Answer:
the correct one is b, Decrease the launch speed and Low the launch height
Explanation:
Let's find the solution to the problem in order to answer the questions.
The bullet is fired horizontally with a velocity vo, let's find the time or it takes to reach the ground
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
as it shoots horizontally v_{oy} = 0 and when I reach the floor y = 0
0 = y₀ - ½ g t2
t = [tex]\sqrt{\frac{2y_{o} }{g} }[/tex]
where y₀ is the height of the cliff
at this time the bullet recreates a distance of
x = v₀ t
we substitute
x = v₀ \sqrt{\frac{2y_{o} }{g} }
There, to reduce the range of the bullet, we must decrease its speed. This is the magnitude that most affects the distance and to a lesser degree we can decrease the height.
When checking the answers, the correct one is b
A coil with 25 turns of wire is moving in a uniform magnetic field of 1.5 T. The magnetic field is perpendicular to the plane of the coil. The coil has a crosssectional area of 0.80 m2
. The coil exits the field in 1.0 s.
Find the induced emf.
Given that,
Number of turns, N = 25
Magnetic field, B = 1.5 T
The coil has a crosssectional area of 0.80 m2
The coil exits the field in 1.0 s.
To find,
Induced emf in the coil.
Solution,
The induced emf in the coil is given by :
[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{dB}{dt}\\\\=\dfrac{NBA}{t}\\\\=\dfrac{25\times 1.5\times 0.8}{1}\\\\=30\ V[/tex]
So, the induced emf in the coil is 30 V.
Identify the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles.
A. Direct linear
B. Inverse
C. Quadratic
D. Inverse square
Answer:
D. Inverse square
Explanation:
According to the information you are giving me, you must be referring to Coulomb's law because the electrostatic force in proportion to the displacement of charged particles is [tex] F =\frac{kq_{1}q_{2}}{r²} [/tex].
As you can see, there is a reason as to why this is also referred to as Coulomb's inverse square law because the r² represents the displacement or distance relative to the position of the particles which is squared, and it is inverse because the force and the product of the distance squared is equal to the product of the two charges particles multiplied by coulomb's constant (k) which is approximately 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻².
The mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.
What is electrostatic force?The electrostatic force is an attractive and repulsive force caused by the electric charges of particles. The electrostatic force is the electric force that exists between two stationary charged bodies. It is also known as Coulomb's force.
Hence, electrostatic force inversely proportional to the distance between two charges. If two charges Q and q are separated by a distance r, the magnitude of electrostatic force between them is given by:
F = kQq/r²
So, the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.
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Revolution + tilt = what
A brick of gold is 0.1 m wide, 0.1 m high, and 0.2 m long. The density of gold is 19,300 kg/m3. What pressure does the brick exert on the table if the brick is resting on its side?
Answer:
The pressure exerted by the brick on the table is 18,933.3 N/m².
Explanation:
Given;
height of the brick, h = 0.1 m
density of the brick, ρ = 19,300 kg/m³
acceleration due to gravity, g = 9.81 m/s²
The pressure exerted by the brick on the table is calculated as;
P = ρgh
P = (19,300)(9.81)(0.1)
P = 18,933.3 N/m²
Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².
An object travels in a circular path at speed vand experiences a centripetal acceleration ac. What will be the object's new centripetal
acceleration, if its speed is increased to 2.0V?
Answer:
Option B. 4a꜀
Explanation:
From the question given above, the following data were obtained:
Initial speed (v₁) = v
Initial acceleration (a₁) = a꜀
New speed (v₂) = 2v
New acceleration (a₂) =?
Centripetal acceleration is given by the following equation:
a = v²/ r
Next, we shall make r the subject.
a = v²/ r
Cross multiply
a × r = v²
Divide both side by a
r = v² / a
NOTE: We assume the radius (r) to be constant.
v₁² / a₁ = v₂² / a₂
Thus, we shall determine the new acceleration as follow:
Initial speed (v₁) = v
Initial acceleration (a₁) = a꜀
New speed (v₂) = 2v
New acceleration (a₂) =?
v₁² / a₁ = v₂² / a₂
v² / a꜀ = (2v)² / a₂
v² / a꜀ = 4v² / a₂
Cross multiply
v² × a₂ = a꜀ × 4v²
Divide both side by v²
a₂ = a꜀ × 4v² / v²
a₂ = a꜀ × 4
a₂ = 4a꜀
Therefore, the new centripetal acceleration of the object is 4a꜀
Answer:
4.0 · ac
Explanation:
Just did it
Describe how electric potential energy, kinetic energy, and work change when two charges of opposite sign are placed near each other.
