A buffer solution is prepared from equal volumes of 0.200 M acetic acid and 0.600 M sodium acetate. Use 1.80 x 10−5 as Ka for acetic acid. (a) What is the pH of the solution? (b) Is the solution acidic or basic? (c) What is the pH of a solution that results when 3.00 mL of 0.034 M HCl is added to 0.200 L of the original buffer

Answers

Answer 1

Answer:

a. pH = 5.22

b. Acidic.

c. pH = 5.14

Explanation:

a. It is possible to find the pH of a buffer using Henderson-Hasselbalch equation (H-H equation):

pH = pKa + log₁₀ [A⁻] / [HA]

Where pKa is -log Ka (For acetic acid =  4.74), [A⁻] is molar concentration of conjugate base (Acetate salt) and [HA] concentration of the weak acid (Acetic acid).

Replacing:

pH = 4.74 + log₁₀ [0.600M] / [0.200M]

You use the concentration of the acetic acid and sodium acetate because you're adding equal volumes, doing the ratio of the species the same

pH = 5.22

b. As the solution has a pH lower that 7.0, it is considered as a acidic solution.

c. When you add HCl to the buffer, the reaction is:

CH₃COO⁻ + HCl → CH₃COOH + Cl⁻

Where acetate ion reacts with the acid producing acetic acid.

As you have 0.200L of the buffer, 0.100L are of the acetate ion and 0.100L of the acetic acid. Initial moles of both compounds and moles of HCl added are:

CH₃COO⁻: 0.100L ₓ (0.600mol / L) = 0.0600 moles

CH₃COOH: 0.100L ₓ (0.200mol / L) = 0.0200 moles

HCl: 3.0mL = 3x10⁻³L ₓ (0.034mol / L) =  0.00010 moles HCl

The moles added of HCl are the same moles you're consuming of acetate ion and producing of acetic acid. Thus, moles after the reaction are:

CH₃COO⁻: 0.0600 moles - 0.0001 moles = 0.0509 moles

CH₃COOH: 0.0200 moles + 0.0001 moles = 0.0201 moles

Replacing in H-H equation:

pH = 4.74 + log₁₀ [0.0509moles] / [0.0201moles]

pH = 5.14

Answer 2

(a) The pH of the solution is 5.22

(b) The solution is Acidic

(c) The pH of the resultant solution is 5.14

Henderson-Hasselbalch Equation:

(a) The pH of a buffer can be calculated by using (H-H equation):

pH = pKa + log₁₀ [A⁻] / [HA]

Where pKa is -log Ka (for acetic acid =  4.74),

[A⁻] is the molar concentration of Acetate salt, and

[HA] concentration of the Acetic acid

According to the question:

pH = 4.74 + log₁₀ [0.600M] / [0.200M]

pH = 5.22

(b) The pH of the solution is lower than 7.0, therefore it is an acidic solution.

(c) After adding HCl to the buffer, the reaction is:

CH₃COO⁻ + HCl → CH₃COOH + Cl⁻

We have 0.200L of the buffer, 0.100L are of the acetate ion and 0.100L of the acetic acid.

The initial amount of compounds added are:

CH₃COO⁻: 0.100L ₓ (0.600mol / L) = 0.0600 moles

CH₃COOH: 0.100L ₓ (0.200mol / L) = 0.0200 moles

HCl: 3.0mL = 3x10⁻³L ₓ (0.034mol / L) =  0.00010 moles HCl

The HCl reacts with the same amount of acetate ion and produces acetic acid. Thus, moles after the reaction are:

CH₃COO⁻: 0.0600 moles - 0.0001 moles = 0.0509 moles

CH₃COOH: 0.0200 moles + 0.0001 moles = 0.0201 moles

From the H-H equation:

pH = 4.74 + log₁₀ [0.0509moles] / [0.0201moles]

pH = 5.14

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Related Questions

Question 4 (2 points)
CuO(s) + H2(g)
Cu(s) +
H2O(1)
Balance the equation

Answers

Answer:

CuO(s) + H₂(g) --> Cu(s) + H₂O(l)

Explanation:

It is already balanced. You can see that the values of the elements of the reactants are equal to the values of the elements of the products.

