Answer:
[tex]given \: \\ mass \: (m) = 50g \\ kinetic \: enegy \: (k.e) = 25kj \\ velocity(v) = x \\ form \\ k.e = \frac{1}{2} \times MV ^{2} \\ 25 = \frac{1}{2} \times 50 \times v {}^{2} \\ 25 = 25 \times v {}^{2} \\ v {}^{2} = \frac{25}{25} \\ v {}^{2} = 1 \\ v = \sqrt{1} \\ v = 1ms {}^{ - } [/tex]
the car it go fast with velocity 1m/s
A ball rolling at a speed of 4.30 m/s has a kinetic energy of 23.1 J. What is the mass of the ball?
PLEASE HELP
Answer:
Mass = 2.50 kilograms.
Explanation:
Given the following data;
Velocity = 4.3m/s
Kinetic energy = 23.1J
To find the mass of the ball;
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Substituting into the equation, we have
23.1 = ½m*4.3²
46.2 = 18.49m
Mass, m = 46.2/18.49
Mass, m = 2.498 ≈ 2.50kg
A skateboarder coasts a distance of 20 meters in 4 seconds. What is the person's speed?
Answer:
5 m/s
Explanation:
The formula of speed is : distance/time taken.
The skateboarder covered a distance of 20 meters in 4 seconds. So,
Distance = 20 meters
Time Taken = 4 seconds
Speed = 20/4 = 5 m/s
which of these is NOT a metamorphic rock?
Basalt
Slate
Marble
Explanation:
Basalt is not a metamorphic rocks
Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?
The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.
The potential energy can be calculated with the following equation:
[tex] E_{p} = mgh [/tex]
Where:
m: is the mass of the baseball
g: is the acceleration due to gravity
h: is the height
We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:
Potential energy above 1 m[tex] E_{p_{1}} = mg*1 = mg [/tex] (1)
Potential energy above 2 m[tex] E_{p_{2}} = mg*2 = 2mg [/tex] (2)
By entering equation (1) into 2 we have:
[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]
Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.
Therefore, the baseball held 2 m above the ground has more potential energy.
You can learn more about potential energy here: https://brainly.com/question/15813853?referrer=searchResults
I hope it helps you!
4. Determine the net force for the free-body
diagram
Fnorm = 40N
Ffrict =28N
Fapp =44N
Fgrav = 40N
Answer:
Fapp =44N is the correct answer
Explanation:
Please mark brainliest
in a nuclear plant, 1 * 10 ^27 J of energy is available from mass conversion How much mass was lost ?
Answer:
[tex]1.2\times 10^{10}\ kg[/tex]
Explanation:
Given that,
The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]
We need to find how much mass wast lost.
The relation between energy and mass is given by :
[tex]E=mc^2[/tex]
Where
c is speed of light
[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]
So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
a.) Maximum height of the projectile.
b.) The time it takes to reach the maximum height
c.) Time of flight
d.) Range
Answer:
a.) Maximum height of the projectile. =32.5m
b.) The time it takes to reach the maximum height=2.6s
c.) Time of flight=2.6s
d.) Range=99.5m
Explanation:
What do seismic waves and sound waves have in common?
A human cannonball act uses springy bungee cords instead of gunpowder to launch a person through a long cylindrical tube into the air. If a cannon is capable of launching a 55 kg test dummy 11 m into the air when launched straight up, how much energy is stored in the bungee cords? *
A. 539J
B. 605 J
C. 2965J
D. 5929 J
Answer:
Energy stored, E = 5929 J
Explanation:
Given that,
The mass of a test dummy, m = 55 kg
It is launched 11 m into the air.
We need to find the energy stored in the bungee cords. It can be calculated as follows :
[tex]E=mgh\\\\E=55\times 9.8\times 11\\\\E=5929\ J[/tex]
So, 5929 J of energy is stored in the bungee cords.
1/2 means that the voltage (or charge) of the system will increase to half more of what is left in a time equal to t1/2 seconds. Therefore if a system is already at half charge (t1/2 seconds after starting) then after t1/2 more seconds the system will be charged to 50% plus half of 50%. That is 25% more, or 75% of the entire charge. Let's say that four t1/2's have gone by. That means that the charge (or voltage) is at (50% + 1/2*50% + 1/2*1/2*50% + 1/2*1/2*1/2*50%) = 93.75% of maximum charge. Yikes! Now look in your manual for a more simple mathematical derivation of this concept. Given t1/2 to be 0.4406 seconds, how long should it take to reach 75% of maximum charge? answer in seconds.
Answer:
The answer is "0.047".
Explanation:
Given value:
[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]
Calculating the capacitance:
[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]
In this, the t = time, which is taken to calculates its maximum voltage.
[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]
write down the expressions for the heat produced per second in a resistor in terms of potential difference and resistance
Answer:
[tex]H=\frac{V^2}{R}[/tex]
Explanation:
Let H be heat produced per sec
Time, t=1 sec
Resistance of resistor=R ohm
We have to write down the expression for the heat produced per second in a resistor in terms of potential difference and resistance.
We know that
Heat, [tex]H=I^2 Rt=\frac{V^2}{R}t[/tex]
Substitute the value
Then, we get
Heat,[tex]H=\frac{V^2}{R}\times 1[/tex]
[tex]H=\frac{V^2}{R}[/tex]
This is required expression for the heat produced per second in a resistor in terms of potential difference and resistance.
HELP please!!!!!!!!!!!!!!!
. A boy wishes to throw a ball through a house via two small openings, one in the front and the other in
the back window, the second window being directly behind the first. If the boy stands at a distance of 5m
in front of the house and the house is 6m deep and if the opening in the front window is 5m above him
and that in the back window 2m higher, calculate the velocity and the angle of projection of the ball that
will enable him to accomplish his desire.
