 m.
Answer:
a==0.012979m/s^2
t=662.6s
Explanation:
.
Using the Newton equation below
Vf^2 = Vi^2 + 2as
Where Vf= final velocity
Vi= initial velocity
a= acceleration
Vf=45.5 m/s
Vi=28.3 m/s
Xf=48900 m,
Xi=0
a= (Vf^2 - Vi^2)/2s
If we substitute the values,
a=(45.5^2 -28.3^2)/(2×48900)
=(2070.25-800.88)/(2×48900)
=
a= 1269.36/97800
=0.012979m/s^2
Hence, the airplane's acceleration (m/s^2) is =0.012979m/s^2
Using the Newton equation we can calculate the time
a=(vf - vi) /t
Making "t" subject of the formula, we have
t=(vf - vi) /a
a=0.012979m/s^2
If we substitute the values, where
, we have
t= (45.5-28.3)/(2×=0.012979)
=17.2/0.025958
=662.6s
Hence, time elapses (s) while the airplane covers those 40500 m. Is =662.6s
Bill and Janet are pulling on opposite sides of a table. Bill pulls with a force of 250 N to the left, and Janet pulls with a force of 325 N to the right. What is the net force on the table?
Answer: 75 N to the right
Explanation:
When two forces acting in opposite directions, they will cancel in magnitudes. Here, the net force acting on the table is 75 N to the right.
What is force?Force is an external agent acting on an object to change its motion or to deform it. Force is a vector quantity. Hence, it is characterized by a magnitude and direction.
If two equal forces are acting on object from the same direction, they will add up in magnitudes and the net force is their sum. If the two forces are from opposite directions, they will cancel each other in magnitude and the net force will be the substracted value.
Here, Bill is pulling by 250 N to the left and Janet is pulling to the right by 325 N. The force is not balanced because they are unequal.
net force = 325 - 250 = 75 N
The larger force is to the right. Hence, the net force is 75 N to the right.
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Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.
Answer:
The current is 11 Amperes
Explanation:
Electric Current
The electric current is defined as a stream of charged particles that move through a conductive path.
The current intensity can be calculated as:
[tex]\displaystyle I=\frac{Q}{t}[/tex]
Where:
Q = Electric charge
t = Time taken by the charge to move through the conductor
The current intensity is often measured in Amperes.
The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:
[tex]\displaystyle I=\frac{55}{5}[/tex]
I = 11 Amp
The current is 11 Amperes
A block of mass, m, sits on the ground. A student pulls up on
the block with a tension, T, but the block remains in contact
with the ground. What is the normal force on the block?
Answer a
Explanation: a
If your heart is beating at 76.0 beats per minute, what is the frequency of your heart's oscillations in hertz?A) 3.98 HzB) 4560 HzC) 2.54 HzD) 1450 HzE) 1.27 Hz
Answer:
E) 1.27 Hz
Explanation:
If the heart beats 76 times in a minute, this means that the time needed for a single beat (the period of the oscillation), is just 1/76 of a minute, as follows:[tex]T = \frac{1}{76} min = 0.013 min = 0.79 sec. (1)[/tex]
The frequency of the oscillation, by definition, is just the inverse of the period T, as follows:[tex]f = \frac{1}{T} = \frac{1}{.79sec} = 1.27 Hz (2)[/tex]
The right answer is the E).The speed of sound in air is 10 times faster than the speed of a wave on a certain string. The density of the string is 0.002kg/m. The tension in the string is __________.
Answer:
The tension on the string is 2.353 N.
Explanation:
Given;
the speed of sound in air, v₀ = 343 m/s
then, the speed of sound on the string, v = 343 / 10 = 34.3 m/s
mass per unit length, m/l = μ = 0.002 kg/m
The speed of sound on the string is given as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu[/tex]
where;
T is the tension on the string
T = (34.3)²(0.002)
T = 2.353 N
Therefore, the tension on the string is 2.353 N.
A heat pump has a coefficient of performance of 3.85 and operates with a power consumption of 7020 W. How much energy does it deliver into a home during 1 h of continuous operation?