What is the number of Cl atoms in a 784 gram pure sample of NC13?

Answers

Answer:

idk

Explanation:

idk cool pee bee mee nee hee gee fee kee

In a 784 gram pure sample of NC13, there are approximately 1.33 x 10²⁵ chlorine atoms.

To determine the number of chlorine (Cl) atoms in a given sample, we need to utilize the Avogadro's number and the molar mass of chlorine.

The molar mass of chlorine (Cl) is approximately 35.45 grams/mol. To calculate the number of moles in the sample, we divide the given mass by the molar mass:

Number of moles of Cl = Mass / Molar mass

Number of moles of Cl = 784 g / 35.45 g/mol

Number of moles of Cl ≈ 22.08 mol

According to Avogadro's number, there are 6.022 x 10²³ entities (atoms, molecules, or formula units) in 1 mole of a substance. Therefore, to find the number of chlorine atoms, we multiply the number of moles by Avogadro's number:

Number of Cl atoms = Number of moles of Cl x Avogadro's number

Number of Cl atoms = 22.08 mol x 6.022 x 10²³ atoms/mol

Number of Cl atoms ≈ 1.33 x 10²⁵ atoms

Therefore, in a 784 gram pure sample of NC13, there are approximately 1.33 x 10²⁵ chlorine atoms.

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Which element has 4 valence electrons in the 3p sublevel?
The Periodic Table
A. Ga
B. Si
C. N
D. S

Answers

Answer:

D . Sulphur

Explanation:

the element with a 3p4 valence configuration, look in period 3 and group XVI, and that is ...

S, sulfur.

It’s definitely D: sulpher

Which best describes the trends in electonegativity on the periodic table

Answers

Hey! :)

__________ ☆ ☆__________________________________

Answer:

The answer is Electronegativity increases up and to the right

Explanation:

When you move from left to right it increases ( in the periodic table )

But when you move down the table electronegativity decreases.

So “ Electronegativity increases up and to the right” describes the trends the best.

Hope this helps! :)

____________☆ ☆________________________________

By, BrainlyMember ^-^

Good luck!

why Al is a member of group 13 rather than group 3?

Answers

Answer:

Boron and Aluminium

Explanation:

Boron and Aluminium are present in Group 13 of the modern periodic table. Group 13 (IUPAC System) can also be referred to as Group III-A. Logically, Boron and Aluminum can't be placed alongwith elements such as Yttrium as they don't exhibit properties of a transition metal.

To condition the buret, add a small volume of ____________ to the buret and rotate the barrel ____________ so that the liquid makes contact with the full inner surface of the barrel. Complete this action _________ and discard each volume in a designated waste container.

Answers

Answer:

Acid, Horizontally, Drain off the acid by opening the stopcock

Explanation:

A buret is a calibrated glass appratus used to measure and deliver accurate volume of liquid, usually acids, in acid-base titrations.

Before usually the buret to carry out your titration reaction, it is advised to condition or prepare your buret for use.

To condition the buret, add a small volume of the acid to the buret and rotate the barrel horizontally to ensure that the liquid ( acid) makes contact with the inner surface of the barrel o the buret.

This procedure is done to wash off any previous acid or liquid that the buret had been used for in previous titrations.

Complete this action by opening the stopcock of the buret to drain off the acid and discarding each volume in a designated waste container.

Note that acids could be corrosive and dangerous to the skin and so should be handled with great care

An electrode has a negative electrode potential. Which statement is correct regarding the potential energy of an electron at this electrode?

A. An electron at this electrode has the same potential energy as it has at a standard hydrogen electrode.
B. An electron at this electrode has a lower potential energy than it has at a standard hydrogen electrode.
C. An electron at this electrode has a higher potential energy than it has at a standard hydrogen electrode.

Answers

Answer:

C. An electron at this electrode has a higher potential energy than it has at a standard hydrogen electrode.

Explanation:

The standard hydrogen electrode (SHE) is used to measure the electrode potential of substances. The standard hydrogen electrode is arbitrarily assigned an electrode potential of zero. Recall that electrode potentials are always measured as reduction potentials in electrochemical systems.