Answer:
As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.
Explanation:
1. To get to school, a girl walks 1 km North in 15 minutes. She
then walks 200 m South-west in 160 seconds.
What is the girl's average velocity for her walk to school?
The girl's average velocity is 1.13 m/s
The formula used to determine average velocity is:
Velocity = distance/ timeV = D/tThis means to determine the girl's average velocity is necessary to find out the total distance and the total time.
Distance:
1 km north and 200 m SouthwestAs you can see there are two different distances and they are in different units (meters vs kilometers), let's convert the kilometers to meters so both distances are in the same unit.
1 x 1000 = 1000 (1 km = 1000 meters)Add the two distances:
1000 meters + 200 meters = 1200 meters
Time
15 minutes and 160 seconds
Let's convert the minutes into seconds:
15 x 60 = 900
Add the time:
900 + 160 = 1060
Finally, calculate the average velocity:
1200 meters / 1060 seconds = 1.13 meters per secondLearn more about velocity in: https://brainly.com/question/862972
A system consists of two particles. Particle 1 with mass 2.0 k g 2.0kg is located at ( 2.0 m , 6.0 m ) (2.0m,6.0m) and has a velocity of ( 3.1 m / s , 2.6 m / s ) (3.1m/s,2.6m/s). Particle 2 with mass 4.5 k g 4.5kg is located at ( 4.0 m , 1.0 m ) (4.0m,1.0m) and has a velocity of ( 1.1 m / s , 0.6 m / s ) (1.1m/s,0.6m/s). Determine the position and the velocity of the center of mass of the system.
Answer:
[tex]Position:(3.38m ,2.53m)[/tex]
[tex]Velocity=(1.72m/s,1.22m/s)[/tex]
Explanation:
From the question we are told that
Mass of particle 1
[tex]M_1=2.0kg[/tex]
Co-ordinate of particle 1 (2.0m,6.0m)
Velocity of Particle 1
[tex]V_1= (3.1 m / s , 2.6 m / s )[/tex]
Mass of particle 2
[tex]M_2=4.5kg[/tex]
Co-ordinate of particle 2 (4.0m,1.0m)
Velocity of Particle 1
[tex]V_2=( 1.1 m / s , 0.6 m / s )[/tex]
Generally the Position is mathematically given as
[tex]X =\frac{ ((M_1 * Cx_1) + (M_2 *Cx_2)}{(M_1 + M_2)}[/tex]
[tex]X=\frac{2*2+4.5*4}{2+4.5}[/tex]
[tex]X=3.38[/tex]
[tex]Y=\frac{(M_1* Cy_1 + M_2* Cy_2)}{(M_1 + M_2)}[/tex]
[tex]Y =\frac{(2 * 6 + 4.5 * 1)}{(2 + 4.5)}[/tex]
[tex]Y= 2.53 m[/tex]
Therefore the position is given as
[tex]Position:(3.38m ,2.53m)[/tex]
Solving for Velocity
Generally the velocity of the system is mathematically Given as
[tex]V_x =\frac{ (M_1 * vx_1 + M_2 * Vx_2)}{(M_1 + M_2)}[/tex]
[tex]V_x=\frac{ (2 * 3.1 + 4.5 *1.1)}{(2 + 4.5)}[/tex]
[tex]V_x=1.72m/s[/tex]
For Y
[tex]V_y =\frac{(M_1* vy_1 + M_2* Vy_2)}{(M_1 + M_2)}[/tex]
[tex]V_y=\frac{ (2 * 2.6) + (4.5*0.6)}{(2 + 4.5)}[/tex]
[tex]V_y=1.22m/s[/tex]
Therefore Velocity
[tex]V=(1.72m/s,1.22m/s)[/tex]
A steel cable of diameter 3.0 cm supports a load of 2.0kN. What is the fractional length increase of the cable compared with the length when there is no load if Y=2.0 x 10^11 Pa?
