The total angle the tires rotate through during his trip is 8156 radian.
What is angle?The study of shapes and their measurements falls under the umbrella of geometry, a subfield of mathematics. It also emphasises how the shapes are arranged in relation to one another and their spatial characteristics. We are aware that geometry is divided into 2D and 3D categories.
All geometrical shapes are first created by the intersection of points, lines, rays, and plane surfaces. The distance between the two lines is known as a "Angle" when the two lines or rays converge at a single location.
Given that:
A boy rides his bicycle 2.08 km.
The wheels have radius 25.5 cm.
So, perimeter of the wheel = 2πr = 2π×25.5 cm = 160.22 cm.
Total angle the tires rotate through during his trip
= ( 2.08 km/ 160.22 cm)× 2π
= 8156 radian.
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HURRY
Water boils at 100°C and freezes at 0°C. What best describes the molecules of water at 25°C?
A.
The particles are spread very far apart.
B.
The particles are close together and do not move.
C.
The particles are free to move easily past each other.
D.
The particles are in fixed positions.
Answer:
In be either B or C ! :))
Explanation:
Ik its not much but hope it helped for now :D
The separation distance in B is _____ times greater than in A, the force of attraction is _______ than A.
The separation distance in B is two times greater than in A, the force of attraction is greater than A.
What is force of attraction?Force of attraction is described as a force that pulls the body near due to its attraction. Some of these force of attraction include:
magnetic force, electric force, electrostatic force and gravitational force.The force of attraction is given by the formula:
Fg = G* m1m2/r2
where
Fg is the force of attraction,
G is the gravitational constant with the value of 6.67 ×10−11 Nm2/kg2,
m1 is the mass of a body,
m2 is the mass of other body.
r is the distance between the two bodies.
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A person stands in an elevator. The elevator starts from rest and travels from the first floor to the fifth floor of the building. Which of the following forces has a magnitude equal to the person's weight during the entire elevator ride?
The gravitational force exerted by the elevator on the person.
The gravitational force exerted by the person on Earth.
The normal force exerted by the elevator on the person.
The normal force exerted by the person on the elevator.
The person's weight during the entire elevator ride is equal to magnitude of the normal force exerted by the elevator on the person.
What is normal force?Every day, we experience the typical force. For instance, when a book is placed on a table, the usual response force prevents the book from falling through the table, even though gravity is pulling the book downward. That implies that there is a force acting to push it upward. The word "normal force" refers to the force. Normal in this context refers to being perpendicular to the ground.
The person's apparent weight during the entire elevator ride is equal to magnitude of the normal force exerted by the elevator on the person.
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I NEED ASAP
Heat energy in the atmosphere always moves _____.
A.
from cloudy to clear regions
B.
from low pressure to high pressure regions
C.
from high temperature to low temperature areas
D.
from low temperature to high temperature areas
Answer:
from high temperature to low temperature areas
Explanation:
If it is correct, could you please give me brainliest? I would really appreciate it! Thank you!
A satellite of mass M2 orbits a planet of mass M1 in a uniform circular orbit with a constant tangential velocity, v. The distance between the satellite and the center of the planet is d. If the satellite is moved such that the distance between the satellite and the center is doubled, what is the new gravitational field strength compared to the original gravitational field strength?
The gravitational field strength of the moon at this new distance is gr/4
What is meant by gravitational field ?The gravitational field is the amount of gravitational force that would be applied to a little mass at that location per unit of mass. It is a vector field that is oriented in the mass's expected direction of force.
A gravitational field is the force field that surrounds any mass or collection of masses in space. Although this field spreads out in all directions, the gravitational force becomes weaker the further an object is from the source. This is a method of calculating the gravitational pull. Weight divided by mass equals the strength of the gravitational field. Strength of gravitational field = mass/weight in kilograms, or N/kg.
The complete question is : A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v.
The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance?
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When an object experiences balanced forces on Earth, it would be?