For an electrode that has a negative electrode potential, electrons at this electrode have a higher potential energy compared to electrons at the standard hydrogen electrode. Electrons flow from this electrode to the hydrogen electrode.

On the other hand, a positive electrode potential implies that an electron at this electrode has a lower potential energy than it has at a standard hydrogen electrode. Hence electrons will flow from the standard hydrogen electrode to this electrode.

g The most common position for an double bond in an unsaturated fatty acid is delta _________(fill in the number).

Answers

Answer:

The most common position for an double bond in an unsaturated fatty acid is delta 9 (Δ⁹)

Explanation:

Unsaturated fatty acids are carboxylic acids which contains one or more double bonds. The chain length as well as the number of double bonds is written separated by a colon. The positions of the double bonds are specified starting from the carboxyl carbon, numbered as 1, by superscript numbers following a delta (Δ). For example, an 18-carbon fatty acid containing a  single double bond between carbon number 9 and 10 is written as 18:1(Δ⁹).

In most monounsaturated fatty acids, the double bond is between C-9 and C-10 (Δ⁹), and the other double bonds of polyunsaturated fatty acids are generally Δ¹² and Δ¹⁵. This positioning is due to the nature of the biosynthesis of fatty acids. In the mammalian hepatocytes, double bonds are introduced easily into fatty acids at the Δ⁹ position, but cannot introduce additional double bonds between C-10 and the methyl-terminal end. However, plants are able to introduce these additional double bonds at the  Δ¹² and Δ¹⁵ positions.

How does the carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere?

Answers

Answer:

The calculator add the CO2 released from the use of electricity, released from driving and the CO2 from the waste that we disposed.

Explanation:

The carbon dioxide, CO2 is what the human body does not need, therefore, we breathe it out, hence taking in oxygen(respiration process). The plants need oxygen for the production of their own food.

The carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere through the consideration of several factors such as the kind of food that we eat.

Therefore, if we are to use the carbon calculator to determine the amount of CO2 that each individual releases into the atmosphere we will have:

The amount of CO2 that each individual releases into the atmosphere =( CO2 released from the use of electricity) + (CO2 released from driving) + (the CO2 from the waste that we disposed).

What does light do in the photoelectric effect?
O A. Light turns metal into electricity.
B. Light knocks electrons off metal atoms.
C. Light reacts with metal atoms.
D. Light is turned into electricity by the metal.

Answers

Answer:

it's B: light knocks electrons off metal atoms

The distance from the Moon to Earth is 5.46 * 108 km. How long does it take a laser need to travel between the moon and earth?
a. 1.64 X 1020 s
b. 1.82 X 103 s
c. 1.82 s
d. 0.182 s
e. 1.64 X 1017 s

Answers

Answer:

B. 1.82(10³) seconds (1820 seconds)

Explanation:

Speed of Light: 3.00(10⁸) m/s or 3.00(10⁵) km/s

We know the distance from the Moon to Earth as 5.46(10⁸) km

We simply divide the distance by the speed of light:

[tex]\frac{5.46(10^8)}{3.00(10^5)}[/tex]

We should get 1820 seconds or B. 1.82(10³) as our answer.

The solubility of nitrogen gas at 25°C and a nitrogen pressure of 522 mmHg is 4.7 × 10 –4 mol/L. What is the value of the Henry's Law constant in mol/L·atm?

Answers

Answer:

6.8 × 10⁻⁴ mol/L.atm

Explanation:

Step 1: Given data

Solubility of nitrogen gas at 25°C (S): 4.7 × 10⁻⁴ mol/L

Partial pressure of nitrogen gas (P): 522 mmHg

Step 2: Convert the partial pressure of nitrogen to atm

We will use the relationship 1 atm = 760 mmHg.

[tex]522mmHg \times \frac{1atm}{760mmHg} = 0.687atm[/tex]

Step 3: Calculate the value of the Henry's Law constant (k)

We will use Henry's law.

[tex]S = k \times P\\k = \frac{S}{P} = \frac{4.7 \times 10^{-4}mol/L }{0.687atm} = 6.8 \times 10^{-4} mol/L.atm[/tex]

What is the shape of a molecule that has 4 atoms bonded to a central atom
and no lone pairs of electrons?
A. Octahedral
B. Cubic
C. Tetrahedral
D. Trigonal-pyramidal

Answers

Answer:

C. Tetrahedral

Explanation:

Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which means it has tetra (which translates to four) domains hence tetrahedral.

Tetrahedral is the shape of a molecule that has 4 atoms bonded to a central atom and no lone pairs of electrons. Hence, option C is correct.

What is an atom?

An atom consists of a central nucleus that is usually surrounded by one or more electrons.

Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which mean it has tetra (which translates to four) domains hence tetrahedral.

Hence, option C is correct.

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Name MgSo4.7H2O /Cs3PO4.H2O

Answers

Answer:

MgSo4.7H2O = Magnesium sulfate

Cs3PO4.H2O = Cesium Phosphate

Hope this helps!

You are working on an experiment that requires Iodine (I) to have a full outer shell. What element could you combine it with to get a full outer shell? A. Lithium (Li) B. Sulfur (S) C. Neon (Ne) D. Oxygen (O)

Answers

Answer:

A. Lithium

Explanation:

Hello,

In this case, we can find out the required element by noticing that iodine has seven valence electrons as it is in group VIIA, therefore, it needs one spare electron to successfully attain the octet, that is completing eight electrons in total. For that reason, since lithium is group in IA, it will be able to provide the missing electron to iodine in order to get the full outer shell as required, thereby, lithium iodide will be formed.

Take into account that sulfur will share two electrons so two iodine atoms will be required, neon does not provide any electron as it is a noble gas and oxygen behave as well as sulfur.

Regards.

Answer:

Lithium

Explanation:

Answer via Educere/ Founder's Education

Classify each molecule by whether its real bond angles are the same as or different than its model (ideal) bond angles. In other words, do the bond angles change when you switch between Real and Model mode at the top of the page?

Answers

The question is incomplete; the complete question is: Classify each molecule by whether its real bond angles are the same as or different than its model (ideal) bond angles. In other words, do the bond angles change when you switch between Real and Model mode at the top of the page? Same (angles do not change) Different (angles change) Answer Bank | H2O | CO2, SO2, XeF2, BF3 CIF3, NH3, CH4, SF4, XeF4, BrF5, PCI5,SF6

Answer:

Compounds whose real bond angle are the same as ideal bond angle;

SF6, BF3, CH4, PCI5

Compounds whose real bond angles differ from ideal bond angles;

H2O, CO2, SO2, XeF2, CIF3, NH3, SF4, XeF4, BrF5

Explanation:

According to the valence shell electron pair repulsion theory (VSEPR), molecules adopt various shapes based on the number of electron pairs on the valence shell of the central atom of the molecule. The electron pairs usually orient themselves as far apart in space as possible leading to various observed bond angles.

The extent of repulsion of lone pairs is greater than that of bond pairs. Hence, the presence of lone pairs on the valence shell of the central atom in the molecule distorts the bond angles of molecules away from the ideal bond angles predicted on the basis of valence shell electron pair repulsion theory.

For instance, methane is a perfect tetrahedron having an ideal bond angle of 109°28'. Both methane and ammonia are based on a tetrahedron, however, the presence of a lone pair of electrons on nitrogen distorts the bond angle of ammonia to about 107°. The distortion of lone pairs in water is even more as the bond angles of water is about 104°.

Write the empirical formula

Answers

Answer:

[tex]Fe(C_{2}H_{3}O_{2})_{3}\\Fe (OH)_{3}\\\\NH_{4}(C_{2}H_{3}O_{2})\\\\NH_{4}OH[/tex]

Explanation:

[tex]Fe^{3+}(C_{2}H_{3}O_{2})^{-}_{3}--->Fe(C_{2}H_{3}O_{2})_{3}\\Fe^{3+} (OH^{-})_{3}--->Fe (OH)_{3}\\\\NH_{4}^{+}(C_{2}H_{3}O_{2})^{-}--->NH_{4}(C_{2}H_{3}O_{2})\\\\NH_{4}^{+}OH^{-} ---> NH_{4}OH[/tex]

If you combine 24.2 g of a solute that has a molar mass of 24.2 g/mol with 100.0 g of a solvent, what is the molality of the resulting solution

Answers

Answer: 10 moles/kg.

Explanation:

Given, Mass of solute = 24.2 g

Molar mass of solute = 24.2 g/mol

[tex]\text{Moles of solute =}\dfrac{\text{Mass of solute}}{\text{Molar mass of solute}}\\\\=\dfrac{24.2}{24.2}=1[/tex]

Mass of solvent = 100.0g = 0.1 kg  [1 g=0.001 kg]

[tex]\text{Molality}=\dfrac{\text{Moles of solute}}{\text{kilograms of Solvent}}\\\\=\dfrac{1}{0.1}\\\\=10\ moles/kg[/tex]

Hence, the molality of the resulting solution is 10 moles/kg.

Question 3 (11 points)
A gas has a volume of 690.0mL at -15.1°C and 392.0 mmHg. What would the volume of the gas be at
233.0°C and 0.700 atm of pressure? Answer with no decimal places.

Answers

Answer:

V2 = 0.998L

v2 = 0.000998mL

Explanation:

P1 = 392mmHg

V1 = 690mL

T1 = -15.1°C = 257.9k

P2 = 0.700atm = 532mmHg

V2 = ?

T2 = 233°C = 506K

using general gas equation

P1V1/T1 = P2V2/T2

(392 x 690.0 x 10^-³)/257.9 =(532 x V2)/506

1.05=(532 x V2)/506

1.05 x 506 =(532 x V2)

531.3 =(532 x V2)

V2 = 531.3/532

V2 = 0.998L

v2 = 0.000998mL

The solubility of carbon tetrachloride (CCl4) in water at 25 ∘C is 1.2 g/L. The solubility of chloroform (CHCl3) at the same temperature is 10.1 g/L. Why is chloroform almost 10 times more soluble in water than carbon tetrachloride?

Answers

Answer:

I WOULD ANSWER IT VERY SOON

Explanation:

if a 0.15% protein solution and a 0.12% protein solution are separated by a semipermeable membrane, what will happen?

Answers

Answer:

Water molecules will move across the semipermeable membrane from the 0.12% protein solution to the 0.15% protein solution in a process known as osmosis.

Explanation:

Due to the difference in the concentrations of the two solutions as well as the presence of a semipermeable membrane, a concentration gradient is setup. The 0.15% protein solutions contains more protein molecules than the 0.12% protein solution. Water molecules will move across the semipermeable membrane from the 0.12% protein solution to the 0.15% protein solution in a process known as osmosis.

Osmosis is the movement of water molecules across a semipermeable membrane from a region of lower solute concentration or higher concentration of water molecules to a region of higher solute concentration or lower concentration of water molecules until an equilibrium concentration is attained.

This is a passive process and is facilitated by the concentration gradient as well as a presence of a semipermeable membrane which allows only water molecules to move across it but not solute molecules.

What is the electron geometry and molecular geometry of:

A. H2O

B. CH2CL2

C. OPCL3

D. CO3^2-

E. ALCL6^3-

F. SO2

G. PCL5

Answers

Answer:

H2O

Electron geometry-tetrahedral

Molecular geometry bent

CH2Cl2

Electron geometry- tetrahedral

Molecular geometry-tetrahedral

OPCL3

Electron geometry- tetrahedral

Molecular geometry- tetrahedral

CO3^2-

Electron geometry- trigonal planar

Molecular geometry- trigonal planar

ALCL6^3-

Electron geometry-octahedral

Molecular geometry- octahedral

SO2

Electron geometry-tetrahedral

Molecular geometry-bent

PCL5

Electron geometry-trigonal bipyramidal

Molecular geometry- trigonal bipyramidal

Explanation:

Water contains four electron domains this corresponds to a tetrahedral electron geometry. How ever, there are two lone pairs in the molecule hence it is bent.

CH2Cl2 is shows a tetrahedral molecular geometry and a tetrahedral electron geometry. This can only be observed from the structure of the compound.

OPCL3 is bonded to four groups making it a tetrahedral molecule. There are non lone pairs on phosphorus so the molecule is not bent.

CO3^2- is bonded to three groups which leads to a trigonal planar geometry.

ALCL6^3- contains six bonding groups which arrange themselves at the corners of a regular octahedron at a bond angle of 90°.

SO2 has four electron domains leading to a tetrahedral electron domain geometry according to valence shell electron pair repulsion theory. However, the lone pairs on the central atom in the molecule leads to a bent molecular geometry.

PCL5 has five electron domains without lone pairs of electrons on its central atom. Hence the molecule possess a trigonal bipyramidal geometry.

The electron geometry and molecular geometry of the molecule are as follows:

A. H₂O: The electron geometry is tetrahedral because it has four electron domains (two bonding pairs and two lone pairs). However, due to the presence of two lone pairs, the molecular geometry is bent or V-shaped.

B. CH2Cl₂: The electron geometry is tetrahedral. However, the molecular geometry is trigonal planar because two of the electron domains are occupied by chlorine atoms, resulting in a bent shape.

C. OPCl₃: The electron geometry is tetrahedral. However, the molecular geometry is trigonal pyramidal because one of the electron domains is occupied by a lone pair on phosphorus.

D. CO3⁻²: The electron geometry is trigonal planar because it has three electron domains (three single bonds). The molecular geometry is also trigonal planar.

E. AlCl6⁻³: The electron geometry is octahedral because it has six electron domains. The molecular geometry is also octahedral.

F. SO₂: The electron geometry is trigonal planar because it has three electron domains (two single bonds and one lone pair). The molecular geometry is bent or V-shaped due to the presence of a lone pair on sulfur.

G. PCl₅: The electron geometry is trigonal bipyramidal because it has five electron domains. The molecular geometry is also trigonal bipyramidal.

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Identify the following substances:
(1) An acidic gas which gives dense white fumes with NH3
(11 An alkane which can also be called a green house gas.
(iii) A solid which when kept in the open, forms a solution after som
(iv) An alloy used in electrical fittings.
(v) A metal which gives hydrogen gas on reacting with both dilute a
Write equations for the following reactions:
Aluminium oxide and Sodium hydroxide.
(ii) Zine and dilute sulphuric acid.
(
11​

Answers

Answer:

1) HCl (Hydrochloric acid reacts with NH3 and forms dense fumes)

2) Methane (It is from the group of alkanes and is a green house gas)

3) Deliquescent substance (It is a solid which when kept in open forms a solution after sometime)

4) Brass (It is a solid-in-solid solution used to make electrical fittings)

5) Aluminium

Question 2:

1)    Al₂O₃ + 2NaOH    ⇒   2NaAlO₂  (Sodium Aluminate) + H₂O

2)   Zn +  H₂SO₄   (dilute)  =>  ZnSO₄  (Zinc Sulphate) + H₂

Answer:

HCl is the gasmethanedeliquescent substances (they absorbs water out of the air until they dissolve themselves into liquid solutions. )brass

equations

Aluminium oxide and Sodium hydroxide react to form water and sodium aluminate

Al2O3 + 2NaOH → 2NaAlO2 + H2O

Zinc reacts with dilute sulphuric acid to form zinc sulphate and hydrogen gas

Zn + H2SO4 → ZnSO4 +H2

A sample of a pure compound that weighs 59.8 g contains 27.6 g Sb (antimony) and 32.2 g F (fluorine). What is the percent composition of fluorine

Answers

Answer:

53.85%

Explanation:

Data obtained from the question include:

Mass of antimony (Sb) = 27.6g

Mass of Fluorine (F) = 32.2g

Mass of compound = 59.8g

Percentage composition of fluorine (F) =..?

The percentage composition of fluorine can be obtained as follow:

Percentage composition of fluorine = mass of fluorine/mass of compound x 100

Percentage composition of fluorine = 32.2/59.8 x 100

= 53.85%

Therefore, the percentage composition of fluorine in the compound is 53.85%

The following reaction is part of the electron transport chain. Complete the reaction and identify which species is reduced. The abbreviation Q represents coenzyme Q. Use the appropriate abbreviation for the product.

FADH2 + Q →

The reactant that is reduced is: _____

Answers

Answer:

[tex]FADH_2 + Q --> FAD + QH_2[/tex]

The reactant that is reduced is [tex]FADH_2[/tex]

Explanation:

The complete equation is as below:

[tex]FADH_2 + Q --> FAD + QH_2[/tex]

Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.

In the above reaction, [tex]FADH_2[/tex] loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to [tex]QH_2[/tex] , hence the reducing agent.

In order words, [tex]FADH_2[/tex] is reduced while coenzyme Q is oxidized.

Status: Not yet answered | Points possible: 1.00
A sample of chlorine gas starting at 681 mm Hg is placed under a pressure of 992 mm Hg and reduced to a volume of 543.8 mL.
What was the initial volume, in ml, of the chlorine gas container if the process was performed at constant temperature?
Type answer:

Answers

Answer:

V1 = 792.1 ml

Explanation:

The product of pressure and volume is constant when temperature is constant. This relationship is known as Boyle's law.

To answer this, I assume the chlorine gas will behave as a perfect gas. In reality this is not completely true.

P1*V1 = P2*V2

Given:

P1 = 681 mm Hg

V1 = ?

P2 = 992 mm Hg

V2 = 543.8 ml

V1 = ( P2 * V2 ) / P1

V1 = (992 *543.8 ) / 681

V1 = 792.143318649046 ml

V1 = 792.1 ml

Consider 1 M solutions of NaCl, ethyl alcohol (CH3CH2OH), and hydrofluoric acid. Rank them in terms of how well they conduct electricity and explain why you ranked them this way.

Answers

Answer:

conductivity increasing order CH₃-CH₂-OH < HF< NaCl

Explanation:

NaCl is the better conductor comparing with remaining two. it is strong electrolyte. dissociation percent always nearly eqaul to 100% but HF is weaker acid than NaCl and dissociation percent <100% . So, the no of ions furnished by HF less than that of NaCl

CH₃-CH₂-OH organic compound . in general it is not treated as an electrolyte and it cannot carry any charge. If it  carries, it is very very less compared to remaining two

A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent composition of fluorine

Answers

Answer:

The percent composition of fluorine is 65.67%

Explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

[tex]percent composition element A=\frac{total mass of element A}{mass of compound} *100[/tex]

In this case, the percent composition of fluorine is:

[tex]percent composition of fluorine=\frac{39.6 g}{60.3 g} *100[/tex]

percent composition of fluorine= 65.67%

The percent composition of fluorine is 65.67%

Answer:

The percent composition of fluorine is 65.67%

Explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

In this case, the percent composition of fluorine is:

percent composition of fluorine= 65.67%

The percent composition of fluorine is 65.67%

can someone assist me with this chemistry question please?​

Answers

Answer:

490 J.

Explanation:

The following data were obtained from the question:

Mass (m) = 5 Kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

Potential energy (P.E) =..?

Potential energy is the energy stored in a body by virtue of its location. Mathematically, it can be expressed as:

P.E = mgh

Where:

m is the mass of the object measured in kilograms (Kg).

g is the acceleration due to gravity and the value is 9.8 m/s².

h is the height to which the object is located measured in metre (m)

P.E is the potential energy measured in joule (J).

With the above formula, we can obtain the potential energy possed by the object as follow:

P.E = mgh

P.E = 5 x 9.8 x 10

P.E = 490 J

The,the potential energy possed by the object is 490 J

Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønsted-Lowery Theory.
Use the internet or your textbook as a reference to name the following and indicate if they are an acid or a base:
a. HCI
b. KOH
c. HNO
d. Mg(OH),

Answers

Answer and Explanation:

1. Arrhenius Theory which describes the concept protonic. The substance that gives H+ ions when diluted in water is called as an acid (e.g. HCl) and the substance that dissociates OH-ions whenever it is diluted in water is called as the base (e.g. NaOH)

on the other hand

Bronsted Lowery Theory describes the concept of a proton donor-acceptor. The proton-donating species is an acid and the proton-accepting species is known as a base.

2. The Chemical name and nature of acid is shown below:-

Nature Chemical Name

a. HCl Acidic Hydrochloric Acid

b. KOH Basic Potassium hydroxide

c. HNO Acidic Nitric Acid

d. Mg(OH)2 Basic Magnesium hydroxide

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