Answer:
1.429*10^-5 m
Explanation:
From the question, we are given that
Diameter of the cable, d = 3 cm = 0.03 m
Force on the cable, F = 2 kN
Young Modulus, Y = 2*10^11 Pa
Area of the cable = πd²/4 = (3.142 * 0.03²) / 4 = 0.0028 / 4 = 0.0007 m²
The fractional length = Δl/l
Δl/l = F/AY
Δl/l = 2000 / 0.0007 * 2*10^11
Δl/l = 2000 / 1.4*10^8
Δl/l = 1.429*10^-5 m
Therefore, the fractional length is 1.429*10^-5 m long
Example
A 1.8 m tallman stand in an elevator accelerating upward at 12 m/s?,
what is the blood pressure in the brain and foot.
Take the height difference between the heart and the brain to be
0.35 m?
13.3 x 103 Pa] & [Pblood = 1060 kg.m-3]
Note: [: P Heart
Answer:
Explanation:
From the given information; the diagram below shows a clearer understanding.
The blood pressure in the brain [tex]P_{brain} = P_{heart} - \delta ( a - g ) h[/tex]
= 13300 - 1060 (12-9.81) 0.35
= 13300 - 1060 (2.19) 0.35
= 13300 - 812.49
= 12487.51 Pa
The blood pressure in the feet [tex]P_{feet} = P_{heart} + \delta (a + g) h[/tex]
= 13300 + 1060 (12 + 9.81) 1.45
= 13300 + 1060( 21.81 ) 1.45
= 13300 + 33521.97
= 46821.97 Pa
Answer:
The blood pressure in the brain = [tex]12487.51 pa[/tex]The blood pressure in the feet = [tex]46821.97pa[/tex]Explanation:
[tex]P_brain = P_heart - y(a - g)h\\\\P_brain = 13300 - 1060 (12-9.81)0.35\\\\P_brain = 12487.51 pa\\\\[/tex]
[tex]P_feet = P_heart + y(a+g)*h_r\\\\P_feet = 13300 + 1060(12+9.81)*(1.8-0.35)\\\\P_feet = 46821.97pa[/tex]
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A 0.290 kg block on a vertical spring with a spring constant of 5.00 ✕ 103 N/m is pushed downward, compressing the spring 0.110 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above the point of release?
___m
Answer:
The height at point of release is 10.20 m
Explanation:
Given:
Spring constant : K= 5 x 10 to the 3rd power n/m
compression x = 0.10 m
Mass of block m= 0.250 kg
Here spring potential energy converted into potential energy,
mgh = 1/2 kx to the 2 power
For finding at what height it rise,
0.250 x 9.8 x h = 1/2 x 5 x 10 to the 3 power x (0.10)to the 2 power) - ( g= 9.8 m/8 to the 2 power
h= 10.20
Therefore, the height at point of release is 10.20 m
what is the average gravitational force of attraction between the earth and the sun? the earth averages a distance of about 150 million km. the earth has a mass of 5.97x10^24 kg, and the sun has a mass of about 2x10^30 kg.
Answer:
B
Explanation:
Hhhhh
A circus performer walked up and to the right for a total displacement of 10\,\text m10m10, start text, m, end text along a diagonal tightrope angled 30 \degree30°30, degree above the ground.
What was the vertical displacement of the circus performer in \text mmstart text, m, end text?
Answer:
5m
Explanation:
khan academy
Vertical displacement of the circus performer is 5 m.
What is Displacement?Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.
A circus performer walked up and to the right for a total displacement of 10 m, start to end along a diagonal tightrope angled 30° degree above the ground.
Vertical displacement = 10 sin 30° = 5 m
Vertical displacement of the circus performer is 5 m.
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Assume that it takes an average of 3 man-hours to stack 1 ton of a particular item. In order to stack 36 tons in 6 hours, the number of people required is:______.
A) 9
B) 12
C) 15
D) 18
E) 21
Answer:
option (d)
Explanation:
Given,
1 ton of a particular item can be stack in= 3 man-hours
36 ton of a particular item can be stack in= 36 x 3 man-hours
= 108man- hours
Number of hours = 6 hours
Number of people = [tex]\frac{108 \text{man-hours}}{6}[/tex]
= 18
Hence, the number of people required is 18.