A)at rest
B)moving northward
C) moving southward
D) floating around.
When an object experiences balanced forces on Earth, it would be at rest (option A).
What is a balanced force?Balanced forces are those forces that are opposite in direction and equal in size. They are considered as a state of equilibrium. Balanced forces are unable to change the motion or direction of an object i.e. they keep an object moving at a constant velocity.
When forces are balanced, they cancel each other out, resulting in no change in motion for the object they are acting on. Unbalanced forces do not cancel each other out, and result in a change in motion for the object they are acting on.
The characteristics of balanced forces are as follows:
The condition of rest or movement of an item does not change with balanced forcesBalanced forces do not permit a moving item to shift direction or speedThe net forces acting are zero with balanced forces.This suggests that an object on Earth will remain at rest if it experiences balanced forces.
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Earth's third atmosphere (atmosphere III) was a thick atmosphere of primarily water vapor and carbon dioxide.
What occurred during the third atmosphere on Earth?
Responses
a Increased oxygen allowed reptiles to thrive.
b Helium and hydrogen gases escaped Earth's gravity.
c Heat energy was retained, and water vapor condensed.
d Ultraviolet light split water vapor into hydrogen and oxygen.
During the third atmosphere on Earth, the same effect on Earth as it did on Mars. Heat energy was retained while water vapor was condensed.
What was the third atmosphere of Earth-like?The third atmosphere on the planet was created by volcanic outgassing and comet ice. This atmosphere had no oxygen, but plenty of carbon dioxide, water vapor, nitrogen gas, and methane gas.
When Earth's crust started to cool 2.5 billion years ago, there was less water vapor in the atmosphere, and more water condensed as liquid, resulting in the formation of Earth's third atmosphere.
This atmosphere was produced by volcanic outgassing, and it was the first to survive on Earth. A planet's atmosphere did not form through accretion while the formation of the planet's star.
Instead, its atmosphere forms as a result of internal volcanic activity or the aggregation of material from comet impacts.
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I NEED ASAP
What part of the water cycle involves convection transporting water?
A.
rainfall being absorbed by the ground
B.
rain forming and falling from the sky
C.
water evaporating and rising into the air
D.
flow of water down a stream
a 0.2 kg vase has a potential energy of 100j
The height above the ground in which the vase is raised is 51.02 m.
What is the height of the vase?
The height above the ground in which the vase is raised is calculated by applying the formula for gravitational potential energy.
Gravitational potential energy of an object is the energy possessed by the object due to the object's position above the ground.
Mathematically, the formula for gravitational potential energy is given as;
P.E = mgh
where;
m is the mass of the objectg is acceleration due to gravityh is the height above the ground in which the object is raisedThe given parameters include;
mass of the vase = 0.2 kg
potential energy of the vase = 100 J
acceleration due to gravity = 9.8 m/s²
h = P.E / mg
h = (100) / (0.2 x 9.8)
h = 51.02 m
Thus, the height of the vase is a function of the potential energy and mass of the vase.
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The complete question is below:
a 0.2 kg vase has a potential energy of 100j. What is the height of the vase?
Franscisco wants to invesitgate how changing the shape makes the same amount of ice melt faster or slower when placed in a water bath. Which two column headings describe controlled variable?
The two column headings describe controlled variable be: pressure and temperature.
What is control variable?
Anything kept constant or constrained in a research study is referred to as a control variable. Despite not being relevant to the study's objectives, this variable is controlled because it might have an impact on the results.
Variables can be controlled either directly by maintaining their value throughout a study (for example, by maintaining a constant room temperature in an experiment) or indirectly by using techniques like randomization or statistical control (e.g., to account for participant characteristics like age in statistical tests). Research biases like omitted variable bias can be avoided by including control variables in your analysis.
In the case of Franscisco wants to investigate how changing the shape makes the same amount of ice melt faster or slower when placed in a water bath, the two column headings describe controlled variable be: pressure and temperature.
