a car is travelig at 20.0 m/s when the driver applies the brakes and comes to a stop. if the car slows down uniformly with an acceleration of -4.20 m/s, about how far does the car travel before coming to a rest

Answers

Answer 1

Since acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then

0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x

⇒   ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m


Related Questions

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
bead collides elastically with a larger 0.60 kg bead initially at rest. After the collision the smaller
bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along
the wire in the first 5.0 s following the collision?||

Answers

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

Using a balance, determine the mass of the ball and basket of the ballistic pendulum. Fire the ballistic pendulum
and measure the maximum height the pendulum reaches. Use the conservation of energy (initial KE + initial GPE =
final KE + final GPE; KE = 12mv2; GPE = mgh) to calculate the initial speed of the pendulum after the ball has
collided with the pendulum basket. Next, use the conservation of momentum (total initial p = total final p; p = mv)
to determine the initial speed of the ball before it collided with the pendulum basket.
=
=

Answers

The conservation of energy and moment allows to find the results for the velocity of the pendulum and the bullet in the system are:

The velocity of the pendulum (bullet + basket) is: v₀ = 1.98 m  The speed of the bullet, depending on the mass are:

          m (kg)    v (m / s)

            0.05      41.58

            0.10       21.78

            0.15       15.18

            0.20      11.88

           0.25       9.90

The conservation of mechanical energy is one of the most important principles of physics, it establishes that if there is no friction force, the energy is constant at all points. Mechanical energy is the sum of the kinetic energy plus the potential energies.

In the attachment we can see a diagram of the system, let's start by finding the speed of the pendulum when it leaves, for this we use the  conservation of energy.

Starting point. In the lowest part of the movement.

      Em₀ = K = ½ (m + M) v₀²

Final point. At the top of the movement.

      Em_f = U = (m + M) g y

Energy is conserved because there is no friction.

      Em₀ = Em_f

      ½ (m + M) v₀² = (m + M) g y

      [tex]v_o = \sqrt{2gy}[/tex]  

They indicate a table with several measurements of the masses and the period, let's use the relationship of the simple harmonic motion.

        y = y₀ cos wt

The period and the angular velocity are related.

        w = 2π / T

       

we substitute

          y = y₀ cos ( [tex]2 \pi \frac{t}{T}[/tex] )

Let's analyze how long it takes to reach the point of maximum height, the period is the time of a complete oscillation, therefore from the lowest point to the highest point we have ¼ of oscillation, consequently the time to the highest point.

        t = T / 4

        y = y₀ cos ( [tex]2 \pi 4[/tex])  

        y = y₀

Therefore the point of maximum amplitude coincides with the maximum height and must be average by the student, suppose that the height is

          y₀ = 20 cm = 0.20 m

Let's calculate the initial velocity.

     v₀ = [tex]\sqrt{2 \ 9.8 \ 0.20 }[/tex]  

     v₀ = 1.98 m / s

They ask for the speed of the bullet before striking the basket of mass

       M = 1 Kg.

The conservation of the momentum that for an isolated system the momentum is constant in all the instants. Let's form the system by the bullet and the basket.

Initial instant. Before the crash

       p₀ = m v

Final moment. Right after the crash.

      P_f = (m + M) v₀

 

The momentum is conserved because the system is isolated.

      p₀ = p_f

      m v = (m + M) v₀

      v = m + M / m v₀

they have tabulated various mass for the bullet, we calculate the speed of each bullet.

m = 0.05 kg

    v = [tex]\frac{0.05+1}{0.05} \ 1.98[/tex]  

    v = 41.58 m / s

m = 0.10 kg

     v = [tex]\frac{0.10+1}{0.10} \ 1.98[/tex]  

     v = 21.78 m / s

m = 0.15 kg

     v = [tex]\frac{0.15+1}{0.15y}[/tex]  

     v = 15.18 m / s

m = 0.20 kg

     v = 11.88 m / s

m = 0.25 kg

     v = 9.9 m / s

In conclusion with the conservation of energy and the momentum we can find the results for the speed of the pendulum and the bullet in the system are:

The velocity of the pendulum (bullet + basket) is: v₀ = 1.98 m  The speed of the bullet, depending on the mass are:

          m (kg)    v (m / s)

            0.05      41.58

            0.10       21.78

            0.15       15.18

            0.20      11.88

           0.25       9.90

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A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?​

Answers

By using Lami's theorem, Mass m = 1.75 kg approximately

Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.