Answer:
97.3 MJ
Explanation:
The formula for the coefficient of Perfomance is given as
COE = Q/W, where
COE is the coefficient of Perfomance
Q is the heat provided
W serves as the work input.
Dividing both sides of the equation by a factor of time t, we get the coefficient of Perfomance in terms of heating power and input power, so we say
COE = P / P(i),
making heating power, P the subject of formula, we have
P = COE * P(i)
P = 3.85 * 7020 * 1 * 3600
P = 97297200 J
P = 97.3 MJ
Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster
Answer:
52.095 m/s
Motorcycle a was moving faster
Explanation:
We start by using one of the equations of motion
V = u + at
If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as
V(a) = u(a) + a(a).t
If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as
V(b) = u(b) + a(b).t
Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have
0 = u(a) - u(b) + a(a).t - a(b).t
-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have
u(b) - u(a) = [a(a) - a(b)]t
Since we have the values for acceleration and the time, we substitute so that
u(b) - u(a) = (4.55 - 18.9)3.63
u(b) - u(a) = -14.35 * 3.63
u(b) - u(a) = -52.095, or we rearrange to get
u(a) - u(b) = 52.095 m/s
A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What is the 3250 kg car’s initial velocity calculated to the nearest tenth? Record your answer in the boxes below. Be sure to use the correct place value.
Answer:
2.1 m/s
Explanation:
According to law of conservation of momentum;
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the common velocity
Given
m1 = 2150kg
m2 = 3250kg
u1 = 10.0m/s
u2 = ?
v = 5.22m/s
Substitute and get u2
2150(10) + 3250u2 = (2150+3250)5.22
21,500 + 3250u2 = 5400(5.22)
3250u2 = 28,188 - 21500
3250u2 = 6688
u2 = 6688/3250
u2 = 2.1 m/s
Hence the 3250 kg car’s initial velocity has an initial velocity of 2.1 m/s
PLEASE HELP ME ASAP!! GUYSSS!! I AM IN CLASS AND DYING! LITERALLY
Billy and Ashley live in the same time zone. Billy lives in Brazil (blue smiley face on the image below). Ashley lives in Eastern Canada (yellow smiley face on the image below).
One day, Billy and Ashley are both outside at 1:32 pm. They are talking on the phone to each other. As they talk, Billy notices the sky in Brazil getting progressively darker. Eventually, it feels like it is nighttime, because it is so dark. Billy thinks the world is coming to an end. He asks Ashley if she is experiencing the same thing in Canada. Ashley has no idea what he is talking about. “It’s perfectly bright and sunny where I am,” she says.
Ashley and Billy conclude that the world is not coming to an end. They reach out to some 7th graders to figure out what is happening. The 7th graders tell Billy that he is experiencing a solar eclipse. To help Billy and Ashley understand, create a model to show why Billy is experiencing an eclipse in Brazil, but Ashley is not experiencing the eclipse in Canada.
Your model must include:
The sun, the earth, the moon, and solar energy (clearly labeled).
How accurate your scale is.
How solar energy interacts with both the moon and with Earth.
The tilt of the moon’s orbit relative to the Earth’s orbit
Why Billy is experiencing the solar eclipse and why Ashley is not.
Answer:
sounds like a you problem
Explanation:
yeah
A 1.2-kg object moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 6.0 m/s in the opposite direction. If the object is in contact with the wall for 2.0 ms, what is the magnitude of the average force on the object by the wall?
a. 9.8 kN.
b. 8.4 kN.
c. 7.7 kN.
d. 9.1 kN.
e. 1.2 kN.
Given that,
Mass of the object, m = 1.2 kg
Initial speed of the object, u = 8 m/s
Final speed of the object, v = -6 m/s (in opposite direction)
Time, t = 2 ms
To find,
The average force on the object by the wall.
Solution,
Let F be the force. Using Newton's second law of motion,
F = ma, a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1.2\times ((-6)-8)}{2\times 10^{-3}}\\\\=8400\ N[/tex]
or
F = 8.4 N
So, the magnitude of average force in the object by the wall is 8.4 N.