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The L-shaped object in the figure(Figure 1) consists of three masses connected by light rods.
Part A
What torque must be applied to this object to give it an angular acceleration of 1.00 rad/s2 if it is rotated about the xaxis?
Part B
If it is rotated about the y axis?
Part C
If it is rotated about the z axis (which is through the origin and perpendicular to the plane of the figure)?
The torque required, obtained by finding the product of the moment of inertia and the angular acceleration are as follows;
The torque, τ, that must be applied to the object to give it an angular acceleration of 1.00 rad/s² are;
Part A
τₓ = 9.0 N·mPart B
[tex]\tau_y[/tex] = 10.0 N·mPart C
[tex]\tau_z[/tex] = 19 N·mWhat is an angular acceleration?Angular acceleration is the rate of change of angular velocity with time.
The torque is found from the product of the moment of inertia and the angular acceleration, therefore;
τ = I·α
Where;
τ = The torque
I = The moment of inertia of the mass
α = The angular acceleration
The moment of inertia of a point mass is; I = m·r²
Part A
The mass rotating about the x-axis, m = 9.0 kg
The distance to the point mass, r = 1.0 m
Therefore;
Iₓ = 9.0 kg × (1.0 m)² = 9.0 kg·m²
At α = 1.00 rad/s², we get;
τₓ = 9.0 kg·m² × 1.00 rad/s² = 9.0 N·mThe torque that must be applied to give it an angular acceleration of 1.00 rad/s² if it is rotated about the x-axis is; 9.0 N·m
Part B
If it is rotated about the y-axis, we get;
m = 2.5 kg
r = 2.0 m
[tex]I_y[/tex] = 2.5 kg × (2.0 m)² = 10.0 kg·m²
[tex]\tau_y[/tex] = 10.0 kg·m² × 1.00 rad/s² = 10.0 N·mPart C
The combined moment of inertia of the point masses are therefore;
[tex]I_z[/tex] = (9.0 + 10.0) kg·m² = 19.0 kg·m²
The torque required is therefore;
[tex]\tau_z[/tex] = 19.0 kg·m² × 1.00 rad/s² = 19.0 N·mLearn more about the moment of inertia of an object here:
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Expert help me i will mark the brainliest
Floods are the most common type of natural disaster, occurring when an overflow of water submerges normally dry land.
What is flood about?Floods are frequently caused in coastal areas by heavy rainfall, rapid snowmelt, or a storm surge from a tropical cyclone or tsunami.
Flooding has a negative impact on people's lives. Damage to property and infrastructure Road closures, erosion, and landslides are all possible.
It leads to destruction of houses and properties.
In order to control flooding, it is important to clear the gutters and have an adequate channel for water to pass.
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A fluid in an insulated, flexible bottle is heated by a high resistance wire and expands. If 9.0 kj of heat is applied to the system and it does 5.0 kj of work, how much does the internal (thermal) energy of the fluid change?
The change in the internal energy of the system is 4 kJ.
What is the first law of thermodynamics?We know that according to the first law of thermodynamics, energy can neither be created nor destroyed but it can be converted from one form to the other.
In this case we know that the internal energy can be obtained by the use of the formula;
ΔE = q + w
ΔE = Change in internal energy
q = Heat absorbed or evolved
w = work done
Where;
q = 9.0 kJ
w = 5.0 kJ
It then follows that;
ΔE = 9 - 5
ΔE = 4 kJ
The gas expands hence the work done is negative.
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The speeds of a 600-kg roller coaster car at the top of three consecutive hills are shown below. The radii of the hills are shown. Determine the acceleration, net force, and normal force experienced by the car at the top of each hill.
Answer:
they will fly
Explanation:
yes flying is fun
The acceleration, net force, and normal force by the car at the top of hill A are 4.5 meter/second² , 3180 N and 3180 N.
The acceleration, net force, and normal force by the car at the top of hill B are 4.17 meter/second² , 3379N and 3379 N.