By using Lami's theorem, we can get how much mass is hanging from the rope.

Let the angle between the rope = α = 180 - 40

α = 140 degrees

The angle between one of the rope and mass = β = 20 + 90

β = 110 degrees

The angle between the mass and the other rope = γ = 360 - (140 + 110)

γ = 360 - 250

γ = 110 degrees

W/ sinα = T/ sinβ = T/sinγ

W/ sinα = T/ sinβ

Substitute all the necessary parameters

W/sin140 = 25/sin 110

W / 0.643 = 25 / 0.939

W = 17.1 N

Weight W = mg

17.1 = 9.8m

mass m = 17.1/9.8

Mass m = 1.7455 kg

Mass m = 1.75 kg approximately

Therefore, 1.75 kg mass is hanging from the rope.

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A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration

Answers

50x6=300 this is the answer I think

The acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].

We know that acceleration is the change in velocity divided by the change in time. In this case, the bicycle is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.

We can use the following equation to find the acceleration:

a = (v2 - v1) / t

where:

a is the acceleration

v2 is the final velocity (6 m/s)

v1 is the initial velocity (0 m/s)

t is the time

Plugging in the values from the problem, we get:

a = (6 m/s - 0 m/s) / 50 s

= 0.12 m/[tex]s^{2}[/tex].

Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].

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Assertion: In domestic electric circuits, the metallic body is connected to the earth wire, which
provides a low-resistance conducting path for the current.

Reason: It ensures that any leakage of current to the metallic body of the appliance keeps its

potential to that of the earth, and the user may not get a severe electric shock. pls fast

Answers

Answer:

The answare is it ensures that any leakage of current to the metallic body of the appliance keeps its potential to that of the earth, and the user may not get a severe electric shock.

Explain briefly about viscous force ​

Answers

The viscous force ​refers to the resistance of a fluid to flow.  It is measured in Newton-second per square meter.

The viscous force can be defined as the resistance that a fluid has to flow in a given space.

Viscous force is proportional to the fluid velocity, while this constant is called viscosity.

The viscous force can be measured in Newton-second per square meter (abbreviated as N s/m2).

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1. A student adds water and sugar to a jar and seals the jar so that nothing can get in or out. The
student then finds the mass of the jar containing the water and sugar. After some sugar dissolves, the
student finds the mass of the jar and its contents again.
Water
Sugar
and
Water
Sugar
Sugar
Before
After
Vhat will happen to the mass of the jar containing the water and sugar after some of the sugar
issolves?
a. The mass will stay the same
b. The mass will increase
c. The mass will decrease
The moon will donend on how much sunar dissolves

Answers

Answer:

The mass will stay the same throughout time

how many bears are witching the category of the

Answers

Polar Bear. A Grizzly Bear. ... Panda Bear. ... Sun Bear. ... Andean Bear. ... North American Black Bear. ... Short-Faced Bear. ... Asiatic Black Bear.

The parking brake on a 1200kg automobile has broken, and the vehicle has reached a momentum of 7800kg.m/s. What is the velocity of the vehicle?

Answers

Answer:

Velocity of the vehicle (v) = 6.5 m/s

Explanation:

Mass of automobile (m) = 1200 kg

Momentum of vehicle (p) = 7800 kg m/s

By using formula of momentum:

[tex] \rm p = mv \\ \rm 7800 = 1200 \times v \\ \rm v = \frac{7800}{1200} \\ \rm v = 6.5 \: m {s}^{ - 1} [/tex]

Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s

Answers

Answer:

The car that is hald as massive

Explanation:

We can use the eqation for kinetic energy to solve this problem

KE = 1/2mv^2 (where m is mass and v is velocity/speed)

Lets give the original car a mass of 100kg and use the equation

KE = 1/2(100kg)(16m/s)^2 = 12800J

and now lets find kinetic energy of the half as massive car

KE2 = 1/2(50kg)(32m/s)^2 = 25600J

From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity

What’s 5.1 cm in Newton’s?