Two spheres, 1.00 kg each, whose centers are 2.00 m apart, would have what gravitational force between them? A. 3.14 X 10-17 N
B. 1.67 X 10-11 N
C. 8.17 X 10-6N
D. 5.78 X 10-6 N
Answer: B
Explanation: the teacher just told us the answer
The gravitational force between the two spheres is [tex]1.67 \times 10^{-11} \ N[/tex].
The given parameters;
mass of each sphere, m = 1.00 kgdistance between their center mass, r = 2 mThe gravitational force between the two spheres is determined by applying Newton's law of universal gravitation as shown below;
[tex]F = \frac{Gm_1 m_2 }{r^2} \\\\[/tex]
where;
G is universal gravitation constant = 6.67 x 10⁻¹¹ N/m[tex]F = \frac{(6.67\times 10^{-11})\times (1\times 1)}{2^2} \\\\F = 1.67 \times 10^{-11} \ N[/tex]
Thus, the gravitational force between the two spheres is [tex]1.67 \times 10^{-11} \ N[/tex].
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How would the mass and weight of an object on the Moon compare to the mass and weight of the same object on Earth? * Mass and weight would both be less on the Moon. Mass would be the same but its weight would be less on the Moon. Mass would be less on the Moon and its weight would be the same. Mass and weight would both be the same on the Moon.
Answer:
B. Mass would be the same but its weight would be less on the Moon.
Explanation:
The mass of a body can be expressed as the quantity of matter it contains. While the weight of a body is the extent of the gravitational force impressed on the body by a massive body.
Thus, the mass of a body is constant either on the Earth or on the Moon. But the weight would be less on the Moon because the gravitational force on the Moon is far less than that on the Earth. Therefore the weight would be less on the Moon.
The appropriate option is B.
The mass will remain same on both moon and Earth, but weight will be lesser on Moon than Earth. Hence, option (B) is correct.
The prime focus to solve this problem is the mass and weight of an object. The mass of a body can be expressed as the quantity of matter it contains. While the weight of a body is the extent of the gravitational force impressed on the body by a massive body.
So, the mass of a body is constant either on the Earth or on the Moon. But the weight of an object will depend on the mass and the gravitational acceleration.
W = mg
Here, W is weight, m is mass and g is gravitational acceleration.
Weight would be less on the Moon because the gravitational force on the Moon is far less (due to lower value of g) than that on the Earth. Therefore the weight would be less on the Moon.
Thus, we can conclude that the mass will remain same on both moon and Earth, but weight will be lesser on Moon than Earth. Hence, option (B) is correct.
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If an atom contains 13 protons, then it has (2.4)a.13 electrons. b. 26 electrons. c. 13 neutrons. d.26 neutrons.
If an atom contains 13 protons, then it has 13 electrons.
*
If a rock falls for 3 seconds off of a bridge, how far will the rock fall?
-30 m
-45m
-60m
-75m
Suppose a uniform solid sphere of mass M and radius R rolls without slipping down an inclined plane starting from rest. The linear velocity of the sphere at the bottom of the incline depends on?
Answer:
None of the mass or the radius of the sphere
Explanation:
When a uniform solid sphere of any given mass, say M and any given radius, say R, rolls without slipping downwards an inclined plane that starts from rest. The linear velocity of the sphere at about the bottom of the inclined happens not to depend on either of its mass or that of the radius of its sphere.
The size, shape, and color of an object would be an example of a
O physical change
O physical property
O chemical change
chemical property
Answer:
physical change
Explanation:
its only changing things you see.
A bicycle has a momentum of 36 kg* m/s and a very!I city of 4 m/s.What is the mass of the bicycle?
p = 36 kgm/s
v = 4m/s
we know that,
p = mv
so,
[tex]m = \frac{p}{v} [/tex]
[tex]m = \frac{36}{4} [/tex]
[tex]m = 9kg[/tex]
Help me please,
A ball is thrown straight up in the air. What is the velocity and acceleration at the top of the path?
A) v 0m/s, = 0m/s/s
B) v = 0m/s, a 10m/s/s
C) v = 10m/s, a 10m/s/s
D) v = 10m/s, a = 0m/s/s
E) None of the above
Option B
Explanation:
no distance was given only the acceleration due to the fact that it went up (10m/s/s)
s0 it is
0 m/s and 10m/s/s (option B)