The acceleration, net force, and normal force by the car at the top of hill C are 4.0 meter/second² , 3480 N and 3480 N.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
On hill A;
The centripetal acceleration = v²/r = 6²/8 meter/second² = 4.5 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.5) N = 3180 N.
The normal force = 3180 N
On hill B;
The centripetal acceleration = v²/r = 5²/6 meter/second² = 4.17 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.17) N = 3379 N.
The normal force = 3379 N.
On hill A;
The centripetal acceleration = v²/r = 4²/4 meter/second² = 4.0 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.0) N = 3480 N.
The normal force = 3480 N.
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Earth’s surface contains a variety of landforms, formed by weathering and erosion. Which of the following describes a change to Earth’s surface due to weathering? Choose the three that apply.
The following describes a change to Earth’s surface due to weathering include the following below:
A. plants creating a crack in a rock formation
B. rocks along the beach being reshaped by wave action.
F. glaciers scraping rocks across the land
What is Weathering?This is referred to as the process which involves the breaking down of rocks and minerals on Earths surface as a result of certain factors such as rain, glacier etc. They form cracks when they come in contact with rocks afterf a given period of time before they are disintegrated.
Weathering occurs when plants creating a crack in a rock formation and also when the rocks along the beach are being reshaped by wave action.It also involves the glaciers scraping rocks across the land which is therefore the reason why option A, B and F was chosen as the correct choice.
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The options are:
A. plants creating a crack in a rock formation
B. rocks along the beach being reshaped by wave action
C. sand being blown to a new location by the wind
D. sediments moved from place to place by a river
E. rain washing soil down a steep hill
F. glaciers scraping rocks across the land
A uniform 1.2-kg rod that is 0.67 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both springs hang straight down from the ceiling. The springs have identical lengths when they are unstretched. Their spring constants are 65 N/m and 30 N/m. Find the angle that the rod makes with the horizontal.
The angle that the rod makes with the horizontal is 9⁰.
What is the vertical direction for left spring?The vertical direction of the left spring is determined by applying the principle of equilibrium force as shown below.
The given parameters;
mass of the rod, m = 1.2 kgweight of the rod, w = mg = 1.2 x 9.8 = 11.76 Nspring constant for left spring, K_L = 65 N/mspring constant for right spring, K_r = 30 N/mstretch in the left spring, = X_Lstretch in the right spring, = X_r length of the rod, L = 0.67 mangle the rod makes with the horizontal, θ = ?Apply the principle of equilibrium of force in vertical direction for left spring;
K_L(X_L) = 0.5(W)
65(X_L) = 0.5(11.76)
X_L = 5.88/65
X_L = 0.09 m
Apply the principle of equilibrium of force in vertical direction for right spring;
K_r(X_r) = 0.5(W)
30(X_r) = 0.5(11.76)
X_r = 5.88/30
X_r = 0.196 m
The angle made with the horizontal is calculated as;
θ = arc tan(X_r - X_L) / L
θ = arc tan[(0.196 - 0.09) / 0.67]
θ = arc tan(0.158)
θ = 8.99⁰
θ ≈ 9⁰
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6. Mikey can kick the ball to Sage with a force of 20 N, making it travel 60m. Give the work done on the ball.
Answer:
Explanation:
Given:
F =20 N
D = 60 m
________
W - ?
W = F·D = 20·60 = 1 200 J
Only the first problem below please thank you so much
The initial speed of the second ball is c. 26.8 m/s
What is speed?Speed is the distance per unit time moved by an object/
How to find the initial speed of the ball?Since the ball is a projectile, to find the initial speed of the second ball, we need to find the maximum height of the first ball using
h = u²sin²Ф/2g where
u = initial velocity of ball = 32 m/s, Ф = angle of projection = 57° and g = acceleration due to gravity = 9.8 m/s²Substituting the values of the variables into the equation, we have
h = u²sin²Ф/2g
h = (32 m/s)²× (sin57°)²/(2 × 9.8 m/s²)
h = 1024 m²/s²× (0.8387)²/(19.6 m/s²)
h = 1024 m²/s²× (0.7034)/(19.6 m/s²)
h = 720.249 m²/s²/(19.6 m/s²)
h = 36.75 m
Now, since a second projectile is thrown vertically to the same maximum height, we need to find its initial speed.