Therefore, option (d) is correct.
A guitar player can change the frequency of a string by "bending" it-pushing it along a fret that is perpendicular to its length. This stretches the string, increasing its tension and its frequency. The B string on a guitar is 64 cm long and has a tension of 74 N. The guitarist pushes this string down against a fret located at the center of the string, which gives it a frequency of 494 Hz. He then bends the string, pushing with a force of 4.0 N so that it moves 8.0 mm along the fret.
* What is the new frequency?
Answer:
[tex]f'=504hz[/tex]
Explanation:
From the question we are told that
The B string on a guitar is 64 cm long
The B string tension tension of 74 N.
Frequency of 494 Hz
Pushed with a Force of 4.0 N
It moves 8.0 mm along the fret.
Generally the equation for frequency of ring under tension is mathematically given as
[tex]2Lf=\sqrt{x\frac{T}{\mu} }[/tex]
[tex]2*(64/100)*494=\sqrt{\frac{74}{m/0.64}[/tex]
[tex](632.32)^2={\frac{74}{m/0.64}[/tex]
[tex](632.32)^2=74*{\frac{0.64}{m}[/tex]
[tex](632.32)^2={\frac{47.36}{m}[/tex]
[tex]m=1.18450761*10^-^4[/tex]
Therefore finding the New frequency f'
[tex]f'=\frac{(\sqrt{\frac{74+11}{(\frac{1.18450761*10^-^4}{0.642})}})}{2*0.642}[/tex]
[tex]f'=\frac{(\sqrt{(\frac{74+11}{1})*(\frac{0.642}{1.18450761*10^-^4}})}{2*0.642}[/tex]
[tex]f'=\frac{(\sqrt{(\frac{85}{1})*(\frac{0.642}{1.18450761*10^-^4}})}{2*0.642}[/tex]
[tex]f'=\frac{(\sqrt{(\frac{54.57}{1.18450761*10^-^4}})}{2*0.642}[/tex]
[tex]f'=\frac{678.7471973}{2*0.642}[/tex]
[tex]f'=572.9111096hz[/tex]
Why are stars considered to be the building blocks of the universe?
A. Stars are found throughout the galaxy
B. Stars become novas, supernovas, and Black Holes
C. Nuclear fusion within stars creates needed elements for he universe
D. The sun is a star
The x-axis of a position-time graph represents
Answer:
The y-axis represents position relative to the starting point, and the x-axis represents time.
Explanation:
A tired squirrel (mass of approximately 1 kg) does push-ups by applying a force to elevate its center-of-mass by 5 cm in order to do a mere 0.50 Joule of work. If the tired squirrel does all this work in 2 seconds, then determine its power.
Answer:
Power = 0.25 Watts
Explanation:
Given:
Work done = 0.50 Joule of work
Time taken = 2.0 second
Find:
Power
Computation:
Power = Work done / Time taken
Power = 0.50 J / 2
Power = 0.25 Watts
If the tired squirrel does all this work in 2 seconds with work of 0.5 J the power is 0.25 Watts.
Given:
Mass, m = 1 kg
Work, W = 0.5 J
Time, t = 2 s
The concept of power, which measures the pace at which work is done or the rate at which energy is transmitted or converted, is crucial to physics. It measures how quickly energy is produced or utilized in a system, to put it simply. In the International System of Units (SI), power is a scalar quantity and is measured in watts (W).
The power is given by:
Power = Work ÷ Time
P = 0.50 Joules ÷ 2 seconds
P = 0.25 Watts
Hence, the power exerted by the tired squirrel is 0.25 Watts.
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pls help, i have no idea where to start
Answer:
Use equation 1/2 * m * v²
Explanation:
where m = mass in kg
and v = velocity in m/s
plug accordingly.
Which of the following remains constant during the motion of a projectile fired from a planet?
A. Momentum
B. Kinetic energy
C. Horizontal component of velocity
D. Vertical component of velocity
Answer:
C. Horizontal component of velocity
Explanation:
Object in motion stays in motion,
nothing works against its motion in the horizontal direction, unlike in the vertical direction, gravity pulls object down.
