A camper stands in a valley between two parallel cliff walls. He claps his hands and notices that the echo from the nearby wall returns 0.9 s later while the echo from the farther wall returns 1.10 s later. If the air temperature is -10 C, how wide is the valley?

Answers

Answer 1
5,658 ft is your answer I believe

Related Questions

What event has inspired your life so far? How has this event changed you?

Easy pts! I will give Brainliest. :)

Answers

the art event called “cant help myself” its very emotional if you understand it :)

How long will it take to travel 150km at an average speed of 40 km/h

Answers

Answer:

6,000 minutes

Explanation:

To calculate distance u multiply speed and time or speed and rate

what is light ....
Drop some thanks..​

Answers

Answer:

Light is a form of a energy which a human eye makes the things visible

Explanation:

I hope it's help u

A person makes a loud sound and hears the echo of this sound 1.2s later .calculate how far the person is from the object causing the echo assume that the speed of sound is 330m/s calculate the distane

Answers

Answer:

198m

Explanation:

Distance = speed x time

. d = 330m/s x 1.2s = 396m

This is the distance travelled by the sound from the person to the object and then back to the person. To get the distance from the person to the object, we would have to divide by 2.

. distance = 396 / 2 = 198m

what is the full meaning of hip​

Answers

Answer:

History in Perspective (education) HIP. Health Information Professional. HIP.

Explanation:

hope this helps

Hi can u help me in my physics homework

Answers

Answer:

a.) [tex]5 seconds[/tex]

b.) [tex]9.5 m/s[/tex]

Explanation:

Solution is attached.

17. [06.05]
What particles are involved in nuclear reactions, but not in chemical reactions? (1 point)
Neutrons and protons
Neutrons and electrons
Protons and electrons
Electrons only

Answers

Answer:

What particles are involved in nuclear reactions, but not in chemical reactions? (1 point)

Ans Option A Neutrons and protons

Eva's pillows are really old and very flat. She is very used to them, so she thinks that they are fine. What would be a healthier option?
А. Fuller pillows that keep her neck straight
B. Stacking pillows so that her head is elevated.
C. Eliminating pillows and just sleeping on the mattress.
D. Using the pillows to get her feet higher than her head.

Answers

Answer:

I think c

Explanation:

have a good day/night/ whatever

Fuller pillows that keep her neck straight. The correct option is A.

Thus, Broader pillows that properly support her neck and head would be a better choice. Better sleeping posture and a lower incidence of neck and back pain can both be encouraged by pillows that keep the neck and spine in their natural alignment.

Flat pillows could not offer enough support, which could result in poor alignment and long-term discomfort or suffering.

Stacking pillows in Option B may provide some elevation, but it might not necessarily provide the essential neck and spine support. Option C (without using pillows) can fail to give the head and neck the necessary support and cushioning.

Thus, Fuller pillows that keep her neck straight. The correct option is A.

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Dhdjrjfbjsjfnsmctejzbrnj

Answers

The answer is D

I hope this helps :)

PLS ANSWER FAST CORRECT ANSWER WILL BE BRAINLIEST

Answers

Answer:

Current

Explanation:

People wear special snowshoes when there is a snowfall in the cold countries. Why?

Answers

Answer:

The fundamental function of snowshoes is to offer float, allowing you to avoid sinking into snow. Hikers who do not have snowshoes may find themselves knee- or waist-deep in unconsolidated snow if they attempt to traverse it without snowshoes, a practice known as post-holing.

Explanation:

Answer:

Explanation:

I live in a cold country and I own snow shoes. I have to confess I've never thought about this question before.

If the snow is fresh, it is also very loosely packed. If you wear ordinary shoes, the first thing that will happen is that you will sink. How far depends on how deep the snow is. I can see you up to your waist in snow, if the snowfall is heavy enough.

So to prevent that, my snowshoes are 3 feet long and about 1 foot wide, Except for a small hole near the middle, the entire area is covered. I weigh about 140 pounds.

A very small calculation should tell you that if I wear house shoes (mine are 8" long by about 3 inches wide). The pressure is going to be 140 pounds / (2/3 * 1/4) = 140 // 2/12 = 140 / 1/6 = 140 *  6 = 840 pounds / square foot. Trust me, that is a lot of pressure.

What do the snowshoes accomplish?

140 / (3*1) = 46.7 pounds per square foot. You might sink a little, but you are not going down as far as you would with street clothes shoes.

The units are not the normal units you would use, but the ratio is going to be roughly the same. 840 / 46.

All of this is very approximate. That's what physics is all about. Approximations lead you to understanding.

How can you find a springs constant for the F=-Kx formula?