Using the equation of motion v² = u² - 2gh where
u = initial speed, v = speed at maximum height = 0 m.s, g = acceleration due to gravity = 9.8 m/s² and h = maximum height = 36.75 mMaking u subject of the formula, we have
u = √(v² + 2gh)
Substituting the values of the variables into the equation, we have
u = √(v² + 2gh)
u = √[(0 m/s)² + 2 × 9.8 m/s² × 36.75 m]
u = √[0 m²/s² + 19.6 m/s² × 36.75 m]
u = √[720.3 m²/s²]
u = 26.84 m/s
u ≅ 26.8 m/s
So, the initial speed of the second ball is c. 26.8 m/s
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An ice hockey player begins at one goal and skates forward at constant speed to the other goal, 54 meters away, in a time of 9
seconds. He then instantly reverses direction and and skates 27 m backwards, in an additional 6 seconds.
Considering "forwards" to be the positive direction, what is the player's total displacement and average velocity over the whole 15
seconds?
Answer:21
Explanation:
it is trust
The moon's gravity is one-sixth that of the earth. How does the period of a 0.50m long pendulum on the moon compare to the period of the same pendulum on Earth?
Question 20 options:
The period is the same on the moon and on Earth.
The period on Earth is longer.
There isn't enough information to answer the question.
The period on the moon is longer.
The period on the moon is longer. So, the option(D) is correct.
What is a simple pendulum?A basic pendulum is a machine in which the point mass is hung from a fixed support by a light, inextensible string. The mean position of a simple pendulum is shown by a vertical line flowing through a fixed support.
The length of the simple pendulum, abbreviated L, is the vertical distance between the point of suspension and the suspended body's center of mass (when it is in mean position). The resonant mechanism supporting this type of pendulum has a single resonant frequency.
Time period of a pendulum is given by: T = 2π√(l/g)
Where: l = length of the pendulum and g = acceleration due to gravity.
As the moon's gravity is one-sixth that of the earth, we can conclude from the expression of pendulum that the period on the moon is longer.
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if you walk 6 km at an average speed of 3 km/h how much time does it take
Answer:
7,229sec
Explanation:
first convert 6km to m and km/h to m/s
1km = 1000m
6km = 6 × 1000m = 6000m
3km/h to m/s
3 × 1000m/ 60min × 60sec = 3000m/3600sec = 0.83m/s
Time=?
distance= average speed/velocity × Time
6000 = 0.83 × t
t=6000/0.83
t= 7,229 sec
or 120min 29sec
Bryan rolls a 2kg ball across a rough, grassy field. The field slows the ball with an acceleration of -0.5 m/s^2.
a. Draw the FBD
b. Determine the frictional force the field acts on the ball.
The drawing of free body diagram is attached in answer.
The frictional force the field acts on the ball is 1 newton.
What is acceleration?
Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the ball: m = 2 kg.
Acceleration of the ball during slow down: a = -0.5 m/s².
We have to find: the frictional force the field acts on the ball: f =?
In this case, the frictional force the field acts on the ball: f = mass × acceleration = 2 kg × 0.5 m/s² = 1 newton.
Hence, the frictional force the field acts on the ball is 1 newton.
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Identify the element by its symbol and name after looking at the element model pictured below. Symbol: Name:
The atom that has been shown is an atom of carbon(C).
What is the atom?We know that in an atom is the smallest particle of a substance that can be able to take part in a chemical reaction. In this case, we have a an atom that have been shown. As expected, the protons that are in the atom have been shown as the circle that is in the innermost part of the image.