Answers

0.051 newton meter.

A block of mass M is attached to a spring of negligible mass and can slide on a horizontal surface along the x-direction, as shown above. There is friction present between the block and the surface. The spring exerts no force on the block when the center of the block is located at x=0. At the instant shown above, the block is located at x=0 and moving toward the right with speed v=v0. (a) For the instant shown above, with the block located at x=0 and moving to the right, predict the direction of the net force on the block. If the net force is zero, select “The net force is zero.”

_ To the left _ The net force is zero _ To the right
Briefly justify your prediction.

Answers

Answer:

Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point

The diagram shows a nephron.

A nephron. W points to branch of renal artery. X points to branch of renal vein. Y points to tubular point of nephron. Z points to collecting duct.

Where is the blood first filtered?

Answers

Answer:

w

Explanation:

renal artery...the blood flow into the kidney via this blood vassles

and the filtration take place is called ultrafiltration

Why is saving important to the economy.......and to you?

Answers

Answer: Saving is important to the economic progress of a country because of its relation to investment. If there is to be an increase in productive wealth, some individuals must be willing to abstain from consuming their entire income.

Explanation:

Savings is important to the economy because it enables growth and development of a nation.

Importance of savings

The importance of savings to the economy in general can not be over emphasized.

The following are some importance of savings to the economy;

Growth in the economy: when people save money the economy grows.Development: The increase in the economy due to savings can help in the development of a nation.

Thus, savings is important to the economy because it enables growth and development of a nation.

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if you immerse an object into a known mass of water, the measured mass of the water will _____, and will be equal to the mass of the water displaced by the immersed object.

Answers

Answer: decrease

Explanation: it does

Which statement best explains why a wet saw used to cut through a fine optical crystals is constantly lubricated with oil

Answers

The major reason why a wet saw that is used in cutting optical crystals is constantly lubricated with oil is largely due to friction, lubrication decreases friction and minimises the increase of internal energy.

Friction is basically the coming together of two parts that rubs against each other, it causes heat and lead to  deterioration of surfaces, it can also lead to wear and tear.

Although, despite it down side, friction is desire-able in most applications

e.g the brake system of vehicles, and if not for friction, we humans cannot walk without falling

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which distance indicator can be used to measure the most distant objects?

Answers

The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae

In the field of Astronomy, there are different kind of distance indicators that can be used to measure the distance objects.

Few among them are :

Cepheids Type Ia supernovae Parallax Main-sequence fitting

Cepheid variables can be measured up to 18 million light years.

The expansion rate of the universe can also be measured by trying to measure the apparent brightness of the Type Ia supernovae

Parallax means illusory state of an object when viewed from different points

Main sequence fitting makes use of a H-R diagram of the cluster to determine the distance to a stellar cluster.

The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae

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A dart is thrown at a target that is supported by a wooden backstop. It strikes the backstop with an initial velocity of 350 m/s [E] The dart comes to rest in 0.0050 s.

a. What is the acceleration of the dart?
b. How far does the dart penetrate into the backstop?​

Answers

Answer:u=350m/sec

v=0m/sec

t=0.005sec

a=v-u/t

=0-350/0.005

= -350/0.005

= -350×1000/5

= -70×1000

= -70000 m/sec^2

Explanation: i think this will help you thankyou

Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help
guide the content of your paragraph.
1. According to your data, was your hypothesis for each experiment correct? (Be sure to refer to your data and graphs
when answering this question.)
2. Summarize the conclusions that you can draw from this experiment. Use the questions above to gulde your ideas.
3. Summarize any difficulties or problems you had in performing the experiment that might have affected the results.
Describe how you might change the procedure to avoid these problems.
4. Give at least one more example from real life where the principles demonstrated in this lab are evident.

Answers

Answer:

Sample answer: part 1:

What was your hypothesis?

This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:

"The viscosity of honey decreases as temperature increases".

According to your data, do you think your hypothesis was correct?

Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.

The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.

Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:

"one problem was that the temperature of the honey increased too fast"

And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.

part 2:

Viscosity depends strongly on temperature, but this relation depends also on the given material.

Generally, we would see that the viscosity decays exponentially as the temperature increases.

So for the first question:

What effect did the temperature have on the viscosity of the honey?

You should have seen that, as the temperature increased, the viscosity decreased.

Now, we need to give some practical examples where knowledge of viscosity is important.

The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.

Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.

So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.

Explanation:

The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the
wavelength? If the frequency is 200. Hz, what is the speed of the wave?

Answers

Answer:

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

Distance between adjacent antipodes is 20 cm

We know that distance between two adjacent anti nodes is equal to half of the wavelength

So \frac{\lambda }{2}=20cm

2

λ

=20cm

\lambda =40cmλ=40cm

We have to find the speed of the wave in the string

Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec

So speed of the wave in the string will be 3.2 m/sec

An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?

Answers

Answer:

I = 250N*s

Explanation:

I = F*t

I =  impulse or momentum

F = Force

t = time

I = 25N*10s

I = 250N*s

NEES HELP!!!!
Which of the following is "NOT" a theory of the formation of the universe?
A. Steady State Theory
B. Doppler Theory
C. Oscillating Theory
D. Big Bang Theory

Answers

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

which term is equal to velocity change per second?

Answers

Answer:

Acceleration  is measured in meters per second squared (m/s²) change in velocity is measured in meters per second (m/s) time taken

For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?

Answers

Answer:2 reactants 2 products.

this is a balanced chemical equation. That means the number of chlorine before the arrow will be the same after the arrow

Explanation: i think this answer will help you very much

Can you see people on puppies not to do stairs exercise when it is very hot and humid what is the reason for this warning Ate it makes muscles Louis loser in Punta do you speak it can you spell ate the whole way too unhealthy levels see it needs to be cool outside for exercise to be effective date it is really uncomfortable to exercise when it is really hot

Answers

Answer:

Exercising is not only good for their physical and mental health, but also helps them to socialise with other dogs and puppies, which is crucial to their ...

Explanation:

Two Magnets are placed near each other on the space station orbiting earth. The south poles are facing each other which statement explains what what happen to the magnets.


A. They will be repelled because they are in each others magnetic field


B. They will be attracted because they’re magnetic fields will add together


C. They will not move because they are not in earths gravitational field.


D. They will not move because they do not have electric fields.

Answers

Explanation: A) They will be repelled because they are in each others magnetic field

The change in the momentum of an object is represented by the following formula:
Impulse = (Force)(time) = change in momentum
I = F • t = pfinal – pinitial
A 1.0 kg rabbit traveling east at 10 m/s spots a predator, turns around, and then begins to travel west at 21 m/s.
What is the change in momentum of the rabbit, and what is another term for this concept?

The rabbits change of momentum is

A. 31 kg•m/s east

B. 31 kg•m/s west

C. 15.5 kg•m/s, west

D. 15.5 kg•m/s, east

This value can also be referred to as

E. Collisions

F. Potential energy

G. Kinetic energy

H. Impulse

Please help will mark brainliest

Answers

Hi there!

Recall that:

Change in momentum = mass × change in velocity

Or:

Δp = mΔv = m(vf - vi)

Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).

Thus:

Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.

The correct answer is B.

Change in momentum is EQUIVALENT to the quantity of IMPULSE.

The correct answer is H.

What is the relationship between transit duration and orbital period?

Answers

Answer:

The length of time between each transit is the planet's "orbital period", or the length of a year on that particular planet. Not all planets have years as long as a year on the Earth! Some planets discovered by Kepler orbit around their stars so quickly that their years only last about four hours!

I hope it helps.

Answer:

lenght of year po

Explanation:

hope it helps

Simplicity of conducting the study is to ________ as ability to test large numbers of participants is to ________.

Answers

Simplicity of conducting the study is to archival research; as ability to test large numbers participants is to survey.

Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.

What is Archival research?

Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.

Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.

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A machine does 2500 J of work in 1 min. What is the power developed by the machine?

Answers

Answer:

41.7 watts

Explanation:

power=work done/time

2500/60seconds

=41.6666

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