Answers

Answer:

As per the Hooke's Law, if spring is stretched, the force exerted is proportional to the increase in length from the equilibrium length. The formula to calculate the spring constant is as follows: k= -F/x, where k is the spring constant. F is the force and x is the change in spring's length.



Use the graph of velocity versus time for an object to answer the question.

Which statement fairly compares segment 2 and segment 3?
(1 point)
O These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
These represent different periods of time, but the force acting on the object is the same during each period of time.
O These represent different periods of time, and the force during segment 2 is different than the force during segment 3.
O These represent equal periods of time, and the force acting on the object is the same during each period of time.​

Answers

The statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.

Since segment 2 starts at t = 60 s and ends at t = 150 s, the time interval is Δt = 150 - 60 = 90 s.

Also, segment 3 starts at t = 150 s and ends at t = 240 s, the time interval is Δt = 240 - 150 = 90 s.

So, their time periods are the equal.

We notice that segment 2 is less steep than segment 3 this implies that the acceleration in each segment is different, since the acceleration is the slope of the graph.

Since force is determined by acceleration, this implies that the force on segment 2 is different form the force acting in segment 3.

So, we have equal time periods but different forces.

So, the statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.

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Answer:

Segments 2 and 3 have equal periods of time but the force during segment 2 is different than the force during segment 3 !! :)

Explanation:

How much work is required for a 74 kg sprinter to accelerate from rest to 2.2 m/s?

Answers

Answer:

179.1 kg

Explanation:

Answer:

Should be 179.1 kg

Explanation:

eleven wa=eighs 47 kg. her height is 1.63 m. what is her bmi

Answers

Answer:

17.7kg/[tex]m^{2}[/tex]

Explanation:

                       BMI =

                             =  [tex]\frac{weight (kg)}{height (m) . height (m)}[/tex]

                             = 47kg/(1.63m×1.63m)

                             = 17.689kg/[tex]m^{2}[/tex]

                             ≈ 17.7kg/[tex]m^{2}[/tex]

a spherical conductor of radius 10cm contains 10 mui c charge calculate the surfacecharge density

Answers

(a) Since the charge at any point inside sphere is zero.

by Gauss law,E=0.

(b) Just outside, E=q/4πϵ  o ​  r  2   so, E=10  5  NC  −1  

(c) q=1.6×10  −7 C r=18 cm E=q/4πϵ  o  r  2 E=4.4×10  4  NC  −1

Wind energy is the example of A) potential energy B)mechanical energy C) Kinetic energy

Answers

Answer:

Kinetic Energy

Explanation:

Its on the internet

The energy transferred per unit electric charge in a circuit is .
A current
B charge
C power
D potential difference​

Answers

Answer:

(D)

E = V Q      energy of charge Q  thus V = E / Q

In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by a chain. (Neglect the weight of the chain.) The block is initially accelerating at 4.0 m/s.


How much force is being exerted by the chain?

Answers

Answer:

2,800 n

Explanation:

hope this helps, have a nice day/night! :D

The force of 2812.5 N is being exerted by the chain.

What is force?

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given that:

Mass of the  hunk of anorthosite moon rock : m = 500.0 kg.

Acceleration of the hunk: a = 4.0 m/s².

Acceleration due to gravity in moon = 1.625 m/s².

So, required force = 500.0(4.0 +1.625) n = 2812.5 N.

The force of 2812.5 N is being exerted by the chain.

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Tại sao khi bị sì hơi quả bóng bay sẹp lại?

Answers

Answer:

what is this language??

các phân tử khí sẽ bị lọt ra ngoài, theo nguyên tắc vật lý thì áp suất khí bên trong càng cao thì các hạt phân tử khí bị lọt ra càng nhanh.

A fan operating at 260V with a current being supplied at 13A. What is the effective resistance at which it is being operated?

Answers

Answer:

20 ohms

Explanation:

Resistance=Potential difference÷Electric current

X=260÷13

X=20

Do you think humans will ever walk on the sun?