The electrons are found around the shells of the atom. The electrons that are in the shells of the atom must be equal to the number of protons that are in the atom of the element.
Given that the number of electrons must be equal to the number of protons and the number of protons gives us the identity of the element that have been shown in the image, we can conclude that this is an atom of carbon.
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.
A 2155 kg demolition ball swings at the end of a 17.5m cable on the arc of a vertical
circle. At the lowest point of the swing, the ball is moving at 8.6m/s. Determine the
tension in the cable at the lowest point. (Hint: T-mg =mv^2/r)
Answer:
Thread tension:
T = F + P = 9 108 + 21 120 ≈ 30 230 N
Explanation:
Given:
m = 2155 kg
R = 17.5 m
V = 8.6 m/s
g = 9.8 m/s²
_______________
T - ?
Modulus of centripetal force (force is directed towards the center of the circular arc):
[tex]F = \frac{m\cdot V^2}{R} = \frac{2155\cdot 8.6^2}{17.5} = 9108 N[/tex]
Ball weight (directed vertically down):
W = m·g = 2155·9.8 ≈ 21 120 N
Let's use the hint. Thread tension:
T = F + W = 9 108 + 21 120 ≈ 30 230 N
The tension in the cable at the lowest point of the swing is [tex]30248.196 N[/tex].
To determine the tension in the cable at the lowest point of the swing, we can use the hint provided:
[tex]T-mg=\frac{mv^{2}}{r}[/tex]
where T represents tension,
m is the mass of the demolition ball (2155 kg),
g is the acceleration due to gravity (approximately 9.8 m/s^2),
v is the velocity of the ball (8.6 m/s), and
r is the radius of the circular path (17.5 m).
Plugging in the given values, we have:
[tex]T-2155\times 9.81=\frac{2155\times 8.6^{2}}{17.5}[/tex]
[tex]T=30248.196 N[/tex]
Therefore, the tension in the cable at the lowest point of the swing is approximately [tex]30248.196 N[/tex].
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Which statement about dwarf planet locations is correct
The correct statement about dwarf planet locations is :
Ceres is found in the asteroid belt and Eris, Makemake, Haumea, and Pluto are found in the Kuiper Belt.
What are dwarf planets?A dwarf planet is described as a small planetary-mass object that is in direct orbit of the Sun, smaller than any of the eight classical planets but still a world in its own.
There are as of now five formally grouped dwarf planets in our solar system and they include:
Ceres, Pluto, Haumea, Makemake and Eris.
Ceres location is that it is situated inside the asteroid belt between the orbits of Mars and Jupiter, while the other smaller person planets are situated in the external nearby planetary group in, or close to, the Kuiper belt.
Another six articles are in all likelihood predominate planets, yet are sitting tight for official grouping, and there might be upwards of 10,000 diminutive person planets in the solar system.
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Complete question:
Which statement about dwarf planet locations is correct?
Eris is found in the Kuiper Belt and Makemake, Haumea, Ceres, and Pluto are found in the asteroid belt.
Ceres is found in the asteroid belt and Eris, Makemake, Haumea, and Pluto are found in the Kuiper Belt.
Ceres and Pluto are found in the Kuiper Belt and Makemake, Eris, and Haumea are found in the asteroid belt.
Haumea and Makemake are found in the asteroid belt and Pluto, Ceres, and Eris are found in the Kuiper Belt.
Help me please I need it as soon as possible
Answer: B im sorry if its wrong
Explanation:
A 100 Newton tin box is prevented from falling by holding it on both sides. If the pushing forces are 400 newtons each, what is the coefficient of friction?
The coefficient of friction is 0.125
What is the coefficient of friction?The friction coefficient is defined as the ratio of the frictional resistive force to the perpendicular force pushing the objects together. The friction coefficient is represented as, μ = f × N
where is the friction coefficient μ ,
F is the frictional force,
and N is the normal force.