Answer:
1) The angle of projection of the ball is approximately 52.496° above the horizontal
2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s
Explanation:
In the projectile motion of the ball, the parameters are;
The distance the boy stands from the front of the house = 5 m
The depth of the house, front to back = 6 m
The height of the opening of the front window above him = 5 m
The height of the back window = 2 m higher than the front window
Therefore, the height of the back window = 5 m + 2 m = 7 m
1) The general formula for the vertical height of a parabolic projectile motion is given as follows;
y = a·x² + b·x + c
At y = 0, x = 0, therefore, c = 0
At y = 5, x = 5, we have;
5 = a·5² + b·5
∴ 5 = 25·a + 5·b...(1)
At y = 7, x = 11, we have;
7 = a·11² + b·11
7 = 121·a + 11·b...(2)
Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;
For equation (1);
a = (5 - 5·b)/25 = 1/5 - b/5
a = 1/5 - b/5
For equation (2);
a = (7 - 11·b)/121 = 7/121 - b/11
a = 7/121 - b/11
∴ 1/5 - b/5 = 7/121 - b/11
1/5 - 7/121 = b/5 - b/11
86/605 = 6·b/55
b = (86/605) × (55/6) = 43/33
b = 43/33
a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33
∴ y = (-2/33)·x² + (43/33)·x
The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33
The slope of the curve at any point on the projectile = -4/33·x + 43/33
The slope at the origin is given by plugging x = 0 as follows
The slope at the origin = -4/33 × 0 + 43/33 = 43/33
The slope at the origin = tan(θ) = 43/33
Where;
θ = The angle of projection of the ball
∴ θ = arctan(43/33) ≈ 52.496°
The angle of projection of the ball, θ ≈ 52.496° above the horizontal
2) At the back widow, the equation for the vertical height, 'h', is given as follows;
[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]
Where;
h = The vertical height of the back window = 7 m
tan∠θ = 43/33
x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m
g = The acceleration due to gravity = 9.8 m/s²
v₁ = The velocity with which the boy throws the ball
cos²∠θ = cos²(arctan(43/33)) = 1089/2938
Plugging in the values gives;
[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]
[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]
[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]
The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.
Why does it take a long time for the earth to rotate?
24hrs or i full year as in 365 days
Answer:
earth takes a long time to rotate due to the tidal effects the moon has on earth's rotation
Explanation:
I hope this helps!
Can someone help me with this answer the question pls don’t guess and actually help me I’ll give brainliest
Answer: clastic sedimentary rock
Explanation: Hope this helps!
Which of these is not a scalar quantity?
Answer:
options?!?
Explanation:
give us some options
4. A substance is cut into several piece and compared to the density of the
original sample. The density of each piece will be:-
areater
bl the same
Answer:
The density pf each piece will be the same, since density is defined as a mass per unit volume, so even when you cut an object it will not change
Which one of the following best describes a fuse?
examples of non viscous liquid
The fluids that have no resistance or zero resistance to internal friction are known as non- viscous fluids. • The fluid which has more resistance to flow is called viscous fluid. Viscosity is a property of a fluid, which is a degree of the amount of resistance between the fluid layers.
which event involves throwing a spherical weight from the shoulder?
a. discus throw
b. hammer throw
c. shot put
Answer:
c. shot put
Explanation:
cause the shot is a ball
Below is a diagram of the orbits of the inner planets examine the diagram and answer questions three and four 
Answer:
C is the answer
Explanation:
Earth is the third planet from the sun
you are cheating on your test, I know
Answer:
C..
Explanation:
I'm not sure about answer...
An electric iron is connected to the mains power supply of 220 V. When the electric iron is
adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a
power of 840 W. Calculate the current and resistance in each case.
Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
The final velocity of a car is 30m/s. The car is accelerating at a rate of 2.5m/s2
over an 2.8m/s2
8 second period of time. What is the initial velocity of the car?
Answer:
10m/s
Explanation:
Vf=v0+at
30m/s=v0+2.5m/s^2*8s
Solve for v0=10m/s
Sorry for the vague explanation I'm on my phone right now. Hope this still helps!
Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.
To find the initial velocity of the car, we can use the kinematic equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).
Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:
30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).
Now, solve for the initial velocity (u):
30 m/s = u + 20 m/s.
Subtract 20 m/s from both sides:
u = 30 m/s - 20 m/s = 10 m/s.
Therefore, the initial velocity of the car is 10 m/s.
To know more about Initial velocity, here
brainly.com/question/28395671
#SPJ2
write the ratio of the following?
CaCO3
C2H6
Fe(NO3)3
Answer:
C2H6 up the road to be with its own in
SOMEONE HELP ME PLEASE
Free is the movement of an object towards earth solely because of gravity.
What is freefall? Free fall is when objects falling near earth’s surface accelerate downward at rate of 9.8 m/s2.
Give an example of an object in free fall
Which graph shows a vehicle traveling at a constant speed?
(look at the attached photo)
Question 6 of 59
A wave has a wavelength of 5 m and a speed of 65 m/s. What is the frequency of this wave in Hz?
Answer:
13 Hz Ans..
Explanation:
Data:
wavelength = 5 m
v = 65 m\s
f = ?
Formula:
v = f w
f= v\w
Solution:
f = 65 \ 5
f = 13 Hz Ans .........
What happens when an object becomes cold?
Energy is added to it.
Mass is removed from it.
Cold is added to it.
Heat is removed from it.
Answer:
Heat is removed from it.
Explanation:
A object will become cold when it loses its heat to its surroundings. I would look up the 3 Principles of Heat Transfer.
I hope this helped! :)
4. Premature wrinkling due to overexposure to the Sun, what am I?
Premature Aging
Mark as brainlist
what are the 3 types of family goals