a car completes a 200km journey at an average speed of xkm/h. the car completes the return journey of 200 km at an average speed of (x+10)km/h. show that the difference of the time taken for each of the two journeys is 2000/x(x+10) hours​

Answers

Answer 1

Answer:

The difference of the time taken for each of the two journeys is given as follows;

The difference of time = 2000/(x·(x + 10))

Step-by-step explanation:

The speed with which the car completes the 200 km journey = x km/h

The speed with which the car completes the return journey = (x + 10) km/h

Let t₁ represent the time it takes the car to complete the 200 km and let t₂ represent the time it takes the car to complete the return journey, we have;

t₁ = 200/(x)

t₂ = 200/(x + 10)

The difference of the time taken for each of the two journeys = t₁ - t₂

We have;

t₁ - t₂ = 200/(x) - 200/(x + 10)

200/(x) - 200/(x + 10)  = (200·(x + 10) - 200·x)/((x)·(x + 10)) = 2000/((x)·(x + 10))

∴ t₁ - t₂ = 2000/((x)·(x + 10)) = 2000/(x·(x + 10))

The difference of the time taken for each of the two journeys = t₁ - t₂ = 2000/(x·(x + 10))


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