When the torques on the wheel and axle equal zero, the machine has
_____
Answer:
8
Explanation:
Answer:
rotational equilibrium
Explanation:
The first stage of a space vehicle consumed fuel and oxidizer at the rate of 1.75 x 104 kg/s, with an exhaust speed of 2.40 x 103 m/s. Find the acceleration (in m/s2) of the vehicle just as it lifted off the launch pad on the Earth, if the vehicle's initial mass was 3.00 x 106 kg. (Note: You must include the force of gravity to solve the problem.)
Answer:
[tex]a=4.19 m/s^{2}[/tex]
Explanation:
In order to solve this problem, we must first draw a free body diagram of the situation. (See attached picture)
from this diagram, we can do the following sum of forces:
[tex]\sum F=ma[/tex]
where m is the mass of the rocket and a is its acceleration.
[tex]F_{e}-mg=ma[/tex]
where [tex]F_{e}[/tex] is the force of exhaust. We can solve this for the acceleration, so we get:
[tex]a=\frac{F_{e}-mg}{m}[/tex]
we can find the force of exhaust by using the momentum formula:
Ft=mv
so we can solve this for the force:
[tex]F_{e}=\frac{mv}{t}[/tex]
the problem already tells us what m/t is equal to, so we can directly substitute:
[tex]F_{e}=(1.75x10^{4}kg/s)(2.40x10^3m/s)[/tex]
which yields:
[tex]F_{e}=42x10^6 N[/tex]
So we can now substitute:
[tex]a=\frac{42x10^6N-(3x10^6kg)(9.81m/s^{2})}{3x10^6kg}[/tex]
so:
[tex]a=4.19 m/s^{2}[/tex]
how does a switch work in a circuit
An electric switch is a device that interrupts the electron flow in a circuit. Switches are primarily binary devices: either fully on or off and light switches have a simple design. When the switch is turned off, the circuit breaks and the power flow is interrupted. Circuits consist of a source of power and load.
8 th Grade Physical Science Worksheet Part A: Read the scenario and answer the questions. David read that Fox brake pads and Best Brake pads were the best on the market. He always used NAPA pads and believed they performed the best. He decided to test all three pads and determine which was the best. David used the same car for each set of pads. He drove 25 mph and applied the brakes at the same point on the track. David then measured how many feet the car took to stop after the brakes were applied. 1. The hypothesis was: 2. The effects of the ________________(independent variable) on the __________________________________ (dependent variable). 3. List three constants:
how are all the spheres similar
6. Calculate the total resistance in a series circuit with a fan (3 ohms) and 3 lights (1 ohms each).
15 ohms
6 ohms
12 ohms
9 ohms
PLS HURRY ILL MARK BRAINLYEST
Answer:
R_eq = 6 Ω
Explanation:
In a series circuit the current is constant throughout the circuit and the resistance is the sum of all the resistances in it.
R_eq = ∑ [tex]R_{i}[/tex]
in this case we have
R_eq = R₁1 + 3 R₂
where R₁ is the resistance of the fan and R₂ the resistance of each light, we must clarify that we will assume that the resistance of the lights does not change with temperature
let's calculate
R_eq = 3 + 3 1
R_eq = 6 Ω
Answer:
The awnser is 6 ohms.
Explanation:
what is the name of first magnet
Answer:
[tex]magnetite[/tex]
[tex]hope \: helps...[/tex]
Unit Test
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TIME REMAININO
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Which best describes the energy of a sound wave as it travels through a medium?
It increases
It decreases
It remains the same
It depends on the medium
Answer:
It depends on the medium is answer.
Explanation:
I hope it's helpful!
The energy of sound waves depends on the nature of medium it travels through. As the speed of the wave increases in the medium its energy increases. Hence, option d is correct.
What are sound waves ?Sound waves are type of mechanical waves passing through a medium. Sound waves are longitudinal waves hence, the oscillation of particles is in the same direction of of the wave propagation.
The energy of a wave is directly proportional to the frequency of the wave and inversely proportional to the wavelength. As the density of the medium increases, the speed of the wave decreases and thereby energy too.
Sound waves travels with higher speed through solids. As their energy increases, the waves moves with higher speed. Hence, the energy of sound waves depends on the nature of the medium.
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Can someone please help, ty!!
(Will mark brainliest)
The density of a solid or liquid material divided by the density of water is called
Answer:
I believe the answer is specific gravity
Explanation:Hope this helps :)