Answers

[tex] \: \: \: \: \: [/tex]

yes

because sun have a super nova and if someone get it there that person definitely get burn

hope it helps

[tex] \: \: \: \: \: [/tex]

A vinyl "record" with a diameter of 0.3 m is spinning at a rate of 1 m/s.

a) What would the centripetal acceleration be for a piece of gum (0.005kg) stuck to the outside edge of the record?

b) How much centripetal force will the gum have to overcome to remain "stuck" to the vinyl?​

Answers

This question involves the concepts of centripetal force and centripetal acceleration.

a) The centripetal acceleration for the piece of gum stuck to the outside edge of the record will be "6.67 m/s²".

b) The gum will have to overcome "0.033 N" centripetal force to remain stuck to the vinyl.

a)

The centripetal acceleration of the gum can be found using the following formula:

[tex]a_c=\frac{v^2}{r}[/tex]

where,

[tex]a_c[/tex] = centripetal acceleration = ?

v = linear speed of record = 1 m/s

r = radius of the record = [tex]\frac{diameter}{2}=\frac{0.3\ m}{2}=0.15\ m[/tex]

Therefore,

[tex]a_c=\frac{(1\ m/s)^2}{0.15\ m}\\\\a_c = 6.67\ m/s^2[/tex]

b)

Now, the centripetal force can be given as follows:

[tex]F_c=ma_c\\F_c=(0.005\ kg)(6.67\ m/s^2)\\F_c=0.033\ N[/tex]

Learn more about centripetal force here:

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The attached picture shows the centripetal force.

A bus is moving at a speed of 45 km/h. What is the speed of
the bus in m/s?
a) 1.25×101 m/s
b) 1.5×103 m/s
c) 2.5 m/s
d) 1.5×102 m/s

Answers

.

We want to convert the speed of the bus from kilometers per hour to meters per second.

To do this, multiply the speed in km/hr by 1,000 and divide by 3,600.

The formula to do this is: 1 km/hr = 1,000/3,600 m/s

Therefore, we have that 45 km/hr is:

45 x 1000/ 3,600 ➡️ 12.5 m/s = 1.25 x 10 to the 1st power m/s

The answer is option A.

Real-life situations of microphones.

Answers

Answer:

Microphones are used in many applications such as telephones, hearing aids, public address systems for concert halls and public events, motion picture production, live and recorded audio engineering, sound recording, two-way radios, megaphones, radio and television broadcasting.

Hãy giải thích sự phát âm của cái sáo khi thổi vào nó

Answers

Giải thích các bước giải:

Âm phát ra từ cái sáo khi thổi là do:

-Không khí ngoài ống sáo chuyển động và phát ra âm thanh.

-Thân sáo chuyển động và phát ra âm thanh.

-Thân sáo dao động và phát ra âm thanh.

-Cột không khí trong ống sáo dao động và phát ra âm thanh.

A car begins at rest at a stoplight. After the light turn green, the car begins to accelerate 5 m/s2 over the span of 3.6 seconds. What is the car’s displacement over this period of time?

Hint you can use this equation Xf = Xi + vi · t + 1/2 · a · t2

Answers

Answer:

d=9m

Explanation:

what is the average power supplied by a 60.0 kg person running up a flight of stairs a vertical distance of 4.0 in 4.2s

Answers

Hi there!

We know that:

[tex]P = \frac{W}{t}\\\\[/tex]

Where:

W = Work done (J)

t = time (s)

We can calculate the work using the equation:

[tex]W = \Delta U = mg\Delta h[/tex]

Plug in the given values:

[tex]W = 60(9.8)(4) = 2352J[/tex]

Now, divide by time:

[tex]P = \frac{W}{t} = \frac{2352}{4.2} = \boxed{560W \text{ (Watts)}}[/tex]

A piece of wood is floating in a tub of water. a second piece of wood rests on top of the first piece; it does not touch the water. if the second piece of wood is removed from on top of the first piece and placed in the water, what happens to the water level in the tub?

Answers

Answer:

The water would rise because of displacement in the water

Explanation:

Find the mass of the second object if the force of gravity between the two objects is 0.128N. The mass of the first object is 1300 kg and the 2 objects are 0.23 m apart.​

Answers

Considering the Law of Universal Gravitation, the mass of the second object is 78090.19 kg.

The Law of Universal Gravitation is a law that states that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.

This law establishes that every particle attracts any other particle with a force directly proportional to the product of the masses of both and inversely proportional to the square of the distance that separates them:

[tex]F=G\frac{m1m2}{r^{2} }[/tex]

where m1 and m2 are their masses; r the distance between them and G a universal constant that is called the constant of gravitation.

In this case, you know:

F= 0.128 NG=6.67× 10⁻¹¹ Nm²/kg²m1= 1300 kgm2= ?r= 0.23 m

Replacing:

[tex]0.128 N=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{1300 kg m2}{(0.23 m)^{2} }[/tex]

Solving:

[tex]0.128 N=1.639x10^{-6}\frac{N}{kg }x m2[/tex]

m2=0.128 N ÷ 1.639×10⁻⁶ [tex]\frac{N}{kg}[/tex]

m2=78090.19 kg

In summary, the mass of the second object is 78090.19 kg.

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