As we know, 2f = W
and f = μ × N
Where, W = weight of tin box
Thus, the co-efficient of friction,
μ = W ÷ 2 N
μ = 100N ÷ (2 × 400 N)
μ = 0.125
Thus, the coefficient of friction is 0.125
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A sound pulse emitted underwater reflects off a school of fish and is detected at the same place 0.10 s later. How far away are the fish? (Assume the water temperature is 20 degrees C.)
I'll assume that the properties of the water are that sound waves in fresh water move at a speed of 1497 m/s at a temperature of 25 °C. If the speed is 0.01s, you must divide it by 100 to get 14.97; but, since it travels there and back in 0.01s, you must split it in half i.e 7.485m.
Without a medium, what kind of wave can travel?
Electromagnetic waves
In contrast to mechanical waves, electromagnetic waves can travel without a medium. This implies that electromagnetic waves can pass not only through solid objects like air and rock but also through empty space.
Why do electromagnetic waves not require a medium to travel?Answer and justification Since electromagnetic waves are not conveyed by the vibration of particles, they do not need a medium to travel. Electric and magnetic fields, which can exist anywhere, oscillate, creating waves. Waves can therefore exist in solids, liquids, gases, or empty space.
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The air of an average sneeze travels around 100 miles an hour. Rebecca believes a sneeze induced by a stimulant will produce air that travels at a faster speed than the typical 100 miles per hour. She designs an experiment to induce sneezing. She subjects four participants to different stimulants: pepper, bright light, pollen, and fizzy soda. Once a sneeze is induced, Rebecca measures how fast the air traveled through the nasal passage.
Which statement WOULD NOT be an appropriate hypothesis for Rebecca's experiment?
A Induced sneezes move air at a faster speed than naturally occurring sneezes.
B There is no difference in air speed of induced versus naturally occurring sneezes.
C Using pepper as a stimulant induces more sneezing than any other stimulants.
D All sneezes move air at the same rate of speed.
Based on the study conducted by Rebecca, the statement that would not be an appropriate hypothesis for Rebecca's experiment is:
Using pepper as a stimulant induces more sneezing than any other stimulant; option CWhat is a hypothesis?A hypothesis is an explanation that is given in the form of a statement to explain an observation based on limited evidence and which serves as a starting point for further investigation.
A hypothesis may or may not be true and must be investigated to prove or disprove it.
Experiments are conducted to prove or disprove a given hypothesis.
A hypothesis is divided into a null and an alternate hypothesis.
A null hypothesis is a hypothesis that state that the treatment given to the subjects of the experiment does not produce any significant effect.
An alternate hypothesis states that the treatment given to the subjects of the experiment produces significant effects on the subjects.
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Planet X has a mass m and a radius r. Planet Y has a mass ½ m and a radius ¼ r. An identical tennis ball of mass mt sits on both planets’ surfaces. How does the magnitude of the gravitational force on planet X compare to the magnitude of the gravitational force on planet Y?
The gravitational force on planet X is one-eight (¹/₈) of the magnitude of gravitational force on planet Y.
What is the gravitational force on both planets?
The gravitational force on each planet is directly proportional to the product of mass of the planet and the tennis ball and inversely proportional to the square of the radius of the planets.
F = GmM/r²
where;
G is universal gravitation constantm is the mass of the tennis ballM is the mass of the planetsr is the radius of the planetThe gravitational force on planet X is written as;
F_X = Gm(mt) / r²
where;
m is the mass of planet Xmt is the mass of the tennis ballr is the radius of the planet xThe gravitational force on planet Y is written as;
F_y = G(½m)(mt) / (¼r)²
F_y = ½(Gm(mt) / (¹/₁₆ r²)
F_y = (16 Gm mt)/(2r²)
F_y = 8(G m(mt) ) / r²
F_y = 8(F_X)
F_X = ¹/₈(F